How to convert M20161 to Jan-16 in Oracle where 2016 is the year and 1 is the month.
If "M" literal is going to be always present, then just enclose it in double quotes in the format mask. Since there is no day part it'll default to first day of the month.
select to_date('M20161', '"M"YYYYMM') as res
from dual
Result:
RES
---------
01-JAN-16
To display the date in desired Jan-16 format, use TO_CHAR() function and Mon-YY format model.
select to_char(to_date('M20161', '"M"YYYYMM'), 'Mon-YY') as res
from dual
Result:
RES
------
Jan-16
Related
Unable to retrieve records properly with the formatted date values, need select query with right date format to get all records inserted per day
I have a date string like this in my script -
dateString :='26-MAR-20 05.00.00.00000000 AM';
I want to add 0.313 minutes to this date value. And also I want to
increment it to the next day something like this- '27-MAR-20
05.00.00.00000000 AM';
I tried this
dateString :='26-MAR-20 05.00.00.00000000 AM';
dateString :=to_char(dateField,'DD-MON-YYYY HH24:MI:SS.FF');
dateField := to_timestamp(dateString, 'DD/MON/YYYY HH24:MI:SS.FF') + 0.313 * INTERVAL '1' MINUTE;
I can see the output and inserted these values into the DB but
unable to retrieve records properly with these formatted date values..
I suspect it might be to do with the timestamp fields
When I run this query -
select *from rptallexceptions where exceptiontime between '27-MAR-2020 04.00.00.000000000 AM' and '28-MAR-2020 03.59.00.000000000 AM' order by exceptiontime desc;
--- this one gives 3833 records but expected is 4600
it shows only the records on 27th march., records inserted with timestamp containing 28th march are not retrieved..
select *from rptallexceptions where exceptiontime between '28-MAR-2020 04.00.00.000000000 AM' and '29-MAR-2020 03.59.00.000000000 AM' order by exceptiontime desc;
--- this one returns '0' rows
Excerpt from the script:
cnt :=cnt +1;
dateString :=to_char(dateField,'DD-MON-YYYY HH24:MI:SS.FF');
-- add time difference for each exception.
dateField := to_timestamp(dateString, 'DD/MON/YYYY HH24:MI:SS.FF') + 0.313 * INTERVAL '1' MINUTE;
-- after n*4600 exceptions,update date to next date.
IF REMAINDER(cnt,exceptionsPerDay) = 0 THEN
dateField := to_timestamp(dateField + 1,'DD/MON/YYYY HH24:MI:SS.FF');
END IF;
The way I see it, your problem is that you're comparing timestamps to strings.
Sample table:
SQL> create table test as
2 select to_timestamp('27.03.2020 04:00:00:000000', 'dd.mm.yyyy hh24:mi:ss:ff6') datum, 'A' name from dual
3 union all
4 select to_timestamp('28.03.2020 15:23:00:000000', 'dd.mm.yyyy hh24:mi:ss:ff6') datum, 'A' name from dual;
Table created.
Query should use timestamp, not string:
SQL> select *
2 from test
3 where datum between to_timestamp('25.03.2020 12:00:00:000000am', 'dd.mm.yyyy hh:mi:ss:ff6am') --> timestamp
4 and to_timestamp('28.03.2020 12:00:00:000000am', 'dd.mm.yyyy hh:mi:ss:ff6am'); --> timestamp
DATUM N
--------------------------------------------------------------------------- -
27.03.20 04:00:00,000000000 A
SQL>
You were kind of "lucky" (though, one might call it bad luck as your query didn't fail, but it produced wrong results, according to number of rows being returned) for not getting an error as my database raises (due to different NLS settings):
SQL> select *
2 from test
3 where datum between '25.03.2020 12:00:00:000000am' --> string
4 and '28.03.2020 12:00:00:000000am'; --> string
where datum between '25.03.2020 12:00:00:000000am'
*
ERROR at line 3:
ORA-01830: date format picture ends before converting entire input string
SQL>
Strings are handled differently than dates (or timestamps), or numbers. Maybe you'll see the difference clearly in this example:
SQL> with test (col) as
2 (select '1' from dual union all
3 select '9' from dual union all
4 select '20' from dual
5 )
6 select *
7 from test
8 where col < '9';
CO
--
1
20
SQL>
20 < 9? Yes, if those are strings. The same might have happened to you. Try with proper datatype.
When you do:
dateString :=to_char(dateField,'DD-MON-YYYY HH24:MI:SS.FF');
you are converting whatever is the initial value of dateField to a string; but it looks like that has has not been set yet, so you end up with an empty string (which is the same as null). Your original value of dateString is never being used.
If you skip that and just do:
dateString :='26-MAR-20 05.00.00.00000000 AM';
dateField := to_timestamp(dateString, 'DD/MON/YYYY HH24:MI:SS.FF') + 0.313 * INTERVAL '1' MINUTE;
then you are converting the 2-digit year 20 with a YYYY format element, which will turn it into year 0020, not 2020; but you also don't have AM in the format model, so it will get ORA-01830 anyway, and have HH24 instead of HH. I think your to_char() is attempting to 'correct' the string format, but that's not a great approach.
If you can't control the starting string format then the model has to match that:
dateString :='26-MAR-20 05.00.00.00000000 AM';
dateField := to_timestamp(dateString, 'DD-MON-RR HH:MI:SS.FF AM') + 0.313 * INTERVAL '1' MINUTE;
which gives dateField a value of 2020-03-26 05:00:18.780000.
Later on you do:
dateField := to_timestamp(dateField + 1,'DD/MON/YYYY HH24:MI:SS.FF');
which is also doing an implicit conversion of dateField + 1 - which is converted to a date, incidentally as timestamp + number is a date, not a timestamp - to a string; which will use your NLS_DATE_FORMAT. Presumably that is something like 'DD-MON-YYYY'.
So stepping through that:
dateField + 1 => date '2020-03-27 05:00:18' (losing fractional seconds)
implicit to_char(dateField + 1) => string '27-Mar-2020' (losing time)
to_timestamp(to_char(dateField + 1), '...') => timestamp '2020-03-27 00:00:00.000000' (with time at midnight).
So your between is, at best going to find records between 2020-03-26 05:00:18.780000 and 2020-03-27 00:00:00.0000000 - so it won't pick up any records later than midnight on the 27th.
Don't convert to and from strings when you don't need to; leave data in its native data type (timestamp in this case) and use direct manipulation with intervals.
Using between isn't ideal anyway, because it is inclusive; it would be better to end up with:
exceptiontime >= timestamp '2020-03-26 05:00:18.780000'
and exceptionTime < timestamp '2020-03-27 05:00:18.780000'
I am trying to add a day with a specific date using add_months in oracle database.
I wrote this line:
SELECT ADD_MONTHS('01-JAN-2018', MONTHS_BETWEEN('02-JAN-2018', '01-JAN-2018')) FROM DUAL;
this returns:
01-JAN-18
Why doesn't it return 02-JAN-18?? Can I add one day to the date using this function?
Why doesn't it return 02-JAN-18??
According to MONTHS_BETWEEN documentation,
The MONTHS_BETWEEN function calculates the number of months between
two dates. When the two dates have the same day component or are both
the last day of the month, then the return value is a whole number.
Otherwise, the return value includes a fraction that considers the
difference in the days based on a 31-day month
So,
select MONTHS_BETWEEN('02-JAN-2018', '01-JAN-2018') FROM DUAL ;
yields
.0322580645161290322580645161290322580645
ADD_MONTHS returns the date date plus integer months.
So, .0322.. is considered as integer 0 and your query is equivalent to
SELECT ADD_MONTHS('01-JAN-2018', 0) FROM DUAL;
In order to add 1 months, simply take the difference of two dates.
SELECT ADD_MONTHS(DATE '2018-01-01', DATE '2018-01-02' - DATE '2018-01-01') FROM DUAL;
Or better, add an INTERVAL of 1 month
SELECT DATE '2018-01-01' + INTERVAL '1' MONTH FROM DUAL;
To answer your question, add 1 day, simply use
SELECT DATE '2018-01-01' + 1 FROM DUAL;
I am trying to convert a value to the normal date format. But i am receiving the error ORA-01841: (full) year must be between -4713 and +9999, and not be 0 . I have researched the answers for a similar question in this website but that doesn't address my issue.
-- How the data looks like
select REPLACE(REGEXP_SUBSTR(data_detail, '([^|]*)([$|]|$)', 1, 5), '|', '') from land.LAND_DATA;
Output
2017-11-16T04:45:05.000Z
2017-11-16T04:46:04.000Z
When i am trying to convert the above mentioned output in to an appropriate date format i am receiving the error. What mistake am i doing here
select
TO_DATE(
TO_CHAR(
TO_TIMESTAMP(
REPLACE(REGEXP_SUBSTR(data_detail, '([^|]*)([$|]|$)', 1, 5), '|', ''),
'YYYY-MM-DD"T"HH24:MI:SS.ff3"Z"'),'MM/DD/YYYY HH24:MI:SS'),
'MM/DD/YYYY HH24:MI:SS')
from land.LAND_DATA;
These results are input data for the TO_TIMESTAMP function:
2017-11-16T04:45:05.000Z
2017-11-16T04:46:04.000Z
A year comes first, then a month and a day, and a time follows, which has milliseconds at the very end (after the comma).
This is a snippet from your code:
TO_TIMESTAMP( ....... , 'MM/DD/YYYY HH24:MI:SS' )
the second parameter is a date format model, these letters have the following meaning (in order):
MM - Month (01-12; January = 01).
/ - separator
DD - Day of month (1-31)
/ - separator
YYYY - 4-digit year; S prefixes BC dates with a minus sign.
- separator (space)
HH24 - Hour of day (0-23).
: - separator
MI - Minute (0-59).
: - separator
SS - Second (0-59).
The above format models doesn't match a format of input data, because a month comes first in this format, but your data starts with a year !!!
Use the following format instead:
'yyyy-mm-dd"T"hh24:mi:ss.ff"Z"'
You can test whether a format is fine or gives an error using a simple query like this:
select
to_timestamp( '2017-11-16T04:45:05.000Z', 'yyyy-mm-dd"T"hh24:mi:ss.ff"Z"')
from dual;
TO_TIMESTAMP('2017-11-16T04:4
-----------------------------
2017/11/16 04:45:05.000000000
Am getting the below issue when am using 'mon-d-yyyy' to convert date to char, as i need a single day digit for values from 1 to 9 days in a month.
When i use the 'mon-d-yyyy' format, am losing out on 5 days and getting a wrong date. Any help on this would be great.
select to_char(sysdate-22,'mon-d-yyyy') from dual;--aug-2-2017
select to_char(sysdate-22,'mon-dd-yyyy') from dual;--aug-07-2017
select sysdate-22 from dual;--07-AUG-17 11.06.43
In Oracle date formats, d gets the day of week. The 2 in your output means monday, not august the 2nd.
Try using Fill Mode as Format Model Modifier
select to_char(sysdate-22,'mon-fmdd-yyyy') from dual;
One option might be to piece together the date output you want:
SELECT
TO_CHAR(sysdate-22, 'mon-') ||
TRIM(LEADING '0' FROM TO_CHAR(sysdate-22, 'dd-')) ||
TO_CHAR(sysdate-22, 'yyyy')
FROM dual;
The middle term involving TRIM strips off the leading zeroes, if present, from the date.
Output:
Demo here:
Rextester
SQL>SELECT TO_CHAR(TO_DATE('29-AUG-2017','DD-MON-YYYY') - 22,'"WEEKDAY :"D, MON-FMDD-YYYY') "Before22Days" FROM DUAL;
D- Gives you a numeric weekday(2nd weekday in a week) on AUG-07-2017.
DD-Gives a Numeric Month Day i.e,07th
FMDD-Gives 7th
Before22Days
----------------------
WEEKDAY :2, AUG-7-2017
I need to query 2 tables, one contains a TIMESTAMP(6) column, other contains a DATE column. I want to write a select statement that prints both values and diff between these two in third column.
SB_BATCH.B_CREATE_DT - timestamp
SB_MESSAGE.M_START_TIME - date
SELECT SB_BATCH.B_UID, SB_BATCH.B_CREATE_DT, SB_MESSAGE.M_START_TIME,
to_date(to_char(SB_BATCH.B_CREATE_DT), 'DD-MON-RR HH24:MI:SS') as time_in_minutes
FROM SB_BATCH, SB_MESSAGE
WHERE
SB_BATCH.B_UID = SB_MESSAGE.M_B_UID;
Result:
Error report -
SQL Error: ORA-01830: date format picture ends before converting entire input string
01830. 00000 - "date format picture ends before converting entire input string"
You can subtract two timestamps to get an INTERVAL DAY TO SECOND, from which you calculate how many minutes elapsed between the two timestamps. In order to convert SB_MESSAGE.M_START_TIME to a timestamp you can use CAST.
Note that I have also removed your implicit table join with an explicit INNER JOIN, moving the join condition to the ON clause.
SELECT t.B_UID,
t.B_CREATE_DT,
t.M_START_TIME,
EXTRACT(DAY FROM t.diff)*24*60 +
EXTRACT(HOUR FROM t.diff)*60 +
EXTRACT(MINUTE FROM t.diff) +
ROUND(EXTRACT(SECOND FROM t.diff) / 60.0) AS diff_in_minutes
FROM
(
SELECT SB_BATCH.B_UID,
SB_BATCH.B_CREATE_DT,
SB_MESSAGE.M_START_TIME,
SB_BATCH.B_CREATE_DT - CAST(SB_MESSAGE.M_START_TIME AS TIMESTAMP) AS diff
FROM SB_BATCH
INNER JOIN SB_MESSAGE
ON SB_BATCH.B_UID = SB_MESSAGE.M_B_UID
) t
Convert the timestamp to a date using cast(... as date). Then take the difference between the dates, which is a number - expressed in days, so if you want it in minutes, multiply by 24*60. Then round the result as needed. I made up a small example below to isolate just the steps needed to answer your question. (Note that your query has many other problems, for example you didn't actually take a difference of anything anywhere. If you need help with your query in general, please post it as a separate question.)
select ts, dt, round( (sysdate - cast(ts as date))*24*60, 2) as time_diff_in_minutes
from (select to_timestamp('2016-08-23 03:22:44.734000', 'yyyy-mm-dd hh24:mi:ss.ff') as ts,
sysdate as dt from dual )
;
TS DT TIME_DIFF_IN_MINUTES
-------------------------------- ------------------- --------------------
2016-08-23 03:22:44.734000000 2016-08-23 08:09:15 286.52