404 - Http the requested is not available JavaEE Spring MVC - spring

I am not very familiar with Spring MVC DriverManagerDataSource.I am trying to return a JSP from my controller. My Controller method is running well but when returning view, I'm getting a 404 error.
I don't know why I got this error If I'm telling this: in the web.xml
<servlet-mapping>
<servlet-name>spring</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
spring-servlet
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns = "http://www.springframework.org/schema/beans"
xmlns:xsi = "http://www.w3.org/2001/XMLSchema-instance"
xmlns:context = "http://www.springframework.org/schema/context"
xmlns:mvc = "http://www.springframework.org/schema/mvc"
xsi:schemaLocation =
"
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc.xsd
">
<context:component-scan base-package="controllers"></context:component-scan> <!-- com.javatpoint. -->
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/jsp/"></property>
<property name="suffix" value=".jsp"></property>
</bean>
<bean class = "org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name = "driverClassName" value = "com.mysql.jdbc.Driver"></property>
<property name = "url" value = "jdbc:mysql://localhost:3306/empleados"></property>
<property name = "username" value = "---"></property>
<property name = "password" value = "---"></property>
</bean>
<bean id="jt" class="org.springframework.jdbc.core.JdbcTemplate">
<property name="dataSource" ref="ds"></property>
</bean>
<bean id = "dao" class = "dao.EmpDao">
<property name = "template" ref = "jt"></property>
</bean>
</beans>
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0">
<display-name>SpringMVC</display-name>
<context-param>
<param-name>contextClass</param-name>
<param-value>
org.springframework.web.context.support.AnnotationConfigWebApplicationContext
</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>spring</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
HomeController.java
package EjemploCRUD.SpringMVC.controller;
import java.io.IOException;
import javax.servlet.http.HttpServletResponse;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.servlet.ModelAndView;
#Controller
public class HomeController {
#RequestMapping(value="/")
public ModelAndView test(HttpServletResponse response) throws IOException{
return new ModelAndView("index");
}
}
MvcConfiguration.java
package EjemploCRUD.SpringMVC.config;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.ComponentScan;
import org.springframework.context.annotation.Configuration;
import org.springframework.web.servlet.ViewResolver;
import org.springframework.web.servlet.config.annotation.EnableWebMvc;
import org.springframework.web.servlet.config.annotation.ResourceHandlerRegistry;
import org.springframework.web.servlet.config.annotation.WebMvcConfigurerAdapter;
import org.springframework.web.servlet.view.InternalResourceViewResolver;
#Configuration
#ComponentScan(basePackages="EjemploCRUD.SpringMVC")
#EnableWebMvc
public class MvcConfiguration extends WebMvcConfigurerAdapter{
#Bean
public ViewResolver getViewResolver(){
InternalResourceViewResolver resolver = new InternalResourceViewResolver();
resolver.setPrefix("/WEB-INF/views/");
resolver.setSuffix(".jsp");
return resolver;
}
#Override
public void addResourceHandlers(ResourceHandlerRegistry registry) {
registry.addResourceHandler("/resources/**").addResourceLocations("/resources/");
}
}
Error
Type Status Report
Message The requested resource [/SpringMVC/] is not available
Description The origin server did not find a current representation for the target resource or is not willing to disclose that one exists.
folder structure,

in your application you used both (java-based and xml-based) configuration types. in this answer, used the xml-based configuration.
try with following steps.
modify the spring-servlet.xml file as follows,
<context:component-scan base-package="controllers, EjemploCRUD.SpringMVC.controller"></context:component-scan>
<mvc:resources mapping="/resources/**" location="/resources/" />
config the location of spring-servlet.xml file in web.xml file as follows,
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring-servlet.xml</param-value>
</context-param>
in your application spring-servlet.xml and web.xml files are located under the WEB-INF/views directory.but these files not relevant to the view.hence, please move these two files into WEB-INF folder(best practice).
as per the web.xml file, configured the views (jsp files) path is WEB-INF/views directory. but in your folder structure index.jsp file is located under the WEB-INF folder. hence, get this error. please move index.jsp file into WEB-INF/views folder.

Related

Spring mvc Component scan requestmapping not working

I am new to Spring and Spring-MVC. I am using 4.3.3.RELEASE.I have generated project using maven-webapp-archetype and added sping dependencies and dispatcher-servelt later.
As per my web.xml I have initialized Dispatcher-servlet using spring-dispatcher-servlet.xml
I have already tried
Added inet.controller.* instead inet.controller in base-package
Changing URL pattern to /* from /
Adding to dispatcher servlet
but still when I try http://loclahost:8080/inet/welcome server is throwing 404.
Web.xml
<!DOCTYPE web-app PUBLIC
"-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd" >
<web-app>
<display-name>Archetype Created Web Application</display-name>
<servlet>
<servlet-name>spring-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>spring-dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
Spring-dispatcher-servlet.xml
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-4.3.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-4.3.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-4.3.xsd">
<mvc:default-servlet-handler />
<context:component-scan base-package="inet.controller"/>
<bean
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value>/WEB-INF/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
Below is my directory structure:
HelloController
package inet.controller;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.servlet.ModelAndView;
#Controller
public class HelloController {
#RequestMapping("/welcome")
public ModelAndView helloWorld() {
ModelAndView modelAndView = new ModelAndView("helloPage");
modelAndView.addObject("message", "Hi All");
return modelAndView;
}
}
You need to tell the spring how to find the controllers from urls that you are hitting. So it what is missing in your configuration
to do that add <mvc:annotation-driven/> tag in your dispatcher xml configuration. it adds some mapping handlers
RequestMappingHandlerMapping
RequestMappingHandlerAdapter
ExceptionHandlerExceptionResolver
And some necessary message converters for you.
What does <mvc:annotation-driven /> do?

Get model from controller to jsp page

I try to figure out what wrong that I cannot get arraylist from controller to my jsp page. Here I post my code if can somebody find out where could be the problem. Thanks in advance.
web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
id="StudentWebApp" version="3.0">
<display-name>Archetype Created Web Application</display-name>
<servlet>
<servlet-name>mvc-dispatcher-servlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/mvc-dispatcher-servlet.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>mvc-dispatcher-servlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
mvc-dispatcher-servlet:
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd">
<context:component-scan base-package="cz.webapp.student"/>
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value>/WEB-INF/view/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
</beans>
controller:
/*
* To change this license header, choose License Headers in Project Properties.
* To change this template file, choose Tools | Templates
* and open the template in the editor.
*/
package cz.webapp.student.controllers;
import cz.webapp.student.entity.Student;
import cz.webapp.student.service.StudentService;
import java.util.List;
import java.util.Map;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Component;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import static org.springframework.web.bind.annotation.RequestMethod.GET;
import org.springframework.web.bind.annotation.RequestParam;
/**
*
* #author Jenda
*/
#Component
#RequestMapping("/StudentWebApp/*")
public class StudentController {
#Autowired
StudentService studentServiceImpl;
#RequestMapping(value="/students", method=GET)
public String showAllStudent(Map<String, Object> model){
List<Student> studentList = studentServiceImpl.findAll();
///Zkouška dat
studentList.add(new Student(1,"Martina", 25));
model.put("students", studentList);
return "StudentWebApp/index";
}
}
index.jsp:
Your return type in showAllStudent should be changed to ModelAndView.
#RequestMapping(value="/students", method=GET)
public ModelAndView showAllStudent(Map<String, Object> model){
List<Student> studentList = studentServiceImpl.findAll();
studentList.add(new Student(1,"Martina", 25));
model.put("students", studentList);
return new ModelAndView("StudentWebApp/index", model);
}

#Autowired is not working with jersey and spring

When I am running test at that time #Autowired is working but when I run the web app and try to fetch data at that time its throwing null pointer exception.
this is my controller
In this BuyerRepo is always null
import com.retail.exception.InvalidIdException;
import com.retail.model.Buyer;
import com.retail.repository.BuyerRepo;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Component;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.Produces;
#Path("/buyer")
#Component
public class BuyerController {
#Autowired
private BuyerRepo buyerRepo;
#GET
#Produces("application/json")
public Buyer searchFields() throws InvalidIdException {
String buyerId = "51";
Buyer buyer;
try {
buyer = buyerRepo.getBuyer(Long.parseLong(buyerId));
} catch (NumberFormatException e) {
buyer = buyerRepo.getBuyer(buyerId);
}
return buyer;
}
}
In repository entity manager is always null
this is buyerRepository
import com.retail.exception.InvalidIdException;
import com.retail.model.Buyer;
import org.springframework.stereotype.Repository;
import javax.persistence.NoResultException;
#Repository
public class BuyerRepo extends AbstractRepository {
public Buyer getBuyer(String buyerName) throws InvalidIdException {
javax.persistence.Query buyerId = entityManager.createNativeQuery("select b.buyer_id from buyer b where b.name = :name").setParameter("name", buyerName);
Integer id;
try {
id = (Integer) buyerId.getSingleResult();
} catch (NoResultException e) {
return null;
}
return getBuyer(id);
}
public Buyer getBuyer(long buyerId) throws InvalidIdException {
Buyer buyer = entityManager.find(Buyer.class, buyerId);
if (buyer == null) throw new InvalidIdException("Invalid Article ID");
return buyer;
}
}
this is applicationContext.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:tx="http://www.springframework.org/schema/tx" xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-2.5.xsd">
<context:annotation-config/>
<context:component-scan base-package="com.retail"/>
<bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="org.postgresql.Driver"/>
<property name="url" value="jdbc:postgresql://localhost/retail"/>
<property name="username" value="retail_user"/>
<property name="password" value="password"/>
</bean>
<bean id="entityManagerOne" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource"/>
<property name="packagesToScan" value="com.retail"/>
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="showSql" value="true"/>
<property name="databasePlatform" value="org.hibernate.dialect.PostgreSQLDialect"/>
</bean>
</property>
</bean>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerOne"/>
</bean>
<tx:annotation-driven transaction-manager="transactionManager"/>
</beans>
this is servlet-context.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<mvc:annotation-driven />
<context:annotation-config />
<context:component-scan base-package="com.retail" />
</beans>
this is web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_5.xsd">
<servlet>
<servlet-name>retail</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>com.retail.web</param-value>
</init-param>
<init-param>
<param-name>com.sun.jersey.api.json.POJOMappingFeature</param-name>
<param-value>true</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>retail</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
classpath:applicationContext.xml
/WEB-INF/servlet-context.xml
</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<listener>
<listener-class>org.springframework.web.context.request.RequestContextListener</listener-class>
</listener>
<welcome-file-list>
<welcome-file>/WEB-INF/views/index.jsp</welcome-file>
</welcome-file-list>
</web-app>
You have to wire a interface instead of class. so there are two ways:
To let BuyerRepo to implement one interface
Useing #Inject or #Resource instead of #Autowired
I Have encountered this situation,
you need to add some jar file
gradle project:
compile group: 'org.glassfish.jersey.ext', name: 'jersey-spring3', version: '2.22.2'
maven project:
<dependency>
<groupId>org.glassfish.jersey.ext</groupId>
<artifactId>jersey-spring3</artifactId>
<version>2.22.2</version>
</dependency>
another solution is web.xml file:
<servlet>
<servlet-name>jersey-serlvet</servlet-name>
<servlet-class>com.sun.jersey.spi.spring.container.servlet.SpringServlet</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>cn.ice</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>jersey-serlvet</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
You can try using the SpringServlet instead of the jersey provided servlet container to achieve Jersey-Spring integration.
<servlet-class>com.sun.jersey.spi.spring.container.servlet.SpringServlet</servlet-class>
The documentation for this class states :
A servlet or filter for deploying root resource classes with Spring integration.
This class extends ServletContainer and initiates the WebApplication with a Spring-based
IoCComponentProviderFactory, SpringComponentProviderFactory, such that instances of resource and provider
classes declared and managed by Spring can be obtained.
Classes of Spring beans declared using XML-based configuration or auto-wire-based confguration will be
automatically registered if such classes are root resource classes or provider classes. It is not necessary to provide
initialization parameters for declaring classes in the web.xml unless a mixture of Spring-managed and Jersey-
managed classes is required.
The servlet supports configuration of child applicationContexts, see CONTEXT_CONFIG_LOCATION.
Looks like your buyerRepo has no public setter. It's also not possible to set it through the constructor. How about write a setter for it and put the #Autowired annotation on the setter instead. Like this:
#Repository
public class BuyerRepo extends AbstractRepository {
private BuyerRepo buyerRepo;
#Autowired
public void setBuyerRepo(BuyerRepo buyerRepo)
{
this.buyerRepo = buyerRepo;
}
//...Other code is omitted.
}

'Application context not configured for this file' error after moving and renaming the default application-config.xml of IntelliJ IDEA

I have created a Spring Mvc application using IntelliJ IDEA and then I moved and renamed the default application-config file to another directory.
Now I am getting this error : 'Application context not configured for this file'
The new place of the file is src/main/webapp/WEB-INF/spring/appServlet/servlet-context.xml
The file is this one:
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd">
<!-- Enables the Spring MVC #Controller programming model -->
<mvc:annotation-driven/>
<mvc:resources mapping="/resources/**" location="/"/>
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/pages/"/>
<property name="suffix" value=".jspx"/>
</bean>
<context:component-scan base-package="com.apress.prospring3.ch17.web.controller"/>
</beans>
Any ideas?
Thank you.
Check the config of spring in the web.xml file.
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
classpath:applicationContext.xml
</param-value>
</context-param>
The contextConfigLocation parameter config the xml location about spring,
Check you web.xml is correct.
If you load the xml by java code,like #skiabox, you can ignore this warning.
I've configured application context from code (a new feature of spring 3.1) so I believe that IntelliJ idea will keep complaining.
Here is the code.
package com.apress.prospring3.ch17.web.init;
import org.springframework.web.WebApplicationInitializer;
import org.springframework.web.context.support.XmlWebApplicationContext;
import org.springframework.web.servlet.DispatcherServlet;
import javax.servlet.MultipartConfigElement;
import javax.servlet.ServletContext;
import javax.servlet.ServletException;
import javax.servlet.ServletRegistration;
public class MyWebAppInitializer implements WebApplicationInitializer{
#Override
public void onStartup(ServletContext container) throws ServletException {
XmlWebApplicationContext appContext = new XmlWebApplicationContext();
appContext.setConfigLocation("/WEB-INF/spring/appServlet/servlet-context.xml");
ServletRegistration.Dynamic dispatcher = container.addServlet("appServlet", new DispatcherServlet(appContext));
MultipartConfigElement multipartConfigElement = new MultipartConfigElement(null, 5000000, 5000000, 0);
dispatcher.setMultipartConfig(multipartConfigElement);
dispatcher.setLoadOnStartup(1);
dispatcher.addMapping("/");
}
}
Satur6ay's comment helps me particularry.
But xml-file was coloured "red" by Idea.
I found thar resources folder had not "resource"-icon, but had standard gray folder icon.
So, I went to File -> Project Structure -> my module -> found there "resorces" folder -> "Mark as" -> Resources.
xml-reference in web.xml become valid and all other references in xml-spring-configs ()become green-valid
Adding this worked for me!! thx to satur6ay
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
classpath:applicationContext.xml
</param-value>
</context-param>

Spring MVC HTTP 404 error

I learning SpringMVC so I am followed Spring 3.0 MVC Series from HERE.
As you can see, I completed Part1, Part2, and I am right now on Part3 where I am learning how to handle forms with Spring 3 MVC.
But I get this HTTP 404 eror, when I try to run my application. Project strucutre and this error you can see at image below.
How I can fix this?
ContactController.java code:
package net.viralpatel.spring3.controller;
import net.virtalpatel.spring3.form.Contact;
import org.springframework.stereotype.Controller;
import org.springframework.validation.BindingResult;
import org.springframework.web.bind.annotation.ModelAttribute;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.SessionAttributes;
import org.springframework.web.servlet.ModelAndView;
#Controller
#SessionAttributes
public class ContactController {
#RequestMapping(value = "/addContact", method = RequestMethod.POST)
public String addContact(#ModelAttribute("contact")
Contact contact, BindingResult result) {
System.out.println("First Name:" + contact.getFirstname() +
"Last Name:" + contact.getLastname());
return "redirect:contacts.html";
}
#RequestMapping("/contacts")
public ModelAndView showContacts() {
return new ModelAndView("contact", "command", new Contact());
}}
spring-servlet.xml code:
<?xml version="1.0" encoding="UTF-8"?>
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<context:component-scan
base-package="net.viralpatel.spring3.controller" />
<bean id="viewResolver"
class="org.springframework.web.servlet.view.UrlBasedViewResolver">
<property name="viewClass"
value="org.springframework.web.servlet.view.JstlView" />
<property name="prefix" value="/WEB-INF/jsp/" />
<property name="suffix" value=".jsp" />
</bean>
****index.jsp code:****
<jsp:forward page="contacts.html"></jsp:forward>
web.xml code:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID" version="2.5">
<display-name>Spring3MVC</display-name>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>spring</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring</servlet-name>
<url-pattern>*.html</url-pattern>
</servlet-mapping>
Just change contact to contacts
change
return new ModelAndView("contact", "command", new Contact());
to
return new ModelAndView("contacts", "command", new Contact());
The issue is in your forward it will check for the contact.jsp but actually you have contacts.jsp (you have suffix property as .jsp )
your index.jsp is forwarded to contacts.html.
But you spring configuration does not have mapping for /contacts.html, you have mapped /contacts instead.
You need to change the /contacts mapping to
#RequestMapping("/contacts.html")
public ModelAndView showContacts() {
return new ModelAndView("contact", "command", new Contact());
}
localhost:8080/Spring3MVC/index.jsp As you can see, I try first to open index.jsp and then redirect to contact.jsp – Zookey 44 mins ago
I think you have it mixed up. 1) There is a typo, you say contact.jsp but the file name is contacts.jsp (file name in eclipse)
2) Where is the contacts.html file ?
I would suggest, you first return to the jsp and see if you can get your controller to return the jsp after that try redirecting to the html file after you create one.

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