Please help!
I want to compare two dates is Access, only problem is, one date is nummeric in the table like 20160316 and the other date is as date in table like #20-02-2016#
How can I calculate how many days are between these two dates?
Thnx a lot!
You can use:
Select
*,
DateDiff("d", CDate(Format([NumericDate], "####\/##\/##")), [TrueDate])
From
YourTable1
or, for positive only differences:
Select
*,
Abs(DateDiff("d", CDate(Format([NumericDate], "####\/##\/##")), [TrueDate]))
From
YourTable1
Related
I am looking to add a number of days (column 1- integer) to a date (column 2- date) to create another date in the future (column 3- date).
What is the code required?
Try using this formula for column3
TIMESTAMPADD(SQL_TSI_DAY,CAST("Table"."Column1_int" AS INTEGER), "Table"."Column2_date")
Thanks for giving me a great start. Here is what ended up working:
TimestampAdd(SQL_TSI_DAY,"Customer"."Cycle Days","Customer"."Next Inspection Date")
"Customer"."Cycle Days" - # (integer) of days to be added to the date
"Customer"."Next Inspection Date" - date
I have a scenario where I need to compare 2 or more dates for given period.
I'm able to succeed when comparing 1 date to a period using between function. But challenge is when I have 2 dates to compare in parallel, getting single row sub query error
select A
from ORDER
where Date1 between sysdate and (sysdate-10)
Above query works fine for single date, please help to get a solution when I have Date 1 and Date 2 and need to compare against the same period (sysdate and (sysdate-10)) and I may have more than 2 dates as well.
Thanks
Shankar
Not having a proper description of your tables or the data they contain, it is difficult to know what you want.
Perhaps something like:
SELECT A
FROM ORDER
GROUP BY A
HAVING COUNT( CASE WHEN datecolumn BETWEEN SYSDATE - 10 AND SYSDATE THEN 1 ELSE NULL END ) > 0
I'm a novice. I have a employee table with a column specifying the joining date and I want to retrieve the list of employees who have joined in the last 3 months. I understand we can get the current date using from_unixtime(unix_timestamp()). How do I calculate the datediff? Is there a built in DATEDIFF() function like in MS SQL? please advice!
datediff(to_date(String timestamp), to_date(String timestamp))
For example:
SELECT datediff(to_date('2019-08-03'), to_date('2019-08-01')) <= 2;
If you need the difference in seconds (i.e.: you're comparing dates with timestamps, and not whole days), you can simply convert two date or timestamp strings in the format 'YYYY-MM-DD HH:MM:SS' (or specify your string date format explicitly) using unix_timestamp(), and then subtract them from each other to get the difference in seconds. (And can then divide by 60.0 to get minutes, or by 3600.0 to get hours, etc.)
Example:
UNIX_TIMESTAMP('2017-12-05 10:01:30') - UNIX_TIMESTAMP('2017-12-05 10:00:00') AS time_diff -- This will return 90 (seconds). Unix_timestamp converts string dates into BIGINTs.
More on what you can do with unix_timestamp() here, including how to convert strings with different date formatting: https://cwiki.apache.org/confluence/display/Hive/LanguageManual+UDF#LanguageManualUDF-DateFunctions
yes datediff is implemented; see:
https://cwiki.apache.org/confluence/display/Hive/LanguageManual+UDF
By the way I found this by Google-searching "hive datediff", it was the first result ;)
I would try this first
select * from employee where month(current_date)-3 = month(joining_date)
first... sorry for my english.
I have a query like this:
Select *
From tableA
Where (
TO_NUMBER(TO_CHAR(dateA(+),'SYYYY')) = 2013
AND TO_NUMBER(TO_CHAR(dateA(+),'MM')) = 02
AND to_number(to_char(dateA(+),'dd')) <= 25
)
and retrieve me the data from each date until last number that I give as parameter, in this case the day 25. This working but delay very much because the form of "Where" statement... anybody know another way that retrieve the data so fast and with the same functionality?
It sounds like you want
SELECT *
FROM tableA
WHERE dateA BETWEEN trunc( date '2013-02-26', 'MM' ) AND date '2013-02-26'
This will return all the rows where dateA is between the first of the month and the specified date. If there is an index on dateA, Oracle would be able to use it for this sort of query (though whether it actually would is a separate issue).
My code in the stored procedure:
SELECT * FROM
my_table ir
WHERE
--where clause goes here
ORDER BY
CASE WHEN p_order_by_field='Id' AND p_sort_order='ASC' THEN IR.ID end,
CASE WHEN p_order_by_field='Id' AND p_sort_order='DESC' THEN IR.ID end DESC,
CASE WHEN p_order_by_field='Date' AND p_sort_order='ASC' THEN TO_CHAR(IR.IDATE, 'MM/dd/yyyy') end,
CASE WHEN p_order_by_field='Date' AND p_sort_order='DESC' THEN TO_CHAR(IR.IDATE, 'MM/dd/yyyy') end DESC;
Problem is that sorting is done based on the char, which comes out wrong for the date case. CASE statement, however, won't allow any other datatype other than char. So what is the solution in this case? I need to be able to pass the p_order_by_field into the stored procedure.
Thanks
Should be simple - just use ISO date format in your case:
TO_CHAR(IR.IDATE, 'yyyy-mm-dd')
and you should be fine.
Another problem could occure when you want to sort on the date difference (let say number of days between two days).
For example such a sort would return number 13 (days) before 9 (days).
The solution is that you concatenate length of date difference and the difference itself:
length(trunc(date2) - trunc(date1)) || to_char(date2 - date1)