Bash: get multiple value from text file in the same line - bash

Question

i have a text file with 2 string per line, i need make a curl command whith these vales
text file:
www.example.com 38494740
www.example.org 49347398
www.example.net 94798340
I need create a command curl for lines, eg.
curl www.example.com/38494740
curl www.example.org/49347398
curl www.example.net/94798340
I have considerate while but i have 2 string per line....
UPDATE:
I need use these values as variable, the command can also be this way curl www.exmple.com/foo/38494740

Answer 1

awk -v OFS="/" '{$1=$1}1' curl
www.example.com/38494740
www.example.org/49347398
www.example.net/94798340
Explanation :
OFS defines how your output fields would be separated. Here its set to "/".
{$1=$1} : is to make awk to reconstruct the records so new OFS will come into effect.
1: is awk's default action to print the line.
As per comments :
while read domain sub
do
curl "$domain"/"$sub"
done < curl

Answer 2

This is one foolproof way of getting it done.
#!/bin/bash
while read -r url port; # Read the tab-spaced file for the 'url' and 'port'
do
curl "${url}"/"${port}" # Construct the URL as "url/port" to run curl command on it
done < file

Answer 3

while read hostname number ; do echo "curl ${hostname}/${number}" ; done < inputFile
Output:
curl www.example.com/38494740
curl www.example.org/49347398
curl www.example.net/94798340

Answer 4

One easy solution is to just use tr to translate all spaces to /:
tr ' ' '/' < inputfile