why does my LG L40 d170 modem not show the final result code?
ex.
AT
OK
AT+CGMI
LG Electronics
Shouldn't it be like this?
AT
OK
AT+CGMI
LG Electronics
OK
i tried 'ATV1' and 'ATQ1', but AFAIK, those are by default.
I cannot say why, but your expectations are correct. If it actually does not give a final result code that is an extremely serious error.
Assuming that the implementation of the AT+CGMI command is just wrong and does not issue a final result code, I will suggest sending a command line with one (or more) command following +CGMI that hopefully will trigger sending a final result code at the end of processing the command line, e.g.
AT+CMGI; V1
Related
All log in this area is not printed (showing inside it's not running). However the last line is execute anyway. I'm so frustrated and sad, totally had no idea. Many thanks if there's any idea on it.
if !reflect.DeepEqual(MachineNow.TCP_machine.Two_D_Dta_Old, twoD_new) {
//the situation should not be executed
log.Println("new to old updated") //all log is not printing (O)
fmt.Println("new", twoD_new[0][0])
fmt.Println("old", MachineNow.TCP_machine.Two_D_Dta_Old[0][0])
MachineNow.TCP_machine.Two_D_Dta_Old = twoD_new //this line is doing anyway (X)
}
Have you checked your “log” output and level?
Maybe you set the output level to be higher than “Println”, so it’s simply ignored.
Try to use debug to know if this runs into this code block or just your assumption.
One more thing to check is: that if you run it by unit test, you need to add the “-v” flag to show output.
Solution: I trasform the object into JSON format and assign to the object. I don't know why but this is the only way to avoid execute that line no matter what. I thought it was just a mistake, now seems that line was indeed executed for unknown reason. it was running windows x64.
new_json, _ := json.Marshal(twoD_new)
_ = json.Unmarshal([]byte(new_json), &MachineNow.TCP_machine.Two_D_Dta_Old)
I have a predicate check(Data,Res) that checksDats according to some rules and returns Res (a function result on Data, assuming Data answers to several criteria).
I have another function generate(N,Data) which generates a N-size Data.
My main program begins with generating many 1-size Data, then if none answered the criteria, we go on to 2-size Data and so on until we reach a certain M upper limit.
main(M):- next_number(N,M), generate(N,Data), check(Data,Res).
However, the program runs for very long time. I wanted to make sure it does not get stuck. For this, I wanted to print the generated Data each time before its being checked. But adding display did not assist, because it only actually displayed if the entire statement was true.
That's not what I want.
I want to keep track of the progran using display, similarly to System.out.println in Java.
Is there any other function that displays anyway? Or an idea how to use display in a way that will always display, regardless if the Data answered the criteria or not?
I thought to do:
(check(Data,Res) -> display(Data);display(Data)).
But I am not sure. Any ideas?
Your long process is likely to be within check - or more precisely, that check fails for most data, causing the system to backtrack repeatedly.
If you display a result in check, you'll have line upon line of tracing. Instead, you could add a write statement to generate, or even to your number generation:
main(M):-
next_number_and_tick(N,M),
generate(N,Data),
check(Data,Res).
next_number_and_tick(N,M) :-
next_number(N,M),
write('Tick - now doing '),
writeln(N).
Upon backtracking, the program will signal the data size it is now working on, giving you an idea of the volume of work it is doing.
The problem in the way you use display is that the entire statement must be true for it to display. Your idea of using "if-then" is good but not accurate. If you want to use it, you should "trick" prolog the following way:
new_check(Data,Res) :- (check(Data,Res) -> display('Victory!'),!; display('Failed Data: '), display(Data), nl, fail).
This way, if the check fails, you will get a report on which Data failed, and if it succeeded everything stops (assuming you want only 1 solution. If you want more, remoce the ! predicate).
Part of my project is to design a 16bit Multiplier with an arrayMultiplier structure. In this array Multiplier instead of using 1 bit adders, I made a 16bit Adder (which is working, I've done simulations). I'm using it as a component in the multiplier.
Note I have attach my last name to every variable according to the professor, please ignore that
I have to put it into a pastebin cause it's too long for posting. Please ignore the comments that say like +16, FA, -1. This is for me to just follow a diagram for proper indexing.
This is an example diagram
https://d2vlcm61l7u1fs.cloudfront.net/media%2F27b%2F27b41d2f-aa6c-4a81-bdc0-16ff1c681fc7%2FphpQ0V3VI.png
**REDACTED **
Third is the error itself
Code Redacted
https://pastebin.com/tZ6ptLYp
I'm not sure what the error is saying so I can't solve the issue. Been working on this for hours so maybe I'm just tired and am not seeing it. Thanks
The problem is that you bind multiple wires to the same output wire.
For example :
Line 57 : ... Arena_16bitOUT_Cout_fa => Arena_Cout_vec(0) ...
Line 61 : ... Arena_16bitOUT_Cout_fa => Arena_Cout_vec(0));
I guess it is just copy/paste errors. I did not read all the logic but if it is not the case, you will need some multiplexing logic.
I made a program that is similar to clearing RAM. However, it always leaves a "Done" message followed by a dotted line after being executed. In addition, if you scroll up, you can see that the program was executed. Is there a way to remove both of these things? If you can't hide the fact that a program was executed, could you suppress the 'Done' message?
I have tried adding ClearHome" and " as the last line of my program, and neither stops the Done message from displaying.
Bonus points if your solution can be contained within the original program.
In a separate program, type the following line of code:
AsmPrgmFDCB00AEC9
Then at the end of the original program, type the following line of code:
Asm(prgmPROGRAMNAME
It is recommended that you test this out first with all programs archived, just running the above line of code alone, in case it fails. Hex codes like that one have been known to fail, and sometimes clears the RAM.
You can also try these other hex codes, but always keep in mind the warning above. My RAM has been cleared by this before, so use caution:
http://tibasicdev.wikidot.com/hexcodes
This works on TI 83 and 84, may be different with other calculator types.
EDIT:
I found a way to do this without an external program, and is much simpler.
Just add the following line of code to the end of your program:
Output(1,1," //no space, just a quote
You may or may not have to add ClrHome before that line of code.
This should prevent the Done message from appearing at the end.
Hope this helps!
Put an empty string at the end of your program, so your last line looks like this:
""
Or this
"
The empty string is stored to ans and will be displayed as a blank line rather than the Done message.
There is also an assembly hexcode to do this without leaving the blank line at the top:
FDCB00AEC9
When run at the end of the program using one of the various methods of running assembly, it will leave you with a blank, fully operational homescreen.
Outputting an empty string will prevent the Done message and also preserve Ans, in case a calling program is expecting to use it.
Output(Y,X,"")
See http://tibasicdev.wikidot.com/output for more details on Output(.
In your situation, run Clear Entries (found under Mem), then scroll up so that the Done message is selected and press Clear to get rid of it.
I'm currently working with a software called CleGo , which is written in O'Caml and I use it in the Toplevel mode. This program computes all Clebsch-Gordan coefficients for a given group representation. Unfortuantely, I can't get the complete output in the terminal. I get:
[[[("-1", ("(0,0,0,0,0,0,1,0,)1", "(0,0,0,0,0,0,-1,0,)1"));
("1", ("(0,0,0,0,0,1,-1,0,)1", "(0,0,0,0,0,-1,1,0,)1"));
("-1", ("(0,0,0,0,1,-1,0,0,)1", "(0,0,0,0,-1,1,0,0,)1"));
...]]]
and I need the complete output that is indicated by "..." in the output. Is there some terminal restrictions that restricts the output to a certain length or is this a special problem of the software?
Any ideas or suggestions would be awesome!