How do I execute commands with quotation marks in bash? - bash

Question

Basically, I have a file (say.sh) which uses an api to save and play text to speech mp3 files. The api uses the URL: http://api.voicerss.org/?key=keygoeshere&src=TEXT_GOES_HERE&hl=en-gb&c=mp3&r=1&f=32khz_8bit_stereo
The script (bellow) uses wget to get the file. In theory, this code should work, but it doesn't. If I echo the wget command, it returns a working command, that successfully runs, but as soon as I remove the echo, it gets confused by the quotation marks and stops working.
#!/bin/bash
TA="http://api.voicerss.org/?key=MY_KEY_IS_HERE&src="
TB="&hl=en-gb&c=mp3&r=1&f=32khz_8bit_stereo"
wget -O example.mp3 \"$TA$#$TB\"
omxplayer example.mp3
If anybody here knows how to fix this, it would be very helpful. Thanks!
EDIT: To run the command I have tried sh say.sh Text here and sh say.sh "Text here". Neither of which work -_-

Answer 1

i don't know that you need to escape any quotes for the wget command, but i think if variables are appended next to each other, you can try using {}:
#!/bin/bash
TA="http://api.voicerss.org/?key=MY_KEY_IS_HERE&src="
TB="&hl=en-gb&c=mp3&r=1&f=32khz_8bit_stereo"
wget -O example.mp3 "${TA}${TB}"
omxplayer example.mp3
give that a try and let us know how it goes.

Answer 2

Thanks for the responses! I managed to fix this by adding the "${TA}${#}${TB}" and using \" to declare a special character to get:
#!/bin/bash
TA="http://api.voicerss.org/?key=keygoeshere&src=\""
TB="\"&hl=en-gb&c=mp3&r=1&f=32khz_8bit_stereo"
wget -O example.mp3 "${TA}${#}${TB}"
omxplayer example.mp3