I wrote the following command:
var=$(printf "$line" | awk -F':' {'print $2'} | sed 's/,//g')
sed -i "s/$var/exampletext/g" "file.txt"
The text is part of a larger script that finds a specific value, and then replaces it with another value.
The basic end result I want is something like this:
sed -i "s/123/exampletext/g" "file.txt"
That should replace all of the 123's in file.txt with exampletext. When I echo $var, it shows the result of 123. Yet when that command is run, it doesn't work - it does not replace 123 with exampletext.
Here is the full script:
INPUT="$1"
while IFS= read -r line;
do
if [[ $line == *"length"* ]];
then
var=$(printf "$line" | awk -F':' {'print $2'} | sed 's/,//g')
sed -i "s|$var|cookiecrisp|g" "vomit.txt"
fi
done < $INPUT
Related
I have a string,
var=refs/heads/testing/branch
I want to get rid of refs/heads/ in the string using shell script, such that I have only:
var=testing/branch
Commands I tried (one per line):
echo $(var) | awk -F\\ {'print $2'}
echo $var | sed -e s,refs/heads/,,
echo "refs/heads/testing/branch" | grep -oP '(?<=refs/heads/\)\w+'
echo "refs/heads/testing/branch" | LC_ALL=C sed -e 's/.*\\//'
echo "refs/heads/testing/branch" | cut -d'\' -f2
echo refs/heads/testing/branch | sed -e s,refs/heads/,,
there are lots of options out there ,try easy ones:
echo $var | cut -d "/" -f 3,4
echo $var | awk -F"/" '{print $3"/"$4}'
Shell parameter expansion: remove the prefix "refs/heads/" from the variable contents
$ var=refs/heads/testing/branch
$ echo "${var#refs/heads/}"
testing/branch
I need to read a json file and take value like 99XXXXXXXXXXXX0 and cccs and write in csv which having column BASE_No and Schedule.
Input file: classedFFDCD_5666_4888_45_2018_02112018012106.021.json
"bfgft":"99XXXXXXXXXXXX0","fp":"XXXXXX","cur_gt":225XXXXXXXX0,"cccs"
"bfgft":"21XXXXXXXXXXXX0","fp":"XXXXXX","cur_gt":225XXXXXXXX0,"nncs"
"bfgft":"56XXXXXXXXXXXX0","fp":"XXXXXX","cur_gt":225XXXXXXXX0,"fgbs"
"bfgft":"44XXXXXXXXXXXX0","fp":"XXXXXX","cur_gt":225XXXXXXXX0,"ddss"
"bfgft":"94XXXXXXXXXXXX0","fp":"XXXXXX","cur_gt":225XXXXXXXX0,"jjjs"
Expected output:
BASE_No,Schedule
99XXXXXXXXXXXX0,cccs
21XXXXXXXXXXXX0,nncs
56XXXXXXXXXXXX0,fgbs
44XXXXXXXXXXXX0,ddss
94XXXXXXXXXXXX0,jjjs
I am using below code for reading file name and date, but unable to read file for BASE_No,Schedule.
SAVEIFS=$IFS
IFS=$(echo -en "\n\b")
for line in `ls -lrt *.json`; do
date=$(echo $line |awk -F ' ' '{print $6" "$7}');
file=$(echo $line |awk -F ' ' '{print $9}');
echo ''$file','$(date "+%Y/%m/%d %H.%M.%S")'' >> $File_Tracker`
Assuming the structure of the json doesnt change for every line, the sample code checks through line by line to retrieve the particular value and concatenates using printf. The output is then stored as new output.txt file.
#!/bin/bash
input="/home/kj4458/winhome/Downloads/sample.json"
printf "Base,Schedule \n" > output.txt
while IFS= read -r var
do
printf "`echo "$var" | cut -d':' -f 2 | cut -d',' -f 1`,`echo "$var" | cut -d':' -f 4 | cut -d',' -f 2` \n" | sed 's/"//g' >> output.txt
done < "$input"
awk -F " \" " ' {print $4","$12 }' file
99XXXXXXXXXXXX0,cccs
21XXXXXXXXXXXX0,nncs
56XXXXXXXXXXXX0,fgbs
44XXXXXXXXXXXX0,ddss
94XXXXXXXXXXXX0,jjjs
I got that result!
I have this shell script variable, var. It keeps 3 entries separated by new line. From this variable var, I want to extract 2, and 0.078688. Just these two numbers.
var="USER_ID=2
# 0.078688
Suhas"
These are the code I tried:
echo "$var" | grep -o -P '(?<=\=).*(?=\n)' # For extracting 2
echo "$var" | awk -v FS="(# |\n)" '{print $2}' # For extracting 0.078688
None of the above working. What is the problem here? How to fix this ?
Just use tr alone for retaining the numerical digits, the dot (.) and the white-space and remove everything else.
tr -cd '0-9. ' <<<"$var"
2 0.078688
From the man page, of tr for usage of -c, -d flags,
tr [OPTION]... SET1 [SET2]
-c, -C, --complement
use the complement of SET1
-d, --delete
delete characters in SET1, do not translate
To store it in variables,
IFS=' ' read -r var1 var2 < <(tr -cd '0-9. ' <<<"$var")
printf "%s\n" "$var1"
2
printf "%s\n" "$var2"
2
0.078688
Or in an array as
IFS=' ' read -ra numArray < <(tr -cd '0-9. ' <<<"$var")
printf "%s\n" "${numArray[#]}"
2
0.078688
Note:- The -cd flags in tr are POSIX compliant and will work on any systems that has tr installed.
echo "$var" |grep -oP 'USER_ID=\K.*'
2
echo "$var" |grep -oP '# \K.*'
0.078688
Your solution is near to perfect, you need to chance \n to $ which represent end of line.
echo "$var" |awk -F'# ' '/#/{print $2}'
0.078688
echo "$var" |awk -F'=' '/USER_ID/{print $2}'
2
You can do it with pure bash using a regex:
#!/bin/bash
var="USER_ID=2
# 0.078688
Suhas"
[[ ${var} =~ =([0-9]+).*#[[:space:]]([0-9\.]+) ]] && result1="${BASH_REMATCH[1]}" && result2="${BASH_REMATCH[2]}"
echo "${result1}"
echo "${result2}"
With awk:
First value:
echo "$var" | grep 'USER_ID' | awk -F "=" '{print $2}'
Second value:
echo "$var" | grep '#' | awk '{print $2}'
Assuming this is the format of data as your sample
# For extracting 2
echo "$var" | sed -e '/.*=/!d' -e 's///'
echo "$var" | awk -F '=' 'NR==1{ print $2}'
# For extracting 0.078688
echo "$var" | sed -e '/.*#[[:blank:]]*/!d' -e 's///'
echo "$var" | awk -F '#' 'NR==2{ print $2}'
I'm trying to compare two CSV files by reading the first line-by-line and grepping the second file for a match. Using Diff is not a viable solution. I seem to be having a problem with having the email address stored as a variable when I grep the second file.
#!/bin/bash
LANG=C
head -2 $1 | tail -1 | while read -r line; do
line=$( echo $line | sed 's/\n//g' )
echo $line
cat $2 | cut -d',' -f1 | grep -iF "$line"
done
Variable $line contains an email address that DOES exist in file $2, but I'm not getting any results.
What am I doing wrong?
File1
Email
email#verizon.net
email#gmail.com
email#yahoo.com
File2
email,,,,
email#verizon.net,,,,
email#gmail.com,,,,
email#yahoo.com,,,,
Given:
# csv_0.csv
email
me#me.com
you#me.com
fee#me.com
and
# csv_1.csv
email,foo,bar,baz,bim
bee#me.com,3,2,3,4
me#me.com,4,1,1,32
you#me.com,7,4,6,6
gee#me.com,1,2,2,6
me#me.com,5,7,2,34
you#me.com,22,3,2,33
I ran
$ pattern=$(head -2 csv_0.csv | tail -1 | sed s/,.*//g)
$ grep $pattern csv_1.csv
me#me.com,4,1,1,32
me#me.com,5,7,2,34
To do this for each line in csv_0.csv
#!/bin/bash
LANG=C
filename="$1"
{
read # don't read csv headers
while read line
do
pattern=$(echo $line | sed s/,.*//g)
grep $pattern $2
done
} <"$filename"
Then
$ ./csv_read.sh csv_2.csv csv_3.csv
me#me.com,4,1,1,32
me#me.com,5,7,2,34
you#me.com,7,4,6,6
you#me.com,22,3,2,33
I'm trying to write a little script which will open a text file and give me an md5 hash for each line of text. For example I have a file with:
123
213
312
I want output to be:
ba1f2511fc30423bdbb183fe33f3dd0f
6f36dfd82a1b64f668d9957ad81199ff
390d29f732f024a4ebd58645781dfa5a
I'm trying to do this part in bash which will read each line:
#!/bin/bash
#read.file.line.by.line.sh
while read line
do
echo $line
done
later on I do:
$ more 123.txt | ./read.line.by.line.sh | md5sum | cut -d ' ' -f 1
but I'm missing something here, does not work :(
Maybe there is an easier way...
Almost there, try this:
while read -r line; do printf %s "$line" | md5sum | cut -f1 -d' '; done < 123.txt
Unless you also want to hash the newline character in every line you should use printf or echo -n instead of echo option.
In a script:
#! /bin/bash
cat "$#" | while read -r line; do
printf %s "$line" | md5sum | cut -f1 -d' '
done
The script can be called with multiple files as parameters.
You can just call md5sum directly in the script:
#!/bin/bash
#read.file.line.by.line.sh
while read line
do
echo $line | md5sum | awk '{print $1}'
done
That way the script spits out directly what you want: the md5 hash of each line.
this worked for me..
cat $file | while read line; do printf %s "$line" | tr -d '\r\n' | md5 >> hashes.csv; done