Is there any way to get session variable in model ? My session driver is session_driver=cookie I have following codes in controller -
use Illuminate\Support\Facades\Session;
I am storing session variable like
session(['current_session_id' => $session_id]);
And in my model , I used
use Illuminate\Support\Facades\Session;
but it prints only _token , when I use
print_r(Session::all());
output
Array ( [_token] => mW5jx64fsAdkF3dOEis3F1Iqyz5Szu15eek0jMTr )
however in controller , it is printing
Array ( [_token] => UoG2PRXUzv7zIKj6WUTXkvM9WeLAe0tesCe3GSdx [current_session_id] => 7072345 )
Please help!!!
Related
I want to implement a search option on my Laravel application, but had this error:Class 'Illuminate\Support\Facades\Input' not found, I have tried to add this row at config/app like this:
'aliases' => [
....
'Input' => Illuminate\Support\Facades\Input::class,
Also at Controller I have added those rows:
use Illuminate\Http\Request;
use Illuminate\Support\Facades\Input;
At Route I have added
Route::any('/search',function(){
$image_tmp = $request->image;
$fileName = time() . '.'.$image_tmp->clientExtension();
$q = Input::get ( 'q' );
$book = Book::where('title','LIKE','%'.$q.'%')->get();
if(count($book) > 0)
return view('home')->withDetails($book)->withQuery ( $q );
else return view ('home')->withMessage('No Details found. Try to search again!');
});
But still it doesn't work.
Try this
config/app.php
use Request instead of Input
'aliases' => [
....
'Input' => Illuminate\Support\Facades\Request::class,
And your controller
use Illuminate\Http\Request;
and remove use Illuminate\Support\Facades\Input; top of your code
you have used the class in the controller but your route is never going to one as you are using a closure. so add Input class in your web.php file. at the top of your web.php file add
<?php
use Illuminate\Support\Facades\Input;
if you are using any latest version of laravel, the Input class no longer exists. so use Request class instead
<?php
use Illuminate\Http\Request;
you can use request() global helper too to get request values.
however i would suggest you to not use closure, rather use controller for logical operation.
I'm having an odd error with saving an encrypted array in Laravel. The model never updates even when save() is called.
There are no console or SQL errors.
When the encryption is disabled, there are no errors and the model updates successfully.
In a Controller, I'm calling the model like so:
$userData = UserData::where('user_id', $user_id)->first();
I then pull the array:
$encryptedData = $userData->app_data;
And I want to add to this array e.g.
$encryptedData['new'] = 'axy';
$encryptedData['time'] = time();
I then update the model and save it:
$userData->app_data = $encryptedData;
$userData->save();
However, here is where the problem starts. The model does not update. It remains as if nothing happens. Hence if I refresh(), I get the same data as if I had never added the two new entries. When I log it, it looks like this:
Array
(
[token] => xyz
[access_token] => abc
)
After the addition of two new entries:
Array
(
[token] => xyz
[access_token] => abc
[new] => 'axy'
[time] => 1234
)
And after the save() and refresh():
Array
(
[token] => xyz
[access_token] => abc
)
The model looks like this:
namespace App;
use Illuminate\Database\Eloquent\Model;
use Illuminate\Support\Facades\Crypt;
use Illuminate\Contracts\Encryption\DecryptException;
class UserData extends Model
{
protected $fillable = [
'user_id', 'app_data'
];
protected $casts = [
'user_id' => 'int',
'app_data' => 'array'
];
public function getAppDataAttribute($value)
{
try {
return decrypt($value);
}
catch (DecryptException $e) {
return $value;
}
}
public function setAppDataAttribute($value)
{
$this->attributes['app_data'] = encrypt($value);
}
}
Why are my additions to the array not being saved?
Edit: The strangeness continues
If I call:
UserData::where('id', $userData->id)->update(['app_data' => $encryptedData]);
Then the model does update and does not encrypt, HOWEVER, when I refresh and log the new 'app_data' field, it is returned as a JSON string and not an array as before. I need to cast/decode it to an array each time I want to use it.
Couple of things to look for.
1) The Laravel encrypter uses the app key. Make sure you have one in your .env file. If not, run php artisan key:generate
2) I assume the array is correctly formatted like this:
Array
(
'token' => 'xyz', // You have a = here and no commas after any other value
'access_token' => 'abc'
)
3) Depending on what you are storing this as, you can test by serializing the array before encrypting it:
$arr = serialize($encryptedData); // After you have added new data to the array
$userData->app_data = $arr;
$userData->save();
This is automatic in Laravel, but may give you a help hunting the bug. Test with your mutator using encryptString() and manually unserialize / decryptString() to see if any odd behavior by stepping through the values as they are mutated.
I use this code in my controller:
public function index() {
$this->load->library('session');
echo "<pre>";
print_r($this->session->all_userdata());
echo "</pre>";
}
and this is the result :
Array
(
[__ci_last_regenerate] => 1524275027
[identity] => admin
[username] => admin
[email] => admin
[user_id] => 1
[old_last_login] => 1524182225
[last_check] => 1524274694
)
I use codeigniter 3.1 with ion_Auth
so how to get all data like user_agent , ip , ... ?
Codigniter session library was re-written for version 3.0 and had some bug-fixes until the most recent version 3.1.8.
In earlier CI versions (2.x), the session data array had 4 items by default:
‘session_id’,
‘ip_address’,
‘user_agent’,
‘last_activity’
Now, in the new CI versions, you can still access these data like this (from the docs:)
session_id: session_id()
ip_address: $_SERVER['REMOTE_ADDR']
user_agent: $this->input->user_agent() (unused by sessions)
last_activity: Depends on the storage, no straightforward way. Sorry!
see: https://www.codeigniter.com/user_guide/libraries/sessions.html#accessing-session-metadata
and: https://www.codeigniter.com/userguide3/installation/upgrade_300.html#step-6-update-your-session-library-usage
This is my code:
return redirect()->route('edit.brand',$id)->with(array( 'brand' => $brand, 'errorName' => $errorName, 'errorCode' => $errorCode));
The result is that, in the FORM of route edit.brand.
It's filled by data with $id, (do the route first and ignore all parameters in 'with' )
How can I show $errorName if they exist
When You are redirecting to route, your parameters goes to flash session. So in edit.brand route You can access it with session helper like so:
session('errorName')
This is for flash data not request parameters That you are using .
Use this one
return Redirect::route('user', array('nick' => $username));
Is there a built-in way to do something like this?
Let's say I have a search-page that has a few parameters in the URL:
example.com/search?term=foo&type=user
A link on that page would redirect to an URL where type is link. I'm looking for a method to do this without manually constructing the URL.
Edit:
I could build the URL manually like so:
$qs = http_build_query(array(
'term' => Input::get('term'),
'type' => Input::get('type')
));
$url = URL::to('search?'.$qs);
However, what I wanted to know is if there is a nicer, built-in way of doing this in Laravel, because the code gets messier when I want to change one of those values.
Giving the URL generator a second argument ($parameters) adds them to the URL as segments, not in the query string.
You can use the URL Generator to accomplish this. Assuming that search is a named route:
$queryToAdd = array('type' => 'user');
$currentQuery = Input::query();
// Merge our new query parameters into the current query string
$query = array_merge($queryToAdd, $currentQuery);
// Redirect to our route with the new query string
return Redirect::route('search', $query);
Laravel will take the positional parameters out of the passed array (which doesn't seem to apply to this scenario), and append the rest as a query string to the generated URL.
See: URLGenerator::route(),
URLGenerator::replaceRouteParameters()
URLGenerator::getRouteQueryString()
I prefer native PHP array merging to override some parameters:
['type' => 'link'] + \Request::all()
To add or override the type parameter and remove another the term:
['type' => 'link'] + \Request::except('term')
Usage when generating routes:
route('movie::category.show', ['type' => 'link'] + \Request::all())
You can do it with Laravel's URLGenerator
URL::route('search', array(
'term' => Input::get('term'),
'link' => Input::get('type')
));
Edit: be sure to name the route in your routes.php file:
Route::get('search', array('as' => 'search'));
That will work even if you're using a Route::controller()
From Laravel documentation:
if your route has parameters, you may pass them as the second argument
to the route method.
In this case, for return an URI like example.com/search?term=foo&type=user, you can use redirect function like this:
return redirect()->route('search', ['term' => 'foo', 'type' => 'user']);
Yes, there is a built in way. You can do your manipulation in Middleware.
The $request passed to the handle method of all middleware has a query property. As an InputBag, it comes with a few methods; Namely, for your intentions: ->set().
Pretty self explanatory, but here's an example:
public function handle(Request $request, Closure $next)
{
$request->query->set('term','new-value');
// now you pass the request (with the manipulated query) down the pipeline.
return $next($request);
}
The Input component should also contain query parameters.
i.e Input::get('foo');