I have this dataframe
structure(list(plate = c("A", "A", "A", "A", "A", "B", "B", "B",
"B", "B", "C", "C", "C", "C", "C"), marker = c("IL-1", "IL-2",
"IL-3", "IL-4", "IL-5", "IL-1", "IL-2", "IL-3", "IL-4", "IL-5",
"IL-1", "IL-2", "IL-3", "IL-4", "IL-5"), sample = c(1, 2, 3,
4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15), result = c(1.94000836127381,
0.426353706529969, 2.07418521661429, 1.58200029160696, 0.812685661255674,
0.546681932009987, 0.199532997122114, 0.100208840148698, 0.720956738045624,
0.444814277410285, 2.25080298569014, 1.61429066532657, 1.1066027850052,
0.927880542016121, 4.1487948134003), LOD = c(0.810456546400942,
0.614177278086376, 0.98739611371029, 0.315142822914328, 0.221497734151459,
0.0191136249820546, 0.364139946842526, 0.983763479804491, 0.982034953153209,
0.851687364910033, 0.893324689832074, 0.978609354294382, 0.62613140416969,
0.0310439168600307, 0.729966088361143)), class = c("tbl_df",
"tbl", "data.frame"), row.names = c(NA, -15L))
As you can see I have different LOD values, for each marker in each plate. So I calculate the mean LOD for each marker using
lod <- dummy_2 |>
group_by (marker) |>
summarise(lod = mean(LOD))
which results in the following mean LOD per marker for all plates
structure(list(marker = c("IL-1", "IL-2", "IL-3", "IL-4", "IL-5"
), lod = c(0.57429828707169, 0.652308859741095, 0.865763665894824,
0.442740564309189, 0.601050395807545)), class = c("tbl_df", "tbl",
"data.frame"), row.names = c(NA, -5L))
So far so good. Now I want to check if the result of my markers are above or below my mean LOD. If it is above my mean LOD, the results must not be changed, if it is below my LOD, the result must be changed in the LOD/2.
I tried to use for loop and mutate in combination with ifelse, but that did not work. I also saw the accross function, but that also did not work. My latest try was...
marker <- unique(dummy_2$marker)
for (i in marker){
dummy_2 <- mutate(result = ifelse(i %in% dummy_2$result < dummy_2$LOD, (i %in% lod$LOD)/2), dummy_2$result)}
Is for loop the right way to go, or is there a better solution?
Any help would be appreciated..
Already found a solution by creating a new dataframe with my mean values and linked this together using left_join to my dataset. Still like to know if this could be possible with a for loop. But for now, problem solved....
I have a program that when I press a pushbutton it loads the options of my combombox, I have three, but for a unknown reason only two works. This function read a .txt file, and then put the strings in the combobox. I tried with addItem() and addItems(), made function again and it didn't work. The function read another two combobox and then loads the options.This is the function:
def cargar_combobox_flujos2(self,event):
anho = int(self.ui.combobox_anho.itemText(self.ui.combobox_anho.currentIndex()))
mes_input = self.ui.combobox_mes.itemText(self.ui.combobox_mes.currentIndex())
dic = {'Enero': 1, 'Febrero': 2, 'Marzo': 3, 'Abril': 4, 'Junio': 5, 'Julio': 7, 'Agosto': 8, 'Septiembre': 9,
'Octubre': 10, 'Noviembre': 11, 'Diciembre': 12}
mes = int(dic.get(mes_input))
lista_ssee=[]
nombre_txt='Graficos Flujos/lista_cbbx_'+str(anho)+'_'+str(mes)+'.txt'
if os.path.isfile(nombre_txt)==True:
archivo = open(nombre_txt, 'r')
c=archivo.read()
lista=c.split(',')
for i in lista:
lista_ssee.append(i)
archivo.close()
option_barras= self.ui.comboBox_barras_CMg2.count()
if option_barras > 1:
self.ui.comboBox_barras_CMg2.clear()
for barra in lista_ssee:
self.ui.comboBox_barras_CMg2.addItems(barra)
I am very new to ruby and I am trying to find if there's an equivalent way to doing the thing in ruby.
In yml syntax, we use a syntax similar to this way to have a default blob and then override them with specific values:
default:
default:
A: {read: 20, write: 10}
B: {read: 30, write: 30}
C: {read: 130, write: 10}
override1:
placeholderA:
A: {read: 10, write: 10}
override2:
placeHolderB:
A: {read: 10, write: 10}
B: {read: 5, write: 5}
C: {read: 5, write: 5}
D: {read: 5, write: 5}
I wanted to know if we can create a hash in ruby where in it will pick the values for the override if they exist, otherwise it will just pick the default value.
I am not sure if ruby merge map is an approach to this problem (since I am still new to ruby, I am exploring options).
Is this possible?
merge could be used:
options = {a:22}
my_defaults = {a:1, b:123}
my_defaults.merge(options)
> {a:22, b:123}
if you are using rails that also provides a reverse_merge which works the other way round and may be clearer to read intent from in some use cases
options = { a:2, b:321 }
my_defaults = {a:1, c:3}
options.reverse_merge(my_defaults)
> {a:2, b:321, c:3}
http://apidock.com/rails/Hash/reverse_merge
I haven't found a solution with data set up quite like mine...
var marketshare = [
{"store": "store1", "share": "5.3%", "q1count": 2, "q2count": 4, "q3count": 0},
{"store": "store2","share": "1.9%", "q1count": 5, "q2count": 10, "q3count": 0},
{"store": "store3", "share": "2.5%", "q1count": 3, "q2count": 6, "q3count": 0}
];
Code so far, returning undefined...
var minDataPoint = d3.min( d3.values(marketshare.q1count) ); //Expecting 2 from store 1
var maxDataPoint = d3.max( d3.values(marketshare.q2count) ); //Expecting 10 from store 2
I'm a little overwhelmed by d3.keys, d3.values, d3.maps, converting to array, etc. Any explanations or nudges would be appreciated.
I think you're looking for something like this instead:
d3.min(marketshare, function(d){ return d.q1count; }) // => 2.
You can pass an accessor function as the second argument to d3.min/d3.max.
Say I have the following table:
[
{numberOfRedStripes: 7, numberOfBlueStripes: 6, stars: 50, foo: "bar"},
{numberOfRedStripes: 1, numberOfBlueStripes: 1, stars: 0, something: "else"}
]
How can I use regex in order to pluck only the docs which their KEYS start with the string 'numberOf', so that the result would be:
[
{numberOfRedStripes: 7, numberOfBlueStripes: 6},
{numberOfRedStripes: 1, numberOfBlueStripes: 1}
]
?
Does this work?
table.map {|row|
row.pluck(r.args(row.keys().filter{|key| key.match("^numberOf")}))
}