I have the following test that fails:
#Test
public void testValidation() {
Validator validator = new LocalValidatorFactoryBean();
Map<String, String> map = new HashMap<String, String>();
MapBindingResult errors = new MapBindingResult(map, Foo.class.getName());
Foo foo = new Foo();
foo.setBar("ba");
validator.validate(foo, errors);
assertTrue(errors.hasFieldErrors());
}
Foo is as follows:
import javax.validation.constraints.Size;
public class Foo {
#Size(min=9, max=9)
private String bar;
// ... public setter and getter for bar
}
I have referenced Manually call Spring Annotation Validation and Using Spring Validator outside of the context of Spring MVC but I'm not sure why this test is failing.
You are trying to use a bean that is actually to be used inside a Spring ApplicationContext outside of it. To prepare it for use you also have to mimic the behavior of the ApplicationContext in regards to object initialization.
The LocalValidatorFactoryBean implements the InitializingBean interface. Which contains a single method which will be normally called by the ApplicationContext once the object is constructed and all dependencies have been injected (the same as a method annotated with #PostConstruct).
As you are using the bean outside of an ApplicationContext you will have to call the afterPropertiesSet method manually before the object is actually ready to be used.
Related
I'm trying to instantiate a component inside a method, to be more precise inside a rest method. I need a new instance of the component every time the rest method is invoked
#Validated
#RestController
#RequestMapping("test")
public class Test {
#GetMapping
public String test() {
// Spring equivalent of
// TestComponent component = new TestComponent();
return component.uuid();
}
}
My component is defined like this
#Scope
#Component
#Transactional
public class TestComponent {
private EntityManager entityManager;
private UUID randomUUID;
#Autowired
public TestComponent(EntityManager entityManager) {
this.entityManager = entityManager;
this.randomUUID = UUID.randomUUID();
}
public String uuid() {
// entityManager transactional stuff
return randomUUID.toString();
}
}
I tried to use a factory method but the instance was not transactional, I tried to use ApplicationContext.getBean but the instance was a singleton. How can I instantiate my component dynamically whenever I need it?
I'm using Spring 3.0.0-RC1
You can use different scopes to define the life cycle and visibility of that bean in the context. The default scope is Singleton, which means only one instance is created.
In your particular case, I think that you should choose between:
Prototype - creates a new instance every time a request for that specific bean is made. It can be defined with #Scope("prototype") annotation.
Request - each HTTP request has its own instance, only valid in the context of a web-aware Spring ApplicationContext. It can be defined with #RequestScope annotation.
To find out more details about all supported scopes, check the documentation.
I'm improving some tests in my stand-alone app. I've created a context in a test and defined a fake class for an interface on it. The app already has a default implementation and my goal is to load the fake class impl instead of it.
#RunWith(SpringJUnit4ClassRunner.class)
#ContextConfiguration(name = "my-test", classes =LauncherUnitTest.ContextConfiguration.class)
public class LauncherUnitTest {
#Autowired
#Qualifier("my-test")
ConfigurableApplicationContext testContext;
#Configuration()
public static class ContextConfiguration {
#Bean("test-exit")
#Primary
public ExitHandler getExitHandler() {
return new TestExitHandler();
}
}
#Before
public void before() throws LauncherException {
launcherObj = Launcher.builder().withParentContext(testContext).build();
assertThat(launcherObj.getExitHandlerName()).isEqualTo("test-exit");
}
The app accepts a parent context in its launcher build method, and I'm creating a new context and using it as the parent.
The issue I'm facing is on the getBean() method that accepts the interface class name. It is returning me the default implementation instead of the test one that I've defined as primary in the parent context.
Strangely, if I request the bean by name it returns me the right one. :(
ExitHandler exitHandler = rootApplicationContext.getBean(ExitHandler.class);
ExitHandler exitHandler2 = rootApplicationContext.getBean("test-exit", ExitHandler.class);
It seems that Spring context is not even looking in the parent context before it returns the bean.
Am I missing something here ?
This question already has answers here:
Injecting beans into a class outside the Spring managed context
(8 answers)
Closed 3 years ago.
Introduction
I have some business logic properties in the application.yml file.
They are loaded into the application via a #ConfigurationProperties annotated class.
How could I use these properties in a class which is not a Spring Bean? It cannot be a singleton, because many objects of it must be created during run-time.
Example
application.yml
business.foo: 2
BusinessProperties.java
#ConfigurationProperties("business")
#Getter // lombok
#Setter // lombok
public class BusinessProperties {
private int foo;
}
TypicalBean.java
#Component
public class TypicalBean {
private final BusinessProperties properties;
#Autowired
public TypicalBean(BusinessProperties properties) {
this.properties = properties;
}
#PostConstruct
public void printFoo() {
System.out.println("Foo: " + properties.getFoo()); // "Foo: 2"
}
}
NonBean.java
public class NonBean {
public void printFoo() {
System.out.println("Foo: ???"); // How to access the property?
}
}
Is there some way to create a non-singleton class, which can have access to configuration (or even other Spring beans) but otherwise works the same as a regular java class? Meaning that I can control its creation, it is collected by the garbage collector if not used anymore, etc.
You can still define the NonBean.class as a Component with Scope.Prototype
#Component
#Scope(value = BeanDefinition.SCOPE_PROTOTYPE)
public class NonBean {
#Autowired
public TypicalBean(BusinessProperties properties) {
this.properties = properties;
}
public void printFoo() {
System.out.println("Foo: " + properties.getFoo());
}
}
The trick is how you create an instance of NonBean.class. In the code where you'll be creating an instance of NonBean.class, use Spring's ObjectFactory<T>
private final ObjectFactory<NonBean> nonBeanFactory;
...
NonBean nonBean = nonBeanFactory.getObject();
The instantiated nonBean object will have been autowired.
All spring-beans creates by SpringApplicationContext. Bean - it's simple POJO-object, but created by Spring and saved in his container. If you want to get access to bean from outside of container - see this:
Getting Spring Application Context
Spring beans are really meant to be used within the application context but you might be able to achieve what you want by autowiring the properties to a static field in a Spring bean.
#Component
public class BusinessPropertiesUtils {
public static BusinessProperties INSTANCE;
#Autowired
public setBusinessProperties(BusinessProperties properties) {
this.INSTANCE = properties;
}
}
And then:
public class NonBean {
public void printFoo() {
System.out.println("Foo: " + BusinessPropertiesUtils.INSTANCE.getFoo());
}
}
PS: this is very hacky and definitely not the "Spring way".
You can configure beans with the prototype scope, which will give you a new instance of the bean every time it's requested.
From the Spring documentation:
In contrast to the other scopes, Spring does not manage the complete lifecycle of a prototype bean. The container instantiates, configures, and otherwise assembles a prototype object and hands it to the client, with no further record of that prototype instance.
...
In some respects, the Spring container’s role in regard to a prototype-scoped bean is a replacement for the Java new operator. All lifecycle management past that point must be handled by the client.
Example of how you can convert the TypicalBean class to a prototype scoped bean:
#Component
#Scope("prototype")
public class TypicalBean {
...
}
Another alternative is to manually instantiate the bean class (or any POJO) and injecting the dependencies (configuration, spring beans, etc.) through the constructor or setter methods, if you have them available or can get them from the Spring Context.
new TypicalBean(properties);
#Component
#PropertySources({ #PropertySource("classpath:mail.properties") })
public class A implements B {
#Value("${mail.team.address}")
private String teamAddress;
// has getter and setters .not shown for brevity.
Now when i call the class i get the value of teamAddress as NULL .But in the property file mail.team.address has some value.
My property file is present under src/main/resource folder
Making a call
A a = new A ();
a.someMethodinClassA();
You can not create instance of class by yourself when you want Spring to resolve #Value annotation.
See documentation:
Note that actual processing of the #Value annotation is performed by a BeanPostProcessor which in turn means that you cannot use #Value within BeanPostProcessor or BeanFactoryPostProcessor types. Please consult the javadoc for the AutowiredAnnotationBeanPostProcessor class (which, by default, checks for the presence of this annotation).
Simple solution for you: just annotate class with any #Component annotation and let Spring to create an instance of your class.
You can't create (with a "new" keywoard) for spring bean. If you do it like this, spring doesn't participate in the object creation and configuration, which means that there is no autowiring, the bean is not in Application Context, etc. And of course, #Value annotation won't be processed among other things
The better way is to inject the class A to the code that you used in your example:
A a = new A ();
a.someMethodinClassA();
Show become:
#Component
public class SomeClass {
private final A a;
public SomeClass(A a) {
this.a = a;
}
public void foo() {
a.someMethodinClassA();
}
}
You should read some basics around spring dependency injection. The class that you have autowired with #Component is scanned via component scanning and its object is created by spring container for you.
that is the reason you should not create the object yourself using new keyword.
wherever in your new class you want to use your class A object you can autowire it as below:
#Component
public class TestC{
private A a; // this object will be injected by spring for you
}
I have a instance of a class that is created outside of Spring that I'd like to have access to Spring beans so that it may fire an event and be observed by Spring beans. I'm not using Spring web, my application is running from the command-line via spring boot.
The only option you have is to expose the Spring context of your application using a static method so that the object that is not managed by Spring can use it to get references to managed beans it needs.
Start with a wrapper for the context. Create a regular managed bean which required reference to the context in its constructor. The reference is assigned to a static class field, which also has a static getter:
#Service
class ContextWrapper {
private static ApplicationContext context;
#Autowired
public ContextWrapper(ApplicationContext ac) {
context = ac;
}
public static ApplicationContext getContext() {
return context;
}
}
Use the static getter to get access to context in the object which is not managed by Spring and get reference to beans using methods available in the context:
SomeBean bean = ContextWrapper.getContext().getBean("someBean", SomeBean.class);
// do something with the bean
Last thing you need is communication channel from Spring beans to non-managed object. For instance, the SomeBean can expose a setter which will accept the non-managed object as a parameter and store the reference in a field for future use. The object mast get references to managed beans using the static context accessor mentioned above and use the setter to make the bean aware of its existence.
#Service
class SomeBean {
// ... your bean stuff
private SomeClass someclass;
public void setSomeClass(Someclass someclass) {
this.someclass = someclass;
}
private void sendEventToSomeClass() {
// communicate with the object not managed by Spring
if (someClass == null) return;
someClass.sendEvent();
}
}
You can inject by constructor that spring beans, something like:
#Service
class Bean {
...
}
class NotBean {
private Bean bean;
public NotBean(Bean bean) {
this.bean = bean;
}
// your stuff (handle events, etc...)
}