Bash: Using pkill to track progress of removing a directory - bash

So I have a shell script that does some long operations, and when they do I want to just output a series of dots (.) until it's done, to show that it's running.
I'm using pkill to test that the process is running, and as long as it is it outputs another dot. This works very well for nearly every place I need it. However, one part of the process involves removing a directory, and that is where it breaks down.
Here is my code:
ERROR=$(rm -rf "$1" 2>&1 >/dev/null)
while pkill -0 rm; do
printf "."
sleep 1
done
printf "\n"
I'm using pkill to test the rm process, but when I do, this is the output I get:
pkill: signalling pid 192: Operation not permitted
pkill: signalling pid 326: Operation not permitted
.pkill: signalling pid 61: Operation not permitted
My script runs up until the dot-output code, including the folder deletion, but then it stops and just outputs those three lines over and over again until I forcibly kill the process.
Anyone have any ideas what's going on? I feel like it's not able to work with the rm operation, but I'm not sure.
Thanks in advance.

The problem is pkill is sending kill(PID, SIG_0) for the processes matched by Regex pattern rm. For some matched processes (shown by the PIDs), you don't have sufficient permission to send SIG_0 to get the process status.
You can use -x (--exact) option (no Regex) to match only process(es) with exact name rm (given there is no rm by other users running):
pkill -0 -x rm
or use pgrep
pgrep -x rm
Better mention your username:
pkill -0 -x -u username rm
pgrep -x -u username rm

Your script is not putting rm into the background, so when pkill is being run, presumably it's finding processes owned by other users and is not able to kill them because you cannot kill another user's process unless you are root.
Since you are spawning the process within the script, if you correctly background the rm then you can get the PID of the rm job from $! and use kill instead of pkill.
You should run the rm command and properly background it. The following untested code should do what you're trying to do:
rm -rf "$1" >/dev/null 2>&1 &
RMPID=$!
while kill -0 $RMPID 2>/dev/null; do
printf "."
sleep 1
done
printf "\n"
wait $RMPID
RESULT=$?
if (( $RESULT != 0 )); then
printf "Error when deleting $1\n"
exit 1
fi
You can read the bash documentation for more details on wait and $! and $?

Related

Is there a command, or programmatic way I can use to extract PIDs, and put them in a space-separated list? [duplicate]

I'm writing a bash script, which does several things.
In the beginning it starts several monitor scripts, each of them runs some other tools.
At the end of my main script, I would like to kill all things that were spawned from my shell.
So, it might looks like this:
#!/bin/bash
some_monitor1.sh &
some_monitor2.sh &
some_monitor3.sh &
do_some_work
...
kill_subprocesses
The thing is that most of these monitors spawn their own subprocesses, so doing (for example): killall some_monitor1.sh will not always help.
Any other way to handle this situation?
pkill -P $$
will fit (just kills it's own descendants)
EDIT: I got a downvote, don't know why. Anyway here is the help of -P
-P, --parent ppid,...
Only match processes whose parent process ID is listed.
and $$ is the process id of the script itself
After starting each child process, you can get its id with
ID=$!
Then you can use the stored PIDs to find and kill all grandchild etc. processes as described here or here.
If you use a negative PID with kill it will kill a process group. Example:
kill -- -1234
Extending pihentagy's answer to recursively kill all descendants (not just children):
kill_descendant_processes() {
local pid="$1"
local and_self="${2:-false}"
if children="$(pgrep -P "$pid")"; then
for child in $children; do
kill_descendant_processes "$child" true
done
fi
if [[ "$and_self" == true ]]; then
kill -9 "$pid"
fi
}
Now
kill_descendant_processes $$
will kill descedants of the current script/shell.
(Tested on Mac OS 10.9.5. Only depends on pgrep and kill)
kill $(jobs -p)
Rhys Ulerich's suggestion:
Caveat a race condition, using [code below] accomplishes what Jürgen suggested without causing an error when no jobs exist
[[ -z "$(jobs -p)" ]] || kill $(jobs -p)
pkill with optioin "-P" should help:
pkill -P $(pgrep some_monitor1.sh)
from man page:
-P ppid,...
Only match processes whose parent process ID is listed.
There are some discussions on linuxquests.org, please check:
http://www.linuxquestions.org/questions/programming-9/use-only-one-kill-to-kill-father-and-child-processes-665753/
I like the following straightforward approach: start the subprocesses with an environment variable with some name/value and use this to kill the subprocesses later. Most convenient is to use the process-id of the running bash script i.e. $$. This also works when subprocesses starts another subprocesses as the environment is inherited.
So start the subprocesses like this:
MY_SCRIPT_TOKEN=$$ some_monitor1.sh &
MY_SCRIPT_TOKEN=$$ some_monitor2.sh &
And afterwards kill them like this:
ps -Eef | grep "MY_SCRIPT_TOKEN=$$" | awk '{print $2}' | xargs kill
Similar to above, just a minor tweak to kill all processes indicated by ps:
ps -o pid= | tail -n +2 | xargs kill -9
Perhaps sloppy / fragile, but seemed to work at first blush. Relies on fact that current process ($$) tends to be first line.
Description of commands, in order:
Print PIDs for processes in current terminal, excl. header column
Start from Line 2 (excl. current terminal's shell)
Kill those procs
I've incorporated a bunch of the suggestions from the answers here into a single function. It gives time for processes to exit, murders them if they take too long, and doesn't have to grep through output (eg, via ps)
#!/bin/bash
# This function will kill all sub jobs.
function KillJobs() {
[[ -z "$(jobs -p)" ]] && return # no jobs to kill
local SIG="INT" # default to a gentle goodbye
[[ ! -z "$1" ]] && SIG="$1" # optionally send a different signal
# my version of 'kill' doesn't seem to understand `kill -- -${PID}`
#jobs -p | xargs -I%% kill -s "$SIG" -- -%% # kill each job's processes group
jobs -p | xargs kill -s "$SIG" # kill each job's processes group
## give the processes a moment to die, before forcing them to.
[[ "$SIG" != "KILL" ]] && {
sleep 0.2
KillJobs "KILL"
}
}
I also tried to get a variation working with pkill, but on my system (xubuntu 21.10) it does absolutely nothing.
#!/bin/bash
# This function doesn't seem to work.
function KillChildren() {
local SIG="INT" # default to a gentle goodbye
[[ ! -z "$1" ]] && SIG="$1" # optionally send a different signal
pkill --signal "$SIG" -P $$ # kill descendent's and their processes groups
[[ "$SIG" != "KILL" ]] && {
# give them a moment to die before we force them to.
sleep 0.2
KillChildren "KILL" ;
}
}

Check if bash script already running except itself with arguments

So I've looked up other questions and answers for this and as you can imagine, there are lots of ways to find this. However, my situation is kind of different.
I'm able to check whether a bash script is already running or not and I want to kill the script if it's already running.
The problem is that with the below code, -since I'm running this within the same script- the script kills itself too because it sees a script already running.
result=`ps aux | grep -i "myscript.sh" | grep -v "grep" | wc -l`
if [ $result -ge 1 ]
then
echo "script is running"
else
echo "script is not running"
fi
So how can I check if a script is already running besides it's own self and kill itself if there's another instance of the same script is running, else, continue without killing itself.
I thought I could combine the above code with $$ command to find the script's own PID and differentiate them this way but I'm not sure how to do that.
Also a side note, my script can be run multiple times at the same time within the same machine but with different arguments and that's fine. I only need to identify if script is already running with the same arguments.
pid=$(pgrep myscript.sh | grep -x -v $$)
# filter non-existent pids
pid=$(<<<"$pid" xargs -n1 sh -c 'kill -0 "$1" 2>/dev/null && echo "$1"' --)
if [ -n "$pid" ]; then
echo "Other script is running with pid $pid"
echo "Killing him!"
kill $pid
fi
pgrep lists the pids that match the name myscript.sh. From the list we filter current $$ shell with grep -v. It the result is non-empty, then you could kill the other pid.
Without the xargs, it would work, but the pgrep myscript.sh will pick up the temporary pid created for command substitution or the pipe. So the pid will never be empty and the kill will always execute complaining about the non-existent process. To do that, for each pid in pids, I check if the pid exists with kill -0. If it does, then it is outputted, effectively filtering all nonexistent pids.
You could also use a normal for loop to filter the pids:
# filter non-existent pids
pid=$(
for i in $pid; do
if kill -0 "$i" 2>/dev/null; then
echo "$i"
fi
done
)
Alternatively, you could use flock to lock the file and use lsof to list current open files with filtering the current one. As it is now, I think it will kill also editors that are editing the file and such. I believe the lsof output could be better filtered to accommodate this.
if [ "${FLOCKER}" != "$0" ]; then
pids=$(lsof -p "^$$" -- ./myscript.sh | awk 'NR>1{print $2}')
if [ -n "$pids" ]; then
echo "Other processes with $(echo $pids) found. Killing them"
kill $pids
fi
exec env FLOCKER="$0" flock -en "$0" "$0" "$#"
fi
I would go with either of 2 ways to solve this problem.
1st solution: Create a watchdog file lets say a .lck file kind of on a location before starting the script's execution(Make sure we use trap etc commands in case script is aborted so that .lck file should be removed) AND remove it once execution of script is completed successfully.
Example script for 1st solution: This is just an example a test one. We need to take care of interruptions in the script, lets say script got interrupted by a command or etc then we could use trap in it too, since at that time it would have not been completed but you may need to kick it off again(since last time it was not completed).
cat file.ksh
#!/bin/bash
PWD=`pwd`
watchdog_file="$PWD/script.lck"
if [[ -f "$watchdog_file" ]]
then
echo "Please wait script is still running, exiting from script now.."
exit 1;
else
touch $watchdog_file
fi
while true
do
echo "singh" > test1
done
if [[ -f "$watchdog_file" ]]
then
rm "$watchdog_file"
fi
2nd solution: Take pid of current running shell using $$ save it in a file. Then check if that process is still running come out of script if NOT running then move on to run statements in script.

Get PID of a timed process, along with the output of time

I have this line of code:
{ time cp $PWD/my_file $PWD/new_file ; } 2> my_log.log
I need to know how long it takes to execute the 'cp' command and I also need to get the PID of the 'cp'. I just want to print the PID of the 'cp' process and get the following in the my_log.log file:
<output of time>
I have tried PID=$! but this does not provide PID of the cp process.
First, you need to send your (timed) cp command to the background with a trailing &, so you can inspect the running processes after launching it.
(I suspect you're already doing this, but it's not currently reflected in the question).
$!, the special variable that contains the PID of the most recently launched background job, in this case reflects the subshell that runs the time command, so we know that it is the parent process of the cp command. To get the (one and only, in this case) child process:
If your platform has the nonstandard pgrep utility (comes with many Linux distros and BSD/macOS platforms), use:
pgrep -P $!
Otherwise, use the following POSIX-compliant approach:
ps -o pid=,ppid= | awk -v ppid=$! '$2 == ppid { print $1 }'
To put it all together, using prgep for convenience:
# Send the timed `cp` command to the background with a trailing `&`
{ time cp "$PWD/my_file" "$PWD/new_file"; } 2> my_log.log &
# Get the `cp` comand's PID via its parent PID, $!
cpPid=$(pgrep -P $!)
To know approximately how long takes cp command you can check new file size
size=$(stat -c %s "${old_file}")
cp "${old_file}" "${new_file}" &
cp_pid=$!
while kill -0 ${cp_pid}; do
cpsize=$(stat -c %s "${new_file}")
echo elapsed time $(ps -p${cp_pid} -oetime=)
echo $((100*cpsize/size)) % done so far..
sleep 3
done
EDIT: following comment stat -c %s "${file}" can be replaced by du "${file}" it's POSIX and more suitable command (see man page).
The simplest one I can think of is
pgrep cp
OK -- from the comments: "Contents of my_log.log will be PID of the cp command followed by the timing output of the cp command":
( time cp $PWD/my_file $PWD/new_file & 2>&1; echo $! ) > my_log.log 2>&1
First, you need to use /usr/bin/time explicitly, and pass the options to append to an output file. Then, use pgrep on the name of the file you are copying (cp will get too many hits):
/usr/bin/time --output=my_log.log --append cp $PWD/my_file $PWD/new_file & pgrep -f my_file > my_log.log
You may want to change the output format, because it's kinda ugly:
18400
0.00user 0.30system 0:02.43elapsed 12%CPU (0avgtext+0avgdata 2520maxresident)k
0inputs+496424outputs (0major+141minor)pagefaults 0swaps
Following what written in one of your comment above... the following is a proper answer:
The following code (just an example):
time (sleep 10 & echo -n "$!"; wait)
will return something like:
30406
real 0m10.009s
user 0m0.004s
sys 0m0.005s
In your case:
time (cp $PWD/old_file $PWD/new_file & echo -n "$!"; wait) &> my_log.log
will do the job.
I find this solution quite elegant since it's a "one liner" despite the "completely negligible overhead" you got in the timing (the timing will be related to the entire subshell (also the echo and the wait). That the overhead is negligible is evident from the result of the sleep command.
The &> redirect stdout and stderr to the same file (so you do not need to specify the 1>&2).
Pay attention that doing
(time sleep 10 & echo -n "$!")
You will get the pid of the time process not sleep or cp in your case.

nonblocking wait ${myPid} in bash [duplicate]

Is there any builtin feature in Bash to wait for a process to finish?
The wait command only allows one to wait for child processes to finish.
I would like to know if there is any way to wait for any process to finish before proceeding in any script.
A mechanical way to do this is as follows but I would like to know if there is any builtin feature in Bash.
while ps -p `cat $PID_FILE` > /dev/null; do sleep 1; done
To wait for any process to finish
Linux (doesn't work on Alpine, where ash doesn't support tail --pid):
tail --pid=$pid -f /dev/null
Darwin (requires that $pid has open files):
lsof -p $pid +r 1 &>/dev/null
With timeout (seconds)
Linux:
timeout $timeout tail --pid=$pid -f /dev/null
Darwin (requires that $pid has open files):
lsof -p $pid +r 1m%s -t | grep -qm1 $(date -v+${timeout}S +%s 2>/dev/null || echo INF)
There's no builtin. Use kill -0 in a loop for a workable solution:
anywait(){
for pid in "$#"; do
while kill -0 "$pid"; do
sleep 0.5
done
done
}
Or as a simpler oneliner for easy one time usage:
while kill -0 PIDS 2> /dev/null; do sleep 1; done;
As noted by several commentators, if you want to wait for processes that you do not have the privilege to send signals to, you have find some other way to detect if the process is running to replace the kill -0 $pid call. On Linux, test -d "/proc/$pid" works, on other systems you might have to use pgrep (if available) or something like ps | grep "^$pid ".
I found "kill -0" does not work if the process is owned by root (or other), so I used pgrep and came up with:
while pgrep -u root process_name > /dev/null; do sleep 1; done
This would have the disadvantage of probably matching zombie processes.
This bash script loop ends if the process does not exist, or it's a zombie.
PID=<pid to watch>
while s=`ps -p $PID -o s=` && [[ "$s" && "$s" != 'Z' ]]; do
sleep 1
done
EDIT: The above script was given below by Rockallite. Thanks!
My orignal answer below works for Linux, relying on procfs i.e. /proc/. I don't know its portability:
while [[ ( -d /proc/$PID ) && ( -z `grep zombie /proc/$PID/status` ) ]]; do
sleep 1
done
It's not limited to shell, but OS's themselves do not have system calls to watch non-child process termination.
FreeBSD and Solaris have this handy pwait(1) utility, which does exactly, what you want.
I believe, other modern OSes also have the necessary system calls too (MacOS, for example, implements BSD's kqueue), but not all make it available from command-line.
From the bash manpage
wait [n ...]
Wait for each specified process and return its termination status
Each n may be a process ID or a job specification; if a
job spec is given, all processes in that job's pipeline are
waited for. If n is not given, all currently active child processes
are waited for, and the return status is zero. If n
specifies a non-existent process or job, the return status is
127. Otherwise, the return status is the exit status of the
last process or job waited for.
Okay, so it seems the answer is -- no, there is no built in tool.
After setting /proc/sys/kernel/yama/ptrace_scope to 0, it is possible to use the strace program. Further switches can be used to make it silent, so that it really waits passively:
strace -qqe '' -p <PID>
All these solutions are tested in Ubuntu 14.04:
Solution 1 (by using ps command):
Just to add up to Pierz answer, I would suggest:
while ps axg | grep -vw grep | grep -w process_name > /dev/null; do sleep 1; done
In this case, grep -vw grep ensures that grep matches only process_name and not grep itself. It has the advantage of supporting the cases where the process_name is not at the end of a line at ps axg.
Solution 2 (by using top command and process name):
while [[ $(awk '$12=="process_name" {print $0}' <(top -n 1 -b)) ]]; do sleep 1; done
Replace process_name with the process name that appears in top -n 1 -b. Please keep the quotation marks.
To see the list of processes that you wait for them to be finished, you can run:
while : ; do p=$(awk '$12=="process_name" {print $0}' <(top -n 1 -b)); [[ $b ]] || break; echo $p; sleep 1; done
Solution 3 (by using top command and process ID):
while [[ $(awk '$1=="process_id" {print $0}' <(top -n 1 -b)) ]]; do sleep 1; done
Replace process_id with the process ID of your program.
Blocking solution
Use the wait in a loop, for waiting for terminate all processes:
function anywait()
{
for pid in "$#"
do
wait $pid
echo "Process $pid terminated"
done
echo 'All processes terminated'
}
This function will exits immediately, when all processes was terminated. This is the most efficient solution.
Non-blocking solution
Use the kill -0 in a loop, for waiting for terminate all processes + do anything between checks:
function anywait_w_status()
{
for pid in "$#"
do
while kill -0 "$pid"
do
echo "Process $pid still running..."
sleep 1
done
done
echo 'All processes terminated'
}
The reaction time decreased to sleep time, because have to prevent high CPU usage.
A realistic usage:
Waiting for terminate all processes + inform user about all running PIDs.
function anywait_w_status2()
{
while true
do
alive_pids=()
for pid in "$#"
do
kill -0 "$pid" 2>/dev/null \
&& alive_pids+="$pid "
done
if [ ${#alive_pids[#]} -eq 0 ]
then
break
fi
echo "Process(es) still running... ${alive_pids[#]}"
sleep 1
done
echo 'All processes terminated'
}
Notes
These functions getting PIDs via arguments by $# as BASH array.
Had the same issue, I solved the issue killing the process and then waiting for each process to finish using the PROC filesystem:
while [ -e /proc/${pid} ]; do sleep 0.1; done
There is no builtin feature to wait for any process to finish.
You could send kill -0 to any PID found, so you don't get puzzled by zombies and stuff that will still be visible in ps (while still retrieving the PID list using ps).
If you need to both kill a process and wait for it finish, this can be achieved with killall(1) (based on process names), and start-stop-daemon(8) (based on a pidfile).
To kill all processes matching someproc and wait for them to die:
killall someproc --wait # wait forever until matching processes die
timeout 10s killall someproc --wait # timeout after 10 seconds
(Unfortunately, there's no direct equivalent of --wait with kill for a specific pid).
To kill a process based on a pidfile /var/run/someproc.pid using signal SIGINT, while waiting for it to finish, with SIGKILL being sent after 20 seconds of timeout, use:
start-stop-daemon --stop --signal INT --retry 20 --pidfile /var/run/someproc.pid
Use inotifywait to monitor some file that gets closed, when your process terminates. Example (on Linux):
yourproc >logfile.log & disown
inotifywait -q -e close logfile.log
-e specifies the event to wait for, -q means minimal output only on termination. In this case it will be:
logfile.log CLOSE_WRITE,CLOSE
A single wait command can be used to wait for multiple processes:
yourproc1 >logfile1.log & disown
yourproc2 >logfile2.log & disown
yourproc3 >logfile3.log & disown
inotifywait -q -e close logfile1.log logfile2.log logfile3.log
The output string of inotifywait will tell you, which process terminated. This only works with 'real' files, not with something in /proc/
Rauno Palosaari's solution for Timeout in Seconds Darwin, is an excellent workaround for a UNIX-like OS that does not have GNU tail (it is not specific to Darwin). But, depending on the age of the UNIX-like operating system, the command-line offered is more complex than necessary, and can fail:
lsof -p $pid +r 1m%s -t | grep -qm1 $(date -v+${timeout}S +%s 2>/dev/null || echo INF)
On at least one old UNIX, the lsof argument +r 1m%s fails (even for a superuser):
lsof: can't read kernel name list.
The m%s is an output format specification. A simpler post-processor does not require it. For example, the following command waits on PID 5959 for up to five seconds:
lsof -p 5959 +r 1 | awk '/^=/ { if (T++ >= 5) { exit 1 } }'
In this example, if PID 5959 exits of its own accord before the five seconds elapses, ${?} is 0. If not ${?} returns 1 after five seconds.
It may be worth expressly noting that in +r 1, the 1 is the poll interval (in seconds), so it may be changed to suit the situation.
On a system like OSX you might not have pgrep so you can try this appraoch, when looking for processes by name:
while ps axg | grep process_name$ > /dev/null; do sleep 1; done
The $ symbol at the end of the process name ensures that grep matches only process_name to the end of line in the ps output and not itself.

Check if Mac process is running using Bash by process name

How do you check if a process on Mac OS X is running using the process's name in a Bash script?
I am trying to write a Bash script that will restart a process if it has stopped but do nothing if it is still running.
Parsing this:
ps aux | grep -v grep | grep -c [-i] $ProcessName
...is probably your best bet.
ps aux lists all the currently running processes including the Bash script itself which is parsed out by grep -v grep with advice from Jacob (in comments) and grep -c [-i] $ProcessName returns the optionally case-insensitive integer number of processes with integer return suggested by Sebastian.
Here's a short script that does what you're after:
#!/bin/bash
PROCESS=myapp
number=$(ps aux | grep -v grep | grep -ci $PROCESS)
if [ $number -gt 0 ]
then
echo Running;
fi
EDIT: I initially included a -i flag to grep to make it case insensitive; I did this because the example program I tried was python, which on Mac OS X runs as Python -- if you know your application's case exactly, the -i is not necessary.
The advantage of this approach is that it scales with you -- in the future, if you need to make sure, say, five instances of your application are running, you're already counting. The only caveat is if another application has your program's name in its command line, it might come up -- regular expressions to grep will resolve that issue, if you're crafty (and run into this).
Research the Darwin man pages for ps, grep, and wc.
A shorter solution:
if pgrep $PROCESS_NAME; then
echo 'Running';
fi
Explanation:
pgrep exits with 0 if there is a process matching $PROCESS_NAME running, otherwise it exist with 1.
if checks the exit code of pgrep, and, as far as exit codes go, 0 is success.
Another way is to use (abuse?) the -d option of the killall command. The -d options won't actually kill the process, but instead print what will be done. It will also exit with status 0 if it finds a matching process, or 1 if it does not. Putting this together:
#!/bin/bash
`/usr/bin/killall -d "$1" &> /dev/null`
let "RUNNING = ! $?" # this simply does a boolean 'not' on the return code
echo $RUNNING
To give credit where its due, I originally pulled this technique from a script in the iTunes installer.
This simple command will do the trick. The brackets around the process name prevent the grep command from showing in the process list. Note there is no space after the comma. There may be some portability issues as ps on some unix systems may require a dash before the options:
ps axo pid,command | grep "[S]kype"
The advantage is that you can use the results in an if statement like this:'
if [[ ! $(ps axo pid,command | grep "[i]Tunes.app") ]]; then
open -a iTunes
fi
Or if you prefer this style:
[[ ! $(ps axo pid,command | grep "[S]kype") ]] && open -a Skype || echo "Skype is up"
Another advantage is that you can get the pid by adding a pipe to awk '{print $1}'.
echo "iTunes pid: $(ps axo pid,command | grep "[i]Tunes.app" | awk '{print $1}')"
You can use either killall or kill, depending on if you are trying to find the task by PID or by name.
By Name:
if ! killall -s -0 $PROCESS_NAME >/dev/null 2>&1; then
# Restart failed app, or do whatever you need to prepare for starting the app.
else
at -f $0 +30seconds # If you don't have this on cron, you can use /usr/bin/at
fi
By PID:
if ! kill -0 $PID 2>/dev/null; then
# Restart app, do the needful.
else
at -f $0 +30seconds
fi
If you look at the OSX Manual you will see a different set of process management commands; since it's not the linux kernel, it makes sense that they would manage processes differently.
https://developer.apple.com/library/mac/documentation/Darwin/Reference/ManPages/man1/killall.1.html
A sample output from my terminal (striking out the user and hostname, of course):
user#localhost:~$ kill -0 782 # This was my old, stale SSH Agent.
bash: kill: (782) - No such process
user#localhost:~$ echo $?
1
user#localhost:~$ kill -0 813 # This is my new SSH agent, I only just created.
user#localhost:~$ echo $?
0
The return code from a kill -0 will always result in a safe way to check if the process is running, because -0 sends no signal that will ever be handled by an application. It won't kill the application, and "kill" is only called "kill" because it's usually used to stop an application.
When you look at the interfaces it uses in the source, you'll see that it's actually interacting with the process table directly (and not grepping a potentially loaded output from ps), and just sending a signal to an application. Some signals indicate the application should shutdown or stop, while other signals tell it to restart services, or re-read configuration, or re-open file descriptors to log files that have been recently rotated. There are a plethora of things that "kill" and "killall" can do that doesn't terminate the application, and it's used regularly to simply send a signal to the application.
I lack the reputation to comment on the killall answer above, but there's killall -s for doing it without sending any signals:
killall -s "$PROCESSNAME" &> /dev/null
if [ $? -eq 0 ]; then
echo "$PROCESSNAME is running"
# if you also need the PID:
PID=`killall -s "$PROCESSNAME" | awk '{print $3}'`
echo "it's PID is $PID"
fi
It has for sure!
pgrep, pkill and pfind for OpenBSD and Darwin (Mac OS X)
http://proctools.sourceforge.net
(also available via MacPorts: port info proctools )
pidof by nightproductions.net
I've extended a pidof script found on the net to use regular expressions (usually substrings) and be case insensitive
#!/bin/sh
ps axc |awk "BEGIN{ n=tolower(\"$1\")}\
tolower(\$5) ~n {print \$1}";
just create a script named "pidof" with this content, and put it in you path, i.e. in one of the dirs in
echo $PATH
and make it executable (maybe using sudo)
chmod 755 /usr/local/bin/pidof
and use it like this, of course
kill -9 `pidof pyth`
does Mac have pidof? ...
if pidof $processname >/dev/null ; then echo $processname is running ; fi
Perhaps too late for the OP but this may help others who find this thread.
The following modification of the amrox theme above works well for restarting applications on my OS X:
killall -d TextEdit &> /dev/null && killall TextEdit &> /dev/null; open -a TextEdit
I use the following AppleScript to update and restart daemons:
tell application "System Events" to set pwd to POSIX path of container of (path to me)
do shell script "launchctl unload -w /Library/LaunchDaemons/time-test.plist; cp -f " & quoted form of pwd & "/time-test.plist /Library/LaunchDaemons; launchctl load -w /Library/LaunchDaemons/time-test.plist" with administrator privileges
It assumes the original or updated plist file is in the same directory as the AppleScript.

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