parse template in view codeigniter - codeigniter

I am new to Codeigniter. I created a template for form and want to parse it within view file. It is parsing but it echos parsed form on the top of the page, not where I want. I am not using template for whole page. I want to render peace of page using parser.
Here is my parser:
<form action = {action}>
<select name = {input_name}>
{options}
<option value = {val}>{name}</option>
{/options}
</select>
And I called this template from my view.php using this function:
$this->parser->parse('form_templates/vehicle_category.php', $form_data);

I should look into the parser library. There is a third parameter for parse function which tells return result instead of echoing. Updated code is:
$this->parser->parse('form_templates/vehicle_category.php', $form_data, true); //true for return default is false

Related

Get Input Data Value in Controller in Laravel

I want to get the value of this input.
<input type="text" name="txtEmployeeNo" value='{{ $employee->employee_no }}'>
Its value is 53210. How can I get that in my controller?
I currently have this on my controller.
$employeeNum = $request->input('txtEmployeeNo');
$employeeSched = Schedule::where(['employee_no'=>$employeeNum])->get();
return view('admin.employeemaintenance.createSchedule',compact(,'employeeSched'));
The problem is when I open and see if it is fetched nothing is showing. I cannot get the input.
Try this, It should must work.
$employeeNum = (isset($request['txtEmployeeNo'])) ? $request['txtEmployeeNo'] : 0;
$employeeSched = Schedule::where(['employee_no'=>$employeeNum])->get();
return view('admin.employeemaintenance.createSchedule',$employeeSched);
In your controller insert this line after opening your function:
dd($request->all);
It will show you everything that has been posted through your form with values. If you get your 'txtEmployeeNo' without value, it means something went wrong when you insterted it in your input.
Check with dev tools if that specific input has any value.
If your input has the value you mentioned and your $request->all() still shows an empty value for your "txtEmployeeNo", then the error is in the HTML/Blade file.
Make sure you create the form correctly
Make sure your input's name equals with the request you are trying to receive in your controller.
If you get null as the value of the $request, that could mean, in your Blade file, the input also has it's value as null.
Try to manually insert a value like <input type="text" name="txtEmployeeNo" value="2"> and see if you get that in your controller. If you do, then the query in your input is wrong.
That's all I could think of without provided Blade and Controller code.
Try this:
$employeeNum = $request->input('txtEmployeeNo');
$employeeSched = Schedule::where('employee_no', $employeeNum)->get();
return view('admin.employeemaintenance.createSchedule',compact('employeeSched'));
well, here is an edit to this answer with the steps needed:
in your routes:
Route::post('yourRouteName','yourController#nameOfFunctionInController')->name('TheNameOfTheRoute');
In your controller:
public function nameOfFunction(Request $request) {
$employeeNum = $request->input('txtEmployeeNo');
$employeeSched = Schedule::where('employee_no', $employeeNum)->get();
return view('admin.employeemaintenance.createSchedule',compact('employeeSched'));
}
And that's it basically.

Thymeleaf + Spring how to pass to a controller a #PathVariable from a form select option value

I would like to use a select box to redirect to an URL containing the select value.
Here bellow the HTML page with thymeleaf variables :
<form th:action="#{/app/}">
<select id="app" name="app">
<option th:each="app : ${apps}"
th:value="${app.id}"
th:text ="${app.name}">
</option>
</select>
<button>Go</button>
</form>
The controller is written as following :
#RequestMapping("/app/{appId}")
public ModelAndView getApp(#PathVariable String appId){...}
My goal is to access the controller with the URL : mydomain/app/{app.id}/
I tried to use th:field onto the select without success. I'm missing something here.
Please, could you explain me how to add the select value to the URL expected by the controller ?
Thank you for the hints
EDIT following #NicolaiEhemann answer
I moved to javascript using jquery and ajax :
$('button').click(function() {
$.ajax({
url: '/app/' + $('#app').val(),
dataType: 'html'
}).done(function(data) {
$('#result').html(data)
});
});
Thank you.
Thymeleaf will only generate static html code. To achieve what you want, you have to write client side javascript to handle the 'input' event event to change the form action when a different value is selected, or handle the form 'submit' event to override the default action of the form submission. The relevant js code will probably be dependent on which framework you use.
Simply, add the path variable to the form action with double uderscores around
i.e. replace <form th:action="#{/app/}"> with <form th:action="#{/app/__${app.id}__">
source: http://forum.thymeleaf.org/Sending-pathvariable-to-controller-td4028739.html

Can't see variable inside content view in Laravel 4 with Blade

I have a problem understanding how variables work inside the Laravel templating system, Blade.
I set the variables in the controller, I can see them in the first view I make, but not inside the next one.
I'm using a master.blade.php file that holds the header and footer of the page, yielding the content in the middle. I can use the variable inside the master.blade.php file, but not inside the content blade file (variable undefined).
For example, for the contact page:
CONTROLLER FUNCTION:
$this->data['page'] = "contact";
$this->layout->content = View::make('pages.contact');
$this->layout->with('data', $this->data);
MASTER.BLADE.PHP:
if ($data['page'] == 'contact')
{ //do something, it works }
#yield('content')
CONTACT.BLADE.PHP:
if ($data['page'] == 'contact')
{// do something. ErrorException Undefined variable: data}
Am I missing something or is it a known restriction?
Thanks!
The problem was that I was passing the variables only to the layout:
Instead of:
$this->layout->content = View::make('pages.contact');
$this->layout->with('data', $this->data);
I fixed it using:
$this->layout->content = View::make('pages.contact', array('data' => $this->data));
$this->layout->with('data', $this->data);
This way passing the variables to the layout, but also to that particular view.
Hope it helps someone.

How to grab content from section within blade template

I have written a training application with each page/slide of the training workbook as a seperate blade template file named as "page1.blade.php", "page2.blade.php" and so on. Each of these files has content of the kind:
#extends('en/frontend/layouts/training_modulename')
{{-- Page title --}}
#section('title')
Page Title
#parent
#stop
{{-- Page content --}}
#section('pageContent')
<div class="pageContentContainer">
<h2>Page Title</h2>
...
</div>
#stop
This works really well when being viewed page by page within the browser. However I also wish to automatically compile all pages into a PDF document. This is being done via dompdf which works amazingly well when I pass each pages html to it manually. However I wish to condense the #section('pageContent') section of each page into one large section which extends a different layout for passing to dompdf.
Given the above context my question is this:
Is there a method in Laravel's blade parser which would allow me to pass it a blade file and just get the rendered html from a particular section? The below pseudo-code demonstrates what I would like to be able to do.
$pages = array(...); // content of the directory
foreach ($pages as $page)
{
$renderedPage = Blade::render($page);
$title = $renderedPage->title;
$pageContent = $renderedPage->pageContent;
}
Instead of doing the normal return of view
return View::make('page');
You can instead store the view in a string
$view = View::make('page');
So then you can do your code something like this (not tested - but you get the idea):
$pages = array(...); // content of the directory
foreach ($pages as $page)
{
$renderedPage[] = view::make($page);
}

Using MVC3, how to get browsers to explicitly interpret a transferred script as HTML?

In my MVC app, I am returning some Javascript. Howveer, I am using the anti-forgery token on the view, so the rendered result would be
<input name="__RequestVerificationToken" type="hidden" value="E8as+4Ff1u/c/+kuFcNXXCREB5pz5GAfH2krN5RvzURJaHZSApuRc4czZqmoITaKdy0XhN5sFfRzl4ne+wB3PkWOscBWzoIxUk3hGaFwDxRXSbMs8K9IwojEAtV5u57MR7hiSujr6MOTpjjbf5FPaYgO4gmH6lSR9mbSyO2IedI=" />
<script type="text/javascript">
// Here, we ensure that jQuery is loaded then load up the rest of our JS in in order.
ord = Math.random() * 10000000000000000;
...
So there is some HTML to be added to the page then the JS.
The issue is that I get the following notification in Chrome:
Resource interpreted as Script but transferred with MIME type
I need the browser to interpret this as HTML in order to make use of the anti-forgery token.
I have tried putting this on the view:
<%#Page Title="" Language="C#" ContentType="text/xml" %>
Which renders:
<%System.Web.WebPages.DynamicPageDataDictionary`1[System.Object] Title="" Language="C#" ContentType="text/xml" %>
<input name="__RequestVerificationToken" type="hidden"
...
...but the same message persists.
In my controller I have also tried:
System.Text.ASCIIEncoding encoding = new System.Text.ASCIIEncoding();
Byte[] bytes = encoding.GetBytes(page.clientScript);
return new ContentResult
{
ContentType = "text/xml", // also tried text/html
Content = Encoding.UTF8.GetString(bytes),
ContentEncoding = System.Text.Encoding.UTF8
};
Same issue.
-- UPDATE --
This is how I'm invoking the MVC app to return the text:
// used to load scripts on to the client script using a non-blocking asynch request
(function() {
function async_load(){
var s = document.createElement('script');
s.type = 'text/javascript';
s.async = true;
s.src = 'http://myserver/MyAppPath/someids';
var x = document.getElementsByTagName('script')[0];
x.parentNode.insertBefore(s, x);
}
if (window.attachEvent)
window.attachEvent('onload', async_load);
else
window.addEventListener('load', async_load, false);
})();
If I've understood correctly, you need an MVC action which returns both html and a script tag that can be injected in a page via a <script... include. You also want to render this via an MVC view.
The biggest issue you've missed is that in order to get this content into the calling page, you need to execute document.write from the script - you can't just send back HTML and script in response to the script include - the browser won't understand it, it's expecting javascript only.
There are a few ways to do this - I have written a full suite of ViewContent MVC controller methods, with the same overloads as View which returns the result of a view to a controller action as a string. I can then pass that back as a string literal (useful for html email generation) but also to a javascript encoder.
In this case, you don't need to be so generalist. We can leverage Darin Dimitrov's answer to this SO: Embed MVC Partial View into a document.write JS call and split your view into a View and a partial. The view writes the document.write() skeleton, and the partial view renders the dynamic html you want to be injected into the page. It's unclear if you're using the Anti Forgery Token in the main view which will call the script (in which case it should be rendered as part of the view that it returns) or if you're actually hard-coding it in the script. The second should definitely not be used but I'm writing this answer as if it is, because that appears to be what you want.
First, your partial view (let's call it Fragment.cshtml, put it in ~/Views/Shared)
<input name="__RequestVerificationToken"
type="hidden"value="[ommitted]" />
<script type="text/javascript">
// Here, we ensure that jQuery is loaded then load up the rest of our JS in in order.
ord = Math.random() * 10000000000000000;
...
Second, the host view, called SomeIds.cshtml
#{ Response.ContentType = "text/javascript"; }
document.write('#Html.Raw(HttpUtility.JavaScriptStringEncode(Html.Partial("~/Views/Shared/Fragment").ToHtmlString()))')
Now this view returns a document.write call that injects the HTML returned by the Fragment.cshtml into the page that includes the script.
Are you returning a PartialView that has all of the markup rendered?
Create a PartialView with your (form and script includes) and in your Controller:
public ActionResult Index(Models.MyModel model)
{
// validate the model if needed
return PartialView("[My PartialView Name]", model);
}
You could put your scripts in separate files, and add the [script src] tags in the PartialView.

Resources