laravel eloquent get table 1 based on search of table 2 - laravel-5

FIXED
So after many responses to this question I finally got my real question thought out and answered but it still leaves me wondering why eloquent can't handle the issue of
A->B->C
Given an object of A accessing all B items based on a value within C (name=script)
The below solution works and because laravel has scopes keeps things clean but I feel like there should be a easier and faster solution.
public function scopeType($query, $type)
{
return $query->join('article_image_types', 'article_image_types.id', '=', 'article_images.article_image_type_id')->where('name', $type);
}
if you have two tables image and image_type and I want to find all images with a specific type what would that look like in eloquent?
Say you have a type of "script" with id "1" I know I can do, from the image collection
where('image_type_id', '1')
but how would i do it so the below worked
where('name', 'script')
GOAL:
I want to be able to access this data easily from a blade file so something like the below using a scope
<input type="text" name="['image']['script']" value="{!! $article->articleimage()->type('script') !!}">
or even better accessing the images based on type through form model binding ['image']['script']
So this works
foreach($article->articleImages->all() as $item) {
dd($item->articleimagetype->name);
}
and will return "script"
But how do get only the one that says "script"
::UPDATE::
So I setup the scope but as I expected the problem I am trying to do this based on the secondary tables name so
$query->where('name', $type);
your solution would work if I wanted to do
$query->where('image_type_id', 1);
SQLSTATE[42S22]: Column not found: 1054 Unknown column 'name' in
'where clause' (SQL: select * from article_images where
article_images.article_id = 32 and article_images.article_id
is not null and name = script)
UPDATE
So doing the below produces what I want EXCEPT I don't get back a type name and i can't seem to get it back with has('articleimagetype') or has('articleimages.articleimagetype')
$article->articleImages()->whereHas('articleimagetype', function($query){
$query->where('name', 'script');
})->has('articleimagetype')->get();

Just use join:
\DB::table('image')
->join('image_type','image_type.id','=', 'image.image_type_id')
->where('image_type.name','=','script')
->get();
EDIT:
after your GOAL update, I see what you want. Laravel has a feature named query scope that will let you easily find the data the way you are trying to.
In your Articleimage model, create a scope:
public function scopeType($query, $type)
{
return $query->join('article_image_type','article_image_type.id','article_image.type_id')
->where('type', $type);
}
Then you can do $article->articleimage()->type('script').

Related

Get data on relation 'B' where relation 'A' does not exits in same id in laravel eloquent

I have two tables named "Student" and "Subscription". If there is at least one active plan in the subscription database, I check by date. I need to get the data if no plan is active. Below is the code I used to get the data. But this is wrong because in this query I am getting all the expired data and I should get the data only if there is not even one plan active in the student id.
$expired_student = Student::wherehas('getSubscription', function ($query) use ($current_date){
$query->where('expired_at','<',$current_date);
})->where('status',1)->count();
anyone can please help me to solve this problem
In you Student model, you can define a relationship method called activeSubscriptions, like this:
public function activeSubscriptions() {
return $this->hasMany(Subscription::class)->where(function($query) {
$query->whereNull('expired_at')->orWhere('expired_at', '>', now());
});
}
And you can use this function like this:
$expiredStudents = Student::doesntHave('activeSubscriptions')->get();

Eloquent with diferent relationships for same table

i need some hints and what is the best way and pratice with laravel to solve this problem!
I have a main table called colors with the fields category_id and type and i have in my models 2 relationships for the category_id, the bluecategory and redcategory.
In some cases i use the id from bluecategory and in other exemples i use the redcategory id.
Now in one page i want to shows all the results from colors, but i can't do this $data->bluecategory or $data->redcategory because i dont'no what record is using what relationship.
My ideia was using a function to send parameters category_id and type and inside the function discover what is the correspondente relashion and return the correct result.
But how i can handle this?
Sorry its a bit confuse!
You could add a scope to your modal and than chain it to your existing query.
Example
public function scopeName($query, $catID, $type)
{
return $query->where('category_id, $catID)
->where('type', $type);
}

How to know what columns are presents in a Eloquent query before to execute it in Laravel 5.5?

Im using Laravel 5.5 and I have and QueryBuilder object (from the "Illuminate/Database/Eloquent/Builder" class).
I want to set an orderBy sentence into my query, but only if this field is present and exists in the QueryBuilder object (as column in the select section sentence).
For example, there is an User model, with the following fields ['id', 'firtsname', 'lastname', 'username','description'].
This is my object:
Use App\User;
$query = User::query();
if ($request->input('sort') != null) {
$model_query->orderBy($request->input('sort'), 'ASC');
}
$users = $query->get();
When I execute it, works fine (if I send you consistent data, of course). But if I set a column what does not exists, it sends and exception. So, the question is, how I can get the columns to retrieve from my $query object? To validate it, and if it's presents, execute the ordening code.
To answer your question, you can get the presence status of a column using Schema::hasColumn()
if (Schema::hasColumn('users', $request->sort)) {
//
}
GOING FURTHER
Now this doesn't seem very efficient, and maybe potentially leak data. Better validating your sort input and accept only proper column names:
$request->validate(['sort' => 'in:column1,column2']);

Wrong ID returned from local Eloquent scope

In my Laravel project I've got a model (and an underlying table) for lessons. Now I'm trying to write a local scope for returning all lessons that have been finished by a particular user. The definition of "finished" is that there exists a row in a table named "lesson_results" with this lesson's ID and the users ID.
My scope currently looks like this:
public function scopeFinished($query, User $user)
{
return $query->join('lesson_results', function($join) use($user)
{
$join->on('lesson_results.lesson_id', '=', 'lessons.id')
->where("user_id", $user->id);
});
}
This kinda works. When I do a Lesson::finished($user)->get() I get out the correct lessons for that user. However the lessons in the collection returned all have the wrong ID's! The ID's I see are the ID's from the lesson_results table. So when I check $lesson->id from one of the returned items I don't get the ID from that lesson, but the ID from the corresponding row in the lesson_results table.
I've checked in mysql and the full query sent from Laravel is the following
select * from `lessons` inner join `lesson_results` on `lesson_results`.`lesson_id` = `lessons`.`id` and `user_id` = 53
This query DO return two columns named id (the one from the lessons table and the one from the lesson_results table) and it seems Laravel is using the wrong one for the result returned.
I don't know if I'm going about this the wrong way or if it's a bug somewhere?
This is on Laravel 7.6.1.
edit: Ok, I think I actually solved it now. Not really sure though if it's a real solution or just a workaround. I added a select() call so the return row now is
return $query->select('lessons.*')->join('lesson_results', function($join) use($user)
...which makes it only return the stuff from the lessons table. But should that really be needed?
One of the same column names will be covered by the other.
Solution 1:
Specify the table with the column, and alias the other table's column if it has same column name.
Lesson::finished($user)->select('lessons.*', 'lesson_results.id AS lesson_result_id', 'lesson_results.column1', 'lesson_results.column2',...)->get();
Solution 2:
Or you can use Eloquent-Builder eager-loading whereHas,(Assuming you have build the relationship between model Lesson and model LessonResult)
public function scopeFinished($query, User $user)
{
return $query->whereHas('lessonResults', function($query) use($user)
{
$query->where("user_id", $user->id);
});
}
So you can get lesson like this:
Lesson::finished($user)->get();

Laravel eloquent query with sum of related table

I have a table users and posts with columns user_id and post_views.
In post_views I keep information how many times post was display.
And now, in query I would like to get user with sum of post_views all his posts.
I tried do something like this:
User::where(['id'=>$id])->with('posts')->get();
And in model I defined:
public function posts()
{
return $this->hasMany('App\Models\Post')->sum('post_views','AS','totalViews');
}
But without success.
How to do it?
Thank you
You can use a modified withCount():
public function posts()
{
return $this->hasMany('App\Models\Post');
}
$user = User::withCount(['posts as post_views' => function($query) {
$query->select(DB::raw('sum(post_views)'));
}])->find($id);
// $user->post_views
You can use
User::withCount('posts')->find($id)
to get the user with the id $id and a posts_count attribute in the response
I'm not fully sure what the intention of ->sum('game_plays','AS','totalVies'); is - you would need to add more context if you want this
Just something to add with regards to your shown code: No need to query by id using where + the get() at the end will make you query for a collection. If you want to get a single result use find when searching by id
As always laravel has a method for that : withSum (Since Laravel v8)
Note : I know that at the time of the message was posted, the method did not exist, but since I came across this page when I was looking for the same result, I though it might be interesting to share.
https://laravel.com/docs/9.x/eloquent-relationships#other-aggregate-functions
In your case it should be :
$user = User::withSum('posts as total_views', 'post_views')->find($id);
Then you can access to the result :
$user->total_views

Resources