Check if a view exists and do an #include in Laravel Blade - laravel

Question

With Laravel Blade, is there an elegant way to check if a view exists before doing an #include?
For example I'm currently doing this:
#if(View::exists('some-view'))
#include('some-view')
#endif
Which gets quite cumbersome when 'some-view' is a long string with variables inside.
Ideally I'm looking for something like this:
#includeifexists('some-view')
Or to make #include just output an empty string if the view doesn't exist.
As an aside, I would also like to provide a set of views and the first one that exists is used, e.g.:
#includefirstthatexists(['first-view', 'second-view', 'third-view'])
And if none exist an empty string is output.
How would I go about doing this? Would I need to extend BladeCompiler or is there another way?

Answer 1

Had a similar issue. Turns out that from Laravel 5.3 there is an #includeIf blade directive for this purpose.
Simply do #includeIf('some-view')

Answer 2

I created this blade directive for including the first view that exists, and returns nothing if none of the views exist:
Blade::directive('includeFirstIfExists', function ($expression) {
// Strip parentheses
if (Str::startsWith($expression, '(')) {
$expression = substr($expression, 1, -1);
}
// Generate the string of code to render in the blade
$code = "<?php ";
$code .= "foreach ( {$expression} as \$view ) { ";
$code .= "if ( view()->exists(\$view) ) { ";
$code .= "echo view()->make(\$view, \Illuminate\Support\Arr::except(get_defined_vars(), array('__data', '__path')))->render(); ";
$code .= "break; } } ";
$code .= "echo ''; ";
$code .= "?>";
return $code;
});