I'm trying to execute this command:
ps -eo pid,args --cols=10000 | awk '/\/opt\/logstash\/logstash-1.5.3\// && $1 != PROCINFO["pid"] { print $1 }'
whith ansible -m shell module (not working example):
ansible -m shell -a '"'ps -eo pid,args --cols=10000 | awk '/\/opt\/logstash\/logstash-1.5.3\// && $1 != PROCINFO[\'pid\'] { print $1 }' '"' all
One of the ways would be to put that into a file, but still it would be nice to run as a command - any ideas?
Bash escaping rules will do:
ansible localhost -m shell -a "ps -eo pid,args --cols=10000 | awk '/\\/opt\\/logstash\\/logstash-1.5.3\\// && \$1 != PROCINFO[\"pid\"] { print \$1 }'"
Mine alternative version that worked:
ansible -m command -a "ps a |grep -E '/opt/logstash/logstash-1.5.3/vendor/jruby' " all --sudo
Check if the process are running:
ansible -m shell -a "ps aux |grep -E '/opt/logstash/logstash-1.5.3/vendor/jruby'|grep -v -e grep |wc" all
A simple way (i.e. without having to rewrite the command much or introduce a bunch of escapes) is to use a temporary variable.
Your original command:
ps -eo pid,args --cols=10000 \
| awk '/\/opt\/logstash\/logstash-1.5.3\// && $1 != PROCINFO["pid"] { print $1 }'
Corresponding ansible call:
x='/\/opt\/logstash\/logstash-1.5.3\// && $1 != PROCINFO["pid"] { print $1 }'; \
ansible all -m shell -a "ps -eo pid,args --cols=10000 | awk '$x'"
Related
Context
Got a daft script that checks a process is running on a group of hosts, like a watchdog, as I say it's a daft script so bear in mind it isn't 'perfect' by scripting standards
Problem
I've ran bash -x and can see that the script finishes its first check without actually redirecting the output of the command to the file which is very frustrating, it means each host is actually being evaluated to the last hosts output
Code
#!/bin/bash
FILE='OUTPUT'
for host in $(cat /etc/hosts | grep webserver.[2][1-2][0-2][0-9] | awk {' print $2 ' })
do ssh -n -f $host -i <sshkey> 'ps ax | grep myprocess | wc -l' > $FILE 2> /dev/null
cat $FILE
if grep '1' $FILE ; then
echo "Process is NOT running on $host"
cat $FILE
else
cat $FILE
echo "ALL OK on $host"
fi
cat $FILE
done
Script traceback
++ cat /etc/hosts
++ awk '{ print $2 }'
++ grep 'webserver.[2][1-2][0-2][0-9]'
+ for host in '$(cat /etc/hosts | grep webserver.[2][1-2][0-2][0-9] | awk {'\'' print $2 '\''})'
+ ssh -n -f webserver.2100 -i <omitted> 'ps ax | grep myprocess | wc -l'
+ cat OUTPUT
+ grep 1 OUTPUT
+ cat OUTPUT
+ echo 'ALL OK on webserver.2100'
ALL OK on webserver.2100
+ cat OUTPUT
+ printf 'webserver.2100 checked \n'
webserver.2100 checked
+ for host in '$(cat /etc/hosts | grep webserver.[2][1-2][0-2][0-9] | awk {'\'' print $2 '\''})'
+ ssh -n -f webserver.2101 -i <omitted> 'ps ax | grep myprocess | wc -l'
+ cat OUTPUT
2
+ grep 1 OUTPUT
+ cat OUTPUT
2
+ echo 'ALL OK on webserver.2101'
ALL OK on webserver.2101
+ cat OUTPUT
2
+ printf 'webserver.2101 checked \n'
webserver.2101 checked
Issue
As you can see, it's registering nothing for the first host, then after it is done, it's piping the data into the file, then the second host is being evaluated for the previous hosts data...
I suspect its to do with redirection, but in my eyes this should work, it doesn't so it's frustrating.
I think you're assuming that ps ax | grep myprocess will always return at least one line (the grep process). I'm not sure that's true. I'd rewrite that like this:
awk '/webserver.[2][1-2][0-2][0-9]/ {print $2}' /etc/hosts | while IFS= read -r host; do
output=$( ssh -n -f "$host" -i "$sshkey" 'ps ax | grep "[m]yprocess"' )
if [[ -z "$output" ]]; then
echo "Process is NOT running on $host"
else
echo "ALL OK on $host"
fi
done
This trick ps ax | grep "[m]yprocess" effectively removes the grep process from the ps output:
the string "myprocess" matches the regular expression "[m]yprocess" (that's the running "myprocess" process), but
the string "[m]yprocess" does not match the regular expression "[m]yprocess" (that's the running "grep" process)
I have the following command line:
egrep '^[0-9]' /etc/hosts | grep -v 127.0.0.1 | awk 'NR==1{ips=$1} NR>1{ips=ips ", " $1} $2=="namenode"{nn=$1} END{ printf "/opt/mapr/server/configure.sh -C %s -Z %s -N mycluster --create-user -D /dev/xvdb\n", ips, nn}'
And that's producing a command line which I will use in my chef cookbook to start a MapR cluster:
/opt/mapr/server/configure.sh -C 10.32.237.251 -Z 10.32.237.251 -N mycluster --create-user -D /dev/xvdb
My first command only prints out that command. How can I modify that command, or add anything else, to automatically execute the command produced by the awk?
Pipe it to the shell:
egrep '^[0-9]' /etc/hosts | grep -v 127.0.0.1 \
| awk 'NR==1{ips=$1}
NR>1{ips=ips ", " $1}
$2=="namenode"{nn=$1}
END{ printf "/opt/mapr/server/configure.sh -C %s -Z %s -N mycluster --create-user -D /dev/xvdb\n", ips, nn}' \
| bash
This question already has an answer here:
Executing ssh command in a bash shell script within a loop [duplicate]
(1 answer)
Closed 9 years ago.
I am Oracle DBA and i am doing some scripting to check if database is live or not on our large number of servers.
I am trying to set value to variable in ssh -X e.g
[oracle#proddb02]$ DB_STAT=`ssh -X proaddb01 'ps -ef | grep pmon | grep -v grep' | awk '{ print $8 }'`
[oracle#proddb02]$ echo $DB_STAT
ora_pmon_pconn01
Above example works perfectly but as i am using ssh command i cannot loop using while as it exit at the first line file which include list of the servers.
so i have to add /dev/null to the command so that it should not exit the loop. but this does not set the variable value.
When i echo the variable it gives nothing.
[oracle#proddb02]$ DB_STAT=`ssh -X proddb01 'ps -ef | grep pmon | grep -v grep' | awk '{ print $8 }'</dev/null`
[oracle#proddb02]$ echo $DB_STAT
[oracle#proddb02]$ echo $DB_STAT
The loop code is
[oracle#proddb02]$cat test.sh
while read line
do
INST_VAR=`echo $line | awk '{ print $1 }'`
HOST_VAR=`echo $line | awk '{ print $2 }'`
SERVER_NAME=$HOST_VAR
INSTANCE_NAME=$INST_VAR
DB_STAT=`ssh -X proaddb01 'ps -ef | grep pmon | grep -v grep' | awk '{ print $8 }'`
echo $DB_STAT
done < host_list.lst
Any help would be much appreciated.
Just do:
DB_STAT=`ssh -X proaddb01 "ps -ef | awk '/[p]mon/'{ print $8 }"`
Here you use:
// to filter the input stream (like grep but witj awk);
the trick with [p]grep to exclude the same line from ps (because [p]grep string will not be found with [p]grep template).
I am trying to write a script to find a reverse SSH PID and kill it if present. I am stuck on "awk" as it gives error. below is the script:
a=('ps -aef | grep "ssh -fN" | grep -v grep | awk '{ print $2 }'')
if [ -n "$a" ]
then
echo "String \"$a\" is not null."
kill -9 "$a"
fi
I commented out if, then, kill and fi lines to debug the script. I get following error:
String "ps -aef | grep "ssh -fN" | grep -v grep | awk {" is not null.
I believe parenthesis for awk is creating the problem and I am unable to get a workaround for this. On Command line, this works perfectly and returns the correct PID.
ps -aef | grep "ssh -fN" | grep -v grep | (awk '{ print $2 }'
Once the PID is passed on to variable "a", I need to issue kill command. OS is Centos 6.4
P.S: I am not fluent on scripting but trying to achieve an objective. Help will be highly appreciated!
There are multiple problems with your script.
You need command substitution to store the output of ps pipeline into an array.
You need to check for the number of elements in the array.
Refer to the array instead of the variable.
The following might work for you:
pids=( $(ps -ef | grep '[s]sh -fN' | awk '{print $2}') )
if [ "${#pids[#]}" -gt 0 ]; then
kill -9 "${pids[#]}";
fi
First, if you have grep and then awk, you can get rid of the greps:
ps -aef | grep "ssh -fN" | grep -v grep | awk '{ print $2 }'
ps -aef |awk ' { if ( ($0 ~ /ssh -FN/) && (! $0 ~ /grep/) ) { print $2 } }'
However, instead of using ps, use pgrep.
pgrep -f "ssh -[fN][fN]" # Will match against either 'ssh -fN' or 'ssh -Nf'
There is even a pkill that will do the entire command for you:
pkill -f "ssh -[fN][fN]"
That will find all of the processes that match that particular string and kill them (if they exist).
This is my bash script:
#!/usr/local/bin/bash -x
touch /usr/local/p
touch /usr/local/rec
DATA_FULL=`date +%Y.%m.%d.%H`
CHECK=`netstat -an | grep ESTAB | egrep '(13001|13002|13003|13004|13061|13099|16001|16002|16003|16004|16061|16099|18001|18002|18003|18004|18061|18099|20001|20002|20003|20004|20061|20099|13000|16000|18000|20000)' | awk '{ print $5 }' | sort -u | wc -l`
netstat -an | grep ESTAB | egrep '(13001|13002|13003|13004|13061|13099|16001|16002|16003|16004|16061|16099|18001|18002|18003|18004|18061|18099|20001|20002|20003|20004|20061|20099|13000|16000|18000|20000)' | awk '{ print $5 }' | sort -u | wc -l > /usr/local/www/p
STAT=`cat /usr/local/www/rec`
if [ "$CHECK" -gt "$STAT" ]; then
echo $CHECK"\n"$DATA_FULL > /usr/local/p
fi
Ofcourse I've runned chmod +x script.sh and then sh script.sh, then I receive the following message: [: : bad number.
Why does it happends?
Run your script using
sh -x script.sh
It'll print every line it executes and the variable output.
Run the netstat command and stat command outside and check.
If these are integer for sure, use this syntax,
if [ "0$(echo $CHECK|tr -d ' ')" -gt "0$(echo $STAT|tr -d ' ')" ];
A simple hack. Only works if $STAT is always either empty or positive number.
Are you sure that both STAT and CHECK are numbers that can be compared with -gt?
probably your /usr/local/www/rec is empty. Try
STAT=`cat /usr/local/www/rec 2>/dev/null || echo 0`
maybe.