Returning returned model object to json String using spring data jpa with hibernate - spring

I am using spring data jpa with hibernate
This is my dao interface
#Repository
public interface IUserDAO extends JpaRepository<User, Integer>{
User findByUsername( final String username );
}
This is my User class
Entity
#Table(name="USER")
public class User {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name="ID", nullable = false)
private int id;
#Column(name="USERNAME", nullable = false)
private String username;
#Column(name="NAME", nullable = false)
private String name;
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
This is my UserImplClass
This is my UserImplClass{
#Autowired
private IUserDAO iUserDAO;
public String findUserByUserName(String username) {
User user =iUserDAO.findByUsername(username);
Convert user to json object from framework level automatically
// i can add my one implemenation of converting user to json here ,but i want to achieve it from framework so that my code is not scattered on every service level
return "jsonStringOfUserObject"
}
Is it possible with spring data jpa with hibernate so that i do not have to write code for converting java object to json string in every service level?
I am using spring ,therefore i want to achieve it from spring .

You have two options to do what you want:
1) If you plan on returning this Object as an HTTP Response, and you use Spring MVC with Controllers you can annotate your controller method as follows:
public #ResponseBody User getUser(){
return userImplClass.findUserByUserName("yourusername");
}
2) If you want the UserImplClass itself to return a JSON String (which I do't recommend, but I leave you the decision), you can use Jackson Object Mapper to do it for you (you can inject it if you declare it as a bean on your configuration xml, or create a new instance of it, I personally prefer injecting it with #Autowired)
public String findUserByUserName(String username) {
User user =iUserDAO.findByUsername(username);
ObjectMapper mapper = new ObjectMapper(); // no need to do this if you inject via #Autowired
return mapper.writeValueAsString(user);
}

Related

How can Ifetch Users conversation list where user A has conversations with User B,C And D?

I'm using Spring Data JPA but I'm stuck on how to create a query based on who a user has chat history with.
I have the two objects of which Message is an entity while Chat-Message is not.
You can take a look from both classes and guide me on how I can create a spring data JPA query that queries certain users conversations with other users:
#Entity
public class Message {
#Id
#GeneratedValue(strategy=GenerationType.AUTO)
Long id;
String message;
#ManyToOne
#JoinColumn(name="fromUser",nullable=false)
private User fromUser;
#ManyToOne
#JoinColumn(name="toUser",nullable=false)
private User toUser;
public Message() { }
public Message(User fromUser, User toUser, String message) {
this.fromUser=fromUser;
this.toUser=toUser;
this.message=message;
}
public Long getId() {
return id;
}
// getters and setters
}
public class ChatMessage {
Long id;
String message;
String sender;
String username;
Long senderId;
public ChatMessage() { }
// getters and setters
public ChatMessage(Message m, Boolean isReply) {
this.sender = m.getFromUser().getFirstname() + " " + m.getFromUser().getLastname();
this.message = m.getMessage();
this.senderId = m.getFromUser().getId();
this.id = m.getId();
}
}
My possible endpoint:
#RequestMapping(value="/conversations",produces = "application/json")
#ResponseBody
public List<Message> myMessages(Principal principal){
String thisUser=principal.getName();
User user=userServiceImpl.findByUsername(thisUser);
// List<Message>messages=messageServiceImpl.finddAll();
List<Message> messages=messageServiceImpl.fetchMessages(user.getId());
return messages;
}
Note that Chat-Message is just an object class for carrying WebSocket messages. My Message Repo:
public interface MessageRepository extends JpaRepository<Message,Long>{
}
Image: [1]: https://i.stack.imgur.com/hVbP3.png
It's not really clear what exactly you need here, and what messageServiceImpl does, for instance. But, maybe this will be useful:
public interface MessageRepository extends JpaRepository<Message, Long> {
// if we get all messages your user sent or received - would it be
// what you mean here a "conversation" ?
List<Message> findByFromUserIdOrToUserId(Long id);
// or you can use #Query to achieve the same
#Query("select m from Message m where m.fromUser.id = :id or m.toUser.id = :id")
List<User> findMessagesForUser(Long id);
}
You can also find more details of how to create queries using Spring Data in their official docs.

Spring boot application I can not get data from oracle database it returns [] in postman

Spring boot application I can not get data from oracle database it returns []. In postman, it returns other requests e.g home method in controller class returns correctly. also, the table created by model class the problem is getting data from the table.
Here is the postman result:
I get this in console:
Model class
#Entity // This tells Hibernate to make a table out of this class
public class Userr {
#Id
#GeneratedValue(strategy=GenerationType.AUTO)
private Integer id;
private String name;
private String email;
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
}
//Controller Class
#RestController
public class MainController {
#Autowired // This means to get the bean called userRepository
// Which is auto-generated by Spring, we will use it to handle the data
private UserRepository userRepository;
#PostMapping(path="/add") // Map ONLY POST Requests
public #ResponseBody String addNewUser (#RequestParam String name
, #RequestParam String email) {
// #ResponseBody means the returned String is the response, not a view name
// #RequestParam means it is a parameter from the GET or POST request
Userr n = new Userr();
n.setName(name);
n.setEmail(email);
userRepository.save(n);
return "Saved";
}
#GetMapping(path="/all")
public #ResponseBody Iterable<Userr> getAllUsers() {
// This returns a JSON or XML with the users
//
return userRepository.findAll();
}
#GetMapping(path="/al")
public List<Userr> printPersonInfo() {
List<Userr> list = new ArrayList<>();
userRepository.findAll().forEach(list::add);
return list;
}
#RequestMapping("/user")
public String home(){
return "PPPPPP";
}
}
//Repository Class
public interface UserRepository extends CrudRepository<Userr, Integer> {
}
Add #Repository annotation to your UserRepository. It will help with your issue.

Spring Data JPA Redis : Cannot write custom method based query

I have configured Spring Data JPA with Redis and using RedisRepositories with provides methods like find(), findAll() etc. All these methods seem to be working just fine, but I am not able to write my custom method like.
RedisEntity findByGenderAndGrade(String gender, String grade);
RedisEntity is a simple POJO Entity class. If you want any more info, please let me know in messages.
Following is my entity:
#Data
#RedisHash("test1")
public class RedisEntity implements Serializable {
#Id
#GeneratedValue
private String id;
private String name;
private String gender;
private Integer grade;
}
Repository:
#Repository
public interface TestRepository extends JpaRepository<RedisEntity, String> {
List<RedisEntity> findAllByGender(String gender);
List<RedisEntity> findAllByGrade(Integer grade);
}
Service/Controller:
#Override
public List<RedisEntity> getById(String id) {
return testRepository.findById(id); //returns data perfectly.
}
#Override
public List<RedisEntity> getAllByGender(String gender) {
return testRepository.findAllByGender(gender); //returns []
}
#Override
public void saveEntity(RedisEntity redisEntity) {
testRepository.save(redisEntity); // saves it in redis perfectly.
}
Also,
findByGender and findAllByGender both give [], although I can see data in my redis database and save it as well.
As requested by FrançoisDupire,
#Configuration
public class RedisConfig {
#Autowired
private DeploymentProperties deploymentProperties;
private static Logger logger = LoggerFactory.getLogger(RedisConfig.class);
#Bean
JedisConnectionFactory jedisConnectionFactory() {
RedisStandaloneConfiguration redisStandaloneConfiguration = new RedisStandaloneConfiguration("localhost", 6379);
redisStandaloneConfiguration.setPassword(RedisPassword.of("root"));
return new JedisConnectionFactory(redisStandaloneConfiguration);
}
#Bean
public RedisTemplate<String, Object> redisTemplate() {
RedisTemplate<String, Object> template = new RedisTemplate<>();
template.setConnectionFactory(jedisConnectionFactory());
return template;
}
}
Also, I had referred this article: Baeldung article on Spring data redis
As mentioned by #JoshJ and verified by myself and others,
The solution to the problem is:
Adding #Indexed annotation
to all those columns/fields which need to be used with all finds.
#Data
#RedisHash("EmployeeDetails")
public class RedisEntity {
#Id
private String employeeId;
private String firstName;
private String lastName;
#Indexed
private String gender;
#Indexed
private String grade;
}
We have the Spring Data Redis Library which provides the scope to write the custom method.Attaching Sample code.
<dependency>
<groupId>org.springframework.data</groupId>
<artifactId>spring-data-redis</artifactId>
<version>2.0.8.RELEASE</version>
</dependency>
Entity Definition
#Data
#RedisHash("EmployeeDetails")
public class RedisEntity {
#Id
private String employeeId;
private String firstName;
private String lastName;
private String gender;
private String grade;
}
Repository Definition
#Repository
public interface RedisEntityRepository extends CrudRepository<RedisEntity, String>{
List<RedisEntity> findAllByGenderAndGrade(String gender, String grade);
}
Implementation
#Component
public class RedisEntityImpl implements RedisEntityService {
#Autowired
private RedisEntityRepository redisEntityRepository;
#Override
public List<RedisEntity> getAllByGenderAndGrade(String gender, String grade) {
return redisEntityRepository.findAllByGenderAndGrade(gender,grade);
}
}
Properties
spring.cache.type = redis
spring.redis.host = localhost
spring.redis.port = 6379

why I can't use string as id

I am trying to create a user model with a CrudRepository:
#Entity
public class User {
#Id
#GeneratedValue
private String username;
private String password;
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
}
public interface UserRepository extends CrudRepository<User, String> {
}
However I got an 500 error every time I call findOne():
#Controller
public class UserController {
#Autowired
private UserRepository users;
#Override
#RequestMapping(value="/register", method=RequestMethod.POST)
public #ResponseBody User register(#RequestBody User userToRegister) {
String username = userToRegister.getUsername();
User user = users.findOne(id);
if (user != null) {
return null;
}
User registeredUser = users.save(userToRegister);
return registeredUser;
}
}
However if I just switch to an long type id instead of username itself then everything works. I think it's common to use string as id. So how to make this work?
I use the embedded hsql database. I didn't wrote any sql code.
The problem is that String username; is annotated with both #Id and #GeneratedValue. #Id means that is should be a primary key, fine it can be a String. But #GeneratedValue means that you want the system to automatically generate a new key when you create a new record. That's easy when the primary key is integer, all databases have a notion of sequence (even if the syntax is not always the same). But if you want String automatically generated keys, you will have do define your own custom generator.
Or if you have no reason for the #GeneratedValue annotation, simply remove it as suggested by Bohuslav Burghardt
Use column annotation like below by putting nullable False.
#Id
#GeneratedValue
#Column(name = "username", nullable = false)
private String username;

spring data mongodb MongoRepository.save(T entity) method not working?

The code is listed below:
#Document
#XmlRootElement
public class User {
#Indexed(unique=true)
private String username;
private String firstName;
private String lastName;
private String password;
...... omit setters and getters
}
public interface UserRepo extends MongoRepository<User, String>{
}
public User update(User user) {
User existingUser = userRepo.findByUsername(user.getUsername());
if (existingUser == null) {
return null;
}
existingUser.setFirstName(user.getFirstName());
existingUser.setLastName(user.getLastName());
return userRepo.save(existingUser);
}
when update method invoked, the finds the user based on username and finishes without any exceptions, the returned User obj has all updated value but the underlying mongodb document is not changed! Can anyone help? Thanks.
you need an Id field with #Id annotation

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