How to check many files exist with ruby code in windows - ruby

I want to check all file having .war extension and move them to another folder in chef-client windows but it does not work.
if !Dir.glob("C:\\tempwar\\*.war").empty?
execute 'mv-war' do
command 'move C:\tempwar\*.war C:\tomcat\webapps\ '
end
end

It's always best to build paths in ruby with ::File.join. This takes care of the path separators in a platform neutral way. Also, it's prefered to use Chef conditionals rather than wrapping things in an if. So try this:
execute 'mv-war' do
command "move #{::File.join('C:', 'tempwar', '*.war')} #{::File.join('C:', 'tomcat', 'webapps'} "
only_if { Dir.glob(::File.join('C:', 'tempwar', '*.war').empty? }
end

The backslash characters here are not being interpreted as a pathname separator. Your \t becomes a tab character, for example, and \* is just a *. Double the backslashes or use a single-quoted string and you have a fighting chance.

Related

Use Dir.chdir to work with a path name with spaces in it

On Mac OSX, using the Ruby Dir class, I want to change to a directory that has spaces in it. I have tried:
Dir.chdir('/Users/Chris/Library/Application\ Support')
but received the exception
Errno::ENOENT: No such file or directory
How do I do this?
Don't Escape Spaces Inside Single Quotes
Don't escape spaces inside single quotes. If you do, the String will contain a literal quote character, which will not match your directory name. Consider:
'\ '
#=> "\\ "
If you have a space in the name, just use proper quoting without escapes for the spaces. Examples include:
Dir.chdir '/Users/Chris/Library/Application Support'
Dir.chdir "/Users/Chris/Library/Application Support"
Dir.chdir %q(/Users/Chris/Library/Application Support)
There may be situations where you need escapes inside single quotes (such as escaping a single-quote character, e.g. '\'') but your example is not one of them.

BASH function for escaping spaces in filenames before opening them

I've been trying to write a function for my bash profile for quite some time now.
The problem I'm trying to overcome is I'm usually provided with file paths that include spaces and it's a pain having to go through and escape all the spaces before I try to open it up in terminal.
e.g.
File -> /Volumes/Company/Illustrators/Website Front Page Design.ai
What I'm trying to end up with is '/Volumes/Company/Illustrators/Website\ Front\ Page\ Design.ai' being opened from my terminal.
So far I've managed to escape the spaces out, but I then get the error "The file ..... does not exist."
My code so far is
function opn { open "${1// /\\ }";}
Any help would be very much appreciated.
The important thing to understand is the difference between syntax and literal data.
When done correctly, escaping is syntax: It's read and discarded by the shell. That is, when you run
open "File With Spaces"
or
open File\ With\ Spaces
or even
open File" "With\ Spaces
...the quoting and escaping is parsed and removed by the shell, and the actual operating system call that gets executed is this:
execv("/usr/bin/open", "open", "File With Spaces")
Note that there aren't any backslashes (or literal quotes) in that syscall's arguments! If you put literal backslashes in your data, then you cause this to be run:
/* this is C syntax, so "\\" is a single-character backslash literal */
execv("/usr/bin/open", "open", "File\\ With\\ Spaces")
...and unless there's a file with backslashes in its name, that just doesn't work, giving the "file does not exist" error you report.
So -- just call open with your name in quotes:
open "$1"
...there's no need for an opn wrappper.
Spaces are problematic in filenames because they're part of bash's default IFS (Internal Field Separator), which is used to separate tokens in a command line. That means that by default, when you use command an argument with spaces, the command will receive 4 arguments rather than 1 containing spaces.
I'm guessing you called your opn function in the same way, thus resulting in only the first part of your path as $1.
Hopefully, the fix is easy : enclose your path in quotes so that bash does not interpret the spaces. By using this, the need for your opn function disappears : open "/Volumes/Company/Illustrators/Website Front Page Design.ai" should work just fine.

What does this Windows bat command mean?

I read the following command from the batch file to run Maven on Windows mvn.bat:
if not "_%M2_HOME:~-1%"=="_\" goto checkMBat
And
if "%#eval[2+2]" == "4" goto 4NTArgs
What does this batch script mean?
ADD 1
As I tried, it seems _%M2_HOME:~-1% returns the _ plus the last 1 letter of the environment variable "_%M2_HOME%. But what's the name of this syntax?
%VAR:~-1% gets the last character in the envvar. The first snippet verifies that the envvar M2_HOME doesn't end with \. Note: Maven's docs say,
Note: For Maven 2.0.9, also be sure that the M2_HOME doesn't have a '\' as last character.
This might be related. They probably want to prepend M2_HOME to subdir names and always include a dirsep. The variable substitution in "_%...%" is unaffected by the initial underscore. Experessing it that way just ensures that the underscore is at the beginning of the output. I can't say for certain, but it may have been expressed that way to avoid a backslashed quote, e.g. "\".
The second is not any CMD/batch that I'm familiar with. The comment (assuming this comes from mvn.bat) says "4NT shell", which I take to mean that this batch file could be run in the Take Command Console which probably has extensions to MS CMD features. For example, %#eval[...] probably does numeric evaluation in 4NT. This would effectively be a check to see if the script were running in a 4NT shell.
The first one takes the last character of %M2_HOME%, adds an underscore to the front, and checks to see if the resulting string is _\ - in short, it checks that the last character of %M2_HOME% is a backslash by using substrings.
The second one is how you determine if 4NT is installed on your computer; if it is, there will be a variable function called #eval.
I found the explanation to "_%M2_HOME:~-1%" below link. It's a variable substring operation.
http://ss64.com/nt/syntax-substring.html

Absolute path in perl's copy command gone wrong?

This is my very simple code, which isn't working, for some reason I can't figure out.
#!/usr/bin/perl
use File::Copy;
$old = "car_lexusisf_gray_30inclination_000azimuth.png";
$new = "C:\Users\Lenovo\Documents\mycomp\simulation\cars\zzzorganizedbyviews\00inclination_000azimuth\lexuscopy.png";
copy ($old, $new) or die "File cannot be copied.";
I get the error that the file can't be copied.
I know there's nothing wrong with the copy command because if I set the value of $new to something simple without a path, it works. But what is wrong in the representation of the path as I've written it above? If I copy and past it into the address bar of windows explorer, it reaches that folder fine.
Tip: print out the paths before you perform the copy. You'll see this:
C:SERSenovodocumentsmycompsimulationrszzzorganizedbyviewsinclination_000azimuthexuscopy.png
Not what we wanted. The backslash is an escape character in Perl, which needs to be escaped itself. If the backslash sequence does not form a valid escape, then it's silently ignored. With escaped backslashes, your string would look like:
"C:\\Users\\Lenovo\\Documents\\mycomp\\simulation\\cars\\zzzorganizedbyviews\\00inclination_000azimuth\\lexuscopy.png";
or just use forward slashes instead – in most cases, Unix-style paths work fine on Windows too.
Here is a list of escapes you accidentally used:
\U uppercases the rest
\L lowercases the rest
\ca is a control character (ASCII 1, the start of heading)
\00 is an octal character, here the NUL byte
\l lowercases the next character.
If no interpolation is intended, use single quotes instead of double quotes.

Single quote string interpolation to access a file in linux

How do I make the parameter file of the method sound become the file name of the .fifo >extension using single quotes? I've searched up and down, and tried many different >approaches, but I think I need a new set of eyes on this one.
def sound(file)
#cli.stream_audio('audio\file.fifo')
end
Alright so I finally got it working, might not be the correct way but this seemed to do the trick. First thing, there may have been some white space interfering with my file parameter. Then I used the File.join option that I saw posted here by a few different people.
I used a bit of each of the answers really, and this is how it came out:
def sound(file)
file = file.strip
file = File.join('audio/',"#{file}.fifo")
#cli.stream_audio(file) if File.exist? file
end
Works like a charm! :D
Ruby interpolation requires that you use double quotes.
Is there a reason you need to use single quotes?
def sound(FILE)
#cli.stream_audio("audio/#{FILE}.fifo")
end
As Charles Caldwell stated in his comment, the best way to get cross-platform file paths to work correctly would be to use File.join. Using that, your method would look like this:
def sound(FILE)
#cli.stream_audio(File.join("audio", "#{FILE}.fifo"))
end
Your problem is with your usage of file path separators. You are using a \. Whereas this may not seem like a big deal, it actually is when used in Ruby strings.
When you use \ in a single quoted string, nothing happens. It is evaluated as-is:
puts 'Hello\tWorld' #=> Hello\tWorld
Notice what happens when we use double quotes:
puts "Hello\tWorld" #=> "Hello World"
The \t got interpreted as a tab. That's because, much like how Ruby will interpolate #{} code in a double quote, it will also interpret \n or \t into a new line or tab. So when it sees "audio\file.fifo" it is actually seeing "audio" with a \f and "ile.fifo". It then determines that \f means 'form feed' and adds it to your string. Here is a list of escape sequences. It is for C++ but it works across most languages.
As #sawa pointed out, if your escape sequence does not exist (for instance \y) then it will just remove the \ and leave the 'y'.
"audio\yourfile.fifo" #=> audioyourfile.fifo
There are three possible solutions:
Use a forward slash:
"audio/#{file}.fifo"
The forward slash will be interpreted as a file path separator when passed to the system. I do most my work on Windows which uses \ but using / in my code is perfectly fine.
Use \\:
"audio\\#{file}.fifo"
Using a double \\ escapes the \ and causes it to be read as you intended it.
Use File.join:
File.join("audio", "#{file}.fifo")
This will output the parameters with whatever file separator is setup as in the File::SEPARATOR constant.

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