If I have file.rb:
puts "Hello, World"
then in irb type:
require "./file.rb"
the output will be Hello, World.
Why then, if I have a sinatra file, e.g.
require "sinatra"
get "/" do
return "Hi"
end
and require that, there is no output?
Clarification
What executing the sinatra file via ruby sinatra_app.rb it will start a rack server, and not stop until CTRL+C is pressed. Why does it not do that when required in irb, but it does do that when it is explicitly run with ruby sinatra_app.rb?
Because the script doesn't output anything. There is nothing in the script you showed that would generate any sort of output, there are no calls to print, puts, or p, no writes to any file, nothing.
The first script prints something when required, because it prints something, the second prints nothing when required because, well, it prints nothing. Remove the call to puts from the first script and it won't print anything either. Add a call to puts to the second script and it will print something.
Workaround is require sinatra before requiring file.
Root file:
require "sinatra"
require "/tmp/ddd.rb"
Required file:
get "/" do
return "Hi"
end
I guess it's somehow related to Sinatra startup process. They put get method in default namespace, without namespacing it to separate module.
Related
I was trying to run Sinatra and Ruby in my MacBook, and all was working fine. Then, suddenly, I tried again and it just stays like this:
I can't access to localhost or anything. I don't know what to do. I've been researching for hours. Please, help me.
This is what my ruby code looks like:
require 'sinatra'
gets '/ejemplo1' do
puts 'Hello World'
end
Seems to be a typo. Should be get and not gets.
require 'sinatra'
get '/ejemplo1' do
puts 'Hello World'
end
Additional info:
gets in ruby is a way to get user input:
name = gets
puts "Your name is #{name}"
Like mentioned by #Norly Canarias you should use get for routing in sinatra. Moreover if you use puts statement in get block it will print only in terminal when you run your code not in webpage when you access localhost. Correct way to make it display in webpage is given below
require 'sinatra'
get '/ejemplo1' do
'Hello World'
end
Ubuntu 12.04
Sinatra 1.3.3
Why does passing an argument to a ruby system call (%x[] or ``) give me a 'not found' error in my sinatra app? The same code works fine in a normal ruby script running from the same directory.
I have a file test.rb like this
output = %x["ls"]
p output
When I run it with "ruby test.rb" I get the contents of the current directory in the console, as expected.
If I modify the program to give an argument to the system call like so:
output = %x["ls sub_dir/"]
p output
I get the contents of sub_dir, which sits in the current directory, as expected.
So far so good.
Now if I make a Sintra app with a post method:
require 'rubygems'
require 'bundler/setup'
require 'sinatra'
post "/" do
output = x["ls"]
return output
end
The response to a Post call to "/" returns the contents of the current directory, which includes 'sub_dir', as expected.
If I try to add the argument to the system call to the sinatra app like so:
require 'rubygems'
require 'bundler/setup'
require 'sinatra'
post "/" do
output = x["ls sub_dir/"]
return output
end
the response is nil and there is an error in the console:
sh: 1: ls sub_dir/: not found
Why does adding a parameter to a system call in my sinatra app cause it to crash, when the same code called from a plain ruby script, run from the same location works perfectly.
By the way, the 'ls' example shown here is not the command I really need to run, so please don't explain a different way to get this information. I have an executable file that takes a file name as a parameter that I need to run, which behaves exactly the same way.
Thanks in advance!
If you want to specify a path in relation to the application, you could use something like this:
post "/" do
path = File.join(File.dirname(__FILE__), "sub_dir")
%x[ls #{path}]
end
However, if you want to list the contents of a directory, why not do it in Ruby?
I rewrote the sinatra app in another file in the same directory.
Everything works as expected.
I did not find the reason and I deleted the original file so that I won't lose anymore time trying to figure it out.
I have a 2 scripts:
test1.rb
require 'test2.rb'
puts "hello"
test2.rb
puts "test"
I'm running this by executing ruby test2.rb test1.rb.
But only test is printed out and not hello.
You only need to run ruby test1.rb and the require statement should pull in test2.rb for you - you don't need to put it on the command line as well. (That will try and run test2.rb, passing the string 'test1.rb' as an argument, which is not what you want here)
Edit: the require statement does not look in the current directory by default when trying to find 'test2.rb'. You can explicitly specify it by changing it to:
require File.dirname(__FILE__) + '/test2.rb'
in test1.rb do (assuming test2.rb is in same directory, otherwise give its path relative to test1.rb)
require_relative 'test2.rb'
puts "hello"
and on the command line just do ruby test1.rb
This should work as well
require './test2.rb'
puts "hello"
There are some explanation how you can solve your problem, but not what is going wrong.
With ruby test2.rb test1.rb you call the ruby script with the parameter test1.rb.
You have access to the parameters in the constant ARGV.
An example with this script:
puts "test"
puts 'ARGV= %s' % ARGV
The result when you call it:
C:\Temp>ruby test.rb test2.rb
test
ARGV= test2.rb
So you could also write a program like:
require_relative ARGV.first
The first parameter defines a script to be loaded.
Or if you want to load many scripts you could use:
ARGV.each{|script| require_relative script }
I want to be able to read a currently open file. The test.rb is sending its output to test.log which I want to be able to read and ultimately send via email.
I am running this using cron:
*/5 * * * /tmp/test.rb > /tmp/log/test.log 2>&1
I have something like this in test.rb:
#!/usr/bin/ruby
def read_file(file_name)
file = File.open(file_name, "r")
data = file.read
file.close
return data
end
puts "Start"
puts read_file("/tmp/log/test.log")
puts "End"
When I run this code, it only gives me this output:
Start
End
I would expect the output to be something like this:
Start
Start (from the reading of the test.log since it should have the word start already)
End
Ok, you're trying to do several things at once, and I suspect you didn't systematically test before moving from one step to the next.
First we're going to clean up your code:
def read_file(file_name)
file = File.open(file_name, "r")
data = file.read
file.close
return data
end
puts "Start"
puts read_file("/tmp/log/test.log")
puts "End"
can be replaced with:
puts "Start"
puts File.read("./test.log")
puts "End"
It's plain and simple; There's no need for a method or anything complicated... yet.
Note that for ease of testing I'm working with a file in the current directory. To put some content in it I'll simply do:
echo "foo" > ./test.log
Running the test code gives me...
Greg:Desktop greg$ ruby test.rb
Start
foo
End
so I know the code is reading and printing correctly.
Now we can test what would go into the crontab, before we deal with its madness:
Greg:Desktop greg$ ruby test.rb > ./test.log
Greg:Desktop greg$
Hmm. No output. Something is broken with that. We knew there was content in the file previously, so what happened?
Greg:Desktop greg$ cat ./test.log
Start
End
Cat'ing the file shows it has the "Start" and "End" output of the code, but the part that should have been read and output is now missing.
What happening is that the shell truncated "test.log" just before it passed control to Ruby, which then opened and executed the code, which opened the now empty file to print it. In other words, you're asking the shell to truncate (empty) it just before you read it.
The fix is to read from a different file than you're going to write to, if you're trying to do something with the contents of it. If you're not trying to do something with its contents then there's no point in reading it with Ruby just to write it to a different file: We have cp and/or mv to do those things for us witout Ruby being involved. So, this makes more sense if we're going to do something with the contents:
ruby test.rb > ./test.log.out
I'll reset the file contents using echo "foo" > ./test.log, and cat'ing it showed 'foo', so I'm ready to try the redirection test again:
Greg:Desktop greg$ ruby test.rb > ./test.log.out
Greg:Desktop greg$ cat test.log.out
Start
foo
End
That time it worked. Trying it again has the same result, so I won't show the results here.
If you're going to email the file you could add that code at this point. Replacing the puts in the puts File.read('./test.log') line with an assignment to a variable will store the file's content:
contents = File.read('./test.log')
Then you can use contents as the body of a email. (And, rather than use Ruby for all of this I'd probably do it using mail or mailx or pipe it directly to sendmail, using the command-line and shell, but that's your call.)
At this point things are in a good position to add the command to crontab, using the same command as used on the command-line. Because it's running in cron, and errors can happen that we'd want to know about, we'd add the 2>&1 redirect to capture STDERR also, just as you did before. Just remember that you can NOT write to the same file you're going to read from or you'll have an empty file to read.
That's enough to get your app working.
class FileLineRead
File.open("file_line_read.txt") do |file|
file.each do |line|
phone_number = line.gsub(/\n/,'')
user = User.find_by_phone_number(line)
user.destroy unless user.nil?
end
end
end
open file
read line
DB Select
DB Update
In the cron job you have already opened and cleared test.log (via redirection) before you have read it in the Ruby script.
Why not do both the read and write in Ruby?
It may be a permissions issue or the file may not exist.
f = File.open("test","r")
puts f.read()
f.close()
The above will read the file test. If the file exists in the current directory
The problem is, as I can see, already solved by Slomojo. I'll only add:
to read and print a text file in Ruby, just:
puts File.read("/tmp/log/test.log")
Is there a shorter way to require a file located in the same directory (as the script being executed)?
require File.expand_path(File.dirname(__FILE__) + '/some_other_script')
I read that require "my_script" and require "./my_script" will actually load the script twice (ruby will not recognize that it is actually the same script), and this is the reason why File.expand_path is recommended: if it is used every time the script is required, then it will only be loaded once.
It seems weird to me that a concise language like Ruby does not seem to have a shorter solution. For example, python simply has this:
import .some_other_module_in_the_same_directory
I guess I could monkey-patch require... but that's just evil! ;-)
Since ruby 1.9 you can use require_relative.
Check the latest doc for require_relative or another version of the Core API.
Just require filename.
Yes, it will import it twice if you specify it as filename and ./filename, so don't do that. You're not specifying the .rb, so don't specify the path. I usually put the bulk of my application logic into a file in lib, and then have a script in bin that looks something like this:
#!/usr/bin/env ruby
$: << File.join(File.dirname(__FILE__), "/../lib")
require 'app.rb'
App.new.run(ARGV)
Another advantage is that I find it easier to do unit testing if the loading the application logic doesn't automatically start executing it.
The above will work even when you're running the script from some other directory.
However, inside the same directory the shorter forms you refer to work as expected and at least for ruby 1.9 won't result in a double-require.
testa.rb
puts "start test A"
require 'testb'
require './testb'
puts "finish test A"
testb.rb
puts "start test B"
puts "finish test B"
running 'ruby testa.rb' will result in:
start test A
start test B
finish test B
finish test A
However, the longer form will work even from another directory (eg. ruby somedir/script.rb)
Put this in a standard library directory (somewhere that's already in your default loadpath $:):
# push-loadpath.rb
if caller.first
$: << File.expand_path(File.dirname(caller.first))
end
Then, this should work
% ls /path/to/
bin.rb lib1.rb lib2.rb #...
% cat /path/to/bin.rb
load 'push-loadpath.rb'
require 'lib1'
require 'lib2'
#...
caller gives you access to the current callstack, and tells you what file and where, so push-loadpath.rb uses that to add the file that load'd it to the loadpath.
Note that you should load the file, rather than require it, so the body can be invoked multiple times (once for each time you want to alter the loadpath).
Alternately, you could wrap the body in a method,
# push-loadpath.rb
def push_loadpath
$: << File.expand_path(File.dirname(caller.first))
end
This would allow you to require it, and use it this way:
% ls /path/to/
bin.rb lib1.rb lib2.rb #...
% cat /path/to/bin.rb
require 'push-loadpath'
push_loadpath
require 'lib1'
require 'lib2'
#...