Currently, I have a table MY_TABLE like below:
ID ACCT_TYPE CREDIT_AMT DEBIT_AMT
-- --------- ---------- ---------
1 CDT_01 4 (null)
1 DBT_01 (null) 6
One ID can have multiple ACCT_TYPE like above, and each type has its own amount.
I want to just select the row which has ACCT_TYPE like 'CDT_%' but also the total_amount column which is the total of credit_amt and debit_amt column for the same ID.
My expected output like below:
ID ACCT_TYPE TOTAL_AMT
-- --------- ---------
1 CDT_01 10
I tried with this select statement below but it's no use, I think it's because of different ACCT_TYPE:
Select ID, ACCT_TYPE, SUM(NVL(CREDIT_AMT, 0) + NVL(DEBIT_AMT, 0)) TOTAL_AMT
FROM MY_TABLE WHERE ACCT_TYPE LIKE 'CDT_%' GROUP BY ID, ACCT_TYPE;
Here is the output of the select statement above:
ID ACCT_TYPE TOTAL_AMT
-- --------- ---------
1 CDT_01 4
I just begin to learn some query so I don't know is it really possible to get my expected output.
One way to do it is like below:
with inputs (ID, ACCT_TYPE, CREDIT_AMT, DEBIT_AMT) as
(
select 1, 'CDT_01', 4, null from dual union all
select 1, 'DBT_01', null, 6 from dual
),
prep as
(
select t.*, sum(nvl(credit_amt,0)) over (partition by id) + sum(nvl(debit_amt,0)) over (partition by id) as sum_per_id
from inputs t
)
select id, acct_type, sum_per_id
from prep
where acct_type like 'CDT_%';
Output:
A correlated subquery might be one option; sample data (thank you, #Ranagal) in lines #1 - 5; query that does the job begins at line #6.
SQL> with inputs (ID, ACCT_TYPE, CREDIT_AMT, DEBIT_AMT) as
2 (
3 select 1, 'CDT_01', 4, null from dual union all
4 select 1, 'DBT_01', null, 6 from dual
5 )
6 select a.id,
7 a.acct_type,
8 (select sum(nvl(b.credit_amt, 0)) +
9 sum(nvl(b.debit_amt , 0))
10 from inputs b
11 where b.id = a.id
12 ) total_amt
13 from inputs a
14 where acct_type like 'CDT%';
ID ACCT_T TOTAL_AMT
---------- ------ ----------
1 CDT_01 10
SQL>
Related
I am new to oracle thus this question.
There is a table already existed and I have added a new column to it.
There are 5 rows and I do not want to use update table with where clause to insert the values one by one in the new column. Is there a statement like INSERT ALL to insert the values into the new column in one shot ?
Thanks
You can also use something like below which in-effect I would say is multiple update only, wrapped in single statement.
SQL> select * from test_upd;
ID1 ID2
---------- ----------
1
2
3
4
SQL> update test_upd a set a.id2 =
2 (select
3 case
4 when id1=1 then 100
5 when id1=2 then 200
6 when id1=3 then 300
7 else 5000 end
8 from test_upd b
9 where a.id1=b.id1);
4 rows updated.
SQL> select * from test_upd;
ID1 ID2
---------- ----------
1 100
2 200
3 300
4 5000
Use a MERGE statement:
MERGE INTO your_table dst
USING (
SELECT 1 AS id, 'aaa' AS newvalue FROM DUAL UNION ALL
SELECT 2, 'bbb' FROM DUAL UNION ALL
SELECT 3, 'ccc' FROM DUAL UNION ALL
SELECT 4, 'ddd' FROM DUAL UNION ALL
SELECT 5, 'eee' FROM DUAL
) src
ON (dst.id = src.id)
WHEN MATCHED THEN
UPDATE SET value = src.newvalue;
Which, if you have the table:
CREATE TABLE your_table (id, value) AS
SELECT 1, CAST(NULL AS VARCHAR2(3)) FROM DUAL UNION ALL
SELECT 2, NULL FROM DUAL UNION ALL
SELECT 3, NULL FROM DUAL UNION ALL
SELECT 4, NULL FROM DUAL UNION ALL
SELECT 5, NULL FROM DUAL;
Then, after the MERGE, the table contains:
ID
VALUE
1
aaa
2
bbb
3
ccc
4
ddd
5
eee
db<>fiddle here
I am using Oracle 11.
I have 2 tables
TblA with columns id, entity_id and effective_date.
TblADetail with columns id and value.
If Value = 0 for the effective date, I want to keep looking for the next effective date until I found value <> 0 anymore.
The below query only look for value on 3/10/21.
If value = 0, I want to look for value on 3/11/21. If that's not 0, I want to stop.
But, if that's 0, I want to look for value on 3/12/21. If that's not 0, I want to stop.
But, if that's 0, I want to keep looking until value is not 0.
How can I do that ?
SELECT SUM(pd.VALUE)
FROM TblA p,TblADetail pd
WHERE p.id = pd.id
AND p.effective_date = to_date('03/10/2021','MM/DD/YYYY')
AND TRIM (p.entity_id) = 123
Sample data:
TblA
id entity_id effective_date
1 123 3/10/21
2 123 3/11/21
3 123 3/12/21
TblADetail
id value
1 -136
1 136
2 2000
3 3000
In the above data, for entity_id 123, starting from effective_date 3/10/21, I would like to to return value 2000 (from TblADetail) effective_date 3/11/21.
So, starting from a certain date, I want the results from the minimum date that has non-zero values.
Thank you.
You can do what you need to do by grouping the sum on the effective date, and using the MIN analytic function to find the earliest date. Once you've done that, you simply need to select the date that matches the earliest date.
E.g.:
with tbla as (select 1 id, ' 123' entity_id, to_date('10/03/2021', 'dd/mm/yyyy') effective_date from dual union all
select 2 id, ' 123' entity_id, to_date('11/03/2021', 'dd/mm/yyyy') effective_date from dual union all
select 3 id, ' 123' entity_id, to_date('12/03/2021', 'dd/mm/yyyy') effective_date from dual),
tbla_detail as (select 1 id, -136 value from dual union all
select 1 id, 136 value from dual union all
select 2 id, 2000 value from dual union all
select 3 id, 3000 value from dual),
results as (select a.effective_date,
sum(ad.value) sum_value,
min(case when sum(ad.value) != 0 then a.effective_date end) over () min_effective_date
from tbla a
inner join tbla_detail ad on a.id = ad.id
where a.effective_date >= to_date('10/03/2021', 'dd/mm/yyyy')
and trim(a.entity_id) = '123'
group by a.effective_date)
select sum_value
from results
where effective_date = min_effective_date;
SUM_VALUE
----------
2000
Straightforward; read comments within code. Sample data in lines #1 - 13, query begins at line #14.
SQL> with
2 -- sample data
3 tbla (id, entity_id, effective_date) as
4 (select 1, 123, date '2021-03-10' from dual union all
5 select 2, 123, date '2021-03-11' from dual union all
6 select 3, 123, date '2021-03-12' from dual
7 ),
8 tblb (id, value) as
9 (select 1, -136 from dual union all
10 select 1, 136 from dual union all
11 select 2, 2000 from dual union all
12 select 3, 3000 from dual
13 ),
14 tblb_temp as
15 -- simple grouping per ID
16 (select id, sum(value) value
17 from tblb
18 group by id
19 )
20 -- return TBLA values whose ID equals TBLB_TEMP's minimum ID
21 -- whose value isn't zero
22 select a.id, a.entity_id, a.effective_date
23 from tbla a
24 where a.id = (select min(b.id)
25 from tblb_temp b
26 where b.value > 0
27 );
ID ENTITY_ID EFFECTIVE_
---------- ---------- ----------
2 123 03/11/2021
SQL>
I have a simple table with values (ID) in groups (GRP_ID).
create table tst as
select 1 grp_id, 1 id from dual union all
select 1 grp_id, 1 id from dual union all
select 1 grp_id, 2 id from dual union all
select 2 grp_id, 1 id from dual union all
select 2 grp_id, 2 id from dual union all
select 2 grp_id, 2 id from dual union all
select 3 grp_id, 3 id from dual;
It is straightforward to find a maximum value per group using analytical functions.
select grp_id, id,
max(id) over (partition by grp_id) max_grp
from tst
order by 1,2;
GRP_ID ID MAX_GRP
---------- ---------- ----------
1 1 2
1 1 2
1 2 2
2 1 2
2 2 2
2 2 2
3 3 3
But the goal is to find the maximum value excluding the value of the current row.
This is the expected result (column MAX_OTHER_ID):
GRP_ID ID MAX_GRP MAX_OTHER_ID
---------- ---------- ---------- ------------
1 1 2 2
1 1 2 2
1 2 2 1
2 1 2 2
2 2 2 2
2 2 2 2
3 3 3
Note that in the GRP_ID = 2 a tie on the MAX value exists, so the MAX_OTHER_ID remains the same.
I did manage this two step solution, but I'm wondering if there is a more straightforward and simple solution.
with max1 as (
select grp_id, id,
row_number() over (partition by grp_id order by id desc) rn
from tst
)
select GRP_ID, ID,
case when rn = 1 /* MAX row per group */ then
max(decode(rn,1,to_number(null),id)) over (partition by grp_id)
else
max(id) over (partition by grp_id)
end as max_other_id
from max1
order by 1,2
;
I wish the window functions supported multiple range specifications something like:
max(id) over (
partition by grp_id
order by id
range between unbounded preceding and 1 preceding
or range between 1 following and unbounded following
)
But unfortunately they don't.
As a workaround, you can avoid subqueries and CTEs using the function twice on the different ranges and call coalesce on that.
select grp_id,
id,
coalesce(
max(id) over (
partition by grp_id
order by id
range between 1 following and unbounded following
)
, max(id) over (
partition by grp_id
order by id
range between unbounded preceding and 1 preceding
)
) max_grp
from tst
order by 1,
2
Coalesce works out of the box because of the ordering clause as the result of the window function call will be either the max in the given window or a null value.
Demo - http://rextester.com/SDXVF13962
SELECT GRP_ID,ID, (SELECT Max(ID) FROM TEST A WHERE A.ROWID<>B.ROWID AND A.GRP_ID=B.GRP_ID) maX_ID FROM TEST B;
Got the expected result with Co-Related Query ! Hope this helps .
i have table test2.it contains
ID
1
4
5
10
now i found missing numbers in this sequence.with this query
SELECT min_ID - 1 + level mn FROM
( SELECT MIN(ID) min_ID , MAX(ID) max_ID FROM test2 )
CONNECT BY level <= max_ID - min_ID + 1 minus SELECT ID FROM test2
output is:
MN
---
2
3
6
7
8
9
now i want to combine these 2 columns.I am unable to do this please help me.
i want output like
1 2
4 3
7 5
10 6
8
9
Oracle Setup:
CREATE TABLE test2 (id) AS
SELECT 1 FROM DUAL UNION ALL
SELECT 4 FROM DUAL UNION ALL
SELECT 5 FROM DUAL UNION ALL
SELECT 10 FROM DUAL;
Query:
WITH bounds ( mn, mx ) AS (
SELECT MIN( id ), MAX( id ) FROM test2
),
missing (id, rn) AS (
SELECT id, ROWNUM
FROM (
SELECT mn + LEVEL AS id
FROM bounds
CONNECT BY LEVEL < MX - MN
MINUS
SELECT id
FROM test2
)
),
existing ( id, rn ) AS (
SELECT id, ROWNUM
FROM test2
)
SELECT e.id, m.id
FROM existing e
FULL OUTER JOIN
missing m
ON ( e.rn = m.rn );
Output
ID ID
---------- ----------
1 2
4 3
5 6
10 7
9
8
i have below data.
table A
id
1
2
3
table B
id name data1 data2 datetime
1 cash 12345.00 12/12/2012 11:10:12
1 quantity 222.12 14/12/2012 11:10:12
1 date 20/12/2012 12/12/2012 11:10:12
1 date 19/12/2012 13/12/2012 11:10:12
1 date 13/12/2012 14/12/2012 11:10:12
1 quantity 330.10 17/12/2012 11:10:12
I want to retrieve data in one row like below:
tableA.id tableB.cash tableB.date tableB.quantity
1 12345.00 13/12/2012 330.10
I want to retrieve based on max(datetime).
The data model appears to be insane-- it makes no sense to join an ORDER_ID to a CUSTOMER_ID. It makes no sense to store dates in a VARCHAR2 column. It makes no sense to have no relationship between a CUSTOMER and an ORDER. It makes no sense to have two rows in the ORDER table with the same ORDER_ID. ORDER is also a reserved word so you cannot use that as a table name. My best guess is that you want something like
select *
from customer c
join (select order_id,
rank() over (partition by order_id
order by to_date( order_time, 'YYYYMMDD HH24:MI:SS' ) desc ) rnk
from order) o on (c.customer_id=o.order_id)
where o.rnk = 1
If that is not what you want, please (as I asked a few times in the comments) post the expected output.
These are the results I get with my query and your sample data (fixing the name of the ORDER table so that it is actually valid)
SQL> ed
Wrote file afiedt.buf
1 with orders as (
2 select 1 order_id, 'iphone' order_name, '20121201 12:20:23' order_time from dual union all
3 select 1, 'iphone', '20121201 12:22:23' from dual union all
4 select 2, 'nokia', '20110101 13:20:20' from dual ),
5 customer as (
6 select 1 customer_id, 'paul' customer_name from dual union all
7 select 2, 'stuart' from dual union all
8 select 3, 'mike' from dual
9 )
10 select *
11 from customer c
12 join (select order_id,
13 rank() over (partition by order_id
14 order by to_date( order_time, 'YYYYMMDD HH24:MI:SS' ) desc ) rnk
15 from orders) o on (c.customer_id=o.order_id)
16* where o.rnk = 1
SQL> /
CUSTOMER_ID CUSTOM ORDER_ID RNK
----------- ------ ---------- ----------
1 paul 1 1
2 stuart 2 1
Try something like
SELECT *
FROM CUSTOMER c
INNER JOIN ORDER o
ON (o.CUSTOMER_ID = c.CUSTOMER_ID)
WHERE TO_DATE(o.ORDER_TIME, 'YYYYMMDD HH24:MI:SS') =
(SELECT MAX(TO_DATE(o.ORDER_TIME, 'YYYYMMDD HH24:MI:SS')) FROM ORDER)
Share and enjoy.