Suppose I have created an spring application with following configurations
First::
<servlet>
<servlet-name>springweb</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>springweb</servlet-name>
<url-pattern>/app/*</url-pattern>
</servlet-mapping>
Spring will look for springweb-servlet.xml file. Then it will read all the bean difination from the file and creates bean objects
Here only single application context is created.
Second::
<servlet>
<servlet-name>springweb</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>springweb</servlet-name>
<url-pattern>/app/*</url-pattern>
</servlet-mapping>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/service-context.xml
</param-value>
</context-param>
Here first spring reads all the beans definations from service-context.xml file, which is the root spring context.
Then it reads all the bean definations from the springweb-servlet.xml file, which is the child spring context/WebApplicationContext.
Then all the merge the two parent-child context into one and create spring beans objects
Third::
What if I define the springweb-servlet.xml file in both place.
<servlet>
<servlet-name>springweb</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>springweb</servlet-name>
<url-pattern>/app/*</url-pattern>
</servlet-mapping>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/springweb-servlet.xml,
/WEB-INF/service-context.xml
</param-value>
</context-param>
Related
I'm trying to migrate a application I have in Jersey 1.19, jersey-spring and Spring 5.0.5 to using Jersey 2.25, jersey-spring3 and Spring 5.0.5 but I'm running into trouble.
I've changed the maven dependencies to use the new Jersey version, I run the tomcat and the console shows no problems, if I enter the manager gui I can see that the app is running, but when I try to access the context it just throws 404.
Any ideas as to what could be causing this problem?
jersey 1.19 web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<!-- This web.xml file is not required when using Servlet 3.0 container,
see implementation details http://jersey.java.net/nonav/documentation/latest/jax-rs.html#d4e194 -->
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
classpath:application-context.xml
</param-value>
</context-param>
<servlet>
<servlet-name>jersey-spring</servlet-name>
<servlet-class>com.sun.jersey.spi.spring.container.servlet.SpringServlet</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>io.redbee.challenge.socialmedia</param-value>
</init-param>
<init-param>
<param-name>com.sun.jersey.api.json.POJOMappingFeature</param-name>
<param-value>true</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>jersey-spring</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
<filter>
<filter-name>CorsFilter</filter-name>
<filter-class>org.apache.catalina.filters.CorsFilter</filter-class>
<init-param>
<param-name>cors.allowed.origins</param-name>
<param-value>http://localhost:3000</param-value>
</init-param>
<init-param>
<param-name>cors.allowed.methods</param-name>
<param-value>GET,POST,HEAD,OPTIONS,PUT</param-value>
</init-param>
<init-param>
<param-name>cors.allowed.headers</param-name>
<param-value>Content-Type,X-Requested-With,accept,Origin,Access-Control-Request-Method,Access-Control-Request-Headers,Authorization</param-value>
</init-param>
<init-param>
<param-name>cors.exposed.headers</param-name>
<param-value>Authorization</param-value>
</init-param>
<init-param>
<param-name>cors.support.credentials</param-name>
<param-value>true</param-value>
</init-param>
<init-param>
<param-name>cors.preflight.maxage</param-name>
<param-value>100</param-value>
</init-param>
</filter>
<filter-mapping>
<filter-name>CorsFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
</web-app>
jersey 2.25 web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<!-- This web.xml file is not required when using Servlet 3.0 container,
see implementation details http://jersey.java.net/nonav/documentation/latest/jax-rs.html#d4e194 -->
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
classpath:applicationContext-rest.xml
</param-value>
</context-param>
<servlet>
<servlet-name>jersey-spring</servlet-name>
<servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>jersey.config.server.provider.packages</param-name>
<param-value>io.redbee.challenge.socialmedia</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>jersey-spring</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
<filter>
<filter-name>CorsFilter</filter-name>
<filter-class>org.apache.catalina.filters.CorsFilter</filter-class>
<init-param>
<param-name>cors.allowed.origins</param-name>
<param-value>http://localhost:3000</param-value>
</init-param>
<init-param>
<param-name>cors.allowed.methods</param-name>
<param-value>GET,POST,HEAD,OPTIONS,PUT</param-value>
</init-param>
<init-param>
<param-name>cors.allowed.headers</param-name>
<param-value>Content-Type,X-Requested-With,accept,Origin,Access-Control-Request-Method,Access-Control-Request-Headers,Authorization</param-value>
</init-param>
<init-param>
<param-name>cors.exposed.headers</param-name>
<param-value>Authorization</param-value>
</init-param>
<init-param>
<param-name>cors.support.credentials</param-name>
<param-value>true</param-value>
</init-param>
<init-param>
<param-name>cors.preflight.maxage</param-name>
<param-value>100</param-value>
</init-param>
</filter>
<filter-mapping>
<filter-name>CorsFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
</web-app>
hi i am getting null pointer exception in my application , i want to know my web.xml is correct or wrong,also i am using jar files not MAVEN
`<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.4"xmlns="http://java.sun.com/xml/ns/j2ee"xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/n/j2ee/web-app_2_4.xsd"><context-param>
<param-name>contextConfigLocation</param-name>
<param-value>WEB-INF/Helloweb-servlet.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<listener>
<listener-class>org.springframework.web.context.request.RequestContextListener</listener-class>
</listener>
<servlet>
<servlet-name>Jersey Spring Web Application</servlet-name>
<servlet-class>com.sun.jersey.spi.spring.container.servlet.SpringServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>Jersey Spring Web Application</servlet-name>
<url-pattern>/webresources/</url-pattern>
</servlet-mapping><servlet>
<servlet-name>HelloWeb</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup> </servlet> <servlet-mapping><servlet-name>HelloWeb</servlet-name>
<url-pattern>*.jsp</url-pattern> </servlet-mapping></web-app>
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:/jpaContext.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<filter>
<filter-name>SpringOpenEntityManagerInViewFilter</filter-name>
<filter-class>org.springframework.orm.jpa.support.OpenEntityManagerInViewFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>SpringOpenEntityManagerInViewFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<servlet>
<servlet-name>fitTrackerServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/config/servlet-config.xml</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>fitTrackerServlet</servlet-name>
<url-pattern>*.html</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>fitTrackerServlet</servlet-name>
<url-pattern>/pdfs/**</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>fitTrackerServlet</servlet-name>
<url-pattern>/images/**</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>fitTrackerServlet</servlet-name>
<url-pattern>*.json</url-pattern>
</servlet-mapping>
<display-name>Archetype Created Web Application</display-name>
</web-app>
I was adding security to my demo application, (user-login) by using :this tutorial , I am getting error as: Cannot initialize context because there is already a root application context present - check whether you have multiple ContextLoader* definitions in your web.xml!
I have added my web.xml, Later i found this tutorial, then error was coming: No bean named 'springSecurityFilterChain' is defined. In the tutorial they explained
The MessageSecurityWebApplicationInitializer will automatically register the springSecurityFilterChain Filter for every URL in your application. If Filters are added within other WebApplicationInitializer instances we can use #Order to control the ordering of the Filter instances.
I didnot understand the above message please help me with this
Edit your fitTrackerServlet servlet as:
<servlet>
<servlet-name>fitTrackerServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/config/servlet-config.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
My file web.xml is
<!DOCTYPE web-app PUBLIC
"-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd" >
<web-app id="WebApp_1383925467813">
<display-name>Archetype Created Web Application</display-name>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
<url-pattern>/m/*</url-pattern>
<url-pattern>/t/*</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
Myeclipse reports this error:
The content of element type "servlet-mapping" must match
"(servlet-name,url-pattern)"
What's the problem?
Thank's
Please change your DTD to 3.0 version which allows multiple <url-pattern> tags inside <servlet-mapping>.
I have just made the version change in your web.xml placed it below
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
version="3.0">
<display-name>Archetype Created Web Application</display-name>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
<url-pattern>/m/*</url-pattern>
<url-pattern>/t/*</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
As per the DTD we can have only one <url-pattern> inside a <servlet-mapping> tag.
<!ELEMENT servlet-mapping (servlet-name, url-pattern)>
Rewrite your xml like:
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/m/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/t/*</url-pattern>
</servlet-mapping>
try to remove' / ' from name to you /m/*
and try error resolve
The content of element type "servlet-mapping" is incomplete, it must match "(servlet-name , -pattern)". error and I found this error is temp if you clean you clean your project by using clean option which you can find in the project section
My English is not good. Please understand it.
I'm in charge of maintaining a website built with Spring, tiles and ibatis frameworks.
The problem is all gif, js, etc... go through DispatcherServlet because most of the address of static resources are like /home/images/hbg_01.gif. the resource path is mapped by homeServlet.
But I'd like my static resource to be ignored by any Dispatcher servlet written in Web.xml.
I am new to J2EE. so if it's lack of information. please leave comment. I will give you anything if needed
here's my web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
version="3.0" metadata-complete="true">
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/xml/root-context.xml
/WEB-INF/xml/security.xml
</param-value>
</context-param>
<!-- Processes application requests -->
<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/xml/appServlet/servlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/app/*</url-pattern>
</servlet-mapping>
<servlet>
<servlet-name>adminServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/xml/adminServlet/servlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>adminServlet</servlet-name>
<url-pattern>/admin/*</url-pattern>
</servlet-mapping>
<servlet>
<servlet-name>homeServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/xml/homeServlet/servlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>homeServlet</servlet-name>
<url-pattern>/home/*</url-pattern>
</servlet-mapping>
<servlet>
<servlet-name>monitorServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/xml/monitorServlet/servlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>monitorServlet</servlet-name>
<url-pattern>/monitor/*</url-pattern>
</servlet-mapping>
<servlet>
<servlet-name>monitorDemoServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/xml/monitorDemoServlet/servlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>monitorDemoServlet</servlet-name>
<url-pattern>/monitor_demo/*</url-pattern>
</servlet-mapping>
<servlet>
<servlet-name>projectServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/xml/projectServlet/servlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>projectServlet</servlet-name>
<url-pattern>/project/*</url-pattern>
</servlet-mapping>
<context-param>
<param-name>log4jConfigLocation</param-name>
<param-value>/WEB-INF/log4j.properties</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.util.Log4jConfigListener</listener-class>
</listener>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<filter>
<description></description>
<display-name>encodingFilter</display-name>
<filter-name>encodingFilter</filter-name>
<filter-class>org.springframework.web.filter.CharacterEncodingFilter</filter-class>
<init-param>
<param-name>encoding</param-name>
<param-value>EUC-KR</param-value>
</init-param>
<init-param>
<param-name>forceEncoding</param-name>
<param-value>true</param-value>
</init-param>
</filter>
<filter-mapping>
<filter-name>encodingFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/home/*</url-pattern>
<url-pattern>/project/*</url-pattern>
<url-pattern>/admin/*</url-pattern>
<url-pattern>/monitor/*</url-pattern>
<url-pattern>/monitor_demo/*</url-pattern>
</filter-mapping>
<session-config>
<session-timeout>180</session-timeout>
</session-config>
</web-app>
mvc-static-resources can be of help. Pl. refer :
http://static.springsource.org/spring/docs/3.0.5.RELEASE/spring-framework-reference/html/mvc.html#mvc-static-resources
As you told /home/images/hbg_01.gif. The resource path is mapped by homeServlet.
change url pattern /home/* to avoid mapped to homeServlet like:
<servlet-mapping>
<servlet-name>homeServlet</servlet-name>
<url-pattern>/home/anything/*</url-pattern>
</servlet-mapping>