ignore spaces while comparing tokens files - bash

Question

I have a script in which there is two file. I have to compare both file and have to display the content of mismatching file, e.g.:
file1
file2
content of file1:
abcd
efgh
ijk
content of file2:
abcd=123
efgh=
ijkl=1213
if the matching don't occur, it should display like matching not occur.
if the matching name occur but the value of respective name is not present in file2. It should display like the value is missing.
e.g. aefgh is present in bothy file but the value of efgh is not present in file 2.so it should display the matching value is not present.
file="$HOME/SAMPLE/token_values.txt"
while read -r var
do
if grep "$var" environ.ref >/dev/null
then
:
else
print "$var ((((((Not Present))))))" >> final13.txt
fi
done < "$file"

Answer 1

I guess this script would do it :
#!/bin/bash
#below line removes the blank lines in the first file
fileprocessed1=$( sed '/^$/d' your_file1 )
#below line removes the blank lines and replaces the = with blank space in the second file
fileprocessed2=$( sed '{/^$/d};{s/=/\ /g}' your_file2 )
paste <(echo "$fileprocessed1") <(echo "$fileprocessed2")| awk '{
if($1 == $2)
{
if(length($3) == 0)
{
print NR" : Match found but value Missing for "$2
}
else
{
print NR" : Match found for "$1" with value "$3
}
}
else
{
print NR" : No match for "$1
}
}'
would give :
1 : Match found for bcd with value 123
2 : Match found but value missing for efgh
3 : No match for ijk
for the files you have given.
But I really hope somebody would come with a one-liner for this one. :)

Answer 2

I would tackle it something like this in perl:
#!/usr/bin/env perl
use strict;
use warnings;
open ( my $file1, '<', "~/SAMPLE/token_values.txt" ) or die $!;
chomp ( my #tokens = <$file1> );
open ( my $file2, '<', 'environ.ref' ) or die $!;
my %data = map { /(\w+)=(\w*)/ } <$file2>;
for my $thing ( #tokens ) {
print $thing,"\n" unless $data{$thing} eq '';
}