I have 8 labels named Labelf1, Labelf2 and so on. Now inside a while do loop, that counts from 1 to 8 I want to assign a Caption to the label corresponding to the number the loop is at.
E.g.: the counting variable is i, then I would need to do something like Labelf<i>.Caption := String.
How would I be able to do this?
Related
I am trying to add the user inputs using a while loop and If statements. I am having trouble figuring out how to add all the userNumbers to each other. Any help would be appreciated.
//variables
Declare Integer userIn = 0
Declare Integer total = 0
//read numbers and calculate
While decision == decY
Display “Please enter your numbers: ”
Input decision
If UserIn > 0
Display userNumbers
Set total = userIn + 1
Display “Would you like to enter another number Y/N?”
Input decision
If decision == decN
Display “Done reading numbers, your total is ”, total
End If
End If
End While
Decide on a separator for the input, unless they're only allowed to enter a single number at a time in which case you can skip to 3.
Use string splitting to cut the input up and then loop through that list with for, while, do, until, or etc.
Create a sum total variable and add each input value to it, e.g. sum = sum + split_input[index], or if it will only allow a single input at a time sum = sum + input.
Some Notes:
Adding a value to a variable can be shortened to variable += value to add a value to an existing variable and assign the result to the variable, but not all languages support this syntax.
Not all programming languages start at 0 for list indices, so be sure to change the starting index accordingly.
I have a list of values that range anywhere from 500-1000. I have a second list of values that denote relevant breakpoints in the 500-1000 range (500, 520, 540, 600, etc). I need to return the highest value in the second list that is less than the value in a given number from the first list. I noticed the "N" functions let you set a conditional on them, so for example if I do:
List.Max(List.FirstN(SomeTable[Breakpoints], each _ < 530))
It correctly returns 520 to me. However if I put this inside an AddColumn function and change the 530 to a local field reference:
Table.AddColumn(MyTable, "MinValue", each List.Max(List.FirstN(SomeTable[Breakpoints], each _ < [SomeNumbers])))
Then I get a "We cannot apply field access to the type Number" error. Is what I'm trying to do possible and I'm just formatting it wrong? I always get confused with scope and references in PQ, so it may just be that.
After each, [SomeNumbers] by itself is short for _[SomeNumbers] (which is what you see when filtering a column). In the List.FirstN call, _ refers to a number in the list instead of a row in a table: the value of _ is tied to the closest each, where closeness is measured by the number of layers of nesting between _ and the appearance of each . Therefore, in your code [SomeNumbers] is trying to find the column SomeNumbers on a number, which doesn't exist.
There are a couple ways to fix this:
You can use a let...in statement to store the current value of the SomeNumbers column to use it for later, like so:
each
let
currentNumber = [SomeNumbers],
result = List.Max(List.FirstN(SomeTable[Breakpoints], each _ < currentNumber))
in
result
You can explicitly define a function with the (x) => ... syntax instead of using each twice, like so:
each List.Max(List.FirstN(SomeTable[Breakpoints], (point) => point < [SomeNumbers]))
so this is what I'm trying to do, and I'm not sure how cause I'm new to python. I've searched for a few options and I'm not sure why this doesn't work.
So I have 6 different nodes, in maya, called aiSwitch. I need to generate random different numbers from 0 to 6 and input that value in the aiSiwtch*.index.
In short the result should be
aiSwitch1.index = (random number from 0 to 5)
aiSwitch2.index = (another random number from 0 to 5 different than the one before)
And so on unil aiSwitch6.index
I tried the following:
import maya.cmds as mc
import random
allswtich = mc.ls('aiSwitch*')
for i in allswitch:
print i
S = range(0,6)
print S
shuffle = random.sample(S, len(S))
print shuffle
for w in shuffle:
print w
mc.setAttr(i + '.index', w)
This is the result I get from the prints:
aiSwitch1 <-- from print i
[0,1,2,3,4,5] <--- from print S
[2,3,5,4,0,1] <--- from print Shuffle (random.sample results)
2
3
5
4
0
1 <--- from print w, every separated item in the random.sample list.
Now, this happens for every aiSwitch, cause it's in a loop of course. And the random numbers are always a different list cause it happens every time the loop runs.
So where is the problem then?
aiSwitch1.index = 1
And all the other aiSwitch*.index always take only the last item in the list but the time I get to do the setAttr. It seems to be that w is retaining the last value of the for loop. I don't quite understand how to
Get a random value from 0 to 5
Input that value in aiSwitch1.index
Get another random value from 0 to 6 different to the one before
Input that value in aiSwitch2.index
Repeat until aiSwitch5.index.
I did get it to work with the following form:
allSwitch = mc.ls('aiSwitch')
for i in allSwitch:
mc.setAttr(i + '.index', random.uniform(0,5))
This gave a random number from 0 to 5 to all aiSwitch*.index, but some of them repeat. I think this works cause the value is being generated every time the loop runs, hence setting the attribute with a random number. But the numbers repeat and I was trying to avoid that. I also tried a shuffle but failed to get any values from it.
My main mistake seems to be that I'm generating a list and sampling it, but I'm failing to assign every different item from that list to different aiSwitch*.index nodes. And I'm running out of ideas for this.
Any clues would be greatly appreciated.
Thanks.
Jonathan.
Here is a somewhat Pythonic way: shuffle the list of indices, then iterate over it using zip (which is useful for iterating over structures in parallel, which is what you need to do here):
import random
index = list(range(6))
random.shuffle(index)
allSwitch = mc.ls('aiSwitch*')
for i,j in zip(allSwitch,index):
mc.setAttr(i + '.index', j)
As homework, I must swap letters in a given string. I already figured out how to do this, but not how to display them at once. it involves a for loop. so if I include disp x in the for loop, it displays them between parentheses and a space, but I want them all together, so instead of
"a"
"b"
"c"
I want "abc". Is there a way to do this? Should I push the variable into an array and then display the array after the for loop? How to push variables in to an array?
This is in TI-Nspire CX Cas btw.
To add an element x to an array A use augment(A, {x}).
For your specific case, I would use a string variable (call it string) to which I concatenate the next letter at each iteration of the for loop. So if the next letter to be added is in the variable letter, you would put the following line of code at the end of your for loop: string := string & letter.
here is also way:
Local array
array[dim(array)+1] := value
I would answer you by an example covering your scenario. Let's say we are aiming to have a array listing the elements of binaries when we construct an integer into the base2 (binary).
Define LibPub develope(a,b)=
Func
Local mi,m,q
mi:=mod(a,b)
q:=((a-mi)/(b))
Disp mi
While q≥b
a:=q
m:=mod(a,b)
q:=((a-m)/(b))
Disp m
EndWhile
EndFunc
The above small program develops an integer in decimal base into the binary base; however each binary is shown in a separate line as you mentioned:
ex:
develope(222,2)
0
1
1
1
1
0
1
enter image description here
but this is not what you want, you want is in a single line. IMPORTANCE IS THAT YOU SHOULD LIKELIHOOD WANT EACH ELEMENT BE ACCESSIBLE AS A SEPARATE INTEGER, RIGHT? LIKE AS AN ELEMENT IN A ARRAY LIST, THAT'S WHAT YOU LOOKING FOR RIGHT?
There we Go:
Define LibPub develope(n,b)=
Func
Local q,k,seti,set,valid
valid:=b
If valid>1 Then
q:=n
k:=0
set:={}
While q≠0
seti:=mod(q,b)
q:=int(((q)/(b)))
k:=k+1
seti→set[k]
EndWhile
Else
Disp "Erreur, La base doit être plus grand que 1."
EndIf
Return set
EndFunc
Basically, because we do not know how many elements are going to be added in the array list, the set:={} declares an array with an undefined dim (typically length) in order that dynamically be augmented.
The command seti→set[k] will add the value of the seti whatever it is, into the k position of the array list.
and the return set simply returns the array.
if you need to get access to a specific element, you know how to to that: elementNumber5:=set[5]
I wish it helps.
I'm executing a template with 2 parallel arrays (same size) and I want to list items from both arrays in parallel, how do I use index inside of range?
this obviously doesn't work:
{{range $i, $e := .First}}$e - {{index .Second $i}}{{end}}
One of the predefined global template functions is index.
index Returns the result of indexing its first argument by the
following arguments. Thus index x 1 2 3 is, in Go syntax,
x[1][2][3]. Each indexed item must be a map, slice, or array.
So you are on the right track. The only issue is that you are not accounting for the fact the dot has been reassigned within the range block.
So you need to get back to the original dot, for that we have the following
When execution begins, $ is set to the data argument passed to Execute, that is, to the starting value of dot.
So (assuming there is nothing else going on in your template) you should be able to do:
{{range $i, $e := .First}}$e - {{index $.Second $i}}{{end}}
Personally though, I would create a template function called zip that accepts multiple slices and returns a slice of each pair of values. It would look cleaner in your template and probably get reused somewhere.