I am new to Spring and Spring-MVC. I am using 4.3.3.RELEASE.I have generated project using maven-webapp-archetype and added sping dependencies and dispatcher-servelt later.
As per my web.xml I have initialized Dispatcher-servlet using spring-dispatcher-servlet.xml
I have already tried
Added inet.controller.* instead inet.controller in base-package
Changing URL pattern to /* from /
Adding to dispatcher servlet
but still when I try http://loclahost:8080/inet/welcome server is throwing 404.
Web.xml
<!DOCTYPE web-app PUBLIC
"-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd" >
<web-app>
<display-name>Archetype Created Web Application</display-name>
<servlet>
<servlet-name>spring-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>spring-dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
Spring-dispatcher-servlet.xml
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-4.3.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-4.3.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-4.3.xsd">
<mvc:default-servlet-handler />
<context:component-scan base-package="inet.controller"/>
<bean
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value>/WEB-INF/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
Below is my directory structure:
HelloController
package inet.controller;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.servlet.ModelAndView;
#Controller
public class HelloController {
#RequestMapping("/welcome")
public ModelAndView helloWorld() {
ModelAndView modelAndView = new ModelAndView("helloPage");
modelAndView.addObject("message", "Hi All");
return modelAndView;
}
}
You need to tell the spring how to find the controllers from urls that you are hitting. So it what is missing in your configuration
to do that add <mvc:annotation-driven/> tag in your dispatcher xml configuration. it adds some mapping handlers
RequestMappingHandlerMapping
RequestMappingHandlerAdapter
ExceptionHandlerExceptionResolver
And some necessary message converters for you.
What does <mvc:annotation-driven /> do?
Related
I am not very familiar with Spring MVC DriverManagerDataSource.I am trying to return a JSP from my controller. My Controller method is running well but when returning view, I'm getting a 404 error.
I don't know why I got this error If I'm telling this: in the web.xml
<servlet-mapping>
<servlet-name>spring</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
spring-servlet
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns = "http://www.springframework.org/schema/beans"
xmlns:xsi = "http://www.w3.org/2001/XMLSchema-instance"
xmlns:context = "http://www.springframework.org/schema/context"
xmlns:mvc = "http://www.springframework.org/schema/mvc"
xsi:schemaLocation =
"
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc.xsd
">
<context:component-scan base-package="controllers"></context:component-scan> <!-- com.javatpoint. -->
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/jsp/"></property>
<property name="suffix" value=".jsp"></property>
</bean>
<bean class = "org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name = "driverClassName" value = "com.mysql.jdbc.Driver"></property>
<property name = "url" value = "jdbc:mysql://localhost:3306/empleados"></property>
<property name = "username" value = "---"></property>
<property name = "password" value = "---"></property>
</bean>
<bean id="jt" class="org.springframework.jdbc.core.JdbcTemplate">
<property name="dataSource" ref="ds"></property>
</bean>
<bean id = "dao" class = "dao.EmpDao">
<property name = "template" ref = "jt"></property>
</bean>
</beans>
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0">
<display-name>SpringMVC</display-name>
<context-param>
<param-name>contextClass</param-name>
<param-value>
org.springframework.web.context.support.AnnotationConfigWebApplicationContext
</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>spring</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
HomeController.java
package EjemploCRUD.SpringMVC.controller;
import java.io.IOException;
import javax.servlet.http.HttpServletResponse;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.servlet.ModelAndView;
#Controller
public class HomeController {
#RequestMapping(value="/")
public ModelAndView test(HttpServletResponse response) throws IOException{
return new ModelAndView("index");
}
}
MvcConfiguration.java
package EjemploCRUD.SpringMVC.config;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.ComponentScan;
import org.springframework.context.annotation.Configuration;
import org.springframework.web.servlet.ViewResolver;
import org.springframework.web.servlet.config.annotation.EnableWebMvc;
import org.springframework.web.servlet.config.annotation.ResourceHandlerRegistry;
import org.springframework.web.servlet.config.annotation.WebMvcConfigurerAdapter;
import org.springframework.web.servlet.view.InternalResourceViewResolver;
#Configuration
#ComponentScan(basePackages="EjemploCRUD.SpringMVC")
#EnableWebMvc
public class MvcConfiguration extends WebMvcConfigurerAdapter{
#Bean
public ViewResolver getViewResolver(){
InternalResourceViewResolver resolver = new InternalResourceViewResolver();
resolver.setPrefix("/WEB-INF/views/");
resolver.setSuffix(".jsp");
return resolver;
}
#Override
public void addResourceHandlers(ResourceHandlerRegistry registry) {
registry.addResourceHandler("/resources/**").addResourceLocations("/resources/");
}
}
Error
Type Status Report
Message The requested resource [/SpringMVC/] is not available
Description The origin server did not find a current representation for the target resource or is not willing to disclose that one exists.
folder structure,
in your application you used both (java-based and xml-based) configuration types. in this answer, used the xml-based configuration.
try with following steps.
modify the spring-servlet.xml file as follows,
<context:component-scan base-package="controllers, EjemploCRUD.SpringMVC.controller"></context:component-scan>
<mvc:resources mapping="/resources/**" location="/resources/" />
config the location of spring-servlet.xml file in web.xml file as follows,
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring-servlet.xml</param-value>
</context-param>
in your application spring-servlet.xml and web.xml files are located under the WEB-INF/views directory.but these files not relevant to the view.hence, please move these two files into WEB-INF folder(best practice).
as per the web.xml file, configured the views (jsp files) path is WEB-INF/views directory. but in your folder structure index.jsp file is located under the WEB-INF folder. hence, get this error. please move index.jsp file into WEB-INF/views folder.
I am getting an warnning in springmvc
as No mapping found for HTTP request with URI [/FitnessTracker/] in DispatcherServlet with name 'fitTrackerServlet'
INFO: FrameworkServlet 'fitTrackerServlet': initialization completed in 2194 ms
Feb 26, 2017 9:43:08 AM org.springframework.web.servlet.DispatcherServlet noHandlerFound
WARNING: No mapping found for HTTP request with URI [/FitnessTracker/] in DispatcherServlet with name 'fitTrackerServlet'
When i press url http://localhost:8080/fitnessTracker/ I am getting 404 error.
Thanks
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5">
<servlet>
<servlet-name>fitTrackerServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/config/servlet-config.xml</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>fitTrackerServlet</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
<display-name>Archetype Created Web Application</display-name>
</web-app>
and my servlet-config.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:p="http://www.springframework.org/schema/p"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.2.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.2.xsd">
<mvc:annotation-driven />
<context:component-scan base-package="com.pluralsight.controller"></context:component-scan>
<!--
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/jsp/"/>
<property name="suffix" value=".jsp"/>
</bean>
-->
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"
p:prefix="/WEB-INF/jsp/" p:suffix=".jsp"/>
</beans>
and my controller
#Controller
public class HelloController {
#RequestMapping(value = "/greeting")
public String sayHello (Model model) {
System.out.println("Test");
model.addAttribute("greeting", "Hello WorldX");
return "hello";
}
}
Does your component-scan base-package match the package where your HelloController is in? If not, that is the problem.
<context:component-scan base-package="com.pluralsight.controller"></context:component-scan>
Configures component scanning directives for use with #Configuration
classes. Either basePackageClasses() or
basePackages() (or its alias value()) may be specified to define
specific packages to scan.
Spring does not find your HelloController and so doesn't map anything.
Otherwise you could also follow these steps.
I am wondering why you have you application configured with XML. With this tool you can start a maven project with a Spring boot application that will be, by default, already configured to build exactly what you want.
Then you only need a class with:
#RestController
#RequestMapping("/fitnessTracker")
public class HelloController {
#RequestMapping(value = "/greeting")
public String sayHello (Model model) {
System.out.println("Test");
model.addAttribute("greeting", "Hello WorldX");
return "hello";
}
}
And that's it, Spring will do the rest for you ;)
In my case the problem was that i was using this url-pattern
<url-pattern>/*</url-pattern>
instead of this
<url-pattern>/</url-pattern>
and also i had to add
#RequestMapping(value = "/fitnessTracker")
under the
#Controller
annotation.
I found the solution at : https://www.baeldung.com/spring-mvc-404-error for the pattern.
I tried to to load a simple example of spring mvc with a simple jsp but failed with the following error: No mapping found for HTTP request with URI [/HelloWeb/WEB-INF/jsp/hello.jsp]
I'm using Spring 3.2.2.
I really appreciate your help here.
I tried several thing but still it seems that I can not map my jsp page in the controller.
web.xml looks like that:
<web-app id="WebApp_ID" version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<display-name>Spring MVC Application</display-name>
<servlet>
<servlet-name>HelloWeb</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>HelloWeb</servlet-name>
<url-pattern>*.jsp</url-pattern>
</servlet-mapping>
</web-app>
HelloWeb-servlet.xml looks like that:
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation=" http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<context:component-scan base-package="com.tutorial.spring" />
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/jsp/" />
<property name="suffix" value=".jsp" />
</bean>
</beans>
HelloControll.class looks like that:
package com.tutorial.spring;
import org.springframework.stereotype.Controller;
import org.springframework.ui.ModelMap;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
#Controller
#RequestMapping("/hello")
public class HelloController {
#RequestMapping(method= RequestMethod.GET)
public String printHello(ModelMap modelMap) {
modelMap.addAttribute("message", "Hello Spring MVC Framework!");
return "hello";
}
}
Correct URL to hit your printHello handler method is
/HelloWeb/hello.jsp
I figured it out. foolish mistake.
I named my jsp "Hello.jsp" with capital 'H' and returned in my controller 'hello' with lower case.
Just changed my jsp page to be "hello.jsp".
thanks for your help.
Modify web.xml like this
<servlet-mapping>
<servlet-name>HelloWeb</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
Try to access /YourAppName/hello. Then Spring-MVC will trigger the method printHello() . Then return the jsp view in /WEB-INF/jsp/.
The dispatcher servlet have to map the correct main route:
<servlet-mapping>
<servlet-name>HelloWeb</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
move jsp file to right place as defined in servlet
/WEB-INF/jsp/
The correct URL is http://localhost:8080/hello, without "/HelloWeb"
When I am running test at that time #Autowired is working but when I run the web app and try to fetch data at that time its throwing null pointer exception.
this is my controller
In this BuyerRepo is always null
import com.retail.exception.InvalidIdException;
import com.retail.model.Buyer;
import com.retail.repository.BuyerRepo;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Component;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.Produces;
#Path("/buyer")
#Component
public class BuyerController {
#Autowired
private BuyerRepo buyerRepo;
#GET
#Produces("application/json")
public Buyer searchFields() throws InvalidIdException {
String buyerId = "51";
Buyer buyer;
try {
buyer = buyerRepo.getBuyer(Long.parseLong(buyerId));
} catch (NumberFormatException e) {
buyer = buyerRepo.getBuyer(buyerId);
}
return buyer;
}
}
In repository entity manager is always null
this is buyerRepository
import com.retail.exception.InvalidIdException;
import com.retail.model.Buyer;
import org.springframework.stereotype.Repository;
import javax.persistence.NoResultException;
#Repository
public class BuyerRepo extends AbstractRepository {
public Buyer getBuyer(String buyerName) throws InvalidIdException {
javax.persistence.Query buyerId = entityManager.createNativeQuery("select b.buyer_id from buyer b where b.name = :name").setParameter("name", buyerName);
Integer id;
try {
id = (Integer) buyerId.getSingleResult();
} catch (NoResultException e) {
return null;
}
return getBuyer(id);
}
public Buyer getBuyer(long buyerId) throws InvalidIdException {
Buyer buyer = entityManager.find(Buyer.class, buyerId);
if (buyer == null) throw new InvalidIdException("Invalid Article ID");
return buyer;
}
}
this is applicationContext.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:tx="http://www.springframework.org/schema/tx" xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-2.5.xsd">
<context:annotation-config/>
<context:component-scan base-package="com.retail"/>
<bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="org.postgresql.Driver"/>
<property name="url" value="jdbc:postgresql://localhost/retail"/>
<property name="username" value="retail_user"/>
<property name="password" value="password"/>
</bean>
<bean id="entityManagerOne" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource"/>
<property name="packagesToScan" value="com.retail"/>
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="showSql" value="true"/>
<property name="databasePlatform" value="org.hibernate.dialect.PostgreSQLDialect"/>
</bean>
</property>
</bean>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerOne"/>
</bean>
<tx:annotation-driven transaction-manager="transactionManager"/>
</beans>
this is servlet-context.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<mvc:annotation-driven />
<context:annotation-config />
<context:component-scan base-package="com.retail" />
</beans>
this is web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_5.xsd">
<servlet>
<servlet-name>retail</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>com.retail.web</param-value>
</init-param>
<init-param>
<param-name>com.sun.jersey.api.json.POJOMappingFeature</param-name>
<param-value>true</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>retail</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
classpath:applicationContext.xml
/WEB-INF/servlet-context.xml
</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<listener>
<listener-class>org.springframework.web.context.request.RequestContextListener</listener-class>
</listener>
<welcome-file-list>
<welcome-file>/WEB-INF/views/index.jsp</welcome-file>
</welcome-file-list>
</web-app>
You have to wire a interface instead of class. so there are two ways:
To let BuyerRepo to implement one interface
Useing #Inject or #Resource instead of #Autowired
I Have encountered this situation,
you need to add some jar file
gradle project:
compile group: 'org.glassfish.jersey.ext', name: 'jersey-spring3', version: '2.22.2'
maven project:
<dependency>
<groupId>org.glassfish.jersey.ext</groupId>
<artifactId>jersey-spring3</artifactId>
<version>2.22.2</version>
</dependency>
another solution is web.xml file:
<servlet>
<servlet-name>jersey-serlvet</servlet-name>
<servlet-class>com.sun.jersey.spi.spring.container.servlet.SpringServlet</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>cn.ice</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>jersey-serlvet</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
You can try using the SpringServlet instead of the jersey provided servlet container to achieve Jersey-Spring integration.
<servlet-class>com.sun.jersey.spi.spring.container.servlet.SpringServlet</servlet-class>
The documentation for this class states :
A servlet or filter for deploying root resource classes with Spring integration.
This class extends ServletContainer and initiates the WebApplication with a Spring-based
IoCComponentProviderFactory, SpringComponentProviderFactory, such that instances of resource and provider
classes declared and managed by Spring can be obtained.
Classes of Spring beans declared using XML-based configuration or auto-wire-based confguration will be
automatically registered if such classes are root resource classes or provider classes. It is not necessary to provide
initialization parameters for declaring classes in the web.xml unless a mixture of Spring-managed and Jersey-
managed classes is required.
The servlet supports configuration of child applicationContexts, see CONTEXT_CONFIG_LOCATION.
Looks like your buyerRepo has no public setter. It's also not possible to set it through the constructor. How about write a setter for it and put the #Autowired annotation on the setter instead. Like this:
#Repository
public class BuyerRepo extends AbstractRepository {
private BuyerRepo buyerRepo;
#Autowired
public void setBuyerRepo(BuyerRepo buyerRepo)
{
this.buyerRepo = buyerRepo;
}
//...Other code is omitted.
}
I have developed a REST web application with Spring MVC and I can send JSON objects to a client.
I would like to construct a Javascript/AJAX client that connects to my web application but I don't know how to send the first HTML page (using JSP).
I understand I should serve JSP pages with some embedded AJAX. This AJAX will send requests to my web services.
Update:
The requirement I am not able to achieve is to write the default URI (http://localhost:8084) in browser and see the HTML page I have written in JSP page (home.jsp).
My approach is following:
I have a Controller that sends the root JSP page
#Controller
public class SessionController {
#RequestMapping(value="/", method=RequestMethod.GET)
public String homeScreen(){
return "home";
}
}
But when I run the server I receive this warning
WARNING: No mapping found for HTTP request with URI [/home] in DispatcherServlet with name 'dispatcher'
and nothing is loaded in browser.
Here is my application-context file:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
http://www.springframework.org/schema/aop
http://www.springframework.org/schema/aop/spring-aop-3.1.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-3.1.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-3.1.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.1.xsd">
<context:component-scan base-package="com.powerelectronics.freesun.web" />
<mvc:annotation-driven />
</beans>
And web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>2</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>
30
</session-timeout>
</session-config>
</web-app>
Is my approach correct? Am I wrong at any basic concept?
Can I modify something in my code to make it run?
I would like to see the first page loaded in browser and keep going in that direction.
Thanks in advance.
Try adding a #ResponseBody annotation on the method:
#Controller
public class SessionController {
#RequestMapping(value="/", method=RequestMethod.GET)
#ResponseBody
public String homeScreen(){
return "home";
}
}
This should output home on the page.
If you'd like to use View technologies, e.g. JSP, review the following chapter on the official Spring Framework documentation: http://static.springsource.org/spring/docs/3.1.x/spring-framework-reference/htmlsingle/spring-framework-reference.html#view
Update
"Just as with any other view technology you're integrating with Spring, for JSPs you'll need a view resolver that will resolve your views ". If you'd like to use JSP you should then add the following to your Web application context, then return the name of the file that shall be processed:
<!-- the ResourceBundleViewResolver -->
<bean id="viewResolver" class="org.springframework.web.servlet.view.ResourceBundleViewResolver">
<property name="basename" value="views"/>
</bean>
<bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="viewClass" value="org.springframework.web.servlet.view.JstlView"/>
<property name="prefix" value="/WEB-INF/jsp/"/>
<property name="suffix" value=".jsp"/>
</bean>
Is the above present in your Web application context? You can review the official documentation for further information: http://static.springsource.org/spring/docs/3.1.x/spring-framework-reference/htmlsingle/spring-framework-reference.html#view-jsp-resolver
Place a welcome file tag in web.xml file.
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
You must be having this index.jsp outside of WEB-INF. Put following code in it.
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<%
response.sendRedirect("home");
%>
</body>
</html>
When application is loaded, it will call index.jsp and jsp will redirect it to /home action.
Then your controller will get called.
#Controller
public class SessionController {
// see the request mapping value attribute here, it is /home
#RequestMapping(value="/home", method=RequestMethod.GET)
public String homeScreen(){
return "home";
}
}
This will call your home jsp.
If you want to to return JSON from your spring controller, then you need jackson mapper bean initialized in spring context xml file.
<beans:bean id="jacksonMessageChanger" class="org.springframework.http.converter.json.MappingJacksonHttpMessageConverter">
<beans:property name="supportedMediaTypes" value="application/json" />
</beans:bean>
<beans:bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter">
<beans:property name="messageConverters">
<util:list id="beanList">
<beans:ref bean="jacksonMessageChanger" />
</util:list>
</beans:property>
</beans:bean>
You need to add jar or maven dependency to use jackson mapper.
<dependency>
<groupId>org.codehaus.jackson</groupId>
<artifactId>jackson-mapper-asl</artifactId>
<version>1.8.5</version>
</dependency>
And to return JSON from controller, method would be like this :
#RequestMapping(value="/getContacts", method=RequestMethod.GET)
public #ResponseBody List<Contacts> getContacts(){
List<Contacts> contactList = prepareContactList();
return contactList;
}
This way you will get List in the success function of ajax call in the form of object and by iterating it you can get the details.
Finally I solve this only with configuring the dispatcher in web.xml on a different way.
First I added the view resolver to the servlet configuration file as David Riccitelli suggested me:
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"
p:prefix="/WEB-INF/jsp/" p:suffix=".jsp"/>
And then I configured the servlet mapping in web.xml:
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
That's what I was looking for, and no extra configuration is needed.
Doing this I call my root URL http://localhost:8084 and I can see the home screen I have coded in home.jsp.
Thanks for your support and suggestions.