How do you check if a process on Mac OS X is running using the process's name in a Bash script?
I am trying to write a Bash script that will restart a process if it has stopped but do nothing if it is still running.
Parsing this:
ps aux | grep -v grep | grep -c [-i] $ProcessName
...is probably your best bet.
ps aux lists all the currently running processes including the Bash script itself which is parsed out by grep -v grep with advice from Jacob (in comments) and grep -c [-i] $ProcessName returns the optionally case-insensitive integer number of processes with integer return suggested by Sebastian.
Here's a short script that does what you're after:
#!/bin/bash
PROCESS=myapp
number=$(ps aux | grep -v grep | grep -ci $PROCESS)
if [ $number -gt 0 ]
then
echo Running;
fi
EDIT: I initially included a -i flag to grep to make it case insensitive; I did this because the example program I tried was python, which on Mac OS X runs as Python -- if you know your application's case exactly, the -i is not necessary.
The advantage of this approach is that it scales with you -- in the future, if you need to make sure, say, five instances of your application are running, you're already counting. The only caveat is if another application has your program's name in its command line, it might come up -- regular expressions to grep will resolve that issue, if you're crafty (and run into this).
Research the Darwin man pages for ps, grep, and wc.
A shorter solution:
if pgrep $PROCESS_NAME; then
echo 'Running';
fi
Explanation:
pgrep exits with 0 if there is a process matching $PROCESS_NAME running, otherwise it exist with 1.
if checks the exit code of pgrep, and, as far as exit codes go, 0 is success.
Another way is to use (abuse?) the -d option of the killall command. The -d options won't actually kill the process, but instead print what will be done. It will also exit with status 0 if it finds a matching process, or 1 if it does not. Putting this together:
#!/bin/bash
`/usr/bin/killall -d "$1" &> /dev/null`
let "RUNNING = ! $?" # this simply does a boolean 'not' on the return code
echo $RUNNING
To give credit where its due, I originally pulled this technique from a script in the iTunes installer.
This simple command will do the trick. The brackets around the process name prevent the grep command from showing in the process list. Note there is no space after the comma. There may be some portability issues as ps on some unix systems may require a dash before the options:
ps axo pid,command | grep "[S]kype"
The advantage is that you can use the results in an if statement like this:'
if [[ ! $(ps axo pid,command | grep "[i]Tunes.app") ]]; then
open -a iTunes
fi
Or if you prefer this style:
[[ ! $(ps axo pid,command | grep "[S]kype") ]] && open -a Skype || echo "Skype is up"
Another advantage is that you can get the pid by adding a pipe to awk '{print $1}'.
echo "iTunes pid: $(ps axo pid,command | grep "[i]Tunes.app" | awk '{print $1}')"
You can use either killall or kill, depending on if you are trying to find the task by PID or by name.
By Name:
if ! killall -s -0 $PROCESS_NAME >/dev/null 2>&1; then
# Restart failed app, or do whatever you need to prepare for starting the app.
else
at -f $0 +30seconds # If you don't have this on cron, you can use /usr/bin/at
fi
By PID:
if ! kill -0 $PID 2>/dev/null; then
# Restart app, do the needful.
else
at -f $0 +30seconds
fi
If you look at the OSX Manual you will see a different set of process management commands; since it's not the linux kernel, it makes sense that they would manage processes differently.
https://developer.apple.com/library/mac/documentation/Darwin/Reference/ManPages/man1/killall.1.html
A sample output from my terminal (striking out the user and hostname, of course):
user#localhost:~$ kill -0 782 # This was my old, stale SSH Agent.
bash: kill: (782) - No such process
user#localhost:~$ echo $?
1
user#localhost:~$ kill -0 813 # This is my new SSH agent, I only just created.
user#localhost:~$ echo $?
0
The return code from a kill -0 will always result in a safe way to check if the process is running, because -0 sends no signal that will ever be handled by an application. It won't kill the application, and "kill" is only called "kill" because it's usually used to stop an application.
When you look at the interfaces it uses in the source, you'll see that it's actually interacting with the process table directly (and not grepping a potentially loaded output from ps), and just sending a signal to an application. Some signals indicate the application should shutdown or stop, while other signals tell it to restart services, or re-read configuration, or re-open file descriptors to log files that have been recently rotated. There are a plethora of things that "kill" and "killall" can do that doesn't terminate the application, and it's used regularly to simply send a signal to the application.
I lack the reputation to comment on the killall answer above, but there's killall -s for doing it without sending any signals:
killall -s "$PROCESSNAME" &> /dev/null
if [ $? -eq 0 ]; then
echo "$PROCESSNAME is running"
# if you also need the PID:
PID=`killall -s "$PROCESSNAME" | awk '{print $3}'`
echo "it's PID is $PID"
fi
It has for sure!
pgrep, pkill and pfind for OpenBSD and Darwin (Mac OS X)
http://proctools.sourceforge.net
(also available via MacPorts: port info proctools )
pidof by nightproductions.net
I've extended a pidof script found on the net to use regular expressions (usually substrings) and be case insensitive
#!/bin/sh
ps axc |awk "BEGIN{ n=tolower(\"$1\")}\
tolower(\$5) ~n {print \$1}";
just create a script named "pidof" with this content, and put it in you path, i.e. in one of the dirs in
echo $PATH
and make it executable (maybe using sudo)
chmod 755 /usr/local/bin/pidof
and use it like this, of course
kill -9 `pidof pyth`
does Mac have pidof? ...
if pidof $processname >/dev/null ; then echo $processname is running ; fi
Perhaps too late for the OP but this may help others who find this thread.
The following modification of the amrox theme above works well for restarting applications on my OS X:
killall -d TextEdit &> /dev/null && killall TextEdit &> /dev/null; open -a TextEdit
I use the following AppleScript to update and restart daemons:
tell application "System Events" to set pwd to POSIX path of container of (path to me)
do shell script "launchctl unload -w /Library/LaunchDaemons/time-test.plist; cp -f " & quoted form of pwd & "/time-test.plist /Library/LaunchDaemons; launchctl load -w /Library/LaunchDaemons/time-test.plist" with administrator privileges
It assumes the original or updated plist file is in the same directory as the AppleScript.
Related
So I've looked up other questions and answers for this and as you can imagine, there are lots of ways to find this. However, my situation is kind of different.
I'm able to check whether a bash script is already running or not and I want to kill the script if it's already running.
The problem is that with the below code, -since I'm running this within the same script- the script kills itself too because it sees a script already running.
result=`ps aux | grep -i "myscript.sh" | grep -v "grep" | wc -l`
if [ $result -ge 1 ]
then
echo "script is running"
else
echo "script is not running"
fi
So how can I check if a script is already running besides it's own self and kill itself if there's another instance of the same script is running, else, continue without killing itself.
I thought I could combine the above code with $$ command to find the script's own PID and differentiate them this way but I'm not sure how to do that.
Also a side note, my script can be run multiple times at the same time within the same machine but with different arguments and that's fine. I only need to identify if script is already running with the same arguments.
pid=$(pgrep myscript.sh | grep -x -v $$)
# filter non-existent pids
pid=$(<<<"$pid" xargs -n1 sh -c 'kill -0 "$1" 2>/dev/null && echo "$1"' --)
if [ -n "$pid" ]; then
echo "Other script is running with pid $pid"
echo "Killing him!"
kill $pid
fi
pgrep lists the pids that match the name myscript.sh. From the list we filter current $$ shell with grep -v. It the result is non-empty, then you could kill the other pid.
Without the xargs, it would work, but the pgrep myscript.sh will pick up the temporary pid created for command substitution or the pipe. So the pid will never be empty and the kill will always execute complaining about the non-existent process. To do that, for each pid in pids, I check if the pid exists with kill -0. If it does, then it is outputted, effectively filtering all nonexistent pids.
You could also use a normal for loop to filter the pids:
# filter non-existent pids
pid=$(
for i in $pid; do
if kill -0 "$i" 2>/dev/null; then
echo "$i"
fi
done
)
Alternatively, you could use flock to lock the file and use lsof to list current open files with filtering the current one. As it is now, I think it will kill also editors that are editing the file and such. I believe the lsof output could be better filtered to accommodate this.
if [ "${FLOCKER}" != "$0" ]; then
pids=$(lsof -p "^$$" -- ./myscript.sh | awk 'NR>1{print $2}')
if [ -n "$pids" ]; then
echo "Other processes with $(echo $pids) found. Killing them"
kill $pids
fi
exec env FLOCKER="$0" flock -en "$0" "$0" "$#"
fi
I would go with either of 2 ways to solve this problem.
1st solution: Create a watchdog file lets say a .lck file kind of on a location before starting the script's execution(Make sure we use trap etc commands in case script is aborted so that .lck file should be removed) AND remove it once execution of script is completed successfully.
Example script for 1st solution: This is just an example a test one. We need to take care of interruptions in the script, lets say script got interrupted by a command or etc then we could use trap in it too, since at that time it would have not been completed but you may need to kick it off again(since last time it was not completed).
cat file.ksh
#!/bin/bash
PWD=`pwd`
watchdog_file="$PWD/script.lck"
if [[ -f "$watchdog_file" ]]
then
echo "Please wait script is still running, exiting from script now.."
exit 1;
else
touch $watchdog_file
fi
while true
do
echo "singh" > test1
done
if [[ -f "$watchdog_file" ]]
then
rm "$watchdog_file"
fi
2nd solution: Take pid of current running shell using $$ save it in a file. Then check if that process is still running come out of script if NOT running then move on to run statements in script.
I want to stall the execution of my script until a process is closed (I have the PID stored in a variable).
#!/bin/bash
outputl=$( ps -ef | grep $var4 | awk '{print $2}' ) >> $logfile
while [ "ps -p $outputl" ] > /dev/null;
do
sleep 1;
done
echo "Stopped $instance" >> $logfile
//command...
It stays in the "while" and not continue whit script.
This line:
while [ "ps -p $output1" ]
does not execute the ps command. It simply tests whether the string "ps -p $output1" is not empty, and it obviously isn't. To test the output of a command, use $():
while [ "$(ps -p "$output1")" ]
But since ps produces a header, this will always be true. The best way to test if a PID exists is to use the kill command with signal 0; this doesn't actually send a signal, it just tests whether it's possible to send a signal. I'm assuming this code is being run either by root or the userid running the application being checked. So you can write:
while kill -0 "$output1" 2>/dev/null
Also, your code for getting the PID into $output1 is wrong. ps -ef will also include the grep command, which matches the name you're looking for, so you need to filter that out. Use:
output1=$(ps -ef | grep "$var4" | awk '!/grep/ { print $2 }')
Redirecting the output to $logfile is not necessary, since variable assignments don't print anything.
Many systems have a pgrep command, which can be used by itself to test if a process with a given name exists; if you have this, you can use it instead of reinventing the wheel (and if not, you should be able to install it).
If you have the PID then just wait for it to complete. Try:
outputl=$( ps -ef | awk -v v="$var4" '$0~v{print $2}' )
wait "$outputl"
echo "Stopped $instance" >> $logfile
then look for a better way to find the pid in the first line.
I'm currently creating a lock folder which is created when my script runs, I also move files into sub folders here for processing. When the script ends a TRAP is called which removes the lock folder and contents, all of which is working fine. We had an issue the other day when someone pulled the power from one of the servers so my TRAP was never called so when re-booted the lock folder was still there which meant my scripts couldn't re-start until they were manually removed. What's the best way of checking if the script is already running ? I currently have this approach using process id's:
if ! mkdir $LOCK_DIR 2>/dev/null; then # Try to create the lock dir. This should pass successfully first run.
# If the lock dir exists
pid=$(cat $LOCK_DIR/pid.txt)
if [[ $(ps -ef | awk '{print $2}' | grep $pid | grep -v grep | wc -l) == 1 ]]; then
echo "Script is already running"
exit 1
else
echo "It looks like the previous script was killed. Restarting process."
# Do some cleanup here before removing dir and re-starting process.
fi
fi
# Create a file in the lock dir containing the pid. Echo the current process id into the file.
touch $LOCK_DIR/pid.txt
echo $$ > $LOCK_DIR/pid.txt
# Rest of script below
Checking /proc/ and cmdline is a good call - especially as at the moment you are simply checking that there isn't a process with the process id and not if the process is actually your script.
You could still do this with your ps command - which would offer some form of platform agnosticism.
COMMAND=$(ps -o comm= -p $pid)
if [[ $COMMAND == my_process ]]
then
.....
Note the command line arguments to ps limit it to command only with no header.
Many systems nowadays use tmpfs for directories like /tmp. These directories will therefore always be cleared after a reboot.
If using your pid file, note you can easily see the command
running under that pid in /proc/$pid/cmdline and /proc/$pid/exe.
I would to know if it's possible to detect if amarok is playing music or not, in bash.
I have tested
#! /bin/bash
if [ "$(pidof amarok --play)" ]
then
echo amarok is playing music!
else
echo amarok is not playing!
fi
But I have this error:
pidof: invalid options on command line!
pidof thinks that --play is its option, and that is of course an error.
It would be better to check if --play is inside the commandline that was used to start amarok:
grep -- --play /proc/$(pidof amarok)/cmdline
Another option is to grep output of ps aux:
ps aux | grep [a]marok.*--play
In the both cases we suppose that there only one amarok running in the system.
Update 1.
To check if any music is playing at the moment,
you can so:
grep RUNNING /proc/asound/card*/pcm*/sub*/status
I'm writing a unix shell script and need to check if there are currently running processes with "xyz" in their directory. If yes than continue to next command and show text like "Found It".
If not than don't continue and display text like "Process Not Found".
I tried something like this:
if ps -ef | grep xyz
then
echo "XYZ Process Found!"
else
echo "XYZ Process Not Found!"
fi
But it just showing me the processes and display "process found" even if there's no xyz process.
I believe you want to check the output of the command against a value using Command substition, from the linked bash-hackers wiki The command substitution expands to the output of commands. These commands are executed in a subshell, and their stdout data is what the substitution syntax expands to. Also, count the lines and remove grep. Something like,
if [[ $(ps -ef | grep xyz | grep -v grep | wc -l) != 0 ]]; then
echo "XYZ Process Found!"
else
echo "XYZ Process Not Found!"
fi
Edit
Based on the comments below, you should probably use
if [[ $(ps -ef | grep -c xyz) -ne 1 ]]; then
which is a lot easier to read.
When you run grep xyz, that process - grep xyz - is also running & thus shown in the output of ps -ef.
This running process command line contains xyz. Thus grep passes that line to output.
Hence you always get zero exit status - i.e. success.
2 Solutions:
use if ps -ef | grep '[x]yz'; then. (You may want to suppress grep output with -q)
The grep command being run is grep [x]yz. This gets printed in ps -ef output.
Obviously, grep filters out this line. [x]yz could be matched with \[x\]yz, not with [x]yz.
use if pgrep -f xyz >/dev/null; then
Check man pgrep for more details..
You can also use pgrep. From pgrep(1):
pgrep looks through the currently running processes and lists the
process IDs which match the selection criteria to stdout.
[...]
EXIT STATUS
0 One or more processes matched the criteria.
1 No processes matched.
2 Syntax error in the command line.
3 Fatal error: out of memory etc.
Example output:
[~]% pgrep xterm
18231
19070
31727
You can use it in an if statement like so:
if pgrep xterm > /dev/null; then
echo Found xterm
else
echo xterm not found
fi
Note: pgrep is not a standard utility (ie. it's not in POSIX), but widely available on at least Linux and I believe most BSD systems.
is_xyz_running() {
[ "$(pgrep xyz)" ] && echo true || echo false
}