I am relatively new to Pl Sql and have to write a procedure which does following, It has got 6-7 different queries which are as follows :
Select manager, count(*) bank from abc ..........
select manager , count(*) retail from abc .......
Now each count is for a different department , while manager may be same . So problem is that I am looking for a best approach which helps me to store
the data in separate table which has following structure:
Manager : Count Bank : Count Retail : Count xyz ...........
How do I make sure using Pl sql that each manager has right count for all the columns(bank/retai/xyz) , the first thing is how to store multiple different query result and process it . I think we can use cursor but I need to research on it , also this procedure should be high performance .
Please suggest.
Thanks
XslGuy
This is easily achievable with conditional sums. Hopefully the below will give you enough of an idea of what you need to do:
with sample_data as (select 1 id, 1 dept, 10 val from dual union all
select 2 id, 1 dept, 20 val from dual union all
select 3 id, 2 dept, 30 val from dual union all
select 4 id, 3 dept, 40 val from dual union all
select 5 id, 1 dept, 50 val from dual union all
select 6 id, 3 dept, 60 val from dual union all
select 7 id, 2 dept, 70 val from dual union all
select 8 id, 4 dept, 80 val from dual)
-- end of creating a subquery that contains some sample data. See sql below:
select sum(case when dept = 1 then val end) dept_1_total,
sum(case when dept = 2 then val end) dept_2_total,
sum(case when dept = 3 then val end) dept_3_total
from sample_data
where dept in (1, 2, 3);
DEPT_1_TOTAL DEPT_2_TOTAL DEPT_3_TOTAL
------------ ------------ ------------
80 100 100
Related
Currently, I have a table MY_TABLE like below:
ID ACCT_TYPE CREDIT_AMT DEBIT_AMT
-- --------- ---------- ---------
1 CDT_01 4 (null)
1 DBT_01 (null) 6
One ID can have multiple ACCT_TYPE like above, and each type has its own amount.
I want to just select the row which has ACCT_TYPE like 'CDT_%' but also the total_amount column which is the total of credit_amt and debit_amt column for the same ID.
My expected output like below:
ID ACCT_TYPE TOTAL_AMT
-- --------- ---------
1 CDT_01 10
I tried with this select statement below but it's no use, I think it's because of different ACCT_TYPE:
Select ID, ACCT_TYPE, SUM(NVL(CREDIT_AMT, 0) + NVL(DEBIT_AMT, 0)) TOTAL_AMT
FROM MY_TABLE WHERE ACCT_TYPE LIKE 'CDT_%' GROUP BY ID, ACCT_TYPE;
Here is the output of the select statement above:
ID ACCT_TYPE TOTAL_AMT
-- --------- ---------
1 CDT_01 4
I just begin to learn some query so I don't know is it really possible to get my expected output.
One way to do it is like below:
with inputs (ID, ACCT_TYPE, CREDIT_AMT, DEBIT_AMT) as
(
select 1, 'CDT_01', 4, null from dual union all
select 1, 'DBT_01', null, 6 from dual
),
prep as
(
select t.*, sum(nvl(credit_amt,0)) over (partition by id) + sum(nvl(debit_amt,0)) over (partition by id) as sum_per_id
from inputs t
)
select id, acct_type, sum_per_id
from prep
where acct_type like 'CDT_%';
Output:
A correlated subquery might be one option; sample data (thank you, #Ranagal) in lines #1 - 5; query that does the job begins at line #6.
SQL> with inputs (ID, ACCT_TYPE, CREDIT_AMT, DEBIT_AMT) as
2 (
3 select 1, 'CDT_01', 4, null from dual union all
4 select 1, 'DBT_01', null, 6 from dual
5 )
6 select a.id,
7 a.acct_type,
8 (select sum(nvl(b.credit_amt, 0)) +
9 sum(nvl(b.debit_amt , 0))
10 from inputs b
11 where b.id = a.id
12 ) total_amt
13 from inputs a
14 where acct_type like 'CDT%';
ID ACCT_T TOTAL_AMT
---------- ------ ----------
1 CDT_01 10
SQL>
Using information in Table A, how can I produce results in Table B below?
Table A:
CASE_ID DATE_EFF COPAY STATUS
1 11/04/2016 10 A
1 11/20/2016 5 A
1 11/23/2016 5 R
1 12/01/2016 1 A
1 12/10/2016 2 A
1 12/12/2016 10 A
1 12/31/2016 50 R
For the above CASE_ID, we have dates in Nov 2016 and Dec 2016 only, however, I want to produce a breakdown of this CASE_ID for a period of 6 months as below where for each month the copays are summed where applicable as per the DATE_EFF and for the months that are not within the above dates, a zero is entered. Also, only records with copays with a status of 'A' are summed for any month -- so those with status of 'R' are ignored in the summation. For example, based on data in Table A above, the intended results are as follow:
Table B:
CASE_ID MONTH TOTAL_COPAY
1 01/2017 0
1 12/2016 13
1 11/2016 15
1 10/2016 0
1 09/2016 0
1 08/2016 0
I have below as a possible solution[using a with clause], but can this be achieved without the use of the 'with' clause?
Possible Solution:
WITH
XRF AS
( SELECT CASE_ID, COPAY, DATE_EFF
FROM Table_A WHERE STATUS = 'A'
)
SELECT F.CASE_ID, ST, NVL(SUM(F.COPAY),0) TOTAL_COPAY FROM XRF F PARTITION BY (F.CASE_ID)
RIGHT OUTER JOIN (SELECT '12/2016' ST FROM DUAL UNION ALL
SELECT '11/2016' FROM DUAL UNION ALL
SELECT '10/2016' FROM DUAL UNION ALL
SELECT '09/2016' FROM DUAL UNION ALL
SELECT '08/2016' FROM DUAL UNION ALL
SELECT '07/2016' FROM DUAL) STS
ON (TO_CHAR(LAST_DAY((F.DATE_EFF)),'MM/YYYY') = STS.ST)
GROUP BY F.CASE_ID, ST ORDER BY F.CASE_ID, ST DESC
;
UPDATE AND SOLUTION:
Using the above query, I believe I am have answered my own question by implementing it as below -- not sure though if using this method is expensive when you have millions of records of such CASE_IDs. Any thoughts?
SELECT F.CASE_ID, ST, NVL(SUM(F.COPAY),0) TOTAL_COPAY FROM (SELECT CASE_ID, COPAY, DATE_EFF FROM TABLE_A WHERE STATUS = 'A') F PARTITION BY (F.CASE_ID)
RIGHT OUTER JOIN (SELECT '12/2016' ST FROM DUAL UNION ALL
SELECT '11/2016' FROM DUAL UNION ALL
SELECT '10/2016' FROM DUAL UNION ALL
SELECT '09/2016' FROM DUAL UNION ALL
SELECT '08/2016' FROM DUAL UNION ALL
SELECT '07/2016' FROM DUAL) STS
ON (TO_CHAR(LAST_DAY((F.DATE_EFF)),'MM/YYYY') = STS.ST)
GROUP BY F.CASE_ID, ST ORDER BY F.CASE_ID, ST DESC
;
hoping I might be able to get some advise regarding Oracle SQL…
I have a table roughly as follows (there are more columns, but not necessary for this example)…
LOCATION USER VALUE
1 1 10
1 2 20
1 3 30
2 4 10
2 5 10
2 6 20
1 60
2 40
100
I’ve used rollup to get subtotals.
What I need to do is get the max(value) row for each location and express the max(value) as a percentage or fraction of the subtotal for each location
ie:
LOCATION USER FRAC
1 3 0.5
2 6 0.5
I could probably solve this using my limited knowledge of select queries, but am guessing there must be a fairly quick and slick method..
Thanks in advance :)
Solution using analytic functions
(Please note the WITH MY_TABLE AS serving only as dummy datasource)
WITH MY_TABLE AS
( SELECT 1 AS LOC_ID,1 AS USER_ID, 10 AS VAL FROM DUAL
UNION
SELECT 1,2,20 FROM DUAL
UNION
SELECT 1,3,30 FROM DUAL
UNION
SELECT 2,4,10 FROM DUAL
UNION
SELECT 2,5,10 FROM DUAL
UNION
SELECT 2,6,20 FROM DUAL
)
SELECT LOC_ID,
USER_ID,
RATIO_IN_LOC
FROM
(SELECT LOC_ID,
USER_ID,
RATIO_IN_LOC,
RANK() OVER (PARTITION BY LOC_ID ORDER BY RATIO_IN_LOC DESC) AS ORDER_IN_LOC
FROM
(SELECT LOC_ID,
USER_ID,
VAL,
VAL/SUM(VAL) OVER (PARTITION BY LOC_ID) AS RATIO_IN_LOC
FROM MY_TABLE
)
)
WHERE ORDER_IN_LOC = 1
ORDER BY LOC_ID,
USER_ID;
Result
LOC_ID USER_ID RATIO_IN_LOC
1 3 0,5
2 6 0,5
with inputs ( location, person, value ) as (
select 1, 1, 10 from dual union all
select 1, 2, 20 from dual union all
select 1, 3, 30 from dual union all
select 2, 4, 10 from dual union all
select 2, 5, 10 from dual union all
select 2, 6, 20 from dual
),
prep ( location, person, value, m_value, total ) as (
select location, person, value,
max(value) over (partition by location),
sum(value) over (partition by location)
from inputs
)
select location, person, round(value/total, 2) as frac
from prep
where value = m_value;
Notes: Your table exists already? Then skip everything from "inputs" to the comma; your query should begin with with prep (...) as ( ...
I changed user to person since user is a keyword in Oracle, you shouldn't use it for table or column names (actually you can't unless you use double quotes, which is a very poor practice).
The query will output two or three or more rows per location if there are ties at the top. Presumably this is what you desire.
Output:
LOCATION PERSON FRAC
---------- ---------- ----------
1 3 .5
2 6 .5
I have a table that stored users play list, a video can be viewed by multiple users for multiple times.
A records goes like this:
videoid, userid, time
123, abc , 2013-09-11
It means user(abc) has watched video(123) on 2013-09-11
Now I want to find distinct users watched video list (no duplication), and only show the users that have watched more than two videos.
SELECT videoid, userid
FROM table_play_list
WHERE SOME CONDICTION
GROUP BY userid, videoid
The sql only select distinct users watchlist, I also want to filter users that have watched more than two different videos.
I know I have to google and read the documentation first, some said 'HAVING' could solve this, unfortunately, I could not make it.
If I understand correctly, you are looking for users who watched more than two different videos. You can do this by using count(distinct) with a partition by clause:
select userid, videoid
from (SELECT userid, videoid, count(distinct videoid) over (partition by userid) as cnt
FROM table_play_list
WHERE <ANY CONDITION>
) t
where cnt > 2;
Try like this,
SELECT userid, count(*)
FROM table_play_list
--WHERE SOME CONDITION
GROUP BY user_id
having count(*) >2;
Try this if you need to get the count based on userid and videoid(users who watch the same video more than two times).
SELECT userid, videoid, count(*)
FROM table_play_list
--WHERE SOME CONDITION
GROUP BY user_id, video_id
having count(*) >2;
This is probably best handled with analytics (window functions). Without analytics you will probably need a self-join.
SQL> WITH table_play_list AS (
2 SELECT 123 videoid, 'a' userid FROM dual UNION ALL
3 SELECT 125 videoid, 'a' userid FROM dual UNION ALL
4 SELECT 123 videoid, 'b' userid FROM dual UNION ALL
5 SELECT 123 videoid, 'b' userid FROM dual UNION ALL
6 SELECT 123 videoid, 'c' userid FROM dual
7 )
8 SELECT videoid, userid,
9 COUNT(*) over(PARTITION BY userid) nb_video
10 FROM table_play_list;
VIDEOID USERID NB_VIDEO
---------- ------ ----------
123 a 2
125 a 2
123 b 2
123 b 2
123 c 1
This lists all user/video and the total number of videos watched by each user. As you can see user b has watched the same video twice, I don't know if it's possible in your system.
You can filter with a subquery:
SQL> WITH table_play_list AS (
2 SELECT 123 videoid, 'a' userid FROM dual UNION ALL
3 SELECT 125 videoid, 'a' userid FROM dual UNION ALL
4 SELECT 123 videoid, 'b' userid FROM dual UNION ALL
5 SELECT 123 videoid, 'b' userid FROM dual UNION ALL
6 SELECT 123 videoid, 'c' userid FROM dual
7 )
8 SELECT *
9 FROM (SELECT videoid, userid,
10 COUNT(*) over(PARTITION BY userid) nb_video
11 FROM table_play_list)
12 WHERE nb_video > 1;
VIDEOID USERID NB_VIDEO
---------- ------ ----------
123 a 2
125 a 2
123 b 2
123 b 2
The below will give users who have watched more than two different videos.
SELECT userid, count(distinct video_id)
FROM table_play_list
WHERE SOME CONDICTION
GROUP BY user_id
having count(distinct video_id) >2;
If you use Oracle PL/SQL you can use like this:
SELECT column1, column2
FROM
(
SELECT column1, column2, COUNT(column1)
OVER (PARTITION BY column1) AS cnt
FROM test
GROUP BY column1, column2
ORDER BY column1
)
WHERE cnt > 2
If you use standard SQL you can use like this:
SELECT column1, column2
FROM test
WHERE column1 IN
(
SELECT column1
FROM
(
SELECT column1, column2
FROM test
GROUP BY column1, column2
ORDER BY column1
)
GROUP BY column1
HAVING COUNT(column1) > 2
)
GROUP BY column1, column2
ORDER BY column1
i have below data.
table A
id
1
2
3
table B
id name data1 data2 datetime
1 cash 12345.00 12/12/2012 11:10:12
1 quantity 222.12 14/12/2012 11:10:12
1 date 20/12/2012 12/12/2012 11:10:12
1 date 19/12/2012 13/12/2012 11:10:12
1 date 13/12/2012 14/12/2012 11:10:12
1 quantity 330.10 17/12/2012 11:10:12
I want to retrieve data in one row like below:
tableA.id tableB.cash tableB.date tableB.quantity
1 12345.00 13/12/2012 330.10
I want to retrieve based on max(datetime).
The data model appears to be insane-- it makes no sense to join an ORDER_ID to a CUSTOMER_ID. It makes no sense to store dates in a VARCHAR2 column. It makes no sense to have no relationship between a CUSTOMER and an ORDER. It makes no sense to have two rows in the ORDER table with the same ORDER_ID. ORDER is also a reserved word so you cannot use that as a table name. My best guess is that you want something like
select *
from customer c
join (select order_id,
rank() over (partition by order_id
order by to_date( order_time, 'YYYYMMDD HH24:MI:SS' ) desc ) rnk
from order) o on (c.customer_id=o.order_id)
where o.rnk = 1
If that is not what you want, please (as I asked a few times in the comments) post the expected output.
These are the results I get with my query and your sample data (fixing the name of the ORDER table so that it is actually valid)
SQL> ed
Wrote file afiedt.buf
1 with orders as (
2 select 1 order_id, 'iphone' order_name, '20121201 12:20:23' order_time from dual union all
3 select 1, 'iphone', '20121201 12:22:23' from dual union all
4 select 2, 'nokia', '20110101 13:20:20' from dual ),
5 customer as (
6 select 1 customer_id, 'paul' customer_name from dual union all
7 select 2, 'stuart' from dual union all
8 select 3, 'mike' from dual
9 )
10 select *
11 from customer c
12 join (select order_id,
13 rank() over (partition by order_id
14 order by to_date( order_time, 'YYYYMMDD HH24:MI:SS' ) desc ) rnk
15 from orders) o on (c.customer_id=o.order_id)
16* where o.rnk = 1
SQL> /
CUSTOMER_ID CUSTOM ORDER_ID RNK
----------- ------ ---------- ----------
1 paul 1 1
2 stuart 2 1
Try something like
SELECT *
FROM CUSTOMER c
INNER JOIN ORDER o
ON (o.CUSTOMER_ID = c.CUSTOMER_ID)
WHERE TO_DATE(o.ORDER_TIME, 'YYYYMMDD HH24:MI:SS') =
(SELECT MAX(TO_DATE(o.ORDER_TIME, 'YYYYMMDD HH24:MI:SS')) FROM ORDER)
Share and enjoy.