I want to search name which start with '%' like '%smit' in oracle sql
i have tried with escape '%\%' but not able to find..
You need to tell Oracle that you are using an escape character:
where name like '\%%' escape '\'
Anything in the search pattern after the character specified through the escape option will be treated "as is". So the above searches for any value that starts with the character %. The second % is again treated as a regular wildcard (because it's not prefixed with the escape character)
You can also choose a different escape character:
where name like '#%%' escape '#'
This is nothing Oracle specific, this is how the LIKE operator is defined in the SQL standard
Related
In Oracle '%' stands for any characters in that position.
Example:
Select * from table where id like '%1'
This stands for anything behind the number 1 : XXXXXXXXXXXX1 99999999991.
Is there any other character to express only 1 character ?.
Example of what I mean: (im going to use ~ as that reserved character)
Select * from table where id like '~1'
In this case only 91, x1, X1... etc would enter the select, but XX1 woudn't as you only used one ~.
Select * from table where id like '~~~1'
xxx1, 9991, 8881, etc....
Hope I explained myself, english is not my native language.
Only one wildcard character is represented by underscore, _
You can refer to Oracle's LIKE condition documentation:
like_condition::=
In this syntax:
char1 is a character expression, such as a character column, called the search value.
char2 is a character expression, usually a literal, called the pattern.
esc_char is a character expression, usually a literal, called the escape character.
[...]
The pattern can contain special pattern-matching characters:
An underscore (_) in the pattern matches exactly one character (as opposed to one byte in a multibyte character set) in the value.
A percent sign (%) in the pattern can match zero or more characters (as opposed to bytes in a multibyte character set) in the value. The pattern '%' cannot match a null.
Use an _ underscore.
I am trying to insert a space before the capital letters in oracle. I thought it would be easy using a regexp_replace, but I can't seem to get a proper back reference to the character I am replacing.
select trim(regexp_replace ('FreddyFox', '[A-Z]', ' \1' )) from dual;
Result: '\1reddy \1ox'
I have tried multiple variants of a back reference but I can't seem to find something that satisfies Oracle.
I did look at multiple SO answers but I could not figure out what is wrong.
e.g. regexp_replace: insert a space in a string if not already present
TRIM(regexp_replace ('FreddyFox', '([A-Z])', ' \1' ))
TRIM enables you to trim leading or trailing characters (or both) from a character string. If trim_character or trim_source is a character literal, then you must enclose it in single quotes. Default is both.
regexp_replace ('FreddyFox', '^([A-Z])', ' \1')
I have a teradata database name that contains a dash character -.
Searched the web but in vain. Does somebody know how can you escape the special characters in jdbc connection string? The string looks as follows:
jdbc:teradata://HostName/DATABASE=Database-Name
When I create a connection with this url I get syntax error. Also tried to put database parameter in single or double quotes, and to surround the special charachers with { }.
Thanks for help!
Finally found the answer here: https://jira.talendforge.org/browse/TDI-18863. The correct way is to enclose both parameter name and value in single quotes:
jdbc:teradata://HostName/'DATABASE=Database-Name'
Update: No, this does not work, see comment below.
Answering my own question:
My problem was that I didn't realise that my database name had some trailing whitespaces in the end.
TeraDriver uses single quotes to escape spaces and commas. This means that the database name should be in single quotes. If there are no single quotes, spaces and commas are considered to be the end of parameter value. If there are single quotes in database name, they should be presented as two single quote characters.
'Database-Name '
Whatever is within single quotes will be used with sql query: "database Database-Name". To escape '-' we need double quotes. So both single and double quotes in correct order should be used:
"jdbc:teradata://HostName/DATABASE='\"Database-Name\"'"
Have you tried a \ character which is supposed to be an escape character in Java?
jdbc:teradata://HostName/DATABASE=Database\-Name
I am creating a custom code highlight for notepad++. What I want to do is the following:
some fieldnames are writen in the code with a ' in front of their name, for exampe
if 'variable = "test" then ...
I would like to highlight these words, but notepad++ does not seem to allow a delimiter starting with ' and ending with a space, not does it allow space as an escape character. Also, using ' as a keyword and enabling prefix mode has no effect. Anyone has a suggestion? Should I use another expression to let notepad recognise the space/' ?
Thanks in advance!
If you only need to highlight a single word, you can use a keyword in prefix mode. However when using single or double quotes in a keyword, they need to be escaped with a backslash. So your keyword would be:
\'
This may not be possible in notepad++. I can get the behavior you want using a character other than a single quote, like a back-tic, but it doesn't seem to work with single or double quotes. I suspect those characters are treated special within the syntax highlighter.
When I am trying to execute INSERT statement in oracle, I got SQL Error: ORA-00917: missing comma error because there is a value as Alex's Tea Factory in my INSERT statement.
How could I escape ' ?
To escape it, double the quotes:
INSERT INTO TABLE_A VALUES ( 'Alex''s Tea Factory' );
In SQL, you escape a quote by another quote:
SELECT 'Alex''s Tea Factory' FROM DUAL
Instead of worrying about every single apostrophe in your statement.
You can easily use the q' Notation.
Example
SELECT q'(Alex's Tea Factory)' FROM DUAL;
Key Components in this notation are
q' which denotes the starting of the notation
( an optional symbol denoting the starting of the statement to be fully escaped.
Alex's Tea Factory (Which is the statement itself)
)' A closing parenthesis with a apostrophe denoting the end of the notation.
And such that, you can stuff how many apostrophes in the notation without worrying about each single one of them, they're all going to be handled safely.
IMPORTANT NOTE
Since you used ( you must close it with )', and remember it's optional to use any other symbol, for instance, the following code will run exactly as the previous one
SELECT q'[Alex's Tea Factory]' FROM DUAL;
you can use ESCAPE like given example below
The '_' wild card character is used to match exactly one character, while '%' is used to match zero or more occurrences of any characters. These characters can be escaped in SQL.
SELECT name FROM emp WHERE id LIKE '%/_%' ESCAPE '/';
The same works inside PL/SQL:
if( id like '%/_%' ESCAPE '/' )
This applies only to like patterns, for example in an insert there is no need to escape _ or %, they are used as plain characters anyhow. In arbitrary strings only ' needs to be escaped by ''.
SELECT q'[Alex's Tea Factory]' FROM DUAL
Your question implies that you're building the INSERT statement up by concatenating strings together. I suggest that this is a poor choice as it leaves you open to SQL injection attacks if the strings are derived from user input. A better choice is to use parameter markers and to bind the values to the markers. If you search for Oracle parameter markers you'll probably find some information for your specific implementation technology (e.g. C# and ADO, Java and JDBC, Ruby and RubyDBI, etc).
Share and enjoy.
Here is a way to easily escape & char in oracle DB
set escape '\\'
and within query write like
'ERRORS &\\\ PERFORMANCE';