I have command, which gives me output from telnet. Full output from telnet It looks like this:
telnet myserver.com 1234
Server, Name=MyServer, Age=123, Ver=1.23, ..., ..., ...
This command should filter just the number after Age - "Age=123" which I want to filter:
echo "\n" | nc myserver.com 1234 | (awk -F "=" '{print $3}')
Instead of 123 it gives me this output:
123, Ver
Is there a way how to get just number after Age=?
It's just bad awk filtering parameter, but I tried some other ways with awk but this gave me almost best result... Thank you for any help.
Edit: I forgot, number after Age= is dynamic +1 every day...
I'm not sure about the echo "\n" part but I think that this should do what you want:
nc myserver.com 1234 | awk -F "," '{ split($3, a, /=/); print a[2] }'
Instead of splitting into fields on the =, I've done so on the ,. The third field is then split into the array a on the = and the second half is printed.
I also removed the ( ) around the invocation of awk, which was creating a subshell unnecessarily.
If you're confident about the response never varying containing = or , in other places, you could simplify the awk expression further:
awk -F'[=,]' '{ print $5 }'
The bracket expression allows fields to be split on either = or ,, making the part you're interested in the fifth field.
echo "\n" | nc myserver.com 1234 | awk -F "," '{print substr($3,6)}'
You can run the awk command twice.
awk -F "=" '{print $3}'|awk -F "," '{print $1}'
You can also use the cut command:
cut -d "=" -f 3|cut -d "," -f 1
Related
I have a delimited file that is separated by octal \036 or Hexadecimal value 1e.
I need to count the number of delimiters on each line using a bash shell script.
I was trying to use awk, not sure if this is the best way.
Sample Input (| is a representation of \036)
Example|Running|123|
Expected output:
3
awk -F'|' '{print NF-1}' file
Change | to whatever separator you like. If your file can have empty lines then you need to tweak it to:
awk -F'|' '{print (NF ? NF-1 : 0)}' file
You can try
awk '{print gsub(/\|/,"")}'
Simply try
awk -F"|" '{print substr($3,length($3))}' OFS="|" Input_file
Explanation: Making field separator -F as | and then printing the 3rd column by doing $3 only as per your need. Then setting OFS(output field separator) to |. Finally mentioning Input_file name here.
This will work as far as I know
echo "Example|Running|123|" | tr -cd '|' | wc -c
Output
3
This should work for you:
awk -F '\036' '{print NF-1}' file
3
-F '\036' sets input field delimiter as octal value 036
Awk may not be the best tool for this. Gnu grep has a cool -o option that prints each matching pattern on a separate line. You can then count how many matching lines are generated for each input line, and that's the count of your delimiters. E.g. (where ^^ in the file is actually hex 1e)
$ cat -v i
a^^b^^c
d^^e^^f^^g
$ grep -n -o $'\x1e' i | uniq -c
2 1:
3 2:
if you remove the uniq -c you can see how it's working. You'll get "1" printed twice because there are two matching patterns on the first line. Or try it with some regular ascii characters and it becomes clearer what the -o and -n options are doing.
If you want to print the line number followed by the field count for that line, I'd do something like:
$grep -n -o $'\x1e' i | tr -d ':' | uniq -c | awk '{print $2 " " $1}'
1 2
2 3
This assumes that every line in the file contains at least one delimiter. If that's not the case, here's another approach that's probably faster too:
$ tr -d -c $'\x1e\n' < i | awk '{print length}'
2
3
0
0
0
This uses tr to delete (-d) all characters that are not (-c) 1e or \n. It then pipes that stream of data to awk which just counts how many characters are left on each line. If you want the line number, add " | cat -n" to the end.
I'm trying to reverse the order of words excluding first word in final output. For example, I have a word db.in.com.example I'm using this command to reverse the order
$ basename db.in.com.example | awk -F'.' '{ for (i=NF; i>1; i--) \
printf("%s.",$i); print $1; }'
example.com.in.db
I want to exclude last .db in the output. Like this
example.com.in
I'm having trouble with this. Can this be done using only awk ? Can anybody help me on this ?
$ echo db.in.com.example | awk -F. '{ # set . as delimiter
for(i=NF;i>1;i--) # loop from last to next-to-first
printf "%s%s", $i, (i==2?ORS:".") # output item and ORS or . after next-to-first
}'
example.com.in
If perl is okay
$ echo 'db.in.com.example' | perl -F'\.' -lane 'print join ".", reverse(#F[1..$#F])'
example.com.in
$ echo '1.2.3.db.in.com.example' | perl -F'\.' -lane 'print join ".", reverse(#F[2..$#F])'
example.com.in.db.3
-F'\.' set . as input field separator and save to #F array
reverse(#F[1..$#F]) will give reversed array of elements from index 1 to last index
similarly, #F[2..$#F] will exclude first and second element
join "." to add . as separator between elements of array
See http://perldoc.perl.org/perlrun.html#Command-Switches for details on command line options
You can use cut, tac, and parameter expansion:
reverse=$(basename db.in.com.example |
cut -d. -f2- --output-delimiter=$'\n' |
tac )
echo ${reverse//$'\n'/.}
You've got some nice answers here. I am adding one which in my opinion is more readable, of course if ruby is an option for you:
$ echo "db.in.com.example" | ruby -ne 'p ($_.strip.split(".").drop(1).reverse.join("."))'
"example.com.in"
try following too once, which will reverse the text and it allows you to remove any string from output not only db, you need to just change the variable's value and it should fly then.
echo "db.in.com.example" | awk -v var="db" -F"." '{for(i=NF;i>0;i--){val=$i!=var?(val?val FS $i:$i):val};print val;val=""}'
EDIT: Adding a non-one liner form of solution too now.
echo "db.in.com.example" | awk -v var="db" -F"." '{
for(i=NF;i>0;i--){
val=$i!=var?(val?val FS $i:$i):val
}
print val;val=""
}'
I have a line like:
one:two:three:four:five:six seven:eight
and I want to use awk to get $1 to be one and $2 to be two:three:four:five:six seven:eight
I know I can get it by doing sed before. That is to change the first occurrence of : with sed then awk it using the new delimiter.
However replacing the delimiter with a new one would not help me since I can not guarantee that the new delimiter will not already be somewhere in the text.
I want to know if there is an option to get awk to behave this way
So something like:
awk -F: '{print $1,$2}'
will print:
one two:three:four:five:six seven:eight
I will also want to do some manipulations on $1 and $2 so I don't want just to substitute the first occurrence of :.
Without any substitutions
echo "one:two:three:four:five" | awk -F: '{ st = index($0,":");print $1 " " substr($0,st+1)}'
The index command finds the first occurance of the ":" in the whole string, so in this case the variable st would be set to 4. I then use substr function to grab all the rest of the string from starting from position st+1, if no end number supplied it'll go to the end of the string. The output being
one two:three:four:five
If you want to do further processing you could always set the string to a variable for further processing.
rem = substr($0,st+1)
Note this was tested on Solaris AWK but I can't see any reason why this shouldn't work on other flavours.
Some like this?
echo "one:two:three:four:five:six" | awk '{sub(/:/," ")}1'
one two:three:four:five:six
This replaces the first : to space.
You can then later get it into $1, $2
echo "one:two:three:four:five:six" | awk '{sub(/:/," ")}1' | awk '{print $1,$2}'
one two:three:four:five:six
Or in same awk, so even with substitution, you get $1 and $2 the way you like
echo "one:two:three:four:five:six" | awk '{sub(/:/," ");$1=$1;print $1,$2}'
one two:three:four:five:six
EDIT:
Using a different separator you can get first one as filed $1 and rest in $2 like this:
echo "one:two:three:four:five:six seven:eight" | awk -F\| '{sub(/:/,"|");$1=$1;print "$1="$1 "\n$2="$2}'
$1=one
$2=two:three:four:five:six seven:eight
Unique separator
echo "one:two:three:four:five:six seven:eight" | awk -F"#;#." '{sub(/:/,"#;#.");$1=$1;print "$1="$1 "\n$2="$2}'
$1=one
$2=two:three:four:five:six seven:eight
The closest you can get with is with GNU awk's FPAT:
$ awk '{print $1}' FPAT='(^[^:]+)|(:.*)' file
one
$ awk '{print $2}' FPAT='(^[^:]+)|(:.*)' file
:two:three:four:five:six seven:eight
But $2 will include the leading delimiter but you could use substr to fix that:
$ awk '{print substr($2,2)}' FPAT='(^[^:]+)|(:.*)' file
two:three:four:five:six seven:eight
So putting it all together:
$ awk '{print $1, substr($2,2)}' FPAT='(^[^:]+)|(:.*)' file
one two:three:four:five:six seven:eight
Storing the results of the substr back in $2 will allow further processing on $2 without the leading delimiter:
$ awk '{$2=substr($2,2); print $1,$2}' FPAT='(^[^:]+)|(:.*)' file
one two:three:four:five:six seven:eight
A solution that should work with mawk 1.3.3:
awk '{n=index($0,":");s=$0;$1=substr(s,1,n-1);$2=substr(s,n+1);print $1}' FS='\0'
one
awk '{n=index($0,":");s=$0;$1=substr(s,1,n-1);$2=substr(s,n+1);print $2}' FS='\0'
two:three:four five:six:seven
awk '{n=index($0,":");s=$0;$1=substr(s,1,n-1);$2=substr(s,n+1);print $1,$2}' FS='\0'
one two:three:four five:six:seven
Just throwing this on here as a solution I came up with where I wanted to split the first two columns on : but keep the rest of the line intact.
Comments inline.
echo "a:b:c:d::e" | \
awk '{
split($0,f,":"); # split $0 into array of fields `f`
sub(/^([^:]+:){2}/,"",$0); # remove first two "fields" from `$0`
print f[1],f[2],$0 # print first two elements of `f` and edited `$0`
}'
Returns:
a b c:d::e
In my input I didn't have to worry about the first two fields containing escaped :, if that was a requirement, this solution wouldn't work as expected.
Amended to match the original requirements:
echo "a:b:c:d::e" | \
awk '{
split($0,f,":");
sub(/^([^:]+:)/,"",$0);
print f[1],$0
}'
Returns:
a b:c:d::e
I am trying to make a single line ssh call from a ruby script. My script takes a hostname, and then sets out to return the hostname's machine info.
return_value = %x{ ssh #{hostname} "#{number_of_users}; #{number_of_processes};
#{number_of_processes_running}; #{number_of_processes_sleeping}; "}
Where the variables are formatted like this.
number_of_users = %Q(users | wc -w | cat | awk '{print "Number of Users: "\$1}')
number_of_processes = %Q(ps -el | awk '{print $2}' | wc -l | awk '{print "Number of Processes: "$1}')
I have tried both %q, %Q, and just plain "" and I cannot get the awk to print anything before the output. I either get this error (if I include the colon)
awk: line 1: syntax error at or near :
or if I don't include the slash in front of $1 I just get empty output for that line. Is there any solution for this? I thought it might be because I was using %q, but it even happens with just double quotes.
Use backticks to capture the output of the command and return the output as a string:
number_of_users = `users | wc -w | cat | awk '{print "Number of Users:", $1}'`
puts number_of_users
Results on my system:
48
But you can improve your pipeline:
users | awk '{ print "Number of Users:", NF }'
ps -e | awk 'END { print "Number of Processes:", NR }'
So the solution to this problem is:
%q(users | wc -w | awk '{print \"Number of Users: \"\$1}')
Where you have to use %q, not %, not %Q, and not ""
You must backslash double quotes and the dollar sign in front of any awk variables
If somebody could improve upon this answer by explaining why, that would be most appreciated
Though as Steve pointed out I could have improved my code using users | awk '{ print \"Number of Users:\", NF }'
In which case there is no need to backslash the NF.
I am working on the following bash script:
# contents of dbfake file
1 100% file 1
2 99% file name 2
3 100% file name 3
#!/bin/bash
# cat out data
cat dbfake |
# select lines containing 100%
grep 100% |
# print the first and third columns
awk '{print $1, $3}' |
# echo out id and file name and log
xargs -rI % sh -c '{ echo %; echo "%" >> "fake.log"; }'
exit 0
This script works ok, but how do I print everything in column $3 and then all columns after?
You can use cut instead of awk in this case:
cut -f1,3- -d ' '
awk '{ $2 = ""; print }' # remove col 2
If you don't mind a little whitespace:
awk '{ $2="" }1'
But UUOC and grep:
< dbfake awk '/100%/ { $2="" }1' | ...
If you'd like to trim that whitespace:
< dbfake awk '/100%/ { $2=""; sub(FS "+", FS) }1' | ...
For fun, here's another way using GNU sed:
< dbfake sed -r '/100%/s/^(\S+)\s+\S+(.*)/\1\2/' | ...
All you need is:
awk 'sub(/.*100% /,"")' dbfake | tee "fake.log"
Others responded in various ways, but I want to point that using xargs to multiplex output is rather bad idea.
Instead, why don't you:
awk '$2=="100%" { sub("100%[[:space:]]*",""); print; print >>"fake.log"}' dbfake
That's all. You don't need grep, you don't need multiple pipes, and definitely you don't need to fork shell for every line you're outputting.
You could do awk ...; print}' | tee fake.log, but there is not much point in forking tee, if awk can handle it as well.