I have COL_1 as timestamp which looks like this 5:04:00. I want to round it down to something that looks like this 05:00:00.
So basically round down to a 5 minute bucket. And, add leading zero to hours if needed.
Meaning, 5:01:00 changes to 05:00:00
14:59:00-->14:55:00
14:51:00-->14:50:00
7:13:00-->07:10:00
Why do you store this in a VarChar instead of Time or Interval?
CAST(col AS TIME(0) FORMAT 'hh:mi') -
( (EXTRACT (MINUTE FROM
CAST(col AS TIME(0) FORMAT 'hh:mi')
) MOD 5
) * INTERVAL '1' MINUTE
)
Try this
CAST(TO_CHAR(INPUT_TS,'YYYY-MM-DD') || ' ' ||
CASE WHEN EXTRACT(MINUTE FROM INPUT_TS) > 30 THEN
TRIM(TO_CHAR(EXTRACT(HOUR FROM INPUT_TS) + 1,'00'))
ELSE TRIM(TO_CHAR(EXTRACT(HOUR FROM INPUT_TS) ,'00'))
END || ':00:00' AS TIMESTAMP(6)) AS YOUR_TS
Format as required.
Related
Sample output:
Rise_ID FROM_LOCATION TO_LOCATION SEATS_LEFT
SEATS_TOTAL RIDE_PROVIDER START_ON ENDS _ON IS_STARTED IS_FINISHED 12014 Nandi hills banglore 0 3 11002 13-Nov-20
04.00.13.36 PM. 13-Dec-20 08.02.13.36PM yes yes
one way you can get the difference between the 2 date columns as follows.
If the following SQL SYSDATE is getting the current time, the other column is a hard coded date time column.
SELECT ROUND(minutes_ / 60, 2) || ' Hours '
FROM ( SELECT (sysdate - to_date('14/09/2022 19:35:00', 'DD/MM/YYYY HH24:MI:SS')) * 24 * 60 AS minutes_
FROM dual
);
SELECT FROM_LOCATION || ' - ' || TO_LOCATION
FROM TABLE_OUTPUT T
WHERE (TO_DATE(START_ON, 'DD-MON-YY HH.MI.SS') - TO_DATE(ENDS_ON, 'DD-MON-YY HH.MI.SS')) > 2;
I assuming you are looking this data from a table, also you need to check the format, the current you're using not gonna work, i suggest the format 'DD-MON-YY HH.MI.SS'
Is there a straightforward way to find if a time is between two times? (00:00-23:59) I represent the times by the starting time and an DAY TO SECOND interval, because I want to account for the interval overlapping midnight.
For instance: I have a time 15:20 and want to find if it is in these intervals:
10:00, interval 06:00 - yes
15:00, interval 01:00 - yes
23:30, interval 20:00 - yes
16:00, interval 05:00 - no
And for time 21:00:
20:00, interval 06:00
The data is stored in a table:
CREATE TABLE Opening_Interval
(
IntervalID INTEGER NOT NULL ,
DayOfWeek INTEGER NOT NULL ,
OpenFrom DATE NOT NULL ,
OpenLength INTERVAL DAY (1) TO SECOND (2) NOT NULL ,
);
First thing that comes to mind is
1) Check if wanted_time > beginning_time
2) If yes, check if wanted_time < beginning_time + interval
But I don't think this would work, because in the last scenario the condition would be
1) 21:00 > 20:00? OK
2) 21:00 < 02:00? FAIL
So what would be the correct way to do this?
Edit: related question: when comparing like this: TO_DATE('14:00', 'HH24:MI') >= OPENFROM, and OPENFROM is of DATE type, does the comparison ignore everything except hours and minutes ?
You can try:
to_date(to_char(OpenFrom , 'yyyymmdd') || <<your_time>>, 'yyyymmddhh24:mi')
between OpenFrom and OpenFrom + OpenLength
EDIT:
Try:
to_date(to_char(OpenFrom , 'yyyymmdd') || <<your_time>>, 'yyyymmddhh24:mi')
between OpenFrom and OpenFrom + OpenLength
or
to_date(to_char(OpenFrom + OpenLength , 'yyyymmdd') || <<your_time>>, 'yyyymmddhh24:mi')
between OpenFrom and OpenFrom + OpenLength
Here is a sqlfiddle demo
I'm having date as 41293 in oracle, how can i show it in DD/MON/YYYY format?
If i copy pasted it in Excel and change it to date format, it shows 01/19/13
Please help me.
The value you have is the number of days since the 30th of December 1899. Try:
select to_char(
to_date('1899-12-30', 'YYYY-MM-DD') + 41293,
'DD/MON/YYYY') from dual
Quoting from Oracle forum:
You need a tool to do that, since format is to tell oracle what type of format you have on your date type in the spreadsheet. While you may not have opted to format the date in Excel, it will appear as a date in the previewer. Use the format from this as a guide to enter into the datatype panel.
so, if you have a date that looks like this in the previewer, 19-jan-2006, then your format for the data type panel if you choose to insert that column is going to be DD-MON-YYYY,
Option 1:
Try using the below functions
FUNCTION FROMEXCELDATETIME ( ACELLVALUE IN VARCHAR2 )
RETURN TIMESTAMP
IS
EXCEL_BASE_DATE_TIME CONSTANT TIMESTAMP
:= TO_TIMESTAMP ( '12/31/1899',
'mm/dd/yyyy' ) ;
VAL CONSTANT NUMBER
:= TO_NUMBER ( NULLIF ( TRIM ( ACELLVALUE ),
'0' ) ) ;
BEGIN
RETURN EXCEL_BASE_DATE_TIME
+ NUMTODSINTERVAL ( VAL
- CASE
WHEN VAL >= 60
THEN
1
ELSE
0
END,
'DAY' );
END;
FUNCTION TOEXCELDATETIME ( ATIMESTAMP IN TIMESTAMP )
RETURN VARCHAR2
IS
EXCEL_BASE_DATE_TIME CONSTANT TIMESTAMP
:= TO_TIMESTAMP ( '12/31/1899',
'mm/dd/yyyy' ) ;
DIF CONSTANT INTERVAL DAY ( 9 ) TO SECOND ( 9 )
:= ATIMESTAMP
- EXCEL_BASE_DATE_TIME ;
DAYS CONSTANT INTEGER := EXTRACT ( DAY FROM DIF );
BEGIN
RETURN CASE
WHEN DIF IS NULL
THEN
''
ELSE
TO_CHAR ( DAYS
+ CASE
WHEN DAYS >= 60
THEN
1
ELSE
0
END
+ ROUND ( ( EXTRACT ( HOUR FROM DIF )
+ ( EXTRACT ( MINUTE FROM DIF )
+ EXTRACT ( SECOND FROM DIF )
/ 60 )
/ 60 )
/ 24,
4 ) )
END;
END;
Option 2:
The excel function would be =TEXT(B2,"MM/DD/YY"), to convert an Excel date value stored in B2. Then try using the test character in Oracle
If considering 1900 Jan 1st as start date,
SELECT
TO_CHAR ( TO_DATE ( '1900-01-01',
'YYYY-MM-DD' )
+ 41293,
'DD/MON/YYYY' )
FROM
DUAL
Microsoft's Documentation
Excel stores dates as sequential serial numbers so that they can be used in calculations. January 1, 1900 is serial number 1, and January 1, 2008 is serial number 39448 because it is 39,447 days after January 1, 1900.
Excel has a bug feature where it considers 1900 to be a leap year and day 60 is 1900-02-29 but that day never existed and a correction needs to be applied for this erroneous day.
It does also state that:
Microsoft Excel correctly handles all other leap years, including century years that are not leap years (for example, 2100). Only the year 1900 is incorrectly handled.
Therefore only a single correction is required.
So:
Before 1900-03-01 you can use DATE '1899-12-31' + value.
On or after 1900-03-01 you can use DATE '1899-12-30' + value.
Which can be put into a CASE statement:
SELECT CASE
WHEN value >= 1 AND value < 60
THEN DATE '1899-12-31' + value
WHEN value >= 60 AND value < 61
THEN NULL
WHEN value >= 61
THEN DATE '1899-12-30' + value
END AS converted_date
FROM your_table
In Oracle, is there a function that calculates the difference between two Dates? If not, is a way to display the difference between two dates in hours and minutes?
Query:
SELECT Round(max((EndDate - StartDate ) * 24), 2) as MaximumScheduleTime,
Round(min((EndDate - StartDate) * 24), 2) as MinimumScheduleTime,
Round(avg((EndDate - StartDate) * 24), 2) as AveragegScheduleTime
FROM table1
You can subtract two dates in Oracle. The result is a FLOAT which represents the number of days between the two dates. You can do simple arithmetic on the fractional part to calculate the hours, minutes and seconds.
Here's an example:
SELECT TO_DATE('2000/01/02:12:00:00PM', 'yyyy/mm/dd:hh:mi:ssam')-TO_DATE('2000/01/01:12:00:00AM', 'yyyy/mm/dd:hh:mi:ssam') DAYS FROM DUAL
Results in: 1.5
You can use these functions :
1) EXTRACT(element FROM temporal_value)
2) NUMTOYMINTERVAL (n, unit)
3) NUMTODSINTERVAL (n, unit).
For example :
SELECT EXTRACT(DAY FROM NUMTODSINTERVAL(end_time - start_time, 'DAY'))
|| ' days ' ||
EXTRACT(HOUR FROM NUMTODSINTERVAL(end_time - start_time, 'DAY'))
||':'||
EXTRACT(MINUTE FROM NUMTODSINTERVAL(end_time - start_time, 'DAY'))
||':'||
EXTRACT(SECOND FROM NUMTODSINTERVAL(end_time - start_time, 'DAY'))
"Lead Time"
FROM table;
With Oracle Dates, this is pretty
trivial, you can get either TOTAL
(days, hours, minutes, seconds)
between 2 dates simply by subtracting
them or with a little mod'ing you can
get Days/Hours/Minutes/Seconds
between.
http://asktom.oracle.com/tkyte/Misc/DateDiff.html
Also, from the above link:
If you really want 'datediff' in your
database, you can just do something
like this:
SQL> create or replace function datediff( p_what in varchar2,
2 p_d1 in date,
3 p_d2 in date ) return number
4 as
5 l_result number;
6 begin
7 select (p_d2-p_d1) *
8 decode( upper(p_what),
9 'SS', 24*60*60, 'MI', 24*60, 'HH', 24, NULL )
10 into l_result from dual;
11
11 return l_result;
12 end;
13 /
Function created
Q: In Oracle, is there a function that calculates the difference between two Dates?
Just subtract one date expression from another to get the difference expressed as a number of days. The integer portion is the number of whole days, the fractional portion is the fraction of a day. Simple arithmetic after that, multiply by 24 to get hours.
Q: If not, is a way to display the difference between two dates in hours and minutes?
It's just a matter of expressing the duration as whole hours and remainder minutes.
We can go "old school" to get durations in hhhh:mi format using a combination of simple builtin functions:
SELECT decode(sign(t.maxst),-1,'-','')||to_char(floor(abs(t.maxst)/60))||
decode(t.maxst,null,'',':')||to_char(mod(abs(t.maxst),60),'FM00')
as MaximumScheduleTime
, decode(sign(t.minst),-1,'-','')||to_char(floor(abs(t.minst)/60))||
decode(t.minst,null,'',':')||to_char(mod(abs(t.minst),60),'FM00')
as MinimumScheduleTime
, decode(sign(t.avgst),-1,'-','')||to_char(floor(abs(t.avgst)/60))
decode(t.avgst,null,'',':')||to_char(mod(abs(t.avgst),60),'FM00')
as AverageScheduleTime
FROM (
SELECT round(max((EndDate - StartDate) *1440),0) as maxst
, round(min((EndDate - StartDate) *1440),0) as minst
, round(avg((EndDate - StartDate) *1440),0) as avgst
FROM table1
) t
Yeah, it's fugly, but it's pretty fast. Here's a simpler case, that shows better what's going on:
select dur as "minutes"
, abs(dur) as "unsigned_minutes"
, floor(abs(dur)/60) as "unsigned_whole_hours"
, to_char(floor(abs(dur)/60)) as "hhhh"
, mod(abs(dur),60) as "unsigned_remainder_minutes"
, to_char(mod(abs(dur),60),'FM00') as "mi"
, decode(sign(dur),-1,'-','') as "leading_sign"
, decode(dur,null,'',':') as "colon_separator"
from (select round(( date_expr1 - date_expr2 )*24*60,0) as dur
from ...
)
(replace date_expr1 and date_expr2 with date expressions)
let's unpack this
date_expr1 - date_expr2 returns difference in number of days
multiply by 1440 (24*60) to get duration in minutes
round (or floor) to resolve fractional minutes into integer minutes
divide by 60, integer quotient is hours, remainder is minutes
abs function to get absolute value (change negative values to positive)
to_char format model FM00 give two digits (leading zeros)
use decode function to format a negative sign and a colon (if needed)
The SQL statement could be made less ugly using a PL/SQL function, one that takes two DATE arguments a duration in (fractional) days and returns formatted hhhh:mi
(untested)
create function hhhhmi(an_dur in number)
return varchar2 deterministic
is
begin
if an_dur is null then
return null;
end if;
return decode(sign(an_dur),-1,'-','')
|| to_char(floor(abs(an_dur)*24))
||':'||to_char(mod((abs(an_dur)*1440),60),'FM00');
end;
With the function defined:
SELECT hhhhmi(max(EndDate - StartDate)) as MaximumScheduleTime
, hhhhmi(min(EndDate - StartDate)) as MinimumScheduleTime
, hhhhmi(avg(EndDate - StartDate)) as AverageScheduleTime
FROM table1
You can use the months_between function to convert dates to the difference in years and then use between the decimal years you are interested:
CASE
WHEN ( ( MONTHS_BETWEEN( TO_DATE(date1, 'YYYYMMDD'),
TO_DATE(date1,'YYYYMMDD'))/12
)
BETWEEN Age1DecimalInYears AND Age2DecimalInYears
)
THEN 'It is between the two dates'
ELSE 'It is not between the two dates'
END;
You may need to change date format to match the a given date format and verify that 31 day months work for your specific scenarios.
References:
( found on www on 05/15/2015 )
1. Oracle/PLSQL: MONTHS_BETWEEN Function
2. Oracle Help Center - MONTHS_BETWEEN
I need to add 30 minutes to values in a Oracle date column. I do this in my SELECT statement by specifying
to_char(date_and_time + (.000694 * 31)
which works fine most of the time. But not when the time is on the AM/PM border. For example, adding 30 minutes to 12:30 [which is PM] returns 1:00 which is AM. The answer I expect is 13:00. What's the correct way to do this?
In addition to being able to add a number of days to a date, you can use interval data types assuming you are on Oracle 9i or later, which can be somewhat easier to read,
SQL> ed
Wrote file afiedt.buf
SELECT sysdate, sysdate + interval '30' minute FROM dual
SQL> /
SYSDATE SYSDATE+INTERVAL'30'
-------------------- --------------------
02-NOV-2008 16:21:40 02-NOV-2008 16:51:40
All of the other answers are basically right but I don't think anyone's directly answered your original question.
Assuming that "date_and_time" in your example is a column with type DATE or TIMESTAMP, I think you just need to change this:
to_char(date_and_time + (.000694 * 31))
to this:
to_char(date_and_time + (.000694 * 31), 'DD-MON-YYYY HH24:MI')
It sounds like your default date format uses the "HH" code for the hour, not "HH24".
Also, I think your constant term is both confusing and imprecise. I guess what you did is calculate that (.000694) is about the value of a minute, and you are multiplying it by the number of minutes you want to add (31 in the example, although you said 30 in the text).
I would also start with a day and divide it into the units you want within your code. In this case, (1/48) would be 30 minutes; or if you wanted to break it up for clarity, you could write ( (1/24) * (1/2) ).
This would avoid rounding errors (except for those inherent in floating point which should be meaningless here) and is clearer, at least to me.
UPDATE "TABLE"
SET DATE_FIELD = CURRENT_TIMESTAMP + interval '48' minute
WHERE (...)
Where interval is one of
YEAR
MONTH
DAY
HOUR
MINUTE
SECOND
from http://www.orafaq.com/faq/how_does_one_add_a_day_hour_minute_second_to_a_date_value
The SYSDATE pseudo-column shows the current system date and time. Adding 1 to SYSDATE will advance the date by 1 day. Use fractions to add hours, minutes or seconds to the date
SQL> select sysdate, sysdate+1/24, sysdate +1/1440, sysdate + 1/86400 from dual;
SYSDATE SYSDATE+1/24 SYSDATE+1/1440 SYSDATE+1/86400
-------------------- -------------------- -------------------- --------------------
03-Jul-2002 08:32:12 03-Jul-2002 09:32:12 03-Jul-2002 08:33:12 03-Jul-2002 08:32:13
I prefer using an interval literal for this, because interval '30' minute or interval '5' second is a lot easier to read then 30 / (24 * 60) or 5 / (24 * 60 * 69)
e.g.
some_date + interval '2' hour
some_date + interval '30' minute
some_date + interval '5' second
some_date + interval '2' day
You can also combine several units into one expression:
some_date + interval '2 3:06' day to minute
Adds 2 days, 3 hours and 6 minutes to the date value
The above is also standard SQL and also works in several other DBMS.
More details in the manual: https://docs.oracle.com/database/121/SQLRF/sql_elements003.htm#SQLRF00221
If the data type of the field is date or timestamp, Oracle should always give the correct result if you add the correct number given in number of days (or a the correct fraction of a day in your case). So if you are trying to bump the value in 30 minutes, you should use :
select field + 0.5/24 from table;
Based on the information you provided, I believe this is what you tried to do and I am quite sure it works.
Can we not use this
SELECT date_and_time + INTERVAL '20:00' MINUTE TO SECOND FROM dual;
I am new to this domain.
like that very easily
i added 10 minutes to system date and always in preference use the Db server functions not custom one .
select to_char(sysdate + NUMTODSINTERVAL(10,'MINUTE'),'DD/MM/YYYY HH24:MI:SS') from dual;
Be sure that Oracle understands that the starting time is PM, and to specify the HH24 format mask for the final output.
SELECT to_char((to_date('12:40 PM', 'HH:MI AM') + (1/24/60) * 30), 'HH24:MI') as time
FROM dual
TIME
---------
13:10
Note: the 'AM' in the HH:MI is just the placeholder for the AM/PM meridian indicator. Could be also 'PM'
Oracle now has new built in functions to do this:
select systimestamp START_TIME, systimestamp + NUMTODSINTERVAL(30, 'minute') end_time from dual
Based on what you're asking for, you want the HH24:MI format for to_char.
To edit Date in oracle you can try
select to_char(<columnName> + 5 / 24 + 30 / (24 * 60),
'DD/MM/RRRR hh:mi AM') AS <logicalName> from <tableName>
SELECT to_char(sysdate + (1/24/60) * 30, 'dd/mm/yy HH24:MI am') from dual;
simply you can use this with various date format....