I have 2 files like below. I need a script to find string from file2 in file1 and delete the line which contains the string from file1 and put it in another file (output1.txt). Also it shld print the lines deleted and the string if the string doesn't exist in File1 (Ouput2.txt).
File1:
Apple
Boy: Goes to school
Cat
File2:
Boy
Dog
I need output like below.
Output1.txt:
Apple
Cat
Output2.txt:
Dog
Can anyone help please
If you have awk available on your system:
awk -v FS='[ :]' 'NR==FNR{a[$1]}NR>FNR&&!($1 in a){print $1}' File2 File1 > Output1.txt
awk -v FS='[ :]' 'NR==FNR{a[$1]}NR>FNR&&!($1 in a){print $1}' File1 File2 > Output2.txt
The script is storing in an array a the first element $1 of the first file given in argument.
If the first parameter of the second file is not part of the array, print it.
Note that the delimiter is either a space or a :
Related
I need to get uniq lines when comparing 2 files. These files containing field separator ":" which should be treated as the end of line while comparing strings.
The file1 contains these lines
apple:tasty
apple:red
orange:nice
kiwi:awesome
kiwi:expensive
banana:big
grape:green
orange:oval
banana:long
The file2 contains these lines
orange:nice
banana:long
The output file should be (2 occurrences of orange and 2 occurrences of banana deleted)
apple:tasty
apple:red
kiwi:awesome
kiwi:expensive
grape:green
So the only strings before : should be compared
Is it possible to complete this task in 1 command ?
I tried to complete the task in such way but field separator does not work in that situation.
awk -F: 'FNR==NR {a[$0]++; next} !a[$0]' file1 file2 > outputfile
You basically had it, but $0 refers to the whole line when you want to deal with only the first field, which is $1.
Also you need to take care with the order of the input files. To use the values from file2 for deciding which lines to include from file1, process file2 first:
$ awk -F: 'FNR==NR {a[$1]++; next} !a[$1]' file2 file1
apple:tasty
apple:red
kiwi:awesome
kiwi:expensive
grape:green
One comment: awk is very ineffective with arrays. In real life with big files, better use something like:
comm -3 <(cut -d : -f 1 f1 | sort -u) <(cut -d : -f 1 f2 | sort -u) | grep -h -f /dev/stdin f1 f2
I have two files - file1 & file2.
file1 contains (only words) says-
ABC
YUI
GHJ
I8O
..................
file2 contains many para.
dfghjo ABC kll njjgg bla bla
GHJ njhjckhv chasjvackvh ..
ihbjhi hbhibb jh jbiibi
...................
I am using below command to get the matching lines which contains word from file1 in file2
grep -Ff file1 file2
(Gives output of lines where words of file1 found in file2)
I also need the words which doesn't match/found in file 2 and unable to find Un-matching word.
Can anyone help in getting below output
YUI
I8O
i am looking one liner command (via grep,awk,sed), as i am using pssh command and can't use while,for loop
You can print only the matched parts with -o.
$ grep -oFf file1 file2
ABC
GHJ
Use that output as a list of patterns for a search in file1. Process substitution <(cmd) simulates a file containing the output of cmd. With -v you can print lines that did not match. If file1 contains two lines such that one line is a substring of another line you may want to add -x (only match whole lines) to prevent false positives.
$ grep -vxFf <(grep -oFf file1 file2) file1
YUI
I8O
Using Perl - both matched/non-matched in same one-liner
$ cat sinw.txt
ABC
YUI
GHJ
I8O
$ cat sin_in.txt
dfghjo ABC kll njjgg bla bla
GHJ njhjckhv chasjvackvh ..
ihbjhi hbhibb jh jbiibi
$ perl -lne '
BEGIN { %x=map{chomp;$_=>1} qx(cat sinw.txt); $w="\\b".join("\|",keys %x)."\\b"}
print "$&" and delete($x{$&}) if /$w/ ;
END { print "\nnon-matched\n".join("\n", keys %x) }
' sin_in.txt
ABC
GHJ
non-matched
I8O
YUI
$
Getting only the non-matched
$ perl -lne '
BEGIN {
%x = map { chomp; $_=>1 } qx(cat sinw.txt);
$w = "\\b" . join("\|",keys %x) . "\\b"
}
delete($x{$&}) if /$w/;
END { print "\nnon-matched\n".join("\n", keys %x) }
' sin_in.txt
non-matched
I8O
YUI
$
Note that even a single use of $& variable used to be very expensive for the whole program, in Perl versions prior to 5.20.
Assuming your "words" in file1 are in more than 1 line :
while read line
do
for word in $line
do
if ! grep -q $word file2
then echo $word not found
fi
done
done < file1
For Un-matching words, here's one GNU awk solution:
awk 'NR==FNR{a[$0];next} !($1 in a)' RS='[ \n]' file2 file1
YUI
I8O
Or !($0 in a), it's the same. Since I set RS='[ \n]', every space as line separator too.
And note that I read file2 first, and then file1.
If file2 could be empty, you should change NR==FNR to different file checking methods, like ARGIND==1 for GNU awk, or FILENAME=="file2", or FILENAME==ARGV[1] etc.
Same mechanism for only the matched one too:
awk 'NR==FNR{a[$0];next} $0 in a' RS='[ \n]' file2 file1
ABC
GHJ
I have a 2 files:
file1.txt
rs142159069:45000079:TACTTCTTGGACATTTCC:T 45000079
rs111285978:45000103:A:AT 45000103
rs190363568:45000168:C:T 45000168
file2.txt
rs142159069:45000079:TACTTCTTGGACATTTCC:T rs142159069
rs111285978:45000103:A:AT rs111285978
rs190363568:45000168:C:T rs190363568
Using file2.txt, I want to replace the names (column2 of file1.txt which is column1 of file2.txt) by the entry in column 2. The output file would then be:
rs142159069 45000079
rs111285978 45000103
rs190363568 45000168
I have tried inputing the columns of file2.txt but without success:
while read -r a b
do
cat file1.txt | sed s'/$a/$b/'
done < file2.txt
I am quite new to bash. Also, not sure how to write an output file with my command. Any help would be deeply appreciated.
In your case, using awk or perl would be easier, if you are willing to accept an answer without sed:
awk '(NR==FNR){out[$1]=$2;next}{out[$1]=out[$1]" "$2}END{for (i in out){print out[i]} }' file2.txt file1.txt > output.txt
output.txt :
rs142159069 45000079
rs111285978 45000103
rs190363568 45000168
Note: this assume all symbols in column1 are unique, and that they are all present in both files
explanation:
(NR==FNR){out[$1]=$2;next} : while you are parsing the first file, create a map with the name from the first column as key
{out[$1]=out[$1]" "$2} : append the value from the second column
END{for (i in out){print out[i]} } : print all the values in the map
Apparently $2 of file2 is part of $1 of file1, so you could use awk and redefine FS:
$ awk -F"[: ]" '{print $1,$NF}' file1
rs142159069 45000079
rs111285978 45000103
rs190363568 45000168
I have a binary file with the following format:
file
04550525023506346054(....)64645634636346346344363468badcafe268664363463463463463463463464647(....)474017497417428badcafe34376362623626(....)262
and I need to split it in multiple files (using awk) that look like this:
file1
045505250235063460546464563463634634634436346
file2
8badcafe26866436346346346346346346346464747401749741742
file3
8badcafe34376362623626262
I have found on stackoverflow the following line:
cat file |
awk -v RS="\x8b\xad\xca\xfe" 'NR > 1 { print RS $0 > "file" (NR-1); close("file" (NR-1)) }'
and it works for all the files but the first.
Indeed, the file I called file1, is not created because it does not start with the eye catcher 8badcafe.
How can I fix the previous command line in order to have the output I need?
Thanks!
try:
awk '{gsub(/8badcafe/,"\n&");num=split($0, a,"\n");for(i=1;i<=num;i++){print a[i] > "file"++e}}' Input_file
Substituting the string "8badcafe" to a new line and string's value. Then splitting the current line into an array named a whose field separator is new line. then traversing through the array a's all values and printing them one by one into the file1, file2.... with "file" and a increasing count variable named e.
Output files as follows:
cat file1
045505250235063460546464563463634634634436346
cat file2
8badcafe26866436346346346346346346346464747401749741742
cat file3
8badcafe34376362623626262
File 1 has long string of data between <PhotoField1> multiple times.
Example:
<PhotoField1>alidkfjaeijwoeij<PhotoField1>akdfjalskdfasd<PhotoField1>
File 2 has list of IDs that i want to use to label the Files
Example:
A00565415
A00505050
A54531245
I have an AWK command to parse each string between <PhotoField1> from File1 into its own file, but it only labels the files temp with numbers:
awk -v RS="<PhotoField1>" '{ print $0 > "temp" NR }' File1.xml
I need to replace the temp* part with the a line from the 2nd file
So the new files would be named A00565415, A00505050, A54531245, etc..
- it would be excellent if I could add a .txt to the end of the files: A54531245.txt
The awk command works great for separating it into different files, but i need to be able to name them based on the File2 list.
awk 'NR==FNR{fname[NR]=$0".txt";next} {print > fname[FNR]}' File2.list RS="<PhotoField1>" File1.xml
You can use this awk:
awk -v RS="<PhotoField1>|\n" 'FNR==NR{a[NR]=$0; next}
NF{ print $0 > a[FNR] ".txt" }' file2 file1