I have a question about the following makefile. I use GNU Make v4.1.
define code
foo:=hello
bar:=${foo}
endef
$(eval ${code})
default:
#${foo}
#${bar}
${foo} echoes hello, but ${bar} echoes nothing. Why is this happening?
I expected ${bar} to echo hello too, because I think this is equivalent to the following makefile:
foo:=hello
bar:=${foo}
default:
#${foo}
#${bar}
I'm original poster.I found another function 'value' which return value without expansion.
define code
foo:=hello
bar:=${foo}
endef
$(eval $(value code))
default:
#${foo}
#${bar}
This also works too.
Add $(info ${code}) to see what's going on.
${foo} was expanded when the definition of code was build, so code contains
foo:=hello
bar:=${foo}
If you want ${foo} to be expanded when you run $(eval ${code}), which is what makes eval useful, then you need to make the value of code contain a dollar sign.
define code
foo:=hello
bar:=$${foo}
endef
In this case, you could achieve the same result by making bar a late-expansion definiton:
bar=${foo}
foo:=hello
default:
#${foo}
#${bar}
eval is useful in more complex cases, especially when string being eval'ed is built dynamically.
Related
Make can't define multiple target-specific variables.
But there is a macros from this answer that can solve the problem.
assign-vars = $(foreach A,$2,$(eval $1: $A))
But probably it can't set variable that depends on another variable. For example:
assign-vars = $(foreach A,$2,$(eval $1: $A))
multiple_variable = a=10 \
b=$(shell echo $$(( $(a)-1 )) )
$(call assign-vars, print, $(multiple_variable))
print:
#echo a=$(a)
#echo b=$(b)
I expected to see b=9 as a result from print target but I get b=-1.
How can I fix it?
The problem is that the entire contents of multiple_variable is expanded first, before the for-loop runs. So, it's not possible to refer to earlier variables in the assignment of later variables: they won't be set yet.
When you run:
$(call assign-vars, print, $(multiple_variable))
the first thing make does, is expand the variable multiple_variable: That expands to this:
a=10 b=-1
because when make goes to invoke the shell, the make variable a has not been set yet and so it runs echo $(( -1 )).
I don't really know of a good way to do what you appear to want to do... although I'm not sure I understand what you want to do anyway. It seems like you should take a step back and reconsider your requirements.
If you rewrite it to:
define newline
endef
assign-vars = $(eval $1: $(subst $(newline),$(newline)$1 :,$2))
define print_vars :=
a=10
b=$(shell echo $$(( $(a)-1 )) )
endef
that should do the trick.
EDIT: I only see now, that you are trying to calculate a target specific variable from anothen one. I don't think that will work, as I doubt that there is a specified order in which target specific variables are assigned. So a may or may not be defined when b receives its value.
I'm writing a macro that creates an empty target file name from a given name. And also redirects the named target to that empty target name.
After running this function I'm expecting my Makefile to look like this:
a:./build/._a
./build/._a:
#echo building $#
However I constantly get this:
$ make a
a:./build/._a
Makefile:7: *** missing separator. Stop.
Here's my Makefile:
define empty_target
$(eval $2:=./build/._$1)
$(info $1:$($2))
$(eval $1:$($2))
endef
$(call empty_target,a,_A)
$(_A):
#echo building $#
This will do it:
define empty_target
$(eval $2:=./build/._$1)
$1:$($2)
endef
$(eval $(call empty_target,a,_A))
$(info _A=$(_A))
$(_A):
#echo building $#
And yes, there's a nested eval, which you need if you want the variable assignment to take effect inside of the eval call (otherwise $2 is expanded before it is set, and expands to blank).
As to your original code, I agree, it's somewhat confusing why it raises that error. I can reproduce, and if I add the line blah:blah2 in the middle of empty_target, it seems to get rid of the message. I'm guessing it is a bug in how make colapses whitespace/newlines between the $(eval) calls.
I want to set a variable if it is empty. I tried in this way:
....
TEST := $(something)
...
TEST ?= $(something else)
The first $(something) may return an empty string, however the conditional assignment ?= works only if the previous variable is not set, not if empty.
Any elegant solution to set the variable if empty?
EDIT
I found this solution:
....
TEST := $(something)
...
TEST += $(something else)
TEST := $(word 1, $(TEST))
but I think that there will be one more elegant.
Any elegant solution to set the variable if empty?
GNU make is hardly known for elegant solutions. Unless you find trapdoors and minefields to be elegant. I know only of the two ways to accomplish what you want:
The standard ifeq/endif solution:
ifeq ($(TEST),)
TEST := $(something else)
endif
Use the $(if) function:
TEST := $(if $(TEST),$(TEST),$(something else))
One can try to package that construct into a function too, but that is inadvisable. The function would have the hidden pitfall of occasionally breaking the $(something else) if it contains the , (for which there are only wayward workarounds). (The built-in functions like $(if) are immune to the , bug.)
Elegance test is up to you.
Here's another alternative that I personally find quite elegant, because it's a one-liner and doesn't need the redundant else-branch:
TEST := $(or $(TEST),$(something else))
From GNU make, chapter 7.2, Syntax of Conditionals:
"Often you want to test if a variable has a non-empty value. When the value results from complex expansions of variables and functions, expansions you would consider empty may actually contain whitespace characters and thus are not seen as empty. However, you can use the strip function to avoid interpreting whitespace as a non-empty value. For example:
ifeq ($(strip $(foo)),)
text-if-empty
endif
will evaluate text-if-empty even if the expansion of $(foo) contains whitespace characters."
Folks, I think there's a simpler solution
KDIR ?= "foo"
From: What is ?= in Makefile
Just in case anyone stumbled upon putting the condition in the rule itself. below how I did it, thought it might help others.
In Makefile, suppose we have the following rule with check target and we need to check whether var was passed.
check:
#[ "${var}" ] && echo "all good" || ( echo "var is not set"; exit 1 )
To test this out, run the following commands
$ make check
var is not set
make: *** [check] Error 1
$ make check var=test
all good
So, Now we can pass the variable value or a default value in case it was not passed to a bash script that will be responsible to do the logic. something like the following:
#[ "${var}" ] && ./b.sh ${var} || ./b.sh 'ss'
Here's below what b.sh might look like, though you can add more logic to it.
#!/bin/sh
echo $1
In case you need to distinguish if a variable is undefined or just has an empty value, use $(origin VARNAME) function:
ifeq ($(origin VARNAME),undefined)
VARNAME := "now it's finally defined"
endif
Note that VARNAME is not surrounded by $() - you literally give the name of the variable.
Setting value to variable in Makefile if value defined
ifdef RELEASE_BRANCH
GIT_TAG=$(shell cat projects/${RELEASE_BRANCH}/GIT_TAG)
else
GIT_TAG=$(shell cat release/DEFAULT_GIT_TAG)
endif
In my makefile, I have a variable 'NDK_PROJECT_PATH', my question is how can I print it out when it compiles?
I read Make file echo displaying "$PATH" string and I tried:
#echo $(NDK_PROJECT_PATH)
#echo $(value NDK_PROJECT_PATH)
Both gives me
"build-local.mk:102: *** missing separator. Stop."
Any one knows why it is not working for me?
You can print out variables as the makefile is read (assuming GNU make as you have tagged this question appropriately) using this method (with a variable named "var"):
$(info $$var is [${var}])
You can add this construct to any recipe to see what make will pass to the shell:
.PHONY: all
all: ; $(info $$var is [${var}])echo Hello world
Now, what happens here is that make stores the entire recipe ($(info $$var is [${var}])echo Hello world) as a single recursively expanded variable. When make decides to run the recipe (for instance when you tell it to build all), it expands the variable, and then passes each resulting line separately to the shell.
So, in painful detail:
It expands $(info $$var is [${var}])echo Hello world
To do this it first expands $(info $$var is [${var}])
$$ becomes literal $
${var} becomes :-) (say)
The side effect is that $var is [:-)] appears on standard out
The expansion of the $(info...) though is empty
Make is left with echo Hello world
Make prints echo Hello world on stdout first to let you know what it's going to ask the shell to do
The shell prints Hello world on stdout.
As per the GNU Make manual and also pointed by 'bobbogo' in the below answer,
you can use info / warning / error to display text.
$(error text…)
$(warning text…)
$(info text…)
To print variables,
$(error VAR is $(VAR))
$(warning VAR is $(VAR))
$(info VAR is $(VAR))
'error' would stop the make execution, after showing the error string
from a "Mr. Make post"
https://www.cmcrossroads.com/article/printing-value-makefile-variable
Add the following rule to your Makefile:
print-% : ; #echo $* = $($*)
Then, if you want to find out the value of a makefile variable, just:
make print-VARIABLE
and it will return:
VARIABLE = the_value_of_the_variable
If you simply want some output, you want to use $(info) by itself. You can do that anywhere in a Makefile, and it will show when that line is evaluated:
$(info VAR="$(VAR)")
Will output VAR="<value of VAR>" whenever make processes that line. This behavior is very position dependent, so you must make sure that the $(info) expansion happens AFTER everything that could modify $(VAR) has already happened!
A more generic option is to create a special rule for printing the value of a variable. Generally speaking, rules are executed after variables are assigned, so this will show you the value that is actually being used. (Though, it is possible for a rule to change a variable.) Good formatting will help clarify what a variable is set to, and the $(flavor) function will tell you what kind of a variable something is. So in this rule:
print-% : ; $(info $* is a $(flavor $*) variable set to [$($*)]) #true
$* expands to the stem that the % pattern matched in the rule.
$($*) expands to the value of the variable whose name is given by by $*.
The [ and ] clearly delineate the variable expansion.
You could also use " and " or similar.
$(flavor $*) tells you what kind of variable it is. NOTE: $(flavor)
takes a variable name, and not its expansion.
So if you say make print-LDFLAGS, you get $(flavor LDFLAGS),
which is what you want.
$(info text) provides output.
Make prints text on its stdout as a side-effect of the expansion.
The expansion of $(info) though is empty.
You can think of it like #echo,
but importantly it doesn't use the shell,
so you don't have to worry about shell quoting rules.
#true is there just to provide a command for the rule.
Without that,
make will also output print-blah is up to date. I feel #true makes it more clear that it's meant to be a no-op.
Running it, you get
$ make print-LDFLAGS
LDFLAGS is a recursive variable set to [-L/Users/...]
All versions of make require that command lines be indented with a TAB (not space) as the first character in the line. If you showed us the entire rule instead of just the two lines in question we could give a clearer answer, but it should be something like:
myTarget: myDependencies
#echo hi
where the first character in the second line must be TAB.
#echo $(NDK_PROJECT_PATH) is the good way to do it.
I don't think the error comes from there.
Generally this error appears when you mistyped the intendation : I think you have spaces where you should have a tab.
No need to modify the Makefile.
$ cat printvars.mak
print-%:
#echo '$*=$($*)'
$ cd /to/Makefile/dir
$ make -f ~/printvars.mak -f Makefile print-VARIABLE
Run make -n; it shows you the value of the variable..
Makefile...
all:
#echo $(NDK_PROJECT_PATH)
Command:
export NDK_PROJECT_PATH=/opt/ndk/project
make -n
Output:
echo /opt/ndk/project
This makefile will generate the 'missing separator' error message:
all
#echo NDK_PROJECT_PATH=$(NDK_PROJECT_PATH)
done:
#echo "All done"
There's a tab before the #echo "All done" (though the done: rule and action are largely superfluous), but not before the #echo PATH=$(PATH).
The trouble is that the line starting all should either have a colon : or an equals = to indicate that it is a target line or a macro line, and it has neither, so the separator is missing.
The action that echoes the value of a variable must be associated with a target, possibly a dummy or PHONEY target. And that target line must have a colon on it. If you add a : after all in the example makefile and replace the leading blanks on the next line by a tab, it will work sanely.
You probably have an analogous problem near line 102 in the original makefile. If you showed 5 non-blank, non-comment lines before the echo operations that are failing, it would probably be possible to finish the diagnosis. However, since the question was asked in May 2013, it is unlikely that the broken makefile is still available now (August 2014), so this answer can't be validated formally. It can only be used to illustrate a plausible way in which the problem occurred.
The problem is that echo works only under an execution block. i.e. anything after "xx:"
So anything above the first execution block is just initialization so no execution command can used.
So create a execution blocl
If you don't want to modify the Makefile itself, you can use --eval to add a new target, and then execute the new target, e.g.
make --eval='print-tests:
#echo TESTS $(TESTS)
' print-tests
You can insert the required TAB character in the command line using CTRL-V, TAB
example Makefile from above:
all: do-something
TESTS=
TESTS+='a'
TESTS+='b'
TESTS+='c'
do-something:
#echo "doing something"
#echo "running tests $(TESTS)"
#exit 1
This can be done in a generic way and can be very useful when debugging a complex makefile. Following the same technique as described in another answer, you can insert the following into any makefile:
# if the first command line argument is "print"
ifeq ($(firstword $(MAKECMDGOALS)),print)
# take the rest of the arguments as variable names
VAR_NAMES := $(wordlist 2,$(words $(MAKECMDGOALS)),$(MAKECMDGOALS))
# turn them into do-nothing targets
$(eval $(VAR_NAMES):;#:))
# then print them
.PHONY: print
print:
#$(foreach var,$(VAR_NAMES),\
echo '$(var) = $($(var))';)
endif
Then you can just do "make print" to dump the value of any variable:
$ make print CXXFLAGS
CXXFLAGS = -g -Wall
You could create a vars rule in your make file, like this:
dispvar = echo $(1)=$($(1)) ; echo
.PHONY: vars
vars:
#$(call dispvar,SOMEVAR1)
#$(call dispvar,SOMEVAR2)
There are some more robust ways to dump all variables here: gnu make: list the values of all variables (or "macros") in a particular run.
if you use android make (mka) #echo $(NDK_PROJECT_PATH) will not work and gives you error *** missing separator. Stop."
use this answer if you are trying to print variables in android make
NDK_PROJECT_PATH := some_value
$(warning $(NDK_PROJECT_PATH))
that worked for me
I usually echo with an error if I wanted to see the variable value.(Only if you wanted to see the value. It will stop execution.)
#echo $(error NDK_PROJECT_PATH= $(NDK_PROJECT_PATH))
The following command does it for me on Windows:
Path | tr ; "\n"
I'm trying to create a generic build template for my Makefiles, kind of like they discuss in the eval documentation.
I can't seem to get the wildcard function to work within an eval. The basic code I'm having issues with looks like this.
SRC_DIR = ./src/
PROG_NAME = test
define PROGRAM_template
$(1)_SRC_DIR = $(join $(SRC_DIR), $(1)/)
$(1)_SRC_FILES = $(wildcard $$($(1)_SRC_DIR)*.c)
endef
$(eval $(call PROGRAM_template, $(PROG_NAME)))
all:
#echo $(test_SRC_DIR)
#echo $(test_SRC_FILES)
#echo $(wildcard $(wildcard $(test_SRC_DIR)*.c)
When I run make with this, the output is
./src/test
[correct list of all .c files in ./src/test/]
Basically, the wildcard call within PROGRAM_template is not being eval'd as I expect it. The call results in an empty list.
The join call is being eval'd correctly though.
So, what am I doing wrong? My guess is that
$$($(1)_SRC_DIR)
is not correct, but I can't figure out the right way to do it.
EDIT
Once this was solved, it didn't take long for me to hit another issue with eval.
I posted it as a new question at
Workaround for GNU Make 3.80 eval bug
You need to double escape virtually all of the functions and variables when you use eval. In most cases, the only things that don't need to be double-escaped are function arguments (because the call function will fully expand them). In this case, you technically don't need to double-escape join or SRC_DIR either, but it will simplify your life if you just always double-escape all variables and functions when using eval.
The reason you need the double escapes is that expansion happens twice when using eval. The eval function itself performs expansion, and then expansion is done again when the block is finally parsed as makefile syntax (i.e. when it is actually evaluated).
The way you've got it written, wildcard is invoked on the string literal $( test_SRC_DIR)*.c. If you want, you can see this for yourself by replacing wildcard with info in your version and see what happens.
You need to hold off on actually invoking wildcard until the second expansion, so that it's argument is the result of the expansion of $(test_SRC_DIR).
Try this:
SRC_DIR = ./src/
PROG_NAME = test
define PROGRAM_template
$(1)_SRC_DIR = $$(join $$(SRC_DIR),$(1)/)
$(1)_SRC_FILES = $$(wildcard $$($(1)_SRC_DIR)*.c)
endef
$(eval $(call PROGRAM_template,$(PROG_NAME)))
all:
#echo $(test_SRC_DIR)
#echo $(test_SRC_FILES)
#echo $(wildcard $(test_SRC_DIR)*.c)
EDIT: After posting this, I thought I'd better test it out to make sure it actually works. In doing so, I discovered another problem. You should avoid putting spaces between the comma and argument when calling functions. It causes a literal space character to be prepended to the argument that is passed to the function and leads to unintended results. I've removed the spaces after the commas in the function calls in my version (while this isn't a problem for the call to join, I removed the space there as well just because it's a good habit to get into).