Solving foobar in Ruby? - ruby

Question

So far I have been able to get the numbers to print properly but I don't know how to loop them.
puts "Please enter a number"
val1 = gets.to_i
val2 = val1 % 3
val3 = val1 % 5
def ordinal(a,b,c)
if b == 0 && c == 0
return "foobar"
elsif b == 0
return "foo"
elsif c == 0
return "bar"
else
return a
end
end
val5 = ordinal(val1,val2,val3)
puts "#{val5}"
I also made a loop that works but it won't recognize strings.
n = 0
x = gets.to_i
while n != x
puts "#{n}"
n = n + 1
end
How do I combine my method and loop? Or is there any other way to solve this? But I would prefer if you solve it using my code IF its any good off course so that I can understand it better.

Answer 1

As par your comments, the loop part is easy when leveraging Integer#times.
This is what you have that works for you:
puts "Please enter a number"
val1 = gets.to_i
val2 = val1 % 3
val3 = val1 % 5
def ordinal(a,b,c)
if b == 0 && c == 0
return "footer"
elsif b == 0
return "foo"
elsif c == 0
return "bar"
else
return a
end
end
val5 = ordinal(val1,val2,val3)
puts "#{val5}"
Right now you're just running through the final number. Try using the Integer#times to run a loop up to the number...:
puts "Please enter a number"
num = gets.to_i
num.times do |a|
a += 1 # counting is done from 0 to n-1
b = a % 3
c = a % 5
if b == 0 && c == 0
print "foobar "
elsif b == 0
print "foo "
elsif c == 0
print "bar "
else
print "#{a} "
end
end
print "\n"
Personally I would probably have written this a bit differently, but I guess it's sound enough.
I would probably write something messy because I hate long if...else statements...:
def foo_bar n
n.times {|i| i+=1; print( (i%15==0 && "FooBar ") || (i%3==0 && "Foo ") || (i%5 ==0 && "Bar ") || ("#{i} ") ) }
print "\n"
end
puts "Enter number:"
foo_bar gets.to_i

Answer 2

You can do this too:
def foobar n
n.times do |i|
i += 1
num = ""
num << "Foo" if i % 3 == 0
num << "Bar" if i % 5 == 0
num = i.to_s if num == ""
puts num
end
end
foobar 15
The logic is simpler than Myst's.
You don't need to test if it's a factor of 15.
Output:
1
2
Foo
4
Bar
Foo
7
8
Foo
Bar
11
Foo
13
14
FooBar
=> 15