I am using VS2013, and i want replace some text. Because the file has many alike word， so i have to use regex look ahead, look behind so search and replace.
text.txt:
abc adc
regex:
(?<=a)([a-z])(?=c)
and replace with
xxx$1xxx
But failed to replace all, Anyone konw this why?
Related
Using the variable $TM_DIRECTORY i get 'E:\Archivos\Trabajo\Projectos propios\Sistema wolf\sistema-contable-interface\src\pages\1.Landing'
If i apply this regex: ${TM_DIRECTORY/^.+\\\\(.*)$/$1/}
I get 1.Landing
The thing here is that i want to get just the word Landing. I dont really understand how this regex work. But i really need the snippet to print just the word
I have many text files, and I need to add some text (e.g. MNP) to the beginning of the first line in each file.
How can I do this in Notepad++?
(I'm using v6.6.9)
Make sure to backup your work beforehand, and set proper extension of files to affect and folder to search through before you do this.
You can use regular expressions. Several places around the internet claim that the regex \A works, but it wasn't working for me, it was cycling byte by byte through. I found that \A^ sticks to 0 position of the file.
Oddly, I additionally found that I couldn't replace \A or \A^ and have it take effect. This is what worked for me.
Find: \A^(.*?)
Replace MNP\1
Truthfully, the \1 in Replace isn't even necessary since I'm cheating and basically telling notepad to look for 0 characters.
This should work just as well.
Find: \A^.*?
Replace MNP
Please backup your work beforehand though.
Alternatively, this also seems to work.
Find: .{0}(.*)
Replace: MNP\1
It effectively looks for 0 characters followed by the whole document/line (depending on whether . matches newline is checked, this choice won't matter for the outcome however).
I'm new to regex's and Sublime's and am having issues trying to do a find/replace on all email addresses in a csv file.
I thought it would be reasonably straightforward but seem to be heading down the rabbit hole at a great rate of knots.
Data looks like;
data,data,email#address.com,data,data etc NB: there are about 100 fields per record and about 300 records
My thought was to look for the # symbol, then go left and right until I get to the comma and then replace with my new email address but I just can't get a win.
Any thoughts or am I using the wrong tool for the job?
(Also tagging with Ruby as if I need to do some scripting then I'll try to get figure it out in Ruby)
Thanks,
Liam
user2141046's expression won't find an email address like- "a.b#c.com"
I would suggest using:
[a-zA-Z0-9.!#$%&'+-/=?\^_`{|}~-]+#[a-zA-Z0-9-]+(?:.[a-zA-Z0-9-]+)
Source
I'm not familiar with the ruby language, but a regex that finds what you want is:
\w+\#\w+\.\w+
with the \. maybe unneeded (depending on language).
a perl one-liner that does the exact thing:
perl -pi -e 's/\w+\#\w+\.\w+/<your new email here>/g' <csv file here>
note
make sure you use \# in the enw email in the one liner i wrote, meaning new_email\#server.com
Try this:
[a-zA-Z0-9.!#$%&'*+-/=?\^_`{|}~-]+#[a-zA-Z0-9-]+(?:\.[a-zA-Z0-9-]+)*
It worked perfectly on a very long csv file filled with emails and all other kinds of stuff.
[a-zA-Z0-9.!#$%&'+-/=?\^_`{|}~-]+#[a-zA-Z0-9-]+(?:.[a-zA-Z0-9-]+)
will not work fine, because some domains have 2 or more levels (like com.br)
Use:
[a-zA-Z0-9.!#$%&'+-/=?\^_`{|}~-]+#[a-zA-Z0-9-]+(?:.[\.a-zA-Z0-9-]+)
I'm trying to create a regular (ruby) expression which checks for multiple conditions. I use this regex to replace the content of my object. My regex is close to finished, except two problems I'm facing with regard to markdown.
First of, headers are giving me trouble. For example, I don't want to replace the word "Hi" for "Hello" if "Hi" is in a header.
Hi John <== # should not change
==================
Text: Hi, how are you? <== # Should be: Hello, how are you? after substitution
Or:
#### Hi Peter <== # should not change
Text: Hi, how are you? <== # Should be: Hello, how are you? after substitution
Question: How can I escape markdown headers within my regex? I've tried negative lookbehind and lookahead assertions, but to no avail.
My second problem should be quite easy, but somehow I'm struggling. If words are Italic "hi" I want to find and replace them, without changing the underscores. I can find the word with this regex:
\b[_]*hi[_]*\b
Question 2: But if I would replace it, I would also change the underscores. Is there a way to only detect the word itself and replace it, while still using word boundaries?
Code Example
#website.autolinks.all.each do |autolink|
autolink.name #for example returns "Iphone5"
autolink.url #for example returns "http://www.apple.com"
regex = /\b(?<!##\s)(?<![\d.\[])([_]*)#{autolink.name}([_]*)(?![\d'"<\/a>])\b/
if #permalink.blog_entry.content.match(regex)
#permalink.blog_entry.content.gsub!(regex, "[#{autolink.name}](# {autolink.url})")
end
end
Example text
Iphone5
==============
Iphone5 is the best mobile phone there is, even though the people at Samsung probably think, or perhaps only hope that their Samsung Galaxy S3 is better.
#### Samsung Galaxy S3?
Yes, that's the name of the newest Samsung phone.
This will result in a text with HTML tags, but when I use my regex my content uses Markdown syntax (used before the markdown converter).
Regexes work best when they do one clear thing. If you have multiple conditions, your code should usually reflect that by dividing the processing into steps.
In this case, you have two clear steps:
Use a simple regex or other logic to skip over the header portion of the message.
Once you know you are in the content, use another regex to process the content.
I've found a solution:
regex = /(?<!##\s)(?<![\d.\[a-z])#{autolink.name}(?![\d'"a-z<\/a>])(?!.*\n(==|--))/i
if #permalink.blog_entry.content.match(regex)
#permalink.blog_entry.content.gsub!(regex, "[\\0](#{autolink.url})")
end
I'm having problems about a regexp.
I'm trying to implement a regex to select just the tab indent blocks, but i cant find a way of make it work:
Example:
INDENT(1)
INDENT(2)
CONTENT(a)
CONTENT(b)
INDENT(3)
CONTENT(c)
So I need blocks like:
INDENT(2)
CONTENT(a)
CONTENT(b)
AND
INDENT(3)
CONTENT(c)
How I can do this?
really tks, its almost that, here is my original need:
table
tr
td
"joao"
"joao"
td
"marcos"
I need separated "td" blocks, could i adapt your example to that?
It depends on exactly what you are trying to do, but maybe something like this:
^(\t+)(\S.*)\n(?:\1\t.*\n)*
Working example: http://www.rubular.com/r/qj3WSWK9JR
The pattern searches for:
^(\t+)(\S.*)\n - a line that begins with a tab (I've also captured the first line in a group, just to see the effect), followed by
(?:\1\t.*\n)* - lines with more tabs.
Similarly, you can use ^( +)(\S.*)\n(?:\1 .*\n)* for spaces (example). Mixing spaces and tabs may be a little problematic though.
For the updated question, consider using ^(\t{2,})(\S.*)\n(?:\1\t.*\n)*, for at least 2 tabs at the beginning of the line.
You could use the following regex to get the groups...
[^\s]*.*\r\n(?:\s+.*\r*\n*)*
this requires that your lines not begin with white space for the beginning of the blocks.