welcome page after running dynamic web project [duplicate] - spring

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Set default home page via <welcome-file> in JSF project
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Closed 6 years ago.
I'm trying to let a welcome page displaying after running a dynamic web project.
When googling I found a lot of tutorials but I can't found the solution.
I share:
The structure of my project (I want that the page welcome.xhtml will displayed by default).
The file web.xml is:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
id="WebApp_ID"
version="3.0">
<display-name>HiSpring</display-name>
<welcome-file-list>
<welcome-file>welcome.xhtml</welcome-file>
</welcome-file-list>
<context-param>
<description>State saving method: 'client' or 'server' (=default). See JSF Specification 2.5.2</description>
<param-name>javax.faces.STATE_SAVING_METHOD</param-name>
<param-value>client</param-value>
</context-param>
<context-param>
<param-name>javax.servlet.jsp.jstl.fmt.localizationContext</param-name>
<param-value>resources.application</param-value>
</context-param>
<listener>
<listener-class>com.sun.faces.config.ConfigureListener</listener-class>
</listener>
<servlet>
<servlet-name>Faces Servlet</servlet-name>
<servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>/faces/*</url-pattern>
</servlet-mapping>
</web-app>
Once clicking on HiSpring > Run As > Run on Server, I should have
This url: http://localhost:8080/HiSpring/faces/welcome.xhtml. However, I got http://localhost:8080/HiSpring/.
Could you please tell me what I missed; Thanks in advance.

According to your web.xml tomcat would look for /welcome.xhtml and has no clue that this might be in /faces/welcome.xhtml. The URL is fine (if welcome.xhtml is in /)
There might be a more elegant JSF version (I'm not much of a JSF guy) - some possible solutions that come to my mind would be
map the faces servlet to *.xhtml do remove the /faces/ part from path (you judge if this is proper JSF - comment if it's not and I'll remove this part)
create a separate explicit redirection, e.g. through a (stupidly simple) index.html (of course, declare index.html as another welcome file) like the following sample:
<html>
<head><title>Redirection</title>
<meta http-equiv="refresh" content="2;URL=/faces/">
<!-- 2 means 2 seconds delay. Change as you like -->
</head>
<body>
<p>redirecting to application. Click here if it doesn't work</p>
</body>
</html>

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My welcome-file is returning an empty page in Open Liberty

On Open Liberty 21.0.0.6., instead of presenting my welcome JSF page, my browser returns empty content when I point it to http://<host>:<port>/<ctxRoot>,
web.xml
<web-app id="WebApp_ID" version="4.0"
xmlns="http://xmlns.jcp.org/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_4_0.xsd">
<display-name>MyJSF</display-name>
<servlet>
<servlet-name>Faces Servlet</servlet-name>
<servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>*.xhtml</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.xhtml</welcome-file>
</welcome-file-list>
</web-app>
and a feature set of:
server.xml
<server>
<featureManager>
<feature>jaxrs-2.1</feature>
<feature>cdi-2.0</feature>
<feature>jpa-2.2</feature>
<feature>jdbc-4.3</feature>
<feature>jsf-2.3</feature>
<feature>mpHealth-3.0</feature>
</featureManager>
ADDITIONAL INFO
I also have some other stuff in my app like JPA and JAX-RS.
ROOT CAUSE - JAX-RS application with "/" application path
In my case the problem is that I had a JAX-RS Application configured to use: #ApplicationPath("/") which was colliding with my goal of having the "/" application path serve up the welcome-file.
SOLUTION
Move the JAX-RS app to its own path within the WAR, e.g:
import javax.ws.rs.core.Application;
#ApplicationPath("/api")
public class TestApp extends Application { }
THOUGHTS
This was easy to stumble into by taking an existing simple JAX-RS app using "/" as the app path, and then adding JSF to it. Then I thought I was having trouble with the JSF implementation.

Spring Websocket, 404 error while connecting. App not using Spring MVC

I'm trying to get working the Spring Example tutorial:
https://spring.io/guides/gs/messaging-stomp-websocket/
But I need it working on an existing Application that I need to add WebSocket support. The idea is once I get the basic working, start building from there.
The differences I have with the example in the URL is:
I'm not using SpringBootApplication, but Tomcat instead (7.0.69)
That implies I do have a web.xml (included below)
I skipped the Application.java with the main... I'm building a WAR and deploying it manually into Tomcat.
Whem I start Tomcat I read the following which seems relevant:
03:06:52,908 INFO SimpleBrokerMessageHandler:157 - Starting...
03:06:52,908 INFO SimpleBrokerMessageHandler:260 - BrokerAvailabilityEvent[available=true, SimpleBrokerMessageHandler [DefaultSubscriptionRegistry[cache[0 destination(s)], registry[0 sessions]]]]
03:06:52,913 INFO SimpleBrokerMessageHandler:166 - Started.
The problem is the following:
When I click on connect on the index.html, I get a 404 when I'm trying to reach the server at the mapping url "/hello" (not sure why info is there, I guess is part of the protocol..) http://localhost:8080/hello/info
I was googling this, even found some answers in stackoverflow. Some have fixed this addding as prefix the DispatcherServlet mapping to the websocket url...
However my app isn't using Spring MVC, so I don't have a DispatcherServlet configured... and I looks like an overkill to include it just for the WebSockets.
I tried adding the annotation #EnableWebMvc to the WebSocketConfig class (in the link is the code, I have the same lines)
Any suggestion will be much appreciated !
WEB.XML
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
id="WebApp_ID" version="3.0">
<display-name>App</display-name>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/classes/applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<listener>
<listener-class>org.springframework.web.context.request.RequestContextListener</listener-class>
</listener>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
I give up trying to avoid having an MVC Dispatcher for an APP witch doesn't use Spring MVC.
This solved it:
web.xml
<servlet>
<!-- Only used by websockets -->
<servlet-name>SpringMVCDispatcherServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/classes/websockets-application-config.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>SpringMVCDispatcherServlet</servlet-name>
<url-pattern>/ws/*</url-pattern>
</servlet-mapping>
And then, in the index.html I only added the prefix /ws/ when connecting (only there, sinding messages without the prefix is ok).

<async-supported>true</async-supported> in web.xml

Someone help me plss, i got this error when i put async-supported tag in web.xml:
cvc-complex-type.2.4.a: Invalid content was found starting with element 'async-supported'. One of '{"http://java.sun.com/xml/ns/javaee":run-as, "http://java.sun.com/xml/ns/javaee":security-role-ref}' is expected.
this is my web.xml
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
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<servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>jersey.config.server.provider.packages</param-name>
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<servlet-name>Jersey Web Application</servlet-name>
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The web.xml goes of an XML schema. If you're not familiar with XML schemas, they describe what elements and attributes an XML document can contain in order to be a valid instance of that schema.
That being said, you can see in the schema location the version of the schema file being used, i.e. ...web-app_2_5.xsd. This means that your web.xml is going to be based on that version of the schema, which maps to that version of the servlet specification, which in your case is 2.5. The problem with this is that async is not introduced to the servlet spec until 3.0. So there is no element specification in the 2.5 schema. So when the xml is being validated, it's saying that not such element <async-supported> is allowed in the document, as it doesn't comply to the schema.
To fix it, just change the version to 3.0 and the schema file to 3_0
<!-- change to 3.0 -->
<web-app version="3.0"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<!-- change to 3_0 -->

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I am integrating my Crystal Report code with Spring Framework.
Initially I had developed simple web application with only jsps (without spring feature) and CRystal Reports are rendering properly. I had tested it with parameters and DB connection Also.
Now I am trying to integrate it with Spring framework. I did all necessary set-up.
Reports are rendering properly, with parameters and DB connection. But when I click on subreport link I am getting error.
"The viewer is unable to connect with the CrystalReportViewerServlet
that handles asynchronous requests. Please ensure that the Servlet and
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Also, images on reports are not displaying (showing cross).I tried to search on different forums but no luck.
Here is my web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5"> <display-name>CRWeb1</display-name>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<context-param>
<param-name>crystal_image_uri</param-name>
<param-value>/reports/crystalreportviewers</param-value>
</context-param>
<context-param>
<param-name>crystal_image_use_relative</param-name>
<param-value>reports</param-value>
</context-param>
<servlet>
<description></description>
<display-name>reports</display-name>
<servlet-name>reports</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet- class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>reports</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<servlet>
<display-name>reports</display-name>
<servlet-name>CrystalReportViewerServlet</servlet-name>
<servlet-class>com.crystaldecisions.report.web.viewer.CrystalReportViewerServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>CrystalReportViewerServlet</servlet-name>
<url-pattern>/CrystalReportViewerHandler</url-pattern>
</servlet-mapping>
</web-app>
Thanks,
Sarika

JSF new website creation

I have a JSF project and I already have an index.xhtml page which is working fine. When I try to add another XHTML page, for some reason it is not connected to my session scoped managed bean. I add the code in my new page but it doesn't work like my index.xhtml. I even copy and pasted the code from index and it still does not work. Any thoughts?
Here is some of the code I have in my new page:
Amount: <h:inputText value="#{transactionBean.amount}" style="color: Yellow; background: Teal;"/>
Price <h:inputText value="#{transactionBean.pricePaid}" style="color: Yellow; background: Teal;"/
Here is my web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
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</context-param>
<servlet>
<servlet-name>Faces Servlet</servlet-name>
<servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
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<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>/faces/*</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>
30
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You've mapped the faces servlet on /faces/* instead of *.xhtml. This means that you need to include /faces path in the URL to get the faces servlet to run.
So, you should not open the page by
http://localhost:8080/SharePortfolioJSF/companies.xhtml
but instead by
http://localhost:8080/SharePortfolioJSF/faces/companies.xhtml
Much better, however, is to just use *.xhtml as URL pattern of the faces servlet, so that you don't need to fiddle with virtual paths.
<servlet>
<servlet-name>Faces Servlet</servlet-name>
<servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>*.xhtml</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.xhtml</welcome-file>
</welcome-file-list>
(note that your <session-timeout> of 30 minutes is the default already, just remove it)
From the comments:
Your second page isn't processed by the faces servlet. Your url pattern for the faces servlet is /faces/*. So all requests must contain the prefix /faces in order to get processed by the servlet.
It should work if you call your page with the following URL:
http://localhost:8080/SharePortfolioJSF/faces/companies.xhtml

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