I'm trying to compare two CSV files by reading the first line-by-line and grepping the second file for a match. Using Diff is not a viable solution. I seem to be having a problem with having the email address stored as a variable when I grep the second file.
#!/bin/bash
LANG=C
head -2 $1 | tail -1 | while read -r line; do
line=$( echo $line | sed 's/\n//g' )
echo $line
cat $2 | cut -d',' -f1 | grep -iF "$line"
done
Variable $line contains an email address that DOES exist in file $2, but I'm not getting any results.
What am I doing wrong?
File1
Email
email#verizon.net
email#gmail.com
email#yahoo.com
File2
email,,,,
email#verizon.net,,,,
email#gmail.com,,,,
email#yahoo.com,,,,
Given:
# csv_0.csv
email
me#me.com
you#me.com
fee#me.com
and
# csv_1.csv
email,foo,bar,baz,bim
bee#me.com,3,2,3,4
me#me.com,4,1,1,32
you#me.com,7,4,6,6
gee#me.com,1,2,2,6
me#me.com,5,7,2,34
you#me.com,22,3,2,33
I ran
$ pattern=$(head -2 csv_0.csv | tail -1 | sed s/,.*//g)
$ grep $pattern csv_1.csv
me#me.com,4,1,1,32
me#me.com,5,7,2,34
To do this for each line in csv_0.csv
#!/bin/bash
LANG=C
filename="$1"
{
read # don't read csv headers
while read line
do
pattern=$(echo $line | sed s/,.*//g)
grep $pattern $2
done
} <"$filename"
Then
$ ./csv_read.sh csv_2.csv csv_3.csv
me#me.com,4,1,1,32
me#me.com,5,7,2,34
you#me.com,7,4,6,6
you#me.com,22,3,2,33
Related
I wrote the following command:
var=$(printf "$line" | awk -F':' {'print $2'} | sed 's/,//g')
sed -i "s/$var/exampletext/g" "file.txt"
The text is part of a larger script that finds a specific value, and then replaces it with another value.
The basic end result I want is something like this:
sed -i "s/123/exampletext/g" "file.txt"
That should replace all of the 123's in file.txt with exampletext. When I echo $var, it shows the result of 123. Yet when that command is run, it doesn't work - it does not replace 123 with exampletext.
Here is the full script:
INPUT="$1"
while IFS= read -r line;
do
if [[ $line == *"length"* ]];
then
var=$(printf "$line" | awk -F':' {'print $2'} | sed 's/,//g')
sed -i "s|$var|cookiecrisp|g" "vomit.txt"
fi
done < $INPUT
Let's say I have the following csv file:
A,1
A,2
B,3
C,4
C,5
And for each unique value i in the first column of the file I want to write a script that does some processing using this value. I go about doing it this way:
CSVFILE=path/to/csv
VALUES=$(cut -d, -f1 $CSVFILE | sort | uniq)
for i in $VALUES;
do
cat >> file_${i}.sh <<-!
#!/bin/bash
#
# script that takes value I
#
echo "Processing" $i
!
done
However, this creates empty files for all values of i it is looping over, and prints the actual content of files to the console.
Is there a way to redirect the output to the files instead?
Simply
#!/bin/bash
FILE=/path/to/file
values=`cat $FILE | awk -F, '{print $1}' | sort | uniq | tr '\n' ' '`
for i in $values; do
echo "value of i is $i" >> file_$i.sh
done
Screenshot
Try using this:
#!/usr/bin/env bash
csv=/path/to/file
while IFS= read -r i; do
cat >> "file_$i.sh" <<-eof
#!/bin/bash
#
# Script that takes value $i ...
#
eof
done < <(cut -d, -f1 "$csv" | sort -u)
I need to read a json file and take value like 99XXXXXXXXXXXX0 and cccs and write in csv which having column BASE_No and Schedule.
Input file: classedFFDCD_5666_4888_45_2018_02112018012106.021.json
"bfgft":"99XXXXXXXXXXXX0","fp":"XXXXXX","cur_gt":225XXXXXXXX0,"cccs"
"bfgft":"21XXXXXXXXXXXX0","fp":"XXXXXX","cur_gt":225XXXXXXXX0,"nncs"
"bfgft":"56XXXXXXXXXXXX0","fp":"XXXXXX","cur_gt":225XXXXXXXX0,"fgbs"
"bfgft":"44XXXXXXXXXXXX0","fp":"XXXXXX","cur_gt":225XXXXXXXX0,"ddss"
"bfgft":"94XXXXXXXXXXXX0","fp":"XXXXXX","cur_gt":225XXXXXXXX0,"jjjs"
Expected output:
BASE_No,Schedule
99XXXXXXXXXXXX0,cccs
21XXXXXXXXXXXX0,nncs
56XXXXXXXXXXXX0,fgbs
44XXXXXXXXXXXX0,ddss
94XXXXXXXXXXXX0,jjjs
I am using below code for reading file name and date, but unable to read file for BASE_No,Schedule.
SAVEIFS=$IFS
IFS=$(echo -en "\n\b")
for line in `ls -lrt *.json`; do
date=$(echo $line |awk -F ' ' '{print $6" "$7}');
file=$(echo $line |awk -F ' ' '{print $9}');
echo ''$file','$(date "+%Y/%m/%d %H.%M.%S")'' >> $File_Tracker`
Assuming the structure of the json doesnt change for every line, the sample code checks through line by line to retrieve the particular value and concatenates using printf. The output is then stored as new output.txt file.
#!/bin/bash
input="/home/kj4458/winhome/Downloads/sample.json"
printf "Base,Schedule \n" > output.txt
while IFS= read -r var
do
printf "`echo "$var" | cut -d':' -f 2 | cut -d',' -f 1`,`echo "$var" | cut -d':' -f 4 | cut -d',' -f 2` \n" | sed 's/"//g' >> output.txt
done < "$input"
awk -F " \" " ' {print $4","$12 }' file
99XXXXXXXXXXXX0,cccs
21XXXXXXXXXXXX0,nncs
56XXXXXXXXXXXX0,fgbs
44XXXXXXXXXXXX0,ddss
94XXXXXXXXXXXX0,jjjs
I got that result!
I am trying to grep out the lines in a file where the third field matches certain criteria.
I tried using grep but had no luck in filtering out by a field in the file.
I have a file full of records like this:
12794357382;0;219;215
12795287063;0;220;215
12795432063;0;215;220
I need to grep only the lines where the third field is equal to 215 (in this case, only the third line)
Thanks a lot in advance for your help!
Put down the hammer.
$ awk -F ";" '$3 == 215 { print $0 }' <<< $'12794357382;0;219;215\n12795287063;0;220;215\n12795432063;0;215;220'
12795432063;0;215;220
grep:
grep -E "[^;]*;[^;]*;215;.*" yourFile
in this case, awk would be easier:
awk -F';' '$3==215' yourFile
A solution in pure bash for the pre-processing, still needing a grep:
while read line; do
OLF_IFS=$IFS; IFS=";"
line_array=( $line )
IFS=$OLD_IFS
test "${line_array[2]}" = 215 && echo "$line"
done < file | grep _your_pattern_
Simple egrep (=grep -E)
egrep ';215;[0-d][0-d][0-d]$' /path/to/file
or
egrep ';215;[[:digit:]]{3}$' /path/to/file
How about something like this:
cat your_file | while read line; do
if [ `echo "$line" | cut -d ";" -f 3` == "215" ]; then
# This is the line you want
fi
done
Here is the sed version to grep for lines where 3rd field is 215:
sed -n '/^[^;]*;[^;]*;215;/p' file.txt
Simplify your problem by putting the 3rd field at the beginning of the line:
cut -d ";" -f 3 file | paste -d ";" - file
then grep for the lines matching the 3rd field and remove the 3rd field at the beginning:
grep "^215;" | cut -d ";" -f 2-
and then you can grep for whatever you want. So the complete solution is:
cut -d ";" -f 3 file | paste -d ";" - file | grep "^215;" | cut -d ";" -f 2- | grep _your_pattern_
Advantage: Easy to understand; drawback: many processes.
I'm trying to write a little script which will open a text file and give me an md5 hash for each line of text. For example I have a file with:
123
213
312
I want output to be:
ba1f2511fc30423bdbb183fe33f3dd0f
6f36dfd82a1b64f668d9957ad81199ff
390d29f732f024a4ebd58645781dfa5a
I'm trying to do this part in bash which will read each line:
#!/bin/bash
#read.file.line.by.line.sh
while read line
do
echo $line
done
later on I do:
$ more 123.txt | ./read.line.by.line.sh | md5sum | cut -d ' ' -f 1
but I'm missing something here, does not work :(
Maybe there is an easier way...
Almost there, try this:
while read -r line; do printf %s "$line" | md5sum | cut -f1 -d' '; done < 123.txt
Unless you also want to hash the newline character in every line you should use printf or echo -n instead of echo option.
In a script:
#! /bin/bash
cat "$#" | while read -r line; do
printf %s "$line" | md5sum | cut -f1 -d' '
done
The script can be called with multiple files as parameters.
You can just call md5sum directly in the script:
#!/bin/bash
#read.file.line.by.line.sh
while read line
do
echo $line | md5sum | awk '{print $1}'
done
That way the script spits out directly what you want: the md5 hash of each line.
this worked for me..
cat $file | while read line; do printf %s "$line" | tr -d '\r\n' | md5 >> hashes.csv; done