How to get the Prototype of Bean in Spring Boot - spring

Question

I am using Spring Boot and Spring Data JPA. I have created one entity as a Spring bean with prototype scope. How to I get the bean for each object to persist in database?
#Entity
#Table(name="sample")
#Scope(value=ConfigurableBeanFactory.SCOPE_PROTOTYPE)
public class Sample {
#Id
#GeneratedValue(strategy=GenerationType.AUTO)
private Long id;
private String name;
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
If I don't use the entity as Spring bean then I will use the following code to get the object:
Sample sample = new Sample();
How should I use the object using the Prototype scope bean in Spring Boot?

Answer 1

You dont want to define scope for entity. Entities are not like spring bean.
Spring data uses three important components for persisting into the database.
1) Entity Class - Each table has to be defined its own java object model called entity class.
#Entity
#Table(name="sample")
public class Sample {
#Id
#GeneratedValue(strategy=GenerationType.AUTO)
private Long id;
#Column(name="name") //Column name from the table
private String name;
2) Repo Interface- In Which you can define own implementation of SQL, and it would have save method by default.
public interface SampleRepo extends CrudRepository<Sample,Long>{
List<Sample> findByName(String name);
}
3) Client program:
private SampleRepo s;
//instantiate s using autowired setter/constructor
....
//Select example
List<Sample> sampleList=s.findByName("example");
//Insert example
//Id is auto. So no need to setup explicit value for it.
Sample entity=new Sample();
s.setName("Example");
s.save(entity);