Is there a compiler directive to tell gfortran-gcc compiler that the code is written in free-form? I have code written in a file with '.for' as extension (which is recognized as fixed-form), but the language is f95 free-form.
Adding a flag to the compiler options to force free-form is not possible for my application, hence it needs to be done using directives.
For ifort, the command is:
!DEC$ FREEFORM
For gfortran is should be something like:
!GCC$ DIRECTIVE
I have, unfortunately, not been able to find which command exactly.
No, there is none. Use the -ffree-form compiler option.
Related
I work with a very long Fortran code full of preprocessor (#if) conditionals, Is there any way to compile it and get a source file only with the fraction of the code where conditions are satisfied?
As mentioned by chw21, you can run the preprocessor directly. Either the cpp (with the right flags) or the fpp command, depending on your compiler.
Because you can be unsure about the right flags, you can also let the compiler do that for you. In GCC (gfortran) it is the -E flag, which will force the compiler to stop after preprocessing. You must redirect standard output to a file because the preprocessed code is returned to standard output.
Do note this is different from
Get the compiler options from a compiled executable? which I did go through in detail.
Although -frecord-gcc-switches is great, it only captures the command line arguments.
For example, I am not interested in capturing -O2 which is usually passed in command line. I am more curious about recording all the flags like -fauto-inc-dec which are enabled by -O2.
(In contrast to the link above, do note that I have access to the source, the compiler and the build infrastructure. I just want to capture the flags during compilation. Not picky about any specific gcc version)
You can try -fverbose-asm. That dumps the optimisation options used in a comment at the top of the assembly file.
I currently invoke clang or gcc as
cc -E -DPREPROCESSING ...
when debugging macros.
It has occurred to me that the define is redundant. Is there an expression I could write in the source to detect when the compiler will stop after preprocessing, and so drop this definition from my build scripts?
#if magic
#define PREPROCESSING
#ending
A look at the docs suggests not, but with luck I'm missing something.
Whatever solution you come up with is going to be compiler-specific, since the C standard does not have anything to say about separate preprocessing.
In gcc, you could implement the magic by adding a custom spec file:
%rename cpp old_cpp
*cpp:
%{E:-DPREPROCESSING} %(old_cpp)
You would need to tell gcc to use this spec file (-specs=/path/to/specfile), unless you compiled your own gcc with the above definition added to the built-in cpp spec. If you are using a Makefile, you could add the -specs option above to your CFLAGS.
(I should add that I don't think this is a particularly good idea. But it is possible.)
I have seen makefiles use the -DLINUX flag but can't find any documentation on it.
Is there a place to find information on tools like 'gcc' that are more up-to-date than
the officially released manuals?
It just defines the LINUX symbol for the C preprocessor.
Probably there are pieces of the code that look like:
#ifdef LINUX
//Linux-specific code
#elif defined WINDOWS
//Windows-specific code
#endif
It's the -D option controlling the preprocessor. It defines the LINUX macro, that you can then use with #ifdef.
According to man gcc:
-D name
Predefine name as a macro, with definition 1.
Hence, it let define a constant from the compilation command line.
It defines a preprocessor macro named LINUX. That's it. The macro itself, LINUX, is not a predefined one, it's probably used for a cross-platform codebase where specific sections of code are enabled for a Linux target. For this purpose, one could actually have re-used the predefined linux or __linux__ ones (see the output of gcc -dP -E - < /dev/null to get all the predefined macros on your system).
See http://gcc.gnu.org/onlinedocs/gcc-4.8.2/gcc/ for the standard documentation on gcc (that's obviously for GCC 4.8.2). To my knowledge, that's the best place to look for if this documentation is not already installed (or up-to-date) on your system.
How do I view the output produced by the C pre-processor, prior to its conversion into an object file?
I want to see what the MACRO definitions do to my code.
gcc -E file.c
or
g++ -E file.cpp
will do this for you. The -E switch forces the compiler to stop after the preprocessing phase, spitting all it’s got at the moment to standard output.
Note: Surely you must have some #include directives. The included files get preprocessed, too, so you might get lots of output.
For Visual C++ the switch is /E which spits the preprocessor output to screen.
You can also call the C Preprocessor directly.
cpp infile outfile
Check out man cpp for more info.
For GCC,
gcc -E -dM file.c
or
g++ -E -dM file.cpp
should do the job. -dM, as GNU Preprocessor manual puts it, should generate a list of ‘#define’ directives for all the macros defined during the execution of the preprocessor, including predefined macros.
It depends on the compiler you use.
With GCC, you can specify the -E flag on the command-line to let the compiler produce the pre-processor output.
If using CLion by Jetbrains, you can use the action "clangd: Preprocess current TU"
So hit shift shift and start typing clangd...
Best assign it to a shortcut for simpler reuse in preferences->keymap:
Shout out to marcosbento
PS: TU means 'translation unit' (see here LLVM translation unit)
You can check out my script described here:
http://mosermichael.github.io/cstuff/all/projects/2011/09/16/preprocessor.html
It formats the preprocessor output into a (hopefully) readable html document: lines that are different due to preprocessor are marked in the file.