bash - while loop - rolling 2 dice - bash

Question

I'm writing a bash script that rolls 2 dice(with 6 sides). When the 2 dice hits double sixes I want the script to stop (break) and count how many rolls it took to get double sixes.
#!/bin/bash
DOUBLESIX="6-6"
while (( 0 ==0 )) ; do
dice=$RANDOM; ((dice = dice % 6 )); (( dice = dice +1 ))
dice2=$RANDOM; ((dice2 = dice2 % 6 )); (( dice = dice + 1))
pair="$dice-dice$2"
echo $pair
if [[ "$pair" == "$DOUBLESIX" ]]; then
break
fi
done
echo "It took $count rolls to get 6-6 "
Here's what i have so far. Question is, how do I count how many times the while loop ran and put it in my $count?
Thanks in advance!

Answer 1

I won't comment too much on the other potential issues you have with your code, such as the dice$2 "variable", or the fact you can generate a random number between one and six inclusive with the somewhat simpler ((num = $RANDOM % 6 + 1)) - the learning process of fixing/improving those is what will make you a better coder.
But, for the specific question on how to maintain a count, that's relatively simple. Before the loop starts, insert the following code to initialise the count to zero:
((count = 0))
Then, with each roll of the two dice, use the following to increment the count:
((count = count + 1))
An example of how to do this can be seen below. It's for counting from one to ten but you should get the idea:
((count = 1))
while [[ ${count} -le 10 ]] ; do
echo $count
((count = count + 1))
done
For what it's worth (don't use this if this is a classwork problem, you'd be crazy to think educators don't search the net for plagiarism), here's how I would implement such a beast:
#!/bin/bash
DESIRED="6-6"
((count = 0))
dice="NOT ${DESIRED}"
while [[ "${dice}" != "${DESIRED}" ]] ; do
((count = count + 1))
((die1 = $RANDOM % 6 + 1))
((die2 = $RANDOM % 6 + 1))
dice="${die1}-${die2}"
echo ${dice}
done
echo "It took ${count} rolls to get ${DESIRED}"

Answer 2

I advice to use shuf for this purpose.
#!/bin/bash
declare -i count=1
while [ "6 6" != "$(shuf --input-range='1-6' -r -n 2 | xargs)" ]; do
(( ++count ))
done
echo "It took $count rolls to get double six."
To generating two random numbers between 1 and 6 we use
shuf --input-range='1-6' -r -n 2
shuf [OPTION]... [FILE] write a random permutation of the input lines to standard output. Each output permutation is equally likely. -i lo-hi or --input-range=lo-hi act as if input came from a file containing the range of unsigned decimal integers lo-hi, one per line. -r or --repeat repeat output values, that is, select with replacement. With this option the output is not a permutation of the input; instead, each output line is randomly chosen from all the inputs. -n count or --head-count=count output at most count lines (by default, all input lines are output). If --head-count is not given, shuf repeats indefinitely.
Type man shuf or see coreutils manual for more details.