In MySQL Database Table there are 2 columns
Order TypeID
Order Type
In Order to find a record with ID, I am using below code.
$OrderType = \App\Models\OrderType_Model::find($request->input('OrderTypeID'));
Is there any way to get both by ID and Name ?
You can use a orWhere clause
$orderType = OrderType_Model
->where('OrderTypeId',$request->input('OrderTypeId))
->orWhere('OrderType', $request->input('OrderType))
->first();
$OrderType = \App\Models\OrderType_Model
::where("OrderTypeID", "!=", $request->input('OrderTypeID'))
->where("OrderType", '=', $request->input('OrderType'))->first();
Related
I have two tables users/invoices in 1:n relation. When someone creats an invoice it saves the user_id. Also it's possible (optional) to set a manager (column: project_management_user_id). If there is no manager set (NULL), I want to get the user, who created the record. So for now I have this query. It gives me all invoices with the manager (but not that ones with manager = null.
$query = Invoice::join('users', 'invoices.project_management_user_id', '=', 'users.id')
->select('users.name as name', 'users.color as color', DB::raw("count(invoices.id) as count"))
->get();
Is it possible to add some if-clause like "if project_management_user_id is null, take the user_id"? I read about the whereNull() function, but it filters my whole query
Use leftJoin instead of join in the query.
My working SQL query is as follows:
SELECT post_id
FROM news_tags
ORDER BY (link_clicks+views) DESC
What I've tried so far in eloquent is like this:
$newsTagSaved = NewsTag::
orderBy(DB::raw("`views` + `link_clicks`"), 'desc')
->paginate(12)
->pluck('post_id');
Newstag table has many columns and views and link_clicks are two of them. Now, I'm trying to retrieve the post_id order by desc of sum of views and link_click.
How can I do it in Laravel eloquent?
Thank you!
Do something like this:
$newsTagSaved = NewsTag::select(DB::raw('views + link_clicks as score'))
->orderBy('score', 'desc')
->get();
dd($newsTagSaved);
This will return just score value. If you want to return other fields, simply add them to select. As an example:
$newsTagSaved = NewsTag::select(
DB::raw('views + link_clicks as score'),
'title',
'created_at'
)
->orderBy('score', 'desc')
->get();
dd($newsTagSaved);
i have this raw query and i want to use it in eloquent query builder
but seems i cant use date method in eloquent and gave me this error im new in eloquent. what is the problem:
SQLSTATE[42S22]: Column not found: 1054 Unknown column 'date(prizes.created_at), user_id' in 'group statement' (SQL: select user_id,COUNT(user_id), date(created_at) from `prizes` group by `date(prizes`.`created_at), user_id` having `user_id` = 1 order by `date(created_at)` desc)
raw SQL:
SELECT
user_id,COUNT(user_id), DATE(created_at) FROM prizes
GROUP BY DATE(prizes.created_at), user_id
HAVING user_id = 1
ORDER BY DATE(created_at) DESC
limit 2
Eloquent:
$points = \App\Prize::selectRaw('user_id,COUNT(user_id), date(created_at)')
->groupBy("date(prizes.created_at), user_id")
->orderBy("date(created_at)","DESC")
->having("user_id","=",1)
->get();
what is the the cleanest and best form??
By default, Laravel tries to parse all strings as tables. This means it will add the string between `.
To avoid this, you can put the string in a DB:raw() function to let Laravel know not to parse this string and send it as-is to the database.
->orderBy(\DB::raw("date(created_at)"), "DESC")
Or use the raw method for ordering:
->orderByRaw('date(created_at) desc')
I want to use concat with eloquent , I have two tables (users) and (cars)
From users table I want to use first_name , last_name fields, and from cars table I want to use field called (vin).
$cars = Car::where(DB::raw('concat(first_name," ",vin," ",make)') , 'LIKE' , '%$search%')->paginate();
first_name field from Users table and the rest from Cars table
You can use join() for this as:
$cars = Car::join('users', 'cars.user_id', '=', 'users.id')
->where(DB::raw('concat(users.first_name," ",cars.vin," ",cars.make)') , 'LIKE' , "%$search%")
->select('cars.*')
->paginate();
I want to write a query which selects rows where 2 attributes from 1 entity have equal value.
This would be an example of doing this in raw SQL:
Select * from users u where u.username = u.lastname
Does laravel have any methods that take 2 column names as parameters and return the matching results?
What you need is a DB::raw expression:
DB::table('users')
->where('username', '=', DB::raw('lastname'))
->get();
The only thing DB::raw actually does is to tell the query interpreter not to treat 'lastname' like any other string value but just interpolate it in the SQL as it is.
http://laravel.com/docs/queries#raw-expressions
In Laravel 5, there's now whereColumn for this, for cleaner code:
Users::whereColumn('username', 'lastname')->get();