Good day to everyone.
Could you, please, help me with some of my file preparation problem:
I have a file:
2:1 3:1 4:2 5:1 7:2 34:1 37:3 ...
4:2 6:1 8:1 23:1 25:2 30:1 ...
I would like to get:
20002:1 20003:1 20004:2 20005:1 20007:2 20034:1 20037:3 ...
20004:2 20006:1 20008:1 20023:1 20025:2 20030:1 ...
I tried:
awk '{FS=":"; RS=" "; OFS=":"; ORS=" "}{$1=$1+20000; print $0}'
But it works only partially: it doesnt work with the first line, giving 20002:1:3:1:4:2.., and doesn't work with the first element of each line, giving 4:2 20006:1 20008:1 ...
You can use this (GNU awk only for RT)
awk 'BEGIN{FS=OFS=":";RS="[[:space:]]"}{ORS=RT;$1=$1+20000; print $0}' file
20002:1 20003:1 20004:2 20005:1 20007:2 20034:1 20037:3
20004:2 20006:1 20008:1 20023:1 20025:2 20030:1
Explanation
BEGIN{
#Only run at start of script
FS=OFS=":"
#Set input and output field separator to :
RS="[[:space:]]"
#Set the record separator to any space character e.g `\n` `\t` or ` `
}
{ORS=RT
#Set the output record separator to whatever was captured by the input one, i.e keep newline space or tab in the right places
$1+=20000; print
#Do your math and print, note that `+=` is shorthand for adding to the current value,
#and also that print can be used on it's own as by default it prints $0(you can also use 1
#at the end of the script as this evaluates to true and the default action if no block
#is defined is to print the current line)
}'
In case of not having GNU awk as required by #123's more elegant solution:
$ awk -F"[: ]+" '{for(i=1;i<NF;i+=2){$i+=20000; printf "%s:%s ",$i,$(i+1)} print ""}' cs.txt
20002:1 20003:1 20004:2 20005:1 20007:2 20034:1 20037:3
20004:2 20006:1 20008:1 20023:1 20025:2 20030:1
Related
I have a file 0.txt containing the following value fields contents in parentheses:
(bread,milk,),
(rice,brand B,),
(pan,eggs,Brandc,),
I'm looking in OS and elsewhere for how to prepend the letter x to the beginning of each value between commas so that my output file becomes (using bash unix):
(xbread,xmilk,),
(xrice,xbrand B,),
(xpan,xeggs,xBrand C,),
the only thing I've really tried but not enough is:
awk '{gsub(/,/,",x");print}' 0.txt
for all purposes the prefix should not be applied to the last commas at the end of each line.
With awk
awk 'BEGIN{FS=OFS=","}{$1="(x"substr($1,2);for(i=2;i<=NF-2;i++){$i="x"$i}}1'
Explanation:
# Before you start, set the input and output delimiter
BEGIN{
FS=OFS=","
}
# The first field is special, the x has to be inserted
# after the opening (
$1="(x"substr($1,2)
# Prepend 'x' from field 2 until the previous to last field
for(i=2;i<=NF-2;i++){
$i="x"$i
}
# 1 is always true. awk will print in that case
1
The trick is to anchor the regexp so that it matches the whole comma-terminated substring you want to work with, not just the comma (and avoids other “special” characters in the syntax).
awk '{ gsub(/[^,()]+,/, "x&") } 1' 0.txt
sed -r 's/([^,()]+,)/x\1/g' 0.txt
I am new in bash scripting and I need help with awk. So the thing is that I have a property file with version inside and I want to update it.
version=1.1.1.0
and I use awk to do that
file="version.properties"
awk -F'["]' -v OFS='"' '/version=/{
split($4,a,".");
$4=a[1]"."a[2]"."a[3]"."a[4]+1
}
;1' $file > newFile && mv newFile $file
but I am getting strange result version="1.1.1.0""...1
Could someone help me please with this.
You mentioned in your comment you want to update the file in place. You can do that in a one-liner with perl:
perl -pe '/^version=/ and s/(\d+\.\d+\.\d+\.)(\d+)/$1 . ($2+1)/e' -i version.properties
Explanation
-e is followed by a script to run. With -p and -i, the effect is to run that script on each line, and modify the file in place if the script changes anything.
The script itself, broken down for explanation, is:
/^version=/ and # Do the following on lines starting with `version=`
s/ # Make a replacement on those lines
(\d+\.\d+\.\d+\.)(\d+)/ # Match x.y.z.w, and set $1 = `x.y.z.` and $2 = `w`
$1 . ($2+1)/ # Replace x.y.z.w with a copy of $1, followed by w+1
e # This tells Perl the replacement is Perl code rather
# than a text string.
Example run
$ cat foo.txt
version=1.1.1.2
$ perl -pe '/^version=/ and s/(\d+\.\d+\.\d+\.)(\d+)/$1 . ($2+1)/e' -i foo.txt
$ cat foo.txt
version=1.1.1.3
This is not the best way, but here's one fix.
Test case
I am assuming the input file has at least one line that is exactly version=1.1.1.0.
$ awk -F'["]' -v OFS='"' '/version=/{
> split($4,a,".");
> $4=a[1]"."a[2]"."a[3]"."a[4]+1
> }
> ;1' <<<'version=1.1.1.0'
Output:
version=1.1.1.0"""...1
The """ is because you are assigning to field 4 ($4). When you do that, awk adds field separators (OFS) between fields 1 and 2, 2 and 3, and 3 and 4. Three OFS => """, in your example.
Minimal change
$ awk -F'["]' -v OFS='"' '/version=/{
split($1,a,".");
$1=a[1]"."a[2]"."a[3]"."a[4]+1;
print
}
' <<<'version=1.1.1.0'
version=1.1.1.1
Two changes:
Change $4 to $1
Since the input field separator (-F) is ["], $4 is whatever would be after the third " (if there were any in the input). Therefore, split($4, ...) splits an empty field. The contents of the line, before the first " (if any), are in $1.
print at the end instead of ;1
The 1 after the closing curly brace is the next condition, and there is no action specified. The default action is to print the current line, as modified, so the 1 triggers printing. Instead, just print within your action when you are done processing. That way your action is self-contained. (Of course, if you needed to do other processing, you might want to print later, after that processing.)
You can use the = as the delimiter, like this:
awk -F= -v v=1.0.1 '$1=="version"{printf "version=\"%s\"\n", v}' file.properties
I have a huge file (this is just a sample) and I would like to select all lines with "Ph_gUFAC1083" and all after until reach one that doesn't have the code (in this example Ph_gUFAC1139)
>uce_353_Ph_gUFAC1083 |uce_353
TTTAGCCATAGAAATGCAGAAATAATTAGAAGTGCCATTGTGTACAGTGCCTTCTGGACT
GGGCTGAAGGTGAAGGAGAAAGTATCATACTATCCTTGTCAGCTGCAAGGGTAATTACTG
CTGGCTGAAATTACTCAACATTTGTTTATAAGCTCCCCAGAGCATGCTGTAAATAGATTG
TCTGTTATAGTCCAATCACATTAAAACGCTGCTCCTTGCAAACTGCTACCTCCTGTTTTC
TGTAAGCTAGACAGAGAAAGCCTGCTGCTCACTTACTGAGCACCAAGCACTGAAGAGCTA
TGTTTAATGTGATTGTTTTCATTAGCTCTTCTCTGTCTGATATTACATTTATAATTTGCT
GGGCTTGAAGACTGGCATGTTGCATTGCTTTCATTTACTGTAGTAAGAGTGAATAGCTCT
AT
>uce_101_Ph_gUFAC1083 |uce_101
TTGGGCTTTATTTCCACCTTAAAATCTTTACCTGGCCGTGATCTGTTGTTCCATTACTGG
AGGGCAAAAATGGGAGGAATTGTCTGGGCTAAATTGCAATTAGGCAGCCCTGAGAGAGGC
TGGCACCAGTTAACTTGGGATATTGGAGTGAAAAGGCCCGTAATCAGCCTTCGGTCATGT
AGAACAATGCATAAAATTAAATTGACATTAATGAATAATTGTGTAATGAAAATGGAAGAG
GAGAGTTAATTGCATGTTACAGTGAGTGTAATGCCTAGATAACCTTGCATTTAATGCTAT
TCTTAGCCCTGCTGCCAAGACTTCTACAGAGCCTCTCTCTGCAGGAAGTCATTAAAGCTG
TGAGTAGATAATGCAGGCTCAGTGAAACCTAAGTGGCAACAATATA
>uce_171_Ph_gUFAC1083 |uce_171
CATGGAAAACGAGGAAAAGCCATATCTTCCAGGCCATTAATATTACTACGGAGACGTCTT
CATATCGCCGTAATTACAGCAGATCTCAAAGTGGCACAACCAAGACCAGCACCAAAGCTA
AAATAACTCGCAGGAGCAGGCGAGCTGCTTTTGCAGCCCTCAGTCCCAGAAATGCTCGGT
AGCTTTTCTTAAAATAGACAGCCTGTAAATAAGGTCTGTGAACTCAATTGAAGGTGGCTG
TTTCTGAATTAGTCAGCCCTCACAAGGCTCTCGGCCTACATGCTAGTACATAAATTGTCC
ACTTTACCACCAGACAAGAAAGATTAGAGTAATAAACACGGGGCATTAGCTCAGCTAGAG
AAACACACCAGCCGTTACGCACACGCGGGATTGCCAAGAACTGTTAACCCCACTCTCCAG
AAACGCACACAAAAAAACAAGTTAAAGCCATGACATCATGGGAA
>uce_4300_Ph_gUFAC1139 |uce_4300
ATTAAAAATACAATCCTCATGTTTGCATTTTGCAGTCGTCAACAAGAAATTGAAGAGAAA
CTCATAGAGGAAGAAACTGCTCGAAGGGTGGAAGAACTTGTAGCTAAACGCGTGGAAGAA
GAGCTGGAGAAAAGAAAGGATGAGATTGAGCGAGAGGTTCTCCGCAGGGTGGAGGAGGCT
AAGCGCATCATGGAAAAACAGTTGCTCGAAGAACTCGAGCGACAGCGACAAGCTGAACTT
GCAGCACAAAAAGCCAGAGAGGTAACGCTCGGTCGTTTGGAAAGTAGAGACAGTCCATGG
CAAAACTTTCAGTGTCGGTTTGTGCCTCCTGTTCGGTTCAGAAAGAGATGGAATACAGCA
AATCTAATTCCCTTCTCATATAAACTTGCATTGCTGCGAAACTTAATTTCTAGCCTATTC
AGAGGAGCTCACTGATATTTAAACAGTTACTCTCCTAAAACCTGAACAAGGATACTTGAT
TCTTAATGGAACTGACCTACATATTTCAGAATTGTTTGAAACTTTTGCCATGGCTGCAGG
ATTATTCAGCAGTCCTTTCATTTT
>uce_1039_Ph_gUFAC1139 |uce_1039
ATTAGTGGAATACAAATATGCAAAAACCAAACAGTTTGGTGCTATAATGTGAAAAGAAAT
TTACACCAATCTTATTTTTAATTTGTATGGGAACATTTTTACCACAAATTCCATATTTTA
ATAATACTATCCCAACTCTATTTTTTAGACTCATTTTGTCACTGTTTTGTAACAGAAACA
CTGTAAATATTATAGATGTGGTAAACTATTATACTTGTTTTCTTATAAATGAAATGATCT
GTGCCAACACTGACAAAATGAATTAATGTGTTACTAAGGCAACAGTCACATTATATGCTT
TCTCTTTCACAGTATGCGGTAGAGCATATGGTTTACTCTTAATGGAACACTAGCTTCTCA
TTAACATACCAGTAGCAATGTCAGAACTTACAAACCAGCATAACAGAGAAATGGAAAAAC
TTATAAATTAGACCCTTTCAGTATTATTGAGTAGAAAATGACTGATGTTCCAAGGTACAA
TATTTAGCTAATACAGTGCCCTTTTCTGCATCTTTCTTCTCAAAGGAAAAAAAAATCCTC
AAAAAAAACCAGAGCAAGAAACCTAACTTTTTCTTGT
I already tried several alternatives without success, the closest I reached was
sed -n '/Ph_gUFAC1083/, />/p' file.txt
that gave me that:
>uce_2347_Ph_gUFAC1083 |uce_2347
GCTTTTCTATGCAGATTTTTTCTAATTCTCTCCCTCCCCTTGCTTCTGTCAGTGTGAAGC
CCACACTAAGCATTAACAGTATTAAAAAGAGTGTTATCTATTAGTTCAATTAGACATCAG
ACATTTACTTTCCAATGTATTTGAAGACTGATTTGATTTGGGTCCAATCATTTAAAAATA
AGAGAGCAGAACTGTGTACAGAGCTGTGTACAGATATCTGTAGCTCTGAAGTCTTAATTG
CAAATTCAGATAAGGATTAGAAGGGGCTGTATCTCTGTAGACCAAAGGTATTTGCTAATA
CCTGAGATATAAAAGTGGTTAAATTCAATATTTACTAATTTAGGATTTCCACTTTGGATT
TTGATTAAGCTTTTTGGTTGAAAACCCCACATTATTAAGCTGTGATGAGGGAAAAAGCAA
CTCTTTCATAAGCCTCACTTTAACGCTTTATTTCAAATAATTTATTTTGGACCTTCTAAA
G
>uce_353_Ph_gUFAC1083 |uce_353
>uce_101_Ph_gUFAC1083 |uce_101
TTGGGCTTTATTTCCACCTTAAAATCTTTACCTGGCCGTGATCTGTTGTTCCATTACTGG
AGGGCAAAAATGGGAGGAATTGTCTGGGCTAAATTGCAATTAGGCAGCCCTGAGAGAGGC
TGGCACCAGTTAACTTGGGATATTGGAGTGAAAAGGCCCGTAATCAGCCTTCGGTCATGT
AGAACAATGCATAAAATTAAATTGACATTAATGAATAATTGTGTAATGAAAATGGAAGAG
GAGAGTTAATTGCATGTTACAGTGAGTGTAATGCCTAGATAACCTTGCATTTAATGCTAT
TCTTAGCCCTGCTGCCAAGACTTCTACAGAGCCTCTCTCTGCAGGAAGTCATTAAAGCTG
TGAGTAGATAATGCAGGCTCAGTGAAACCTAAGTGGCAACAATATA
>uce_171_Ph_gUFAC1083 |uce_171
Do you know how to do it using grep, sed or awk?
Thx
$ awk '/^>/{if(match($0,"Ph_gUFAC1083")){s=1} else s=0}s' file
I made a simple criteria for your request,
If the the start of the line is >, we're going to judge if "Ph_gUFAC1083" existed, if yes, set s=1, set s=0 otherwise.
For the line that doesn't start with >, the value of s would be retained.
The final s in the awk command decide if the line to be printed (s=1) or not (s=0).
If what you want is every line with Ph_gUFAC1139 plus block of lines after that line until the next line starting with >, then the following awk snippet might do:
$ awk 'BEGIN {RS=ORS=">"} /Ph_gUFAC1139/' file.txt
This uses the > character as a record separator, then simply displays records that contain the text you're interested in.
If you wanted to be able to provide the search string using a variable, you'd do it something like this:
$ val="Ph_gUFAC1139"
$ awk -v s="$val" 'BEGIN {RS=ORS=">"} $0 ~ s' file.txt
UPDATE
A comment mentions that the solution above shows trailing record separators rather than leading ones. You can adapt your output to match your input by reversing this order manually:
awk 'BEGIN { RS=ORS=">" } /Ph_gUFAC1139/ { printf "%s%s",ORS,$0 }' file.txt
Note that in the initial examples, a "match" of the regex would invoke awk's default "action", which is to print the line. The default action is invoked if no action is specified within the script. The code (immediately) above includes an action .. which prints the record, preceded by the separator.
This might work for you (GNU sed):
sed '/^>/h;G;/Ph_gUFAC1083/P;d' file
Store each line beginning with > in the hold space (HS) and then append the HS to every line. If any line contains the string Ph_gUFAC1083 print the first line in the pattern space (PS) and discard the everything else.
N.B. the regexp for the match may be amended to /\n.*Ph_gUFAC1083/ if the string match may occur in any line.
This program is used to find the block which starts with Ph_gUFAC1083 and ends with any statement other than Ph_gUFAC1139
cat inp.txt |
awk '
BEGIN{begin=0}
{
# Ignore blank lines
if( $0 ~ /^$/ )
{
print $0
next
}
# mark the line that contains Ph_gUFAC1083 and print it
if( $0 ~ /Ph_gUFAC1083/ )
{
begin=1
print $0
}
else
{
# if the line contains Ph_gUFAC1083 and Ph_gUFAC1139 was found before it, print it
if( begin == 1 && ( $0 ~ /Ph_gUFAC1139/ ) )
{
print $0
}
else
{
# found a line which doesnt contain Ph_gUFAC1139 , mark the end of the block.
begin = 0
}
}
}'
I just started learning about awk programming and am still getting used to it in the bash terminal. If i were to write an expression to match strings that start with de and end with ed, i was wondering how does it go about?
Was thinking of something like:
echo -e "deed\ndeath\ndone\ndeindustrialized" |awk '/^de.ed$/'
where i match the start and match the end in the awk command but it doesn't print out anything. I'll appreciate some help.
It should produce:
deed
deindustrialized
I just started today and would like to know.
The awk part should be:
... | awk '/^de.*ed$/'
deed
deindustrialized
. matches any character and * means that the preceding item will be matched zero or more times.
try with awk:
echo -e "deed\ndeath\ndone\ndeindustrialized" | awk 'NR==1;END{print}'
Following is the explanation too on same.
awk '
NR==1; ###Checking the NR(Number of line) value is 1, if yes then print the current line(awk works on method of pattern/action, if a condition is TRUE then do actions, in case of NO action do default action which is print of current line).
END{print}' ###In END section now, so it will print the last line of Input_file.
I am having this example of ini file. I need to extract the names between 2 patterns Name_Z1 and OBJ=Name_Z1 and put them each on a line.
The problem is that there are more than one occurences with Name_Z1 and OBJ=Name_Z1 and i only need first occurence.
[Name_Z5]
random;text
Names;Jesus;Tom;Miguel
random;text
OBJ=Name_Z5
[Name_Z1]
random;text
Names;Jhon;Alex;Smith
random;text
OBJ=Name_Z1
[Name_Z2]
random;text
Names;Chris;Mara;Iordana
random;text
OBJ=Name_Z2
[Name_Z1_Phone]
random;text
Names;Bill;Stan;Mike
random;text
OBJ=Name_Z1_Phone
My desired output would be:
Jhon
Alex
Smith
I am currently writing a more ample script in bash and i am stuck on this. I prefer awk to do the job.
My greatly appreciation for who can help me. Thank you!
For Wintermute solution: The [Name_Z1] part looks like this:
[CAB_Z1]
READ_ONLY=false
FilterAttr=CeaseTime;blank|ObjectOfReference;contains;511047;512044;513008;593026;598326;CL5518;CL5521;CL5538;CL5612;CL5620|PerceivedSeverity;=;Critical;Major;Minor|ProbableCause;!=;HOUSE ALARM;IO DEVICE|ProblemText;contains;AIRE;ALIMENTA;BATER;CONVERTIDOR;DISTRIBUCION;FUEGO;HURTO;MAINS;MALLO;MAYOR;MENOR;PANEL;TEMP
NAME=CAB_Z1
And the [Name_Z1_Phone] part looks like this:
[CAB_Z1_FUEGO]
READ_ONLY=false
FilterAttr=CeaseTime;blank|ObjectOfReference;contains;511047;512044;513008;593026;598326;CL5518;CL5521;CL5538;CL5612;CL5620|PerceivedSeverity;=;Critical;Major;Minor|ProbableCause;!=;HOUSE ALARM;IO DEVICE|ProblemText;contains;FUEGO
NAME=CAB_Z1_FUEGO
The fix should be somewhere around the "|PerceivedSeverity"
Expected Output:
511047
512044
513008
593026
598326
CL5518
CL5521
CL5538
CL5612
CL5620
This should work:
sed -n '/^\[Name_Z1/,/^OBJ=Name_Z1/ { /^Names/ { s/^Names;//; s/;/\n/g; p; q } }' foo.txt
Explanation: Written readably, the code is
/^\[Name_Z1/,/^OBJ=Name_Z1/ {
/^Names/ {
s/^Names;//
s/;/\n/g
p
q
}
}
This means: In the pattern range /^\[Name_Z1/,/^OBJ=Name_Z1/, for all lines that match the pattern /^Names/, remove the Names; in the beginning, then replace all remaining ; with newlines, print the whole thing, and then quit. Since it immediately quits, it will only handle the first such line in the first such pattern range.
EDIT: The update made things a bit more complicated. I suggest
sed -n '/^\[CAB_Z1/,/^NAME=CAB_Z1/ { /^FilterAttr=/ { s/^.*contains;\(.*\)|PerceivedSeverity.*$/\1/; s/;/\n/g; p; q } }' foo.txt
The main difference is that instead of removing ^Names from a line, the substitution
s/^.*contains;\(.*\)|PerceivedSeverity.*$/\1/;
is applied. This isolates the part between contains; and |PerceivedSeverity before continuing as before. It assumes that there is only one such part in the line. If the match is ambiguous, it will pick the one that appears last in the line.
An (g)awk way that doesn't need a set number of fields(although i have assumed that contains; will always be on the line you need the names from.
(g)awk '(x+=/Z1/)&&match($0,/contains;([^|]+)/,a)&&gsub(";","\n",a[1]){print a[1];exit}' f
Explanation
(x+=/Z1/) - Increments x when Z1 is found. Also part of a
condition so x must exist to continue.
match($0,/contains;([^|]+)/,a) - Matches contains; and then captures everything after
up to the |. Stores the capture in a. Again a
condition so must succeed to continue.
gsub(";","\n",a[1]) - Substitutes all the ; for newlines in the capture
group a[1].
{print a[1];exit}' - If all conditions are met then print a[1] and exit.
This way should work in (m)awk
awk '(x+=/Z1/)&&/contains/{split($0,a,"|");y=split(a[2],b,";");for(i=3;i<=y;i++)
print b[i];exit}' file
sed -n '/\[Name_Z1\]/,/OBJ=Name_Z1$/ s/Names;//p' file.txt | tr ';' '\n'
That is sed -n to avoid printing anything not explicitly requested. Start from Name_Z1 and finish at OBJ=Name_Z1. Remove Names; and print the rest of the line where it occurs. Finally, replace semicolons with newlines.
Awk solution would be
$ awk -F";" '/Name_Z1/{f=1} f && /Names/{print $2,$3,$4} /OBJ=Name_Z1/{exit}' OFS="\n" input
Jhon
Alex
Smith
OR
$ awk -F";" '/Name_Z1/{f++} f==1 && /Names/{print $2,$3,$4}' OFS="\n" input
Jhon
Alex
Smith
-F";" sets the field seperator as ;
/Name_Z1/{f++} matches the line with pattern /Name_Z1/ If matched increment {f++}
f==1 && /Names/{print $2,$3,$4} is same as if f == 1 and maches pattern Name with line if true, then print the the columns 2 3 and 4 (delimted by ;)
OFS="\n" sets the output filed seperator as \n new line
EDIT
$ awk -F"[;|]" '/Z1/{f++} f==1 && NF>1{for (i=5; i<15; i++)print $i}' input
511047
512044
513008
593026
598326
CL5518
CL5521
CL5538
CL5612
CL5620
Here is a more generic solution for data in group of blocks.
This awk does not need the end tag, just the start.
awk -vRS= -F"\n" '/^\[Name_Z1\]/ {n=split($3,a,";");for (i=2;i<=n;i++) print a[i];exit}' file
Jhon
Alex
Smith
How it works:
awk -vRS= -F"\n" ' # By setting RS to nothing, one record equals one block. Then FS is set to one line as a field
/^\[Name_Z1\]/ { # Search for block with [Name_Z1]
n=split($3,a,";") # Split field 3, the names and store number of fields in variable n
for (i=2;i<=n;i++) # Loop from second to last field
print a[i] # Print the fields
exit # Exits after first find
' file
With updated data
cat file
data
[CAB_Z1_FUEGO]
READ_ONLY=false
FilterAttr=CeaseTime;blank|ObjectOfReference;contains;511047;512044;513008;593026;598326;CL5518;CL5521;CL5538;CL5612;CL5620|PerceivedSeverity;=;Critical;Major;Minor|ProbableCause;!=;HOUSE ALARM;IO DEVICE|ProblemText;contains;FUEGO
NAME=CAB_Z1_FUEGO
data
awk -vRS= -F"\n" '/^\[CAB_Z1_FUEGO\]/ {split($3,a,"|");n=split(a[2],b,";");for (i=3;i<=n;i++) print b[i]}' file
511047
512044
513008
593026
598326
CL5518
CL5521
CL5538
CL5612
CL5620
The following awk script will do what you want:
awk 's==1&&/^Names/{gsub("Names;","",$0);gsub(";","\n",$0);print}/^\[Name_Z1\]$/||/^OBJ=Name_Z1$/{s++}' inputFileName
In more detail:
s==1 && /^Names;/ {
gsub ("Names;","",$0);
gsub(";","\n",$0);
print
}
/^\[Name_Z1\]$/ || /^OBJ=Name_Z1$/ {
s++
}
The state s starts with a value of zero and is incremented whenever you find one of the two lines:
[Name_Z1]
OBJ=Name_Z1
That means, between the first set of those lines, s will be equal to one. That's where the other condition comes in. When s is one and you find a line starting with Names;, you do two substitutions.
The first is to get rid of the Names; at the front, the second is to replace all ; semi-colon characters with a newline. Then you print it out.
The output for your given test data is, as expected:
Jhon
Alex
Smith