Total newb here and other fizzbuzz issue - ruby

I'm trying to write a looping fizzbuzz code that ends with the user_input's number. So far the code works, but it loops the number of times you put in for the user_input, not end at the user_input's limit. For example, if I type in 25, it will loop 25 times, and not end at 25. How do I set the parameters/range?
Here is my code:
puts("Please select a number that is at least 25. This is the limit for the fizzbuzz game.")
user_input = gets().chomp().to_i
if
user_input < 25
puts("Please select a larger number.")
else
user_input >= 25
user_input = user_input
counter = 1
while counter < user_input
puts(counter)
counter = counter + 1
(1..user_input).step do |i|
if i % 3 == 0 && i % 5 == 0
puts("fizzbuzz")
elsif i % 3 == 0
puts("fizz")
elsif i % 5 == 0
puts("buzz")
else
puts(i)
end
end
end
end

It is optional to write () when you send no parameters to a method and usually discouraged
You shouldn't use else user_input >= 25, else is enough
user_input = user_input is totally useless line
while cycles with counters isn't the way rubists code, prefer iterators. Moreover, you shouldn't have while here at all
puts 'Please select a number that is at least 25. This is the limit for the fizzbuzz game.'
user_input = gets.chomp.to_i
if user_input < 25
puts 'Please select a larger number.'
else
1.upto(user_input) do |i|
if i % 3 == 0 && i % 5 == 0
puts 'fizzbuzz'
elsif i % 3 == 0
puts 'fizz'
elsif i % 5 == 0
puts 'buzz'
else
puts i
end
end
end
optionally, you can use case-when instead of multiple elsif statements:
puts 'Please select a number that is at least 25. This is the limit for the fizzbuzz game.'
user_input = gets.chomp.to_i
if user_input < 25
puts 'Please select a larger number.'
else
1.upto(user_input) do |i|
case
when [3, 5].all? { |n| i % n == 0 }; puts 'fizzbuzz'
when i % 3 == 0; puts 'fizz'
when i % 5 == 0; puts 'buzz'
else; puts i
end
end
end

Related

Can you someone support me to use ordinal in while loop in Ruby?

I am having a difficult time figuring ordinal in the program below. I need to use the ordinal in the loop statement. When I print statement, It print out backward like 3rd, 2nd, 1st, and so on.
I tried changing my loop statment from (number -= 1) to (number += 1) but that would make infinite while loop. Can someone give me feedback on what I can do here? Thank you.
class Integer
def ordinal
case self % 10
when 1
return "#{self}st"
when 2
return "#{self}nd"
when 3
return "#{self}rd"
else
return "#{self}th"
end
end
end
puts "Let's play a numbers game."
print "How many numbers would you like to enter? >"
number = gets.chomp.to_i
while number >= 1
print "\n\nEnter the #{number.ordinal} positive integer:"
user_int = gets.chomp.to_i
number -= 1
if user_int % 3 == 0
print "#{user_int} is divisible by 3."
else
print "#{user_int} is not divisible by 3."
end
end
puts "\n\nEnd of the Game"
First I'd suggest you to patch Integer class in this way:
module MyIntegerPatch # <------ a custom module
def to_ordinal # <------ to_ordinal is better
case self % 10
when 1
return "#{self}st"
when 2
return "#{self}nd"
when 3
return "#{self}rd"
else
return "#{self}th"
end
end
end
Integer.include MyIntegerPatch # <------ "patch" the class
Then for your loop just use a Range:
(1..number).each do |n| # <---- a range here
puts "\n\nEnter the #{n.to_ordinal} positive integer:"
user_int = gets.chomp.to_i
if user_int % 3 == 0
puts "#{user_int} is divisible by 3."
else
puts "#{user_int} is not divisible by 3."
end
end
Maybe you can try below, use the ruby style times to control
class Integer
def ordinal
case self % 10
when 1
"#{self}st"
when 2
"#{self}nd"
when 3
"#{self}rd"
else
"#{self}th"
end
end
end
puts "Let's play a numbers game."
print 'How many numbers would you like to enter? >'
number = gets.chomp.to_i
number.times do |time|
print "\n\nEnter the #{(time + 1).ordinal} positive integer:"
user_int = gets.chomp.to_i
if user_int % 3 == 0
print "#{user_int} is divisible by 3."
else
print "#{user_int} is not divisible by 3."
end
end
puts "\n\nEnd of the Game"

FizzBuzz Program Output in form of table

I have written the logic for the program to perform FizzBuzz operations:
fizzbuzz
module FizzBuzz
class Operation
def input
puts 'Enter a number upto which Fizz/Buzz needs to be printed'
num = gets.chomp.to_i
fizzbuzz_function(num)
end
def fizzbuzz_function(num)
for i in 1..num
if i % 3 == 0 && i % 5 == 0
puts 'FizzBuzz'
elsif i % 3 == 0
puts 'Fizz'
elsif i % 5 == 0
puts 'Buzz'
else
puts i
end
end
end
end
res = Operation.new
res.input
end
But I am trying to print the output in form of a table.
Here is FizzBuzz in form of a table:
def fizzbuzz_gen(num)
Enumerator.new do |y|
(1..num).each do |i|
if i % 3 == 0 && i % 5 == 0
y << 'FizzBuzz'
elsif i % 3 == 0
y << 'Fizz'
elsif i % 5 == 0
y << 'Buzz'
else
y << i.to_s
end
end
end
end
def fill_to_width(width, e)
result = ""
future_length = -1
while result.length + future_length < width
result << e.next
result << " "
future_length = e.peek.length
end
result.center(width)
end
def format_table(num)
fb = fizzbuzz_gen(num)
begin
puts fill_to_width(75, fb)
puts fill_to_width(75, fb)
loop do
puts "%10s%s%31s%s" % ["", fill_to_width(12, fb), "", fill_to_width(12, fb)]
end
rescue StopIteration
end
end
format_table(100)
There may be less numbers output than specified, in order for one leg not to be shorter than another.

Fizz Buzz in Ruby for dummies

Spoiler alert: I am a true novice. Tasked with figuring out fizz buzz in
ruby for a class and while I have found more than a few versions of code
that solve the problem, my understanding is so rudimentary that I cannot
figure out how these examples truly work.
First question(refer to spoiler alert if you laugh out loud at this):
How do i print out numbers one through 100 in Ruby?
Second question: can 'if else" be used to solve this? My failed code is
below(attachment has screen shot):
puts('Lets play fizzbuzz')
print('enter a number: ')
number = gets()
puts(number)
if number == % 3
puts ('fizz')
elsif number == % 5
puts ('buzz')
elsif number == %15
puts ('fizzbuzz')
end
Thanks,
Thats ok being a novice, we all have to start somewhere right? Ruby is lovely as it get us to use blocks all the time, so to count to 100 you can use several methods on fixnum, look at the docs for more. Here is one example which might help you;
1.upto 100 do |number|
puts number
end
For your second question maybe take a quick look at the small implementation i whipped up for you, it hopefully might help you understand this problem:
1.upto 100 do |i|
string = ""
string += "Fizz" if i % 3 == 0
string += "Buzz" if i % 5 == 0
puts "#{i} = #{string}"
end
First question: this problem has several solutions. For example,
10.times { |i| puts i+1 }
For true novice: https://github.com/bbatsov/ruby-style-guide
another method that can be helpful :
puts (1..100).map {|i|
f = i % 3 == 0 ? 'Fizz' : nil
b = i % 5 == 0 ? 'Buzz' : nil
f || b ? "#{ f }#{ b }" : i
}
As a one liner
(1..100).map { |i| (i % 15).zero? ? 'FizzBuzz' : (i % 3).zero? ? 'Fizz' : (i % 5).zero? ? 'Buzz' : i }
In Regards to your failed code, your conditional statements should be like this:
if number % 3 == 0
puts "Fizz"
end
if number % 5 == 0
puts "Buzz"
end
You don't want the last elsif statement because it will never get executed
(if a number is not divisible by 3 or divisible by 5, then it is certainly not divisible by 15)
Adjust for this by changing the second elsif to simply and if and if the number is divisble by 5 and not by 3, then Fizz will not be outputted but Buzz Will be
I'm just showing you how to correct your code, but as others have pointed out, there are far more elegant solutions in Ruby.
Not the most beautiful way to write it but good for beginners and for readability.
def fizzbuzz(n)
(1..n).each do |i|
if i % 3 == 0 && i % 5 == 0
puts 'fizzbuzz'
elsif i % 3 == 0
puts 'fizz'
elsif i % 5 == 0
puts 'buzz'
else
puts i
end
end
end
fizzbuzz(100)
1.upto(100).each do |x| # Question #1 The 'upto' method here takes is
# what you would use to count in a range.
if (x % 3 == 0) && (x % 5 == 0)
puts " Fizzbuzz"
elsif x % 3 == 0
puts " Fizz"
elsif x % 5 == 0
puts " Buzz"
else
puts x
end
end
Question #2 Yes you can but I would look for a more elegant way to write this as a part of a definition like
def fizzbuzz(last_number)
1.upto(last_number).each do |x|
if (x % 3 == 0) && (x % 5 == 0)
puts " Fizzbuzz"
elsif x % 3 == 0
puts " Fizz"
elsif x % 5 == 0
puts " Buzz"
else
puts x
end
end
end
This is the answer that helped me to understand that no variables are being created with the .each method. Sorry about my indenting. Still learning how to use Stackoverflow text editing.
As for a more complex solution, that's one way you could build
a simple DSL for quickly modifying the FizzBuzz programme (adding new divisors with their own keywords)
class FizzBuzzer
# #return [Hash{String, Symbol => Integer}]
attr_reader :keywords
# #param keywords [Hash{String, Symbol => Integer}]
def initialize(keywords)
#keywords = keywords
end
# #param range [Range]
# #return [void]
def call(range)
range.each do |num|
msg = ''
#keywords.each do |name, divisor|
msg << name.to_s if (num % divisor).zero?
end
msg = num if msg.empty?
puts msg
end
puts
end
end
# create a fizz buzzer with custom keywords for divisors
CLASSIC_FIZZ_BUZZER = FizzBuzzer.new Fizz: 3, Buzz: 5
# print for a particular range
CLASSIC_FIZZ_BUZZER.call(1..25)
# you can easily define an extended fizz buzzer
EXTENDED_FIZZ_BUZZER = FizzBuzzer.new Fizz: 3, Buzz: 5, Bazz: 7, Fuzz: 11 # print 'Fuzz' when divisible by 11
EXTENDED_FIZZ_BUZZER.call(1..25)
Here's a quite elegant solution.
(1..100).each do |num|
msg = ''
msg << 'Fizz' if (num % 3).zero?
msg << 'Buzz' if (num % 5).zero?
msg = num if msg.empty?
puts(msg)
end
It can be even more compact
(1..100).each do |num|
(msg ||= '') << 'Fizz' if (num % 3).zero?
(msg ||= '') << 'Buzz' if (num % 5).zero?
puts msg || num
end
FizzBuzz
(1..100).each do |num|
if num % 3 == 0 && num % 5 == 0
puts "#{num}. FIZZBUZZ!"
elsif num % 3 == 0
puts "#{num}. FIZZ!"
elsif num % 5 == 0
puts "#{num}. BUZZ!"
else
puts "#{num}."
end
end
First question:
for i in 1..100
puts i
end
Here is my most "idiomatic ruby" solution:
class FizzBuzz
def perform
iterate_to(100) do |num,out|
out += "Fizz" if num.divisable_by?(3)
out += "Buzz" if num.divisable_by?(5)
out || num
end
end
def iterate_to(max)
(1..max).each do |num|
puts yield num,nil
end
end
end
class Fixnum
def divisable_by?(num)
self % num == 0
end
end
class NilClass
def +(other)
other
end
end
FizzBuzz.new.perform
And it works:
https://gist.github.com/galori/47db94ecb822de2ac17c

While loop continues despite conditions not being met?

When I run the game and type either "yes" or "no" at the end, it always reverts back to the start of the while loop at line 41, when the conditions for both that and the containing loop are not met.
replay = true
while replay
#Pre-var
print "What difficulty? (1 for easy, 2 for medium, or 3 for hard): "
difficulty = gets.chomp.to_i
until difficulty == 1 || difficulty == 2 || difficulty == 3 do
print "Please type either 1, 2, or 3: "
difficulty = gets.chomp.to_i
end
#Variables
if difficulty == 1
r = Random.new
number = r.rand(100..1000)
puts "You have 15 guesses. "
print "Guess a number with three digits: "
within_num = 50
elsif difficulty == 2
r = Random.new
number = r.rand(1000..10000)
puts "You have 15 guesses. "
print "Guess a number with four digits: "
within_num = 500
elsif difficulty == 3
r = Random.new
number = r.rand(10000..100000)
puts "You have 15 guesses. "
print "Guess a number with five digits: "
within_num = 5000
end
guess = ""
num_guess = 0
guess_array = Array.new
array_location = 0
count_through = 0
array_print = count_through - 1
replay_inner = true
#Body
puts number
while num_guess <= 14 || replay_inner == true #Keeping as <= 14 as to avoid unnecessarily rewriting code, still gives 15 guesses
guess = gets.chomp.to_i
if guess > number * 2
print "That is more than double the number. Guess again: "
elsif guess < number / 2
print "That is less than half the number. Guess again: "
elsif guess > number && guess < number + within_num #within_num: 50 for easy, 500 for medium, 5000 for hard
print "You are close. That is too big. Guess again: "
elsif guess < number && guess > number - within_num
print "You are close. That is too small. Guess again: "
elsif guess < number
print "That is too small. Guess again: " #Hinting the user to how close they are.
elsif guess > number
print "That is too big. Guess again: "
elsif guess == number
puts "Congragulations! You win!"
print "Your "
print guess_array.length
print " incorrect guesses were: "
if num_guess == 0
sleep(0.5)
print "... Oh."
else
while count_through < num_guess #Loop to relay user's guesses with a delay of 0.5 seconds
print guess_array[count_through]
if count_through == num_guess - 2
print ", and "
elsif count_through == num_guess - 1
puts ". "
else
print ", "
end
count_through += 1
sleep(0.5)
end
puts "Would you like to play again? (yes/no)"
replay_answer = gets.chomp
until replay_answer == "yes" || replay_answer == "y" || replay_answer == "no" || replay_answer == "n" do
print "Please answer with yes, y, no, or n: "
replay_answer = gets.chomp
end
if replay_answer == "yes" || replay_answer == "y"
replay = true
puts "yes"
elsif replay_answer == "no" || replay_answer == "n" #Determining whether or not to replay
replay = false
puts "no"
end
end
end
guess_array.push guess
num_guess += 1
#puts num_guess
#puts guess_array[array_location]
array_location += 1
if num_guess >= 15 && guess != number
puts "Sorry, you lost. "
print "Your "
print guess_array.size
print " guesses were: "
while count_through < num_guess
print guess_array[count_through] #Same as loop above; for when player fails to guess correctly
if count_through == num_guess - 2
print ", and "
elsif count_through == num_guess - 1
puts ". "
else
print ", "
end
count_through += 1
sleep(0.5)
end
puts "Would you like to play again? (yes/no)"
replay_answer = gets.chomp
until replay_answer == "yes" || replay_answer == "y" || replay_answer == "no" || replay_answer == "n" do
print "Please answer with yes, y, no, or n: "
replay_answer = gets.chomp
end
if replay_answer == "yes" || replay_answer == "y"
replay = true
replay_inner = true
puts "yes"
elsif replay_answer == "no" || replay_answer == "n" #Determining whether or not to replay
replay = false
replay_inner = false
puts "no"
end
end
end
I think the condition in the while should be:
numberGuess<=14 && replay_inner == true
The way you and especially your fellow programmers will find this and future bugs is by properly commenting your code, e.g.:
# ask the user about an optional replay
replay_answer = gets.chomp
# only accept yes/y/no/n
until replay_answer == "yes" || replay_answer == "y" || replay_answer == "no" || replay_answer == "n" do
print "Please answer with yes, y, no, or n: "
replay_answer = gets.chomp
end
## recoded this to a case, as I think it's much nicer :)
# determining whether to replay or to stop the loop
case replay_answer
when "yes", "y"
replay = true
puts "yes"
when "no", "n"
replay = false
puts "no"
replay_inner = false
end
I've modified a little your code, you should really use some decent editor with at least syntax errors highlighting. I've changed OR to AND condition in inner loop (comment in code) and added way of breaking from it when guessed number. I've also removed second occurence of code responsible of playing again, remember, DRY yourself.
replay = true
while replay
p replay
#Pre-var
print "What difficulty? (1 for easy, 2 for medium, or 3 for hard): "
difficulty = gets.chomp.to_i
until difficulty == 1 || difficulty == 2 || difficulty == 3 do
print "Please type either 1, 2, or 3: "
difficulty = gets.chomp.to_i
end
#Variables
if difficulty == 1
r = Random.new
number = r.rand(100..1000)
puts "You have 15 guesses. "
print "Guess a number with three digits: "
within_num = 50
elsif difficulty == 2
r = Random.new
number = r.rand(1000..10000)
puts "You have 15 guesses. "
print "Guess a number with four digits: "
within_num = 500
elsif difficulty == 3
r = Random.new
number = r.rand(10000..100000)
puts "You have 15 guesses. "
print "Guess a number with five digits: "
within_num = 5000
end
guess = ""
num_guess = 0
guess_array = Array.new
array_location = 0
count_through = 0
array_print = count_through - 1
replay_inner = true
#Body
puts number
while num_guess <= 14 && replay_inner == true #Keeping as <= 14 as to avoid unnecessarily rewriting code, still gives 15 guesses
guess = gets.chomp.to_i
if guess > number * 2
print "That is more than double the number. Guess again: "
elsif guess < number / 2
print "That is less than half the number. Guess again: "
elsif guess > number && guess < number + within_num #within_num: 50 for easy, 500 for medium, 5000 for hard
print "You are close. That is too big. Guess again: "
elsif guess < number && guess > number - within_num
print "You are close. That is too small. Guess again: "
elsif guess < number
print "That is too small. Guess again: " #Hinting the user to how close they are.
elsif guess > number
print "That is too big. Guess again: "
elsif guess == number
puts "Congragulations! You win!"
print "Your "
print guess_array.length
print " incorrect guesses were: "
if num_guess == 0
sleep(0.5)
print "... Oh."
else
while count_through < num_guess #Loop to relay user's guesses with a delay of 0.5 seconds
print guess_array[count_through]
if count_through == num_guess - 2
print ", and "
elsif count_through == num_guess - 1
puts ". "
else
print ", "
end
count_through += 1
sleep(0.5)
end
end
replay_inner = false # or just `break`, you have to break somehow from inner loop here
end
guess_array.push guess
num_guess += 1
#puts num_guess
#puts guess_array[array_location]
array_location += 1
if num_guess >= 15 && guess != number
puts "Sorry, you lost. "
print "Your "
print guess_array.size
print " guesses were: "
while count_through < num_guess
print guess_array[count_through] #Same as loop above; for when player fails to guess correctly
if count_through == num_guess - 2
print ", and "
elsif count_through == num_guess - 1
puts ". "
else
print ", "
end
count_through += 1
sleep(0.5)
end
end
end
puts "\nWould you like to play again? (yes/no)"
replay_answer = gets.chomp
until replay_answer == "yes" || replay_answer == "y" || replay_answer == "no" || replay_answer == "n" do
print "Please answer with yes, y, no, or n: "
replay_answer = gets.chomp
end
if replay_answer == "yes" || replay_answer == "y"
replay = true
replay_inner = true
puts "yes"
elsif replay_answer == "no" || replay_answer == "n" #Determining whether or not to replay
replay = false
replay_inner = false
puts "no"
end
end

If type is character I want to puts error

puts "Let's sum many numbers"
sum = 0
num = 0
while(num != 'x')
puts "Press a number and then Enter if you exit press 'x'"
num = gets.chomp
if num != 'x'
num = num.to_i
print "#{sum} + #{num} = "
sum += num
puts "#{sum}"
elsif num == 'x'
puts "Total sum is #{sum}"
break
else
puts "error!"
end
end
I want to make code to show error If user press char except 'x'.
How should I do?
Change your first if to a condition that checks if the input is a number, e.g.
if num =~ /\A[0..9]+\z/ # or /\A\d+\z/
The way your code is currently, all strings except 'x' are treated as number -- with value 0 in case they aren't really numbers:
'foobar'.to_i # => 0

Resources