New to scripting here. Basically, I am needing to write a program to accept 10 input numbers and return the largest in the list.
I have this code, but obviously it is not running:
class Generator
def getNumbers
number = Array.new
puts "To begin, You will need to enter your numbers."
print "Press Enter to continue."
Console_Screen.pause
10.times do
print "\nPlease enter any number: "
input = STDIN.gets
input.chop!
list.push
return list
end
list.push(number)
print list.max
end
end
Console_Screen.new
Find = Generator.new
end
Can anyone help me with what I coded incorrectly?
There are many problems with your code. Among them I may point:
1) You created an array named number to store your numbers and then tried to push them to another variable named list;
2) As #tadman pointed, you used a return inside a times block and this makes the block to be executed only once;
3) You never invoked getNumbers to make your process really happen!
This code would do what you need:
class Generator
def get_numbers
numbers = Array.new
puts "To begin, You will need to enter your numbers."
puts
10.times do
print "\nPlease enter any number: "
input = STDIN.gets
input.chop!
numbers.push(input.to_i)
end
print numbers.max
end
end
Find = Generator.new
Find.get_numbers
Notice that I changed the name of your method from getNumbers to get_numbers, which is much more Ruby-like.
Notice that I also changed the name of your array from number to numbers, 'cause it will store numbers, not a single number. Naming your varables correctly may help you to think correctly about your problem. It also helps when it comes for other people reading your program. Even you, six months later, will have problems to understand your own code if you don't name things correctly an comment you code well.
By the way, I also pushed the numbers to numbers as integer, using #to_i. This will make the numbers be compared as numbers, not as strings. If you researsh a bit you'll find out this could be a bit different. If someone enters 0300 as a number, it will be considered to be smaller then 200 as string, but when converted to integers, they will be in the correct order.
Consider this approach perhaps:
#script.rb
nums = []
10.times do |c|
puts "enter number #{c+1}"
nums << gets.to_i
end
puts "max number is #{nums.max}"
Example
$ ruby script.rb
enter number 1
#5
enter number 2
#3
enter number 3
#66
enter number 4
#4
enter number 5
#3
enter number 6
#2
enter number 7
#1
enter number 8
#6
enter number 9
#9
enter number 10
#0
#max number is 66
I had the same assignment and this is what I ended up creating. (I had to get a little more involved with input control and I'm sure there's easier ways of doing this. Also had to utilize the variables as part of the grade. I assume to prevent me from ripping off the code above.)
class Screen
def cls
puts ("\n" * 25)
puts "\a"
end
def pause
STDIN.gets
end
end
Console_Screen = Screen.new
num = [] #array to store user input
$counter = 1
loop do
puts "Please enter number " + $counter.to_s + " of a series of 10 numbers in order to determine the largest."
# Console_Screen.pause
loop do
print "Enter Number Here:"
number = gets.chomp
num << number.to_i if number =~ /[0-9]/ #only writes to the array if it's a number
break if number =~ /[0-9]/ #only allow numbers
end
$counter += 1
break if $counter == 11
end
puts "Press Enter to have your numbers sorted and the largest presented to you."
Console_Screen.pause
largest = num.max
puts "This is your largest number: " + largest.to_s
Console_Screen.pause
Related
I have to write a program which asks the user to enter a number.
The program keeps on asking the user for a number until the user types 'Stop'
at which point the sum of the numbers that the user has entered should be printed.
I've tried many,many things and none of my ideas work.
This is what I have - but I can that it isn't correct. What am I doing wrong?
I've only used while loops and arrays
total_user_input = []
# As long as the user inputs a number, the program will keep putting Give me a number
# and then adding that number to the total_user_input array.
puts "Give me a number: "
while user_input = gets.chomp.to_i
#add the input to the array total_user_input
total_user_input.push(user_input.to_i)
puts "Give me a number: "
# If the user however types stop, then the loop is broken and we jump down to the
# sum bit - where all of the numbers in the total_user_input array are added together
# and printed. End of program!
if user_input == "stop"
break
end
sum = 0
total_user_input.each { |num|
sum += num
}
puts sum
end
The output isn't as it should be.
As others have identified the problems with your code let me suggest how you might reorganize it. Ruby provides many ways to execute loops but you many find it desirable to primarily relay on the method Kernel#loop and the keyword break. (As you will learn in time, loop is particularly convenient when used with enumerators.)
def sum_numbers
tot = 0
loop do
print 'Gimme a number: '
s = gets.chomp
break if s == 'Stop'
tot += s.to_i
end
tot
end
The keyword break can optionally take an argument (though why that is not mentioned in the doc I cannot say), in which case it (if a literal) or its value (if a variable or method) is returned by loop. Here one would generally see
break tot if s == 'Stop'
without the final line, tot. As the loop returns tot and that is the last calculation performed by the method, the method will return the final value of tot.
You could have instead written
return tot if user_input == 'Stop'
but I think most coders believe best practice dictates that one should not return from a method from within a loop (or from within nested loops) unless there is a good reason for doing so.
Some small points:
I used print rather than puts to that the user's entry will be shown on the same line as the prompt.
I used s (for "string") rather than user_input because it reduces the chance of spelling mistakes (e.g., user_imput), speeds reading, and (possibly a foible of mine), looks neater. True, s is not descriptive, but one only has to remember its meaning for three consecutive lines of code. Others may disagree.
You could write, break if s.downcase == 'stop' if you want, say, 'stop' or 'STOP' to have the same effect as 'Stop'.
'23O3'.to_i #=> 23 (that's an an oh, not a zero), so in real life you'd want to confirm that either 'Stop' or the string representation of a number had been typed.
This is how I would do this preferring to use loop do end syntax with a break when it should. Also added a bit more text so user knows what's happening.
total_user_input = []
puts 'Give me a number or "stop" to end: '
loop do
user_input = gets.chomp
total_user_input << user_input.to_i
puts "Give me a number: "
break if user_input.downcase == "stop"
end
puts "Total entered: #{total_user_input.inject(&:+)}" unless total_user_input.empty?
puts 'goodbye!'
Note these few things:
get.chomp.to_i will convert every input to integer. ("stop" or any non integer string will be 0)
Arrangement of the flow is quite messy.
total_user_input = []
puts "Give me a number: "
while user_input = gets.chomp.strip
total_user_input.push(user_input.to_i)
sum = 0
total_user_input.each { |num|
sum += num
}
puts sum
if user_input == "stop"
break
end
end
Hope you understand this.
This question already has answers here:
How to find a min/max with Ruby
(5 answers)
Closed 4 years ago.
I have a homework assignment that I need to finish. I think most of the code is working but I am having trouble with the last part. I need to display the largest number that a user enters (into an array). Below is the code I have so far. I am open to any suggestions. Thanks in advance.
Here's the description of the assignment:
Write a Ruby application that allows a user to input a series of 10 integers and determines and prints the largest integer. Your program should use at least the following three variables:
a) counter: A counter to count to 10 (i.e., to keep track of how many numbers have been input and to determine when all 10 numbers have been processed).
b) number: The integer most recently input by the user.
c) largest: The largest number found so far.
class Screen
def cls
puts ("\n")
puts "\a"
end
def pause
STDIN.gets
end
end
class Script
def display_instructions
Console_Screen.cls
print "This script will take the user input of 10 integers and then
will
print the largest."
print "\n\nPress enter to continue."
Console_Screen.cls
Console_Screen.pause
end
def getNumber #accepts user input
list = Array.new
10.times do
Console_Screen.cls
print "This script accepts 10 integers."
print "\n\nPlease type an integer and press enter."
input = STDIN.gets
input.chop!
list.push(input)
end
end
def display_largest(number) #displays the largest integer entered by the
user
Console_Screen.cls
print "The largest integer is " +
end
def runScript
number = getNumber
Console_Screen.cls
display_largest(number)
end
end
#Main Script Logic
Console_Screen = Screen.new
LargestNum = Script.new
answer = ""
loop do
Console_Screen.cls
print "Are you ready to start the script? (y/n): "
print "\n\nWould you like instructions on how this script works? (h): "
answer = STDIN.gets
answer.chop!
break if answer =~ /y|n|h/i
end
if answer == "h" or answer == "H"
LargestNum.display_instructions
print "Are you ready to start the script? (y/n): "
answer = STDIN.gets
answer.chop!
end
if answer == "n" or answer == "N"
Console_Screen.cls
puts "Okay, maybe another time.\n\n"
Console_Screen.pause
else
loop do
LargestNum.runScript
print "\n\nEnter Q to quit or press any key to run the script again: "
runAgain = STDIN.gets
runAgain.chop!
break if runAgain =~ /Q/i
end
end
This question has been asked and answered so many times before. Personally I think, as this answer suggests, the built in .max is the best solution.
[1, 3, 5].max #=> 5
Have you learned about for loops yet? You have to iterate through the array. For a very trivial example, you can do something like
max = 0
for element in list
if element > max
max= element
return max
I am trying to create something that constantly takes a users input until they say stop. Then, add all of the previous numbers together. This is what I have so far:
arr = []
puts "Give me a number:"
while input = gets.chomp
if input == "stop"
break
else
puts "Give me a number:"
arr << input
end
end
sum = arr.inject(:+)
puts sum
This is working fine up until adding the numbers together. The arr.inject(:+) seems to be joining the numbers together rather than adding.
For example, when in the while loop, I am entering 1, 2 and 3 into the gets.chomp, but the program is returning 123 rather that 6.
Where am I going wrong?
arr.inject(0) { |sum,e| sum + e.to_i }
a bit more verbose but your problem is that reading from input == String and you want Integer.
Other solution could be
arr.map(&:to_i).inject(:+)
But the first one is more efficient but less fancy.
It is the combination of
arr << input
and
arr.inject(:+)
For example, if you change the first one to:
arr << input.to_i
then it would not be wrong any more.
I'm trying to set bounds for an array that will later be printed in the console and summed. The lower bound ($a) should be less than 50 and I wrote this code to evaluate for that, but I want it to re-prompt for a number if a higher number is typed. So far, Google and experimentation have failed me.
def num_a
print "Pick a number from 1 to 50: "
$a = Integer(gets.chomp)
until $a < 50
puts "Um, try again please."
# need something here to prompt for another response
# until $a is less than 50
end
end
You could restructure the loop so that the prompt and call to gets are both inside it:
def num_a
# start with a number that doesn't meet the condition
a = 50
# check if the number meets the condition yet
until a < 50
# ask the user to enter a number
print "Pick a number from 1 to 50: "
a = Integer(gets.chomp)
# ask to try again if the number isn't under 50
puts "Um, try again please." unless a < 50
end
# return the entered value to the caller
a
end
Also, as I've shown in the example, I would recommend avoiding the use of global variables ($a in this case).
I am new to Ruby and just can't figure out how you take input for an array from a user and display it.If anyone could clear that I can add my logic to find the biggest number.
#!/usr/bin/ruby
puts "Enter the size of the array"
n = gets.chomp.to_i
puts "enter the array elements"
variable1=Array.new(n)
for i in (0..n)
variable1[i]=gets.chomp.to_i
end
for i in (0..n)
puts variable1
end
How about capturing the array in one line?
#!/usr/bin/ruby
puts "Enter a list of numbers"
list = gets # Input something like "1 2 3 4" or "3, 5, 6, 1"
max = list.split.map(&:to_i).max
puts "The largest number is: #{max}"
You are doing it ok. But try this little change
#!/usr/bin/ruby
puts "Enter the size of the array"
n = (gets.chomp.to_i - 1)
puts "enter the array elements"
variable1=Array.new(n)
for i in (0..n)
variable1[i]=gets.chomp.to_i
end
puts variable1
or for undefined number of values here is one way
#!/usr/bin/ruby
puts "enter the array elements (type 'done' to get out)"
input = gets.chomp
arr = []
while input != 'done'
arr << input.to_i
input = gets.chomp
end
puts arr
I believe that this is a little bit more elegant solution.
puts "Please enter numbers separated by spaces:"
s = gets
a = s.split(" ")
#Displays array
puts a
#Displays max element
puts a.max
First you collect the series of numbers from the user, then you use a split method on the string, which converts it to the array. If you want to use some other separator, like "," than you can write s.split(","). After that you can use your logic to find the biggest number or you could just use max method.
Some feedback:
chomp.to_i is a bit redundant, since the latter will also remove newlines.
for x in y is not commonly seen in idiomatic Ruby code. It basically behaves like each with slightly different scoping rules and probably should have been removed from the language a while ago.
Ruby arrays are dynamic, so no need to preinitialize them. Something like (1..n).map { gets.to_i } would also produce the array you need.
Displaying it can then be done like this: array.each { |n| puts n }
Alternatively you can use the strip approach outlined before, take the numbers as command line arguments in ARGV or pipe into your program using ARGF.