I created a Java Servlet server running on Tomcat 7.0 through eclipse. The Project uses Maven and Spring. The project works perfectly on Linux (Mint) but not on Windows. I am able to get into .jsp pages but not able to access servlets because I get a 404 error(only on Winosws).
So if I look up http://localhost:8080/projectName/index.jsp this will work. But http://localhost:8080/projectName/ServletName I get a 404 error, the servlet is suppose to redirects to a .jsp page.
My web.xml file
<web-app id="WebApp_ID" version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<display-name>projectName</display-name>
<context-param>
<param-name>ApplicationContext</param-name>
<param-value>/WEB-INF/applicationContext.xml</param-value>
</context-param>
<servlet>
<servlet-name>projectName</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet>
<description>
</description>
<display-name>WebService</display-name>
<servlet-name>WebService</servlet-name>
<servlet-class>com.servlet.WebService</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>projectName</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>WebService</servlet-name>
<url-pattern>/WebService</url-pattern>
</servlet-mapping>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<listener>
<listener-class>org.springframework.web.context.request.RequestContextListener</listener-class>
</listener>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
</web-app>
Related
I've been searching and trying all different ways to map my customized 404 page, but nothing is working so far. The following is my web.xml:
<?xml version="1.0" encoding="utf-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
version="2.5">
<display-name>Spring3 MVC Application</display-name>
<servlet>
<servlet-name>spring-web</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<init-param>
<param-name>throwExceptionIfNoHandlerFound</param-name>
<param-value>true</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring-web</servlet-name>
<url-pattern>/</url-pattern>
<url-pattern>*.htm</url-pattern>
</servlet-mapping>
<error-page>
<error-code>404</error-code>
<location>/WEB-INF/views/404.jsp</location>
</error-page>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring-web-servlet.xml</param-value>
</context-param>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
</web-app>
I've tried either just putting up error-page tag or setting up IfNoHandlerFound exception. Nothing seems to be working. Please let me know if any more code or information is needed. Thanks for help.
Verify the real location of your page: <location>/WEB-INF/views/404.jsp</location>
I have maven module project with 4 modules core, web, config and war. I have all the spring configuration file inside config module /resources/spring/*.xml.
When I am added the project in eclipse jboss-eap 6.1 server it is working fine(with un archived format) and after maven build the xml file is moved to conf.jar file, but when I build it and deploy it in jboss-eap it is throwing
IOException parsing XML document from class path resource
[spring/applicationContext.xml]; nested exception is
java.io.FileNotFoundException: class path resource
[spring/applicationContext.xml] cannot be opened because it does not
exist
Below is my web.xml file.
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID" version="2.5">
<display-name>Archetype Created Web Application</display-name>
<description></description>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:/spring/applicationContext.xml,
classpath:/spring/spring-companyFinance-security.xml</param-value>
</context-param>
<context-param>
<param-name>defaultHtmlEscape</param-name>
<param-value>true</param-value>
</context-param>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<listener>
<listener-class>org.springframework.web.context.request.RequestContextListener</listener-class>
</listener>
<listener>
<listener-class>
org.springframework.security.web.session.HttpSessionEventPublisher
</listener-class>
</listener>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:/spring/spring-companyFinance-mvc-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy
</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
Could you tell me where I am wrong?
Context:
I've developed a web-app on Linux Mint using JavaEE 7 on WildFly. My customer has Windows XP and I need to deploy on it. The app is done and I am trying to deploy it (for testing) on my VM on XP. The admin-console works fine. There are also no errors when deploying the app. WildFly registers the app to /app.
Problem: When I try to access the app on http://localhost:8080/app WildFly returns Forbidden if I try to access http://localhost:8080/app/hello.xhtml it returns just "Not found" (No 404).
Note: This is my first web-app and I have no idea where to troubleshoot since there are no errors in the log. Any help is much appreciated.
Java EE7
WildFly 9.0.1 Final
Windows XP SP3
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<context-param>
<param-name>com.sun.faces.enableMissingResourceLibraryDetection</param-name>
<param-value>false</param-value>
</context-param>
<context-param>
<param-name>BootsFaces_USETHEME</param-name>
<param-value>true</param-value>
</context-param>
<context-param>
<param-name>primefaces.THEME</param-name>
<param-value>afternoon</param-value>
</context-param>
<context-param>
<param-name>javax.faces.DEFAULT_SUFFIX</param-name>
<param-value>.xhtml</param-value>
</context-param>
<context-param>
<param-name>javax.faces.DATETIMECONVERTER_DEFAULT_TIMEZONE_IS_SYSTEM_TIMEZONE</param-name>
<param-value>true</param-value>
</context-param>
<servlet>
<servlet-name>Faces Servlet</servlet-name>
<servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>*.xhtml</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>*.faces</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>
30
</session-timeout>
</session-config>
<error-page>
<exception- type>javax.faces.application.ViewExpiredException</exception-type>
<location>/desktop.xhtml</location>
</error-page>
jboss-web.xml
<?xml version="1.0" encoding="UTF-8"?>
<jboss-web xmlns="http://www.jboss.com/xml/ns/javaee">
<context-root>/app</context-root>
</jboss-web>
I have an application which worked in GlasshFish and that I want to migrate Wildfly 8.
I successfully deployed the application in Wildfly but the listener present in web.xml is not called.
web.xml :
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<context-param>
<param-name>javax.faces.PROJECT_STAGE</param-name>
<param-value>Development</param-value>
</context-param>
<servlet>
<servlet-name>ContactAccountActivation</servlet-name>
<servlet-class>ca.evision.eAwards.servlet.ContactAccountActivation</servlet-class>
</servlet>
<servlet>
<servlet-name>Faces Servlet</servlet-name>
<servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<listener>
<listener-class>org.fero.web.tags.LoadMetaModelListner</listener-class>
</listener>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>/faces/*</url-pattern>
<url-pattern>*.xhtml</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>ContactAccountActivation</servlet-name>
<url-pattern>/ContactAccountActivation</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>/pages/loginForm.xhtml</welcome-file>
</welcome-file-list>
<session-config>
<session-timeout>15</session-timeout>
</session-config>
</web-app>
I tested calling this string from an other sample application web.xml and it works correctly. I use the Netbeans 8 lite IDE.
Thanks for your help.
My file web.xml is
<!DOCTYPE web-app PUBLIC
"-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd" >
<web-app id="WebApp_1383925467813">
<display-name>Archetype Created Web Application</display-name>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
<url-pattern>/m/*</url-pattern>
<url-pattern>/t/*</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
Myeclipse reports this error:
The content of element type "servlet-mapping" must match
"(servlet-name,url-pattern)"
What's the problem?
Thank's
Please change your DTD to 3.0 version which allows multiple <url-pattern> tags inside <servlet-mapping>.
I have just made the version change in your web.xml placed it below
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
version="3.0">
<display-name>Archetype Created Web Application</display-name>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
<url-pattern>/m/*</url-pattern>
<url-pattern>/t/*</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
As per the DTD we can have only one <url-pattern> inside a <servlet-mapping> tag.
<!ELEMENT servlet-mapping (servlet-name, url-pattern)>
Rewrite your xml like:
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/m/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/t/*</url-pattern>
</servlet-mapping>
try to remove' / ' from name to you /m/*
and try error resolve
The content of element type "servlet-mapping" is incomplete, it must match "(servlet-name , -pattern)". error and I found this error is temp if you clean you clean your project by using clean option which you can find in the project section