Following are the option on executing a tool appTool
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+ Operations +
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(1) Quick Test
(2) Help
(3) Exit
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I want to check if the script is running and execute it if it is not running, I have created the following script.
#!/bin/bash
service=appTool
checkRunning=`ps -ef | grep -v grep | grep $service | wc -l > 0`
echo $checkRunning
if (( $(ps -ef | grep -v grep | grep $service | wc -l) > 0 ))
then
echo "$service is running!!!"
else
1| /etc/init.d/$service start
fi
When the script is executed I wish to pass the option 1 when the job is scheduled.
How can this be achieved ??
Related
I have simple unix shell script as follows. Which is giving different count for a service
#!/bin/bash
service=$1
ps -ef | grep $service | grep -v "grep" | wc -l
PROCESS_NUM=$(ps -ef | grep $service | grep -v "grep"| wc -l)
echo $PROCESS_NUM
In the above code below line gives output of 2.
ps -ef | grep $service | grep -v "grep" | wc -l
But when same line is assigned to variable as code below its giving output as 3.
PROCESS_NUM=$(ps -ef | grep $service | grep -v "grep"| wc -l)
echo $PROCESS_NUM
Why this is getting increased by 1 and how to tackle it.
You can see what is happening if the script tees the output to a file before counting the lines and then displaying the output after:
#!/bin/bash
service=$1
echo Directly in Script:
ps -ef | grep $service | grep -v grep | tee test.txt | wc -l
cat test.txt
echo Inside Subshell:
RESULT=$(ps -ef | grep $service | grep -v grep | tee test.txt | wc -l)
echo $RESULT
cat test.txt
When the output of a command is captured, bash starts another shell to run the command - but that subshell also shows up in the process list.
When I run that script I get:
$ ./test.sh lca
Directly in Script:
2
gcti 4268 1 0 2018 ? 21:59:03 ./lca 4999
t816826 9159 7009 0 09:22 pts/1 00:00:00 /bin/bash ./test.sh lca
Inside Subshell:
3
gcti 4268 1 0 2018 ? 21:59:03 ./lca 4999
t816826 9159 7009 0 09:22 pts/1 00:00:00 /bin/bash ./test.sh lca
t816826 9166 9159 0 09:22 pts/1 00:00:00 /bin/bash ./test.sh lca
I am trying to capture the number of active processes by running a command and trying to capture the result in a variable of shell script, but unfortunately, nothing is getting captured. The code is as below:
#!/bin/ksh
## Checking whether or not the Previous Build is Completed
count_build_status=`ps -ef | grep BDD_PreCheck.sh | grep -c FT_BGmgmt` | tee -a ${logFile}
echo "The Value of Count Build Status is $count_build_status"
if [[ "${count_build_status}" != "0" ]]
then
echo INFO - The previous build has not ended yet. Please Wait for some time or contact the Administrator | tee -a $logFile
exit 1;
fi
exit 0;
Here, ps -ef | grep BDD_PreCheck.sh | grep -c FT_BGmgmt gives result as 0 if executed individually, but the value stored in 'count_build_status' is null.
Can anyone help?
The problem here is backtick, which does not assign value to the variable when tee'ing is not done inside backtick. It should be included at the end of logFile as in the code below.
#!/bin/bash
logFile=log.txt
## Checking whether or not the Previous Build is Completed
count_build_status=`ps -ef | grep BDD_PreCheck.sh | grep -c FT_BGmgmt | tee -a ${logFile}`
echo "The Value of Count Build Status is $count_build_status"
if [[ "${count_build_status}" != "0" ]]
then
echo INFO - The previous build has not ended yet. Please Wait for some time or contact the Administrator | tee -a $logFile
exit 1;
fi
exit 0;
example: capture output of a cmd-line to a variable and append a logfile with tee:
var=`ps -ef | grep 0 | grep -c 1 | tee -a log`
echo $var
I have a bash script as follows:
if [[ "$1" == "stop" ]]; then
echo "[$(date +'%d/%m/%Y %H:%M:%S:%s')]: Killing all active watchers" >> $LOG
kill -9 $(ps -ef | grep "processname1" | grep -v "grep" | grep -v "$$" | awk
'{print $2}' | xargs)
echo "[$(date +'%d/%m/%Y %H:%M:%S:%s')]: Killing all current processname2
processes" >> $LOG
kill -9 $(ps -ef | grep "processname2" | grep -v "grep" | awk '{print $2}' |
xargs)
exit 0
when i run 'x service stop', the following is outputted:
kill: usage: kill [-s sigspec | -n signum | -sigspec] pid | jobspec ... or kill
-l [sigspec]
Killed
How do i stop the kill usage being displayed? It is successfully killing the process, however the fact that the usage is displayed is causing AWS CodeDeploy to fail.
Thanks!
Adam, please note that this is really just a comment with formatting. Don't take this as a real answer to your question. Please focus on the constructive comments to your question.
In my mis-spent youth, I wrote this bash function to do the ps -ef | grep .... madness:
# ps-grep
psg() {
local -a patterns=()
(( $# == 0 )) && set -- $USER
for arg do
patterns+=("-e" "[${arg:0:1}]${arg:1}")
done
ps -ef | grep "${patterns[#]}"
}
using the knowledge that the pattern [p]rocessname will not match the string [p]rocessname
I created this function to kill a process by partial name, put it in bash_profile, and executed it.
when I run it one command at a time manually, everything works.
but when I call the function, it fails with the output: "illegal process id"
function killServer() {
pid=$(ps -fe | grep '[p]rocessName' | awk '{print $2}')
if [[ -n $pid ]]; then
kill $pid
else
echo "Does not exist"
fi
}
output:
kill: illegal process id: i311821
running
ps -fe | grep '[p]rocessName'
gives:
1543721191 1947 1946 0 9:12AM ?? 0:46.76 ../../jdk/bin/java -server -da -XX:PermSize=256m Xrunjdwp:transport=dt_socket,address=8000,suspend=n,server=y -DMonitorDisabled -Xms2048m -Xmx2048m -Dwrapper.port=32000 -com.XXX.YYY.server.util.Main -b 0.0.0.0 -c default
what is the reason for that?
found the problem:
a space after $2 was missing. after the fix, it works:
ps -ef | grep "[X]XX" | grep -v grep | awk '{print $2 }' | xargs kill -9
We have a script which is checking and sending an alert if process goes down. For some reason it is not capturing it properly for all the users and not sending the alerts in all scenarios.
Please suggest what could be the problem.
Environments – uatwrk1, uatwrk2, uatwrk3 ------- uatwrk100
ServerName - myuatserver
Process to be checked - Amc/apache/bin/httpd
Script is :
#!/bin/ksh
i=1
while (( i<=100 ))
do
myuser=uatwrk$i
NoOfProcess=`ps -ef | grep -v grep | grep $myuser | grep "Amc/apache/bin/httpd" | wc -l`
if [[ $NoOfProcess -eq 0 ]]
then
echo "Amc process is down, sending an alert"
# Assume sendAlert.ksh is fine
./sendAlert.ksh
else
echo "Amc process is running fine" >> /dev/null
fi
(( i+=1 ))
done
I think #Mahesh already indicated the problem in a comment.
When you only want to have a mail once, you can count the users running a httpd process. The backslash in the following command is for avoiding grep -v grep.
ps -ef | grep "A\mc/apache/bin/httpd" | cut -d " " -f1 | grep "^uatwrk"| sort -u | wc -l