Using scss/sass trailing ampersand to target one level back - sass

Question

I have two types of circles, one inside of .poi.licensed and one inside of .poi.unlicensed. I am trying to make it so that the .circle inside of .poi.unlicensed has a $tangerine border instead of $turqoise. How can I used the trailing amerpsand to do so in this situation. Keep in mind that there is a lot of other scss that I am excluding that is unrelated, so it has to stay in this general structure.
I was trying something along the lines of the following, but it compiles to .unlicensed #licensed-v-unlicensed .poi .circle {}
$turqoise: #40e8e3;
$tangerine: #ffa975;
#licensed-v-unlicensed {
.poi {
.circle {
border: 5px solid transparentize($turqoise, 0.1);
.unlicensed & {
border: 5px solid transparentize($tangerine, 0.1);
}
#include breakpoint(medium up) {
border-width: 10px;
}
border-radius: 50%;
box-shadow: 0px 0px 5px rgba(0, 0, 0, 0.4);
width: 100%;
height: 100%;
position: relative;
cursor: pointer;
}
}
}

Answer 1

I ended up using a trick I found on this blog, which was to use #at-root in order to start at the root and target the .unlicensed class. It's a lot more work than I had hoped to do, but the only solution discovered thus far.
$turqoise: #40e8e3;
$tangerine: #ffa975;
#licensed-v-unlicensed {
.poi {
.circle {
border: 5px solid transparentize($turqoise, 0.1);
#at-root #licensed-v-unlicensed .poi.unlicensed .circle {
border: 5px solid transparentize($tangerine, 0.1);
}
#include breakpoint(medium up) {
border-width: 10px;
}
border-radius: 50%;
box-shadow: 0px 0px 5px rgba(0, 0, 0, 0.4);
width: 100%;
height: 100%;
position: relative;
cursor: pointer;
}
}
}