I am trying to use parse.com promises to retrieve job data as well as user relation data associated with the job. I have a function that returns promises but not job data. How do I get the job & employee information from the returned promises?
Logically I want to:
1) Query Parse to get array of jobs
2) For each job, query Parse again to get the employee relation information
3) Create local object that contains job & employee details
4) Add each job object to local array
5) Load table with array of objects once all information has been retrieved from Parse
I can do steps 1-4 but I can't figure out how to wait until all information has been retrieved from Parse to refresh the local table.
function getJobPromises (){
var promises = [];
var Job = Parse.Object.extend("Job");
var query = new Parse.Query(Job);
query.equalTo("company", company);
query.notEqualTo("isDeleted", true);
query.limit(1000); // raise limit to max amount
query.find().then(function(results) {
// Create a trivial resolved promise as a base case.
var promise = Parse.Promise.as();
_.each(results, function(result) {
// For each item, extend the promise with a function to add it to the job array
promise = promise.then(function() {
// Return a promise that will be resolved when the job details have been added to the array
var object = result;
promises.push(getEmployeeName(object));
allJobDataArray = promises;
});
});
return Parse.Promise.when(promises);
}).then(function() {
// Every job has been retrieved
console.log("All items have been returned. Refresh table...");
console.log(allJobDataArray);
});
}
The function that does the relational query to get the users associated with the job
function getEmployeeName(jobObject) {
var employeeNameArray = [];
//Query to get array of employees for the passed in job
var rQuery = jobObject.relation("employee");
return rQuery.query().find({
success: function(employees){
//Get employees full name for each job
for (var i = 0; i < employees.length; i++) {
var objEmployee = employees[i];
var fullName = objEmployee.get("fullName");
employeeNameArray.push(fullName);
console.log(employeeNameArray);
}
},
error: function(error){
response.error(error);
}
});
}
Update
It is now working thanks to #eduardo
I have a public array to hold the job objects.
var jobObjectsArray = [];
In the getEmployeeName function I am creating the job objects and adding them to that array
function getJobPromises (){
var promises = [];
var Job = Parse.Object.extend("Job");
var query = new Parse.Query(Job);
query.equalTo("company", company);
query.notEqualTo("isDeleted", true);
query.limit(1000); // raise limit to max amount
query.find().then(function(results) {
_.each(results, function(result) {
promises.push(getEmployeeName(result));
});
return Parse.Promise.when(promises);
}).then(function(allJobDataArray) {
// allJobDataArray should be actually an Array of Array
console.log(jobObjectsArray);
refreshTable();
});
}
function getEmployeeName(jobObject) {
var employeeNameArray = [];
//Query to get array of employees for the passed in job
var rQuery = jobObject.relation("employee");
return new Promise(
function(resolve, reject) {
rQuery.query().find({
success: function(employees){
//Get employees full name for each job
for (var i = 0; i < employees.length; i++) {
var objEmployee = employees[i];
var fullName = objEmployee.get("fullName");
employeeNameArray.push(fullName);
var objAllJobs = new Object();
objAllJobs["jobId"] = jobObject.id;
objAllJobs["location"] = jobObject.get("location");
objAllJobs["startTime"] = jobObject.get("startTime");
objAllJobs["employee"] = employeeNameArray;
jobObjectsArray.push(objAllJobs);
}
console.log(employeeNameArray);
resolve(employeeNameArray);
},
error: function(error){
reject(error);
}
});
}
);
There was a few incorrect uses of the promise concept. I will go through them, but first here is the final code:
function getJobPromises (){
var promises = [];
var Job = Parse.Object.extend("Job");
var query = new Parse.Query(Job);
query.equalTo("company", company);
query.notEqualTo("isDeleted", true);
query.limit(1000); // raise limit to max amount
query.find().then(function(results) {
_.each(results, function(result) {
promises.push(getEmployeeName(result));
});
return Parse.Promise.when(promises);
}).then(function(allJobDataArray) {
// allJobDataArray should be actually an Array of Array
console.dir(allJobDataArray);
console.log(allJobDataArray[0]);
});
}
function getEmployeeName(jobObject) {
var employeeNameArray = [];
//Query to get array of employees for the passed in job
var rQuery = jobObject.relation("employee");
return rQuery.query().find({
success: function(employees){
//Get employees full name for each job
for (var i = 0; i < employees.length; i++) {
var objEmployee = employees[i];
var fullName = objEmployee.get("fullName");
employeeNameArray.push(fullName);
}
console.log(employeeNameArray);
return employeeNameArray;
},
error: function(error){
response.error(error);
}
});
}
"Parse.Promise.as()" should be used only if you have a value that you want to return as a promise. Something like:
Parse.Promise.as("my value").then(function(foo) {
console.log(foo) // "my value"
});
So if your "getEmployeeName" function is returning a promise, which means that this "rQuery.query().find" returns a promise, you don't have to create a new promise or use the "Parse.Promise.as()", it is already a promise and you can push it to the promises array.
Another problem was that you were not return anything in the "getEmployeeName" method callback. Take a look into my version, I'm returning "employeeNameArray".
My version will only work if this "rQuery.query().find" method returns a promise. If that is not the case, you can create a new promise using its callbacks like this:
function getEmployeeName(jobObject) {
var employeeNameArray = [];
//Query to get array of employees for the passed in job
var rQuery = jobObject.relation("employee");
return new Promise(
function(resolve, reject) {
rQuery.query().find({
success: function(employees){
//Get employees full name for each job
for (var i = 0; i < employees.length; i++) {
var objEmployee = employees[i];
var fullName = objEmployee.get("fullName");
employeeNameArray.push(fullName);
}
console.log(employeeNameArray);
resolve(employeeNameArray);
},
error: function(error){
reject(error);
}
});
}
);
}
Please notice this "new Promise()" depends on the browser support of Promise, I don't know if Parse has an equivalent. Anyways you can use it with a polyfill that implements the necessary code if the browser has no support.
More about standard promises: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Promise
Polyfill: https://github.com/jakearchibald/es6-promise/
Hope this helps.
Related
I am trying to import my class (2500 records) from Parse.com into an Algolia index. There is a limit of 100 records by default which obviously is not working for me. Even if I use query.limit = 1000;
How can the below code be used to import my whole class?
Parse.Cloud.define("createIndex", function(request, response) {
var algoliasearch = require('cloud/algoliasearch.parse.js');
var client = algoliasearch('9PsdfsdWVU7', '3b24e897bfb4esdfsdfsdf209e25c28');
var index = client.initIndex('exercises');
console.log("running");
var objectsToIndex = [];
//Create a new query for Contacts
var query = new Parse.Query('Exercises');
query.limit = 1000;
// Find all items
query.find({
success: function(exercises) {
// prepare objects to index from contacts
objectsToIndex = exercises.map(function(exercise) {
// convert to regular key/value JavaScript object
exercise = exercise.toJSON();
// Specify Algolia's objectID with the Parse.Object unique ID
exercise.objectID = exercise.objectId;
return exercise;
});
// Add or update new objects
index.saveObjects(objectsToIndex, function(err, content) {
if (err) {
throw err;
}
console.log('Parse<>Algolia import done');
});
response.success("worked");
},
error: function(err) {
response.error("failed");
throw err;
}
});
});
Parse.com has a find limit, and all other limitations when you want to "get all the objects", you can find more information here: https://parse.com/docs/js/guide#performance-limits-and-other-considerations
For your current issue you could do this:
Parse.Cloud.define("createIndex", function(request, response) {
var algoliasearch = require('cloud/algoliasearch.parse.js');
var client = algoliasearch('9PsdfsdWVU7', '3b24e897bfb4esdfsdfsdf209e25c28');
var index = client.initIndex('exercises');
console.log("running");
//Create a new query for Contacts
var Exercises = Parse.Object.extend('Exercises');
var query = new Parse.Query(Exercises);
var skip = -1000;
var limit = 1000;
saveItems();
function saveItems() {
skip += limit;
query.skip(skip + limit);
query.limit(limit);
query.find({success: sucess, error: error});
}
function sucess(exercices) {
if (exercices.length === 0) {
response.success("finished");
return;
}
exercises = exercises.map(function(exercise) {
// convert to regular key/value JavaScript object
exercise = exercise.toJSON();
// Specify Algolia's objectID with the Parse.Object unique ID
exercise.objectID = exercise.objectId;
return exercise;
});
index.saveObjects(exercises, function(err) {
if (err) {
throw err;
}
console.log('Parse<>Algolia import done');
response.success("worked");
saveItems();
});
}
function error() {
response.error("failed");
throw err;
}
});
I'm in need to fetch over 1000 elements from a Class.
So I tried following advices on this topic, but something is not working correctly, and already spent the whole day to find a solution.
Parse.Cloud.define("getFollow", function(request, response) {
var following = [];
var user = request.params.user;
user.fetch().then(function(result) {
if (!result.get('following')) {
following = getFollowing({
'user': user
});
}
}).then(function() {
response.success(following);
}, function(error) {
response.error(error);
});
});
function getFollowing(request) {
var count = 0;
var skip = request.skip || 0;
var limit = 1000;
var following = request.following || [];
var Follow = Parse.Object.extend('follow');
var query = new Parse.Query(Follow);
query.limit(limit);
query.ascending('objectId');
query.skip(skip * limit);
query.equalTo('followers', request.user);
query.find().then(function(results) {
skip+= 1;
count = results.length;
/* I can't see any DEBUG, seems nothing is queried */
console.log('[DEBUG] Check <count>: ' + count);
return Parse.Promise.when(results.map(function(result) {
following.push(result.get('followed'));
}));
}).then(function() {
if(count >= limit) {
following = getFollowingUsers({
'user': request.user,
'skip': skip,
'following': following
});
}
}).then(function() {
return following;
}, function(error) {
return error;
});
}
I tried many variant of this code, trying to return the very first result of the query, rather than a collection. I also tried to remove all contraints, but even so, my query seems not to be run.
I also tried to use a Cloud.code function to make this recursively using only Parse.Cloud, but if I do that, I'm having a message Too many recursive calls into Cloud Code
What did I do wrong with this logic ?
I'm in difficulty doing this operation correctly.
I have an Order and for every item I have to get the data from the API, what I'm doing is this:
if ($scope.order.order_items.length > 0) {
var itemArray = [];
for (var i = 0; i < $scope.order.order_items.length; i++) {
var itemId = $scope.order.order_items[i].id;
Items.get({
itemId: itemId
}).$promise.then(function (data) {
itemArray.push(data.item);
});
}
$scope.order.order_items = itemArray;
}
The API receive the request and send the data back but the promise do not return anything...
One more error here is from jshint: Don't make functions within a loop.
It will be nice to solve both the issues for me... I tried to create an external function but having the same issue not returning data I don't know if I was doing it well, the external function I was doing is:
function addItem(id) {
Items.get({
itemId: id
}).$promise.then(function (data) {
console.log(data);
return data.item;
});
}
You are making an asynchronous call from the code and thinking that it will work like synchronously. As you are assigning itemArray to $scope.order.order_items outside the factory, at that time itemArray is blank. Before making that assignment you need to ensure that all the ajax call the each item has been completed or not. You could use $q.all for such scenario. $q.all need an promise array & it will call the .then function when all the promise gets resolved.
if ($scope.order.order_items.length > 0) {
var itemArray = [], promiseArray = [];
for (var i = 0; i < $scope.order.order_items.length; i++) {
var itemId = $scope.order.order_items[i].id;
var currentPromise = Items.get({
itemId: itemId
}).$promise.then(function (data) {
itemArray.push(data.item);
return true; //returning dummy value from promise.
});
promiseArray.push(currentPromise); //creating promise array
}
$q.all(promiseArray) //giving promise array input.
.then(function(data){ //success will call when all promises get resolved.
$scope.order.order_items = itemArray;
},function(error){
console.log("Error occured")
});
}
I would avoid reading and writing to the same array and instead use another array for the actual items.
As Resource returns an instance that gets filled on success you should be fine adding the instances to the scope directly. With that you reduce your code a lot and also remove the jshint warning.
if ($scope.order.order_items.length > 0) {
$scope.order.order_items_with_data = [];
for (var i = 0; i < $scope.order.order_items.length; i++) {
var itemId = $scope.order.order_items[i].id;
$scope.order.order_items_with_data.push(Items.get({itemId: itemId}));
}
}
Given the Objects:
_User: (id, name, etc)
Trip: (id, _user, startDate, endDate, notes)
Is it possible to use the Parse Javascript API to find users who don't have any trips? In SQL it would be:
SELECT * FROM _User WHERE id NOT IN (SELECT _User FROM Trips)
Is that possible in Parse without selecting all users and then checking whether each one has trips?
Perhaps the question is better expressed in code:
var Trip = Parse.Object.extend("Trip");
var innerQuery = new Parse.Query(Trip);
var query = new Parse.Query(Parse.User);
query.doesNotMatchQuery("???", innerQuery);
query.find({
success: function(users) {
users.forEach(function(u){
console.log(u.get('name'));
});
}
});
What should go in the ??? User, _User and id return all Users, not those where there are no Trips.
In the end I used promises for this and can find no way to do it 'out of the box'. It's almost certainly best to wrap this up into cloud code.
Here's some sample code:
// Setup outer query
var query = new Parse.Query("Trip");
query.include('nomad');
query.find().then(function(tripsStartingNextWeek) {
var promises = [];
tripsStartingNextWeek.forEach(function(t){
promises.push((function(t){
var promise = new Parse.Promise();
var toNomad = t.get('nomad');
// inner query
var myFutureTrips = new Parse.Query("Trip");
myFutureTrips.notEqualTo('deleted', true);
myFutureTrips.find().then(function(futureTrips) {
// these records match both queries
if (futureTrips.length > 0) {
// do something
} else {
// do something else
}
promise.resolve();
});
return promise;
})(t));
});
return Parse.Promise.when(promises);
})
.then(function() {
status.success("Last trip job finished");
});
I have 2 tables in parse
Memories and Locations with a relation One-To-One, but the pointer is in Location table ( Pointer )
What i need is to read all memories ten by ten with skip and limit and for each memory to atach a property with location object
By now i have this:
var _ = require('underscore.js');
Parse.Cloud.define("feed", function(request, response) {
var memories = Parse.Object.extend("Memories");
var memoriesQuery = new Parse.Query(memories);
memoriesQuery.skip(0);//request.params.skip);
memoriesQuery.limit(10);//request.params.limit);
memoriesQuery.descending("createdAt");
memoriesQuery.include("group");
var parsedResults = [];
memoriesQuery.find().then(function(memories) {
var promise = Parse.Promise.as();
_.each(memories, function(memory) {
promise = promise.then(function() {
var locations = Parse.Object.extend("Locations");
var locationsQuery = new Parse.Query(locations);
locationsQuery.equalTo("memory", memory);
var subPromise = Parse.Promise();
locationsQuery.first().then(function(location) {
memory["location"] = location;
console.log(JSON.stringify(memory) + " ........ " + memory["location"]);
console.log("=============");
parsedResults.push(memory);
subPromise.resolve(memory);
});
return subPromise ;
});
console.log("-----------");
console.log("Promise:" +promise.toString());
});
return promise;
}).then(function(){
response.success(parsedResults);
});
});
I have no clue what to do.. More than 10 hours of tries.
I appreciate any help!
Finally solved!
Maybe it will help somebody.
Solution:
var _ = require('underscore.js');
var memoriesResult = [];
Parse.Cloud.define("feed", function(request, response) {
var promises = [];
var promise = findMemories();
promise.then(function(memories){
console.log("success promise!!");
_.each(memories, function (memory) {
console.log("each");
promises.push(findLocation(memory));
});
return Parse.Promise.when(promises);
}).then(function(){
console.log("Finish");
response.success(memoriesResult);
}, function(error){
console.error("Promise Error: " + error.message);
response.error(error);
});
});
function findMemories(){
console.log("Enter findMemories");
var memories = Parse.Object.extend("Memories");
var memoriesQuery = new Parse.Query(memories);
memoriesQuery.skip(0);//request.params.skip);
memoriesQuery.limit(10);//request.params.limit);
memoriesQuery.descending("createdAt");
memoriesQuery.include("group");
var promise = new Parse.Promise();
memoriesQuery.find().then(function(memories) {
console.log("Memories found!");
promise.resolve(memories);
}, function(error) {
promise.reject(error);
});
return promise;
}
function findLocation(memory) {
console.log("Enter findLocation");
var locations = Parse.Object.extend("Locations");
var locationsQuery = new Parse.Query(locations);
locationsQuery.equalTo("memory", memory);
var promise = new Parse.Promise();
locationsQuery.first().then(function(location) {
console.log("Location found");
memoriesResult.push({"memory": memory, "location" : location});
promise.resolve(memory);
}, function(error) {
promise.reject(error);
});
return promise;
}
After doing some experiments, I've come up with the following requirements and solution:
You want to page through Memories items a page at a time, sorted by their createdAt
You want the Locations related to each memory
You are limited by the fact that the relationship is Locations->Memories
Your first step is to define the query for memories:
var memoryQuery = new Parse.Query('Memories');
memoryQuery.skip(request.params.skip);
memoryQuery.skip(request.params.limit);
memoryQuery.descending('createdAt');
You can now use this query to limit the Locations objects returned. If your links are all setup correctly you will get back 10 records:
var locationQuery = new Parse.Query('Locations');
// limit to only the page of Memory items requested
locationQuery.matchesQuery('memory', memoryQuery);
// include the Memory pointer's data
locationQuery.include('memory');
var memoriesResult = [];
locationQuery.find().then(function(locations) {
var result = _.map(locations, function(location) {
memory: location.get('memory'),
location: location
});
response.success(result);
}, function(error) {
response.error(error);
});
The only issue with the above is that I'm not sure on the order of the returned records, so you might want to re-sort them before returning them. That is extremely simple though with the underscore library.
This will result in 2 queries no matter the page size.