I have a model SettlementEntries that has a relation to a sub table return $this->hasMany('App\Online', 'entry_id');
When trying to fetch one single Entry i'm able to sum my collection like in the example below.
$item = SettlementEntries::find($id);
$item->Online->sum('field'); // returns the correct sum
My problem starts when the $id is an array, so my result contains 2 SettlementEntries.
$items = SettlementEntries::find($ids);
$items->Online->sum('field'); <- returns zero
What is the correct way to retrieve those sums?
Laravel's Collection makes this very easy, by using dot notation. Some examples here.
The simple way (dot notation):
$sum = $items->sum('Online.field');
More explicit (callback):
Or, if you want to be more explicit, e.g. using conditions/filters: provide a Closure:
$sum = $items->sum(function($item) {
return $item->Online->sum('field');
});
Related
I want to get all the data of today's Date, but during getting it I want to apply an operation on the data of one column only NOT others. This operation is from another function.
$data = Net::whereDate('created_at', Carbon::today())->get();
I have two options:
During getting data, call to that function on the specific column
After getting data, put a loop and then apply that operation and save data into new object
In this table, there is a column called profit, and I want to encode this profit into alphabets by calling encode_code() function remaining the other data as it is.
I don't know how I can do this, please help me if anyone knows.
You can use a foreach loop to get each object from the collection and for each of those object,call the desired function.
$data = Net::whereDate('created_at', Carbon::today())->get();
foreach($data as $key => $dat)
{
$data[$key]->profit = encode_code($dat->profit);
}
I think you should call the function and turn it like this
I just didn't know what you wanted to do, so this is my best
$data = Net::whereDate('created_at', Carbon::today())->get();
foreach($data as $i => $d){
$data[$i]->profit = encode_code（$d->profit);
}
Of course you could loop through your result and encode each row, but this would prevent you from reusing this code.
Instead you could put that encode function directly into the model, so that you can reuse it everywhere:
public function getEncodedProfit() {
return encode_code($this->profit);
}
Now you can just use this function everywhere in your controllers or views like that:
echo $net->getEncodedProfit();
I have an array of ids that i want to sort a given column by them in the collection.
For example,
$suppliersOrder = [8,7,5,1,3,4];
$items = Items::get()->sortBy(function($model) use ($suppliersOrder) {
return array_search($model->supplier_id, $suppliersOrder);
})->values();
This acts like ordering items as [1,3,4,5,7,8] instead of the given order. And if I try sortByDesc, likewise [8,7,5,4,3,1] but I couldn't figure out the way to actually sort them as my given array's order.
My ultimate goal is then running $items->groupBy('supplier.name') so I can have my desired order.
What Alexander Villalobos suggested in the comments, I changed my code like this:
$items = Items::get()->sortBy(function($model) use ($suppliersOrder) {
return rsort($model->supplier_id, $suppliersOrder);
});
Indirect modification of overloaded property App\Item::$supplier_id has no effect
$suppliersOrder = [8,7,5,1,3,4];
$items = Items::get()->sortBy(function($row,$key) use ($suppliersOrder) {
return array_search($row->supplier_id, $suppliersOrder);
});
This should give you sorted collection of items by the order you described in $suppliersOrder. As per Laravel docs, the parameters to the callback function include one being the row for the collection and another being the key of that row in the collection.
Using Laravel 5.3, I have a model with the following function
public function myData() {
return $this->hasMany(MyData::class);
}
and in my collection I have the following
$my_data = MyModel->myData()->get();
All good so far. If I return $my_data I get an eloquent collection with three items.
What I need now though is to create a duplicate of that collection but containing only three of the fields.
I have tried several different things, each of which return an error. The following is the closest I have got, but this returns an empty array - I assume because the fields are located one level deeper than the collection object.
$new_collection = $my_data->only(['field_1', 'field_2', 'field_3']);
What would be the correct way to create a new collection containing all three items, each with only the three selected fields?
Thanks for your help
You could use map:
$slimmed_down = $collection->map(function ($item, $key) {
return [
'field_1' => $item->field_1,
'field_2' => $item->field_2,
'field_3' => $item->field_3
];
});
This will return a new Collection with just the values you want. As far as I know there isn't any other method that does what you want, so iterating over every item and selecting the fields this way is one of the few solutions.
The advantage of using map instead of a standard foreach loop is that when you use map it returns a new instance of Collection.
Edit:
After some thoughts and research about this, the problem you'll have created is that the all the values in the Collection aren't instances of anything anymore. If you don't mind this effect, an even prettier and faster way would be to do this:
$slimmed_down = $collection->toArray()->only(['field_1', 'field_2', 'field_3']);
This basically has the same result.
Using Laravel 9, I just had the same issue :
$my_data->only(['field_1', 'field_2', 'field_3']);
returning an empty array.
I solved it with :
$my_data->map->only(['field_1', 'field_2', 'field_3']);
I want to get alternative products pictures.
dd($alternativeProduct->pictures);
When die and dump i get this result.
I need to get only the picture which is main. If main equals to 1. It is main picture.
When I write
dd($alternativeProduct->pictures->where('main', 1))
I got an empty array.
Here is my relation with Product and Picture relation
public function pictures(){
return $this->hasMany('App\Models\ProductPicture');
}
What can i do ?
The where method in a collection has three parameters: $key, $value and $strict, the last one defaults to true if not passed when calling the method. When $strict is true the comparison is done via === which does not do type coercion, meaning "1" === 1 is false.
From your dump data, I can see that "main" => "1" which means it's a string and you're passing an integer 1 to the where method, resulting in what I described above as a false condition and returning an empty result set. You can fix that by disabling strict comparison:
$alternativeProduct->pictures->where('main', 1, false);
// or the equivalent helper whereLoose
$alternativeProduct->pictures->whereLoose('main', 1);
Or passing a string as the value:
$alternativeProduct->pictures->where('main', "1");
That being said, if that's the only place you're using that collection in that request's context, I suggest that you filter the results at the database level, not after they are fetched, like so:
$alternativeProduct->pictures()->where('main', 1)->get();
Accessing the relations as a method ->pictures(), instead of as a property ->pictures, will return a Query Builder instance that allows you to add conditions to the database query and only fetch the actual items you need from the database, instead of fetching them all and filtering them out afterwards.
You may want to use whereLoose instead:
dd($alternativeProduct->pictures->whereLoose('main', 1))
From the Laravel docs:
The where method uses strict comparisons when checking item values. Use the whereLoose method to filter using "loose" comparisons.
I am using a CDbCriteria with its own conditions, with & order clauses. However, the order i want to give to the elements in the array is way too complex to specify in the order clause.
The solution i have in mind consists of obtaining the active records with the defined criteria like this
$theModelsINeed = MyModel::model()->findAll($criteria);
and then rearrange the order from my php code. How can i do this? I mean, i know how to iterate through its elements, but i don´t know if it is possible to actually change them.
I have been looking into this link about populating active records, but it seems quite complicated and maybe someone could have some better advice.
Thanks
There is nothing special about Yii's active records. The find family of methods will return an array of objects, and you can sort this array like any other array in PHP.
If you have complex sort criteria, this means that probably the best tool for this is usort. Since you will be dealing with objects, your user-defined comparison functions will look something like this:
function compare($x, $y)
{
// First sort criterion: $obj->Name
if ($x->Name != $y->Name) {
return $x->Name < $y->Name ? -1 : 1; // this is an ascending sort
}
// Second sort criterion: $obj->Age
if ($x->Age != $y->Age) {
return $x->Age < $y->Age ? 1 : -1; // this is a descending sort
}
// Add more criteria here
return 0; // if we get this far, the items are equal
}
If you do want to get an array as a result, you can use this method for fetching data that supports dbCriteria:
$model = MyModel::model()->myScope();
$model->dbCriteria->condition .= " AND date BETWEEN :d1 AND :d2";
$model->dbCriteria->order = 'field1 ASC, field2 DESC';
$model->dbCriteria->params = array(':d1'=>$d1, ':d2'=>$d2);
$theModelsINeed = $model->getCommandBuilder()
->createFindCommand($model->tableSchema, $model->dbCriteria)
->queryAll();
The above example shows using a defined scope and modifying the condition with named parameters.
If you don't need Active Record, you could also look into Query Builder, but the above method has worked pretty well for me when I want to use AR but need an array for my result.