Invalid procedure call or argument on split mac excel vba - macos

Question

I am not sure why but this cet = Split(strCSV, " - ") causes Run time error 5: Invalid procedure call or argument.
strCSV = Trim(cWk.Range("P" & i)): dt = CDate(CLng(cWk.Range("H" & i)))
where str = "Cap Style:Snapback - CD / Number:07 / Color:First Avenger(+S$1.50) / Box:none - Only Purchase 3 caps and above - Free Box "
Following code works perfectly on windows but it throws error on the above mentioned line
Option Explicit
Option Compare Text
Sub Get_Data()
Application.ScreenUpdating = False
Dim fName, wkB2 As Workbook, cWk As Worksheet, xWk As Worksheet, frowC As Long, i As Long, j As Long, ch As String, num As String
Dim strCSV As String, dt As Date, shtName As String, cet, temp As String, rng As Range, cel As Range, cl As String, rw As Long, toF As String
On Error GoTo Err
fName = Application.GetOpenFilename
If fName <> False Then
Set wkB2 = Workbooks.Open(fName): Set cWk = wkB2.Worksheets(1): frowC = cWk.Range("P" & Rows.Count).End(xlUp).Row
'Cap Style:Baseball - CC / Number:04 / Color:Grey(+S$2) / Box:none - Only Purchase 3 caps and above - Free Box
'Cap Style:SnapBack - CC / Number:04 / Color:Grey(+S$1.50) / Box:none - Only Purchase 3 caps and above - Free Box
For i = 2 To frowC
strCSV = Trim(cWk.Range("P" & i)): dt = CDate(CLng(cWk.Range("H" & i)))
If strCSV <> "" And IsDate(dt) Then
'ERROR cet = Split(strCSV, " - "): temp = cet(LBound(cet)): cet = Split(temp, ":"): shtName = Trim(cet(UBound(cet)))
For Each xWk In ThisWorkbook.Worksheets
If shtName = Trim(xWk.Name) Then
Set rng = xWk.Range("E3:BD3")
For Each cel In rng
If cel.Value = dt Then
cet = Split(cel.Address, "$"): cl = cet(UBound(cet) - 1): Exit For
End If
Next cel
cet = Split(strCSV, "Number:"): temp = cet(UBound(cet)): cet = Split(temp, "/"): num = Trim(cet(LBound(cet)))
cet = Split(strCSV, " / "): temp = cet(LBound(cet)): cet = Split(temp, " - "): ch = Trim(cet(UBound(cet))): ch = ch & "-" & num
Debug.Print "Ch is " & ch
Set rng = xWk.Range("A1:A" & xWk.Range("A" & Rows.Count).End(xlUp).Row)
For Each cel In rng
If cel.Value = ch Then
rw = cel.Row: Exit For
End If
Next cel
cet = Split(strCSV, "Color:"): temp = cet(UBound(cet)): cet = Split(temp, "("): toF = Trim(cet(LBound(cet)))
For j = rw To rw - 10 Step -1
If Trim(xWk.Range("B" & j)) = toF Then
rw = j: Exit For
End If
Next j
Debug.Print "Address is: " & cl & rw & " for row " & i
xWk.Range(cl & rw) = cWk.Range("O" & i)
Exit For
End If
Next xWk
End If
Next i
wkB2.Close False
Else
Exit Sub
End If
Application.ScreenUpdating = True
MsgBox "Done"
Exit Sub
Err:
MsgBox Err.Description
End Sub

Answer 1

Update: SplitString now handle multi-character delimiters.
We conclude that older versions of Mac Office use the equivalent of VB5. Since the Split function was introduced in VB6. An Invalid procedure call or argument is being thrown because the Split function is not available in VB5.
The workaround would be to create a custom function that works like Spli.
Split Replacement Function
Function SplitString(Text As String, Delimiter As String)
Dim arr() As String, s As String
Dim i As Long, iEnd As Long, iStart As Long, length As Long
length = Len(Delimiter)
ReDim Preserve arr(0)
iStart = 1
Do
iEnd = InStr(Mid(Text, iStart), Delimiter) - 1
If iEnd = -1 Then
ReDim Preserve arr(i)
arr(i) = Mid(Text, iStart)
Exit Do
Else
ReDim Preserve arr(i)
arr(i) = Mid(Text, iStart, iEnd)
iStart = iStart + iEnd + length
i = i + 1
End If
Loop Until iStart = 0
SplitString = arr
End Function
Here are the tests that I ran
Sub BatchTest()
Dim strCSV As String, Temp As String, Delimiter As String
Dim a
strCSV = "Cap Style Snapback - CD / Number 07 / Color First Avenger(+S$1.50) / Box none - Only Purchase 3 caps and above - Free Box"
a = SplitString(strCSV, "/")
TestSplit strCSV, " / "
TestSplit strCSV, " /"
TestSplit strCSV, "/"
TestSplit strCSV, " Color First"
End Sub
Sub TestSplit(Text As String, Delimiter As String)
Dim arr As Variant, sReplcement As String
arr = SplitString(Text, Delimiter)
sReplcement = Replace(Text, Delimiter, "|")
Debug.Print sReplcement
Debug.Print Join(arr, "|")
Debug.Print sReplcement = Join(arr, "|")
End Sub
The Results of the tests
Sub TestRegEx()
MsgBox RegexExtract("sdi 99090 dfddf sdi 5666", "(sdi \d+)", ", ") = "sdi 99090, sdi 5666"
End Sub
Function RegexExtract(ByVal text As String, _
ByVal extract_what As String, _
Optional seperator As String = "") As String
Dim i As Long, j As Long
Dim result As String
Dim allMatches As Object
Dim RE As Object
Set RE = CreateObject("vbscript.regexp")
RE.Pattern = extract_what
RE.Global = True
Set allMatches = RE.Execute(text)
For i = 0 To allMatches.count - 1
For j = 0 To allMatches.Item(i).submatches.count - 1
result = result & seperator & allMatches.Item(i).submatches.Item(j)
Next
Next
If Len(result) <> 0 Then
result = Right(result, Len(result) - Len(seperator))
End If
RegexExtract = result
End Function