how to print same randomint after if/elif? - python-2.6

Question

I want to get randint to be printed the same as in the if/elif statements each time it executes without a new integer returning. Also is there another way instead of having to write so much code after the while statement or is it fine?
from random import *
def randomchance():
return randint(1, 100)
def randomknife():
return randint(1, 8)
skins = ['blue', 'purple', 'pink', 'red']
knives = ['karambit', 'flip', 'bowie', 'butterfly', 'm9 bayonet', 'bayonet', 'daggers', 'falchion']
print 'Welcome to CS GO case lottery'
for skin in skins:
print "Available", skin,
for knife in knives:
print "Available", knife,
print '(blue = common, purple = uncommon, pink = rare, red = epic)'
keys = 10
while keys >0:
resp=raw_input("Enter 'yes' to open a case: ")
if (resp == str('yes') or resp == str('Yes')):
print 'Opening case...'
if (randomchance() >= 35):
print 'You\'ve won a', skins[0]
elif (randomchance() >= 20):
print 'You\'ve won a', skins[1]
elif (randomchance() >= 10):
print 'You\'ve won a', skins[2]
elif (randomchance() >= 5):
print 'You\'ve won a', skins[3]
elif (randomchance() >= 1):
if randomknife == 1:
print 'You\'ve won a', knifes[0]
elif randomknife() == 2:
print 'You\'ve won a', knifes[1]
elif randomknife() == 3:
print 'You\'ve won a', knifes[2]
elif randomknife() == 4:
print 'You\'ve won a', knifes[3]
elif randomknife() == 5:
print 'You\'ve won a', knifes[4]
elif randomknife() == 6:
print 'You\'ve won a', knifes[5]
elif randomknife() == 7:
print 'You\'ve won a', knifes[6]
elif randomknife() == 8:
print 'You\'ve won a', knifes[7]
keys -= 1
elif(resp == str('no') or resp==str('No')):
resp1=raw_input('Would you like to exit? Enter no for exit: ')
if resp1 == 'no' or "No":
exit()
else:
print "Yes or No. Answers only"
else:
print 'You\'ve run out of keys!'

Answer 1

#Konstantin has the right answer for how to choose the random number just once before testing all your conditions.
As to your second question (how to use less code to test all the conditions), take a look at my rewrite/cleanup below. In particular, I used random.choice to pick a knife, and I used a list of thresholds (35, 20, etc.) to pick skins.
I also fixed up a couple bugs, like your if resp1 == 'no' or "No": which should be if resp1 == 'no' or resp1 == "No": (but I used resp1.lower() instead).
And I couldn't stand 'Would you like to exit? Enter no for exit: ', so I made "yes" exit instead. :-)
import random
skins = ['blue', 'purple', 'pink', 'red']
knives = ['karambit', 'flip', 'bowie', 'butterfly', 'm9 bayonet', 'bayonet', 'daggers', 'falchion']
print 'Welcome to CS GO case lottery'
print "Available skins: %s" % ', '.join(skins)
print "Available knives: %s" % ', '.join(knives)
print '(blue = common, purple = uncommon, pink = rare, red = epic)'
for _ in range(10):
resp = raw_input("Enter 'yes' to open a case: ")
while resp.lower() != 'yes':
if resp.lower() == 'no':
if raw_input('Would you like to exit? ').lower() == 'yes':
exit()
else:
print "Yes or no answers only."
resp = raw_input("Enter 'yes' to open a case: ")
print 'Opening case...'
chance = random.randint(1, 100)
for i, n in enumerate([35, 20, 10, 5]):
if chance >= n:
print "You've won a %s skin." % skins[i]
break
if chance < 5:
print "You've won a %s knife." % random.choice(knives)
print "You've run out of keys!"

Answer 2

Try to save to a variable before if/else statement:
number = randomchance();
if (number >= 35): print 'you select a ', number

Answer 3

This is how I would do it:
knives = ['karambit', 'flip', 'bowie', 'butterfly', 'm9 bayonet', 'bayonet', 'daggers', 'falchion']
skins = ['blue'] * 35 + ['purple'] * 20 + ['pink'] * 10 + ['red'] * 5 + [0]
skin = random.choice(skins)
print "You won a " + skin + " skin" if skin else "You won a " + random.choice(knives) + " knife"