Defining beans for different modules of project - spring

My project includes three modules:
koty-application (data access objects)
koty-domain (value objects - model)
koty-webapp (web application using Spring MVC)
I am using Gradle to build project - koty-application produces koty-application.jar, koty-domain produces koty-domain.jar and koty-webapp produces koty-webapp.war (which includes jars).
Temporarily, I defined beans only for koty-webapp module. The structure is like this:
web.xml:
<web-app id="WebApp_ID" version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<display-name>Baza danych kotow</display-name>
<servlet>
<servlet-name>mvc-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/applicationContext.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>mvc-dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
</web-app>
applicationContext.xml:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-4.0.xsd
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-4.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-4.0.xsd">
<context:component-scan base-package="pl.kobietydokodu" />
<context:annotation-config />
<mvc:annotation-driven />
<bean
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value>/WEB-INF/views/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
</beans>
I defined beans for module koty-webapp and it works fine!
But I would like to define another beans for other module - for example KotyDAO for module koty-application. How should I define beans for koty-application module properly?
Full code of my project is here: https://github.com/evodv5/cats

Related

How to map the servlet to a child route(like /blog)?

I'm using SpringMVC and tomcat, and I want to assign all the URLs beginning with /blog to my servlet, here is my code.
web.xml
<web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee
http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd" version="3.1">
<display-name>Spring MVC XML Configuration Example</display-name>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:app-config.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>my-dispatcher-servlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:web-config.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>my-dispatcher-servlet</servlet-name>
<url-pattern>/blog</url-pattern>
</servlet-mapping>
</web-app>
web-config.xml
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd ">
<context:component-scan base-package="com.example" />
<mvc:annotation-driven />
<mvc:resources mapping="/blog/**" location="/WEB-INF/static/blog/" />
</beans>
app-config.xml
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd ">
<context:component-scan base-package="com.example" />
</beans>
It doesn't work. I got a 404 when trying to access /blog/index.html. However, it worked if I changed the servlet-mapping part in web.xml to the following one.
<servlet-mapping>
<servlet-name>my-dispatcher-servlet</servlet-name>
<url-pattern>/</url-pattern> <!-- from /blog to / -->
</servlet-mapping>
But I don't want to do that, I only want the servlet to handle the URLs under /blog, can I do that? Should I change something in web-config.xml to make it work?
As mentioned by M.Deinum in the comments, I should change the servlet-mapping part in web.xml to the following one:
<servlet-mapping>
<servlet-name>my-dispatcher-servlet</servlet-name>
<url-pattern>/blog/*</url-pattern> <!-- notice the asterisk -->
</servlet-mapping>
Then change the mvc:resource part in web-config.xml to the following one.
<mvc:resources mapping="/**" location="/WEB-INF/static/blog/" />
It's done, now open /blog/index.html, it should work now.

How can i make a welcome page with a file which has .html extension

Hello i am new to spring,
I am trying to create a welcome file called index.html
I put my index.html file under webapp folder. My web xml file is
<web-app id="WebApp_ID" version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<display-name>Spring4MVCHelloWorldDemo Web Application</display-name>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring-servlet.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
</welcome-file-list>
</web-app>
And my spring-servlet.xml file is
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-4.0.xsd
http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-4.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-4.0.xsd">
<context:component-scan base-package="com.websystique.springmvc" />
<mvc:annotation-driven />
<bean
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value>/WEB-INF/views/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
</beans>
When i change index.html to index.jsp and create an index.jsp file it works fine. My question is can`t i make welcome page with html extension ? If i can what is my mistake ? thanks
<welcome-file-list>
<welcome-file>index.html</welcome-file>
</welcome-file-list>
You've configured the InternalResourceViewResolver to search files with .jsp suffix. In this case, Spring won't match index.html.
You can replace the suffix value with .html if you need to match files under /WEB-INF/views/{viewName}.html

Freemarker + Spring NoSuchBeanDefinitionException but Bean defined

I am trying to integrate Freemarker with Spring MVC but when I run my app on Tomcat I receive following exception:
org.springframework.context.ApplicationContextException: Must define a single FreeMarkerConfig bean in this web application context (may be inherited): FreeMarkerConfigurer is the usual implementation. This bean may be given any name.; nested exception is org.springframework.beans.factory.NoSuchBeanDefinitionException: No qualifying bean of type [org.springframework.web.servlet.view.freemarker.FreeMarkerConfig] is defined
org.springframework.web.servlet.view.freemarker.FreeMarkerView.autodetectConfiguration(FreeMarkerView.java:177)
org.springframework.web.servlet.view.freemarker.FreeMarkerView.initServletContext(FreeMarkerView.java:149)
.
.
.
It's very strange because I have a FreeMarkerConfig bean defined in my app context . Here is my web.xml and mvc-config.xml files:
web.xml
<?xml version="1.0" encoding="ISO-8859-1"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID" version="2.5">
<display-name>Practic</display-name>
<!--
- Location of the XML file that defines the root application context.
- Applied by ContextLoaderListener.
-->
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:spring/application-config.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<!--
- Servlet that dispatches request to registered handlers (Controller implementations).
-->
<servlet>
<servlet-name>dispatcherServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/mvc-config.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcherServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
mvc-config.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">
<mvc:annotation-driven />
<context:component-scan base-package="pl.zimny.spring" />
<bean id="freemarkerConfig"
class="org.springframework.web.servlet.view.freemarker.FreeMarkerConfigurer">
<property name="templateLoaderPath" value="/WEB-INF/freemarker/"/>
</bean>
<bean id="viewResolver" class="org.springframework.web.servlet.view.freemarker.FreeMarkerViewResolver">
<property name="cache" value="true"/>
<property name="prefix" value="/WEB-INF/view/"/>
<property name="suffix" value=".ftl"/>
</bean>
</beans>
Have anyone an idea for solve this issue?

Spring MVC can't do JSPs? 404

I am just trying to go to a JSP. That's it. It gives a 404, or, if I get it working, no HTML works. Nothing I do works without breaking something else. We have a mixture of JSPs, html, css, etc all under a resources directory we reference as /r/ in our spring dispatcher servlet. Please help me compile spring JSPs. I am about to abandon Spring all together.
Here's my Spring dispatch servlet.
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:aop="http://www.springframework.org/schema/aop" xmlns:jee="http://www.springframework.org/schema/jee"
xmlns:lang="http://www.springframework.org/schema/lang" xmlns:p="http://www.springframework.org/schema/p"
xmlns:tx="http://www.springframework.org/schema/tx" xmlns:util="http://www.springframework.org/schema/util"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-4.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-4.0.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-4.0.xsd
http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee.xsd
http://www.springframework.org/schema/lang http://www.springframework.org/schema/lang/spring-lang.xsd
http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util.xsd">
<mvc:view-controller path="/" view-name="/r/views/welcome.html"/>
<!-- Enable #Controller annotation support -->
<mvc:annotation-driven />
<!-- Allow static resources to be served from the /resources folder -->
<mvc:resources mapping="/r/**" location="/resources/" />
<!-- Scan classpath for annotations (eg: #Service, #Repository etc) -->
<context:component-scan base-package="com.cs" />
<context:property-placeholder location="file:/TcatServer6/Mytime/properties/mytime-agentdesktop/agentdesktop.properties" />
</beans>
Here's my web.xml
<web-app xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
version="2.5">
<display-name>agent-desktop</display-name>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring-security.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<filter>
<filter-name>httpMethodFilter</filter-name>
<filter-class>org.springframework.web.filter.HiddenHttpMethodFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>httpMethodFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<servlet>
<servlet-name>agent-desktop</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>agent-desktop</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
You have to tell Spring how to know how to resolve the view that you're returning from your controller. For example:
<bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="viewClass" value="org.springframework.web.servlet.view.JstlView"/>
<property name="prefix" value="/WEB-INF/jsp/"/>
<property name="suffix" value=".jsp"/>
</bean>
See the official documentation on view resolvers for more info.

Spring Resource handling

I am new to spring framework.i am using mvc resources for handling resources.but still am getting exception
WARNING: No mapping found for HTTP request with URI [/GameApp/static/js/jquery.colorbox.js] in DispatcherServlet with name 'GameApp'
This is my web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app id="WebApp_ID" version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<display-name>GameApp</display-name>
<welcome-file-list>
<welcome-file>
index.jsp
</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>GameApp</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value></param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
<!-- Spring application context declaration -->
classpath:/config/spring-config.xml
</param-value>
</context-param>
<servlet-mapping>
<servlet-name>GameApp</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
</web-app>
and this is my spring-config.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd">
<context:component-scan base-package="com.springsample" />
<bean id="viewResolver"
class="org.springframework.web.servlet.view.InternalResourceViewResolver" >
<property name="prefix">
<value>/WEB-INF/pages/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
<mvc:resources mapping="/static/**" location="/static/" />
<mvc:annotation-driven/>
</beans>
I have placed my static resources in webapp/static...Please explain what might be causing the issue
Your classpath:/config/spring-config.xml needs to go in the DispatcherServlet's contextConfigLocation:
<servlet>
<servlet-name>GameApp</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:/config/spring-config.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
and you can leave empty the root application context contextConfigLocation:
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value></param-value>
</context-param>

Resources