My project structure is shown below.
Here library
When i browser http://localhost:8080/springMOTHER-jsf/index.xhtml then it don't display page index.xhtml
I'm begining with JSF, Please let me know Why ???
Here file web.xml
<web-app xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
version="3.0">
<servlet>
<servlet-name>Faces Servlet</servlet-name>
<servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>*.xhtml</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.xhtml</welcome-file>
</welcome-file-list>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/applicationContext.xml</param-value>
</context-param>
</web-app>
Related
I created a Java Servlet server running on Tomcat 7.0 through eclipse. The Project uses Maven and Spring. The project works perfectly on Linux (Mint) but not on Windows. I am able to get into .jsp pages but not able to access servlets because I get a 404 error(only on Winosws).
So if I look up http://localhost:8080/projectName/index.jsp this will work. But http://localhost:8080/projectName/ServletName I get a 404 error, the servlet is suppose to redirects to a .jsp page.
My web.xml file
<web-app id="WebApp_ID" version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<display-name>projectName</display-name>
<context-param>
<param-name>ApplicationContext</param-name>
<param-value>/WEB-INF/applicationContext.xml</param-value>
</context-param>
<servlet>
<servlet-name>projectName</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet>
<description>
</description>
<display-name>WebService</display-name>
<servlet-name>WebService</servlet-name>
<servlet-class>com.servlet.WebService</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>projectName</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>WebService</servlet-name>
<url-pattern>/WebService</url-pattern>
</servlet-mapping>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<listener>
<listener-class>org.springframework.web.context.request.RequestContextListener</listener-class>
</listener>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
</web-app>
I've been searching and trying all different ways to map my customized 404 page, but nothing is working so far. The following is my web.xml:
<?xml version="1.0" encoding="utf-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
version="2.5">
<display-name>Spring3 MVC Application</display-name>
<servlet>
<servlet-name>spring-web</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<init-param>
<param-name>throwExceptionIfNoHandlerFound</param-name>
<param-value>true</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring-web</servlet-name>
<url-pattern>/</url-pattern>
<url-pattern>*.htm</url-pattern>
</servlet-mapping>
<error-page>
<error-code>404</error-code>
<location>/WEB-INF/views/404.jsp</location>
</error-page>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring-web-servlet.xml</param-value>
</context-param>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
</web-app>
I've tried either just putting up error-page tag or setting up IfNoHandlerFound exception. Nothing seems to be working. Please let me know if any more code or information is needed. Thanks for help.
Verify the real location of your page: <location>/WEB-INF/views/404.jsp</location>
I have an application which worked in GlasshFish and that I want to migrate Wildfly 8.
I successfully deployed the application in Wildfly but the listener present in web.xml is not called.
web.xml :
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<context-param>
<param-name>javax.faces.PROJECT_STAGE</param-name>
<param-value>Development</param-value>
</context-param>
<servlet>
<servlet-name>ContactAccountActivation</servlet-name>
<servlet-class>ca.evision.eAwards.servlet.ContactAccountActivation</servlet-class>
</servlet>
<servlet>
<servlet-name>Faces Servlet</servlet-name>
<servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<listener>
<listener-class>org.fero.web.tags.LoadMetaModelListner</listener-class>
</listener>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>/faces/*</url-pattern>
<url-pattern>*.xhtml</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>ContactAccountActivation</servlet-name>
<url-pattern>/ContactAccountActivation</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>/pages/loginForm.xhtml</welcome-file>
</welcome-file-list>
<session-config>
<session-timeout>15</session-timeout>
</session-config>
</web-app>
I tested calling this string from an other sample application web.xml and it works correctly. I use the Netbeans 8 lite IDE.
Thanks for your help.
My file web.xml is
<!DOCTYPE web-app PUBLIC
"-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd" >
<web-app id="WebApp_1383925467813">
<display-name>Archetype Created Web Application</display-name>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
<url-pattern>/m/*</url-pattern>
<url-pattern>/t/*</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
Myeclipse reports this error:
The content of element type "servlet-mapping" must match
"(servlet-name,url-pattern)"
What's the problem?
Thank's
Please change your DTD to 3.0 version which allows multiple <url-pattern> tags inside <servlet-mapping>.
I have just made the version change in your web.xml placed it below
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
version="3.0">
<display-name>Archetype Created Web Application</display-name>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
<url-pattern>/m/*</url-pattern>
<url-pattern>/t/*</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
As per the DTD we can have only one <url-pattern> inside a <servlet-mapping> tag.
<!ELEMENT servlet-mapping (servlet-name, url-pattern)>
Rewrite your xml like:
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/m/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/t/*</url-pattern>
</servlet-mapping>
try to remove' / ' from name to you /m/*
and try error resolve
The content of element type "servlet-mapping" is incomplete, it must match "(servlet-name , -pattern)". error and I found this error is temp if you clean you clean your project by using clean option which you can find in the project section
i want to integrate jsf2.0 and spring 3.1 and hibernate 4.1. but tomcat has error 404:description The requested resource (/jsfspringhiber/page/default.jsf) is not available.
what is wrong?
following is my web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0">
<display-name>jsfspringhiber</display-name>
<!-- Add Support for Spring -->
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<listener>
<listener-class>
org.springframework.web.context.request.RequestContextListener
</listener-class>
</listener>
<!-- Change to "Production" when you are ready to deploy -->
<context-param>
<param-name>javax.faces.PROJECT_STAGE</param-name>
<param-value>Development</param-value>
</context-param>
<!-- Welcome page -->
<welcome-file-list>
<welcome-file>faces/default.xhtml</welcome-file>
</welcome-file-list>
<!-- JSF mapping -->
<servlet>
<servlet-name>Faces Servlet</servlet-name>
<servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<!-- Map these files with JSF -->
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>/faces/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>*.jsf</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>*.faces</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>*.xhtml</url-pattern>
</servlet-mapping>
</web-app>
I guess your are using eclipse, I think that you have a problem with the deploy.
1) check the tomcat deploy path to see if it is deployed correctly: workspace/.metadata/plugings/org.eclipse.wst.server.core/tmp0/wtpwebapps. (some times help deleting the tmp0, to force tomcat to redeploy).
2) In the project's properties check the deployment assembly and verificy that all the need file are included.
This might work
Okay, if you have the url-pattern as /faces/* , the Faces servlet will prepend every request with /faces. So you will have to access the resource as /jsfspringhiber/faces/page/default.xhtml or just /jsfspringhiber (if the welcome file is listed as faces/page/default.xhtml).
Update: Remove all the servlet-mappings and just use one:
<welcome-file-list>
<welcome-file>default.xhtml</welcome-file>
</welcome-file-list>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>*.xhtml</url-pattern>
</servlet-mapping>
and put the default.xhtml file under WebContent directory.
If you really want to map all those url patterns look at this answer
i use maven. the correct answer is here.
the structure is: